Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Hybridisation of 'P' in PO_4^(3-) is same as that of : -

Answer»

N in `NO_3^(-)`
S' in `SO_3`
I' in `IC l_2^(+)`
I' in `IC l_4^(-)`

SOLUTION :`barO-undersetOunderset"||"OVERSET(" "O^-)overset|P-O^(-) sp^3 `hybridised
Discussion
2.

Hybridisation of Xenon in Xenon hexafluoride is ____.

Answer»

SOLUTION :`sp^3d^3`
Discussion
3.

Hybridisation of P in phosphine is,……………….. .

Answer»

`SP^(3)d`
`sp^(3)d^(2)`
`sp^(3)d^(3)`
`sp^(3)`

SOLUTION :`sp^(3)`
Discussion
4.

Hybridisation of oxygen in diethyl ether is

Answer»

SP
`sp^(2)`
`sp^(3)`
`sp^(3)d`

ANSWER :C
Discussion
5.

Hybridisationof chromiumionsand dichromateions is

Answer»

`SP^(2)`
`Sp^(3)d`
both (a) and ( B)
NONE of these

Answer :B
Discussion
6.

The hybridisation of metal ion in square planar complexes in

Answer»

`sp^2`
`sp^3`
`dsp^2`
`dsp^3`

ANSWER :C
Discussion
7.

Hybridisation of Chlorine atom in ClF_(3) molecules is

Answer»

`SP`
`sp^(3)`
`sp^(3)`
`Sp^(3)d`

ANSWER :B
Discussion
8.

Hybridisation of central sulphur in all oxo anions of sulphur is

Answer»

`SP ^(3)d`
`sp^(3)`
`sp^(3)d ^(2)`
`sp^(2)d`

ANSWER :B
Discussion
9.

Hybridisation of central atom changes for which of the following molecule when undergoes dimerization?

Answer»

`CF_3`
`CIO_3`
`NO_2`
All of these

ANSWER :D
Discussion
10.

Hybridisation of carbon in - CHO group is

Answer»

SP
`sp^(2)`
`sp^(3)`
none of these

Answer :B
Discussion
11.

Hybridisation of carbon in carbonyl group is :

Answer»

SP
`sp^2`
`sp^3`
None

Answer :B
Discussion
12.

Hybridisation of carbon atom in the functional group of an organic carboxylic acid is

Answer»

`sp^(3)`
`sp^(2)`
`sp`
`DSP^(2)`

Answer :B
Discussion
13.

Hybridisation is the chemists attempt to explain the observed molecular shape by constructing hybridised atomic orbitals with the appropriate inter orbital angles. The molecule for which d eviation form normal bond angle is observed, VSEPR theory suggest electron pair repulsive interaction (lp - lp gt lp - bp - bp). While from hybridisation point of view that is departure from normal hybridisation beacuse the angle between any equivalent hybrid orbitals determine the fraction of s and p character of the hybrid and vice - versa. An element 'A' has outer shell electronic configuration is 5s^(2)5p^(6). If A form covalent compoun AF_(2) with fluorine. The orbitals used by 'A' for bonding are

Answer»

d-orbitals
p-orbitals
SP-hybridised ORBITAL
`sp^(3)d` HYBRID orbital

Solution :
Discussion
14.

Hybridisation is a theoretical concept, as state of hybridisation can not be detected ever the spectroscopically: unlike intermediates or transition state in various reactions but it corrects the predictions which are based on overlapping of pure atomic orbitals. VSEPR theory predicts precisely shape and bond angle in a given molecule. Which of the following molecule /ions which are not planr?

Answer»

`[IF_(4)]^(-)`
`[IF_(4)]^(+)`
`[NH+(2)]^(-)`
All of the above are PLANAR

Solution :(A) `[IF_(4)]^(-)RARR` Square3 planar
(B) `[IF_(4)]^(+)rarr` SEE SAW
(C ) `[NH_(2)]^(-)rarrV//` Bent planar
Discussion
15.

Hybridisation involves the mixing of orbitals having comparable energhies of same atom. Hybridised orbitals perform efficient overlapping than overlapping by pure s, p or orbitals. Consider the following compounds and select the incorrect statement from the following : NH_(3),PH_(3),H_(2)S,SO_(2),BF_(3),PCl_(3),IF_(7),P_(4),H_(2)

Answer»

Six molecules out of given compounds involves hybridisation
Three molecules are hypervalent compounds
Six molecules out of above compounds are non-planar in STRUCTURE
TWO molecules out of given compounds involves `(d pi- p pi)` BONDING as well as also involves `( p pi- p pi)` bonding

Solution :(a) INVOLVEMENT of hybridisation `(NH_(3),SO_(2),SO_(3),BF_(3), PCl_(3),IF_(7))`
(b) Hypervalent compounds `(SO_(2),SO_(3),IF_(7))`
(C ) Non-planar molecules `(NH_(3),PH_(3),PCl_(3),IF_(7),P_(4))`
(d) `SO_(2)` [one(` p pi- p pi`) bond and one `(d pi- p pi)` bond], `SO_(3)` [ one `(p pi-p pi)` bond and two `(d pi - p pi)` bonds]
Discussion
16.

Hybridisation is the chemists attempt to explain the observed molecular shape by constructing hybridised atomic orbitals with the appropriate inter orbital angles. The molecule for which d eviation form normal bond angle is observed, VSEPR theory suggest electron pair repulsive interaction (lp - lp gt lp - bp - bp). While from hybridisation point of view that is departure from normal hybridisation beacuse the angle between any equivalent hybrid orbitals determine the fraction of s and p character of the hybrid and vice - versa. In which species number of lone pair on iodine and number of d-orbitals used in hybridisation by iodine are same

Answer»

`ICl_(2)^(+)`
`ICl_(2)^(-)`
`IF_(2)`
`ICl_(4)^(-)`

SOLUTION :
Discussion
17.

Hybridisation involves the mixing of orbitals having comparable energhies of same atom. Hybridised orbitals perform efficient overlapping than overlapping by pure s, p or orbitals. Which of the following is not correctly match between given species and type of overlapping ?

Answer»

<P>`XeO_(3)` : Three `(d PI - p pi)` bonds
`H_(2)SO_(4)` : Two `(d pi - p pi)` bonds
`SO_(3)` : Three `(d pi - p pi)` bonds
`HClO_(4)` : Three `(d pi - p pi)` bonds

Solution :
Discussion
18.

Hybridisation involves:

Answer»

ADDITION of ELECTRON pair
Mixing of ATOMIC orbitals
Removal of electrons
Separation of orbitals

Answer :B
Discussion
19.

Hybridisation inCIF_(3) is

Answer»

`sp^(3)`
`sp^(3)d`
`DSP^(3)`
`sp^(3)d^(2)`

ANSWER :B::C::D
Discussion
20.

hy does PCI_(3) fume in moisture ?

Answer»

Solution :In PRESENCE of moisture `(H_(2)O), PCI_(3)` undergoes hydrolysis giving fumes of HCI.
`PCI_(3) + 3H_(2)O rarr UNDERSET("PHOSPHOROUS acid")(H_(3)PO_(3))+ 3HCI`
Discussion
21.

A weak acid HX has the dissociation constant 1 xx 10^(-5)M. It forms a salt NaX on reaction with alkali. The percentage hydrolysis of 0.1M solution of NaX is

Answer»


ANSWER :1
Discussion
22.

HX is a weak acid (K_(a)=10^(-5)). It forms a salt NaX (0.1 M) on reacting with caustic soda. The degree of hydrolysis of NaX is

Answer»

`0.01%`
`0.0001%`
`0.1%`
`0.5%`

ANSWER :A
Discussion
23.

Hw may spatial orientations are possible in the following compound ?

Answer»

2
8
6
4

Answer :B
Discussion
24.

HVZ reaction of acetic acid leads to the formation of

Answer»

`CH_3 COOH`
`HCOOH`
`C CI_3COOH`
`(COOH)_2`

ANSWER :C
Discussion
25.

HVZ reaction leads to the formation of

Answer»

Chlorosubsititued ACIDS
FORMIC ACID
Oxalic acid
ACETIC acid

ANSWER :A
Discussion
26.

HVZ reaction leads to the formation of:

Answer»

ACETIC ACID
Formic acid
Chlorosubstituted acid
Oxalic acid

ANSWER :C
Discussion
27.

Write HVZ reaction.

Answer»

`alpha`-halo ACID
`BETA`-halo acid
`alpha , beta` - UNSATURATED acid
None of the above

Answer :A
Discussion
28.

HVZ reaction is used to prepare :

Answer»

`ALPHA` -HALO ACID
`BETA`-Halo acid
`alpha-beta`-UNSATURATED acid
None of these.

Answer :A
Discussion
29.

HVZ reaction is characteristic reaction of

Answer»

`alpha - H` ATOM
`BETA - H` atom
` GAMMA - H` atom
`delta - H` atom

ANSWER :A
Discussion
30.

HVZ reaction is specific for,

Answer»

REPLACEMENT of `BETA`-hydrogens
Replacement of `ALPHA`- hydrogens
Replacement of `beta` -carbons
Replacement of `alpha`-carbons

Answer :B
Discussion
31.

Human stomatch produces acid X which helps in digestion

Answer»

MUST be pure water
must be an acid
is not a base
is neither a base nor an acid

Solution :A pure water has pH =7 ie neutral THUS has no effect on LITMUS
Discussion
32.

Human hair wigs are prepared from

Answer»

GLYPTAL
NOMEX
Lexon
Dynel

ANSWER :D
Discussion
33.

Human cannot use cellulose as food- Why ?

Answer»

Solution :HUMAN cannot USE cellulose as food because our digestive system do not CONTAIN the necessary enzymes such as glycosidases (or) cellulases that can hydrolyse the cellulose. But animals contain cellulose enzyme in their digestive system and they can DIGEST cellulose. So cellulose can USED as food for animals but not for human.
Discussion
34.

Human digestive system does not hydrolyse :

Answer»

STARCH
MALTOSE
GLYCOGEN
Cellulose

Answer :D
Discussion
35.

Humancannotusecelluloseas food- Why ?

Answer»

SOLUTION :Human cannotuse celluloseas foodbecauseour digestive SYSTEM do notcontainthenecessaryenzymes suchasglycosidases (or) cellulosethat can hydrolyse the celluose.Butanimalscontain CELLULOSE enzymein theirdigestivesystemand they candigest cellulose. So cellulosecan usedas foodfor animalsbutnot forhuman .
Discussion
36.

HSO_(4)^(-) + OH^(-) rarr SO_(4)^(2-) + H_(2)O Which is correct about conjugate acid base pair

Answer»

`HSO_(4)^(-)` is conjugate acid of BASE `SO_(4)^(2-)`
`HSO_(4)^(-)` is conjugate base of acid `SO_(4)^(2-)`
`SO_(4)^(2-)` is conjugate acid of base `HSO_(4)^(-)`
NONE of these

Solution :`UNDERSET("Conjugate acid")(HSO_(4)^(-)) + OH^(-) rarr underset("Conjugate base")(SO_(4)^(2-)+ H_(2)O)`
Discussion
37.

Human body is an example of:

Answer»

OPEN system
Closed system
Isolated system
None

Answer :B
Discussion
38.

H^(Theta) always act as

Answer»

Nucleophile
Base
Electrophile
Ambiphile

Answer :B
Discussion
39.

HPO_3 has the ability to form metaphosphates , wich can be polymerised. Calogon is a salt of HPO_3 . How many time it is polymerised ?

Answer»

Solution :SODIUM Hexametaphosphate
`HPO_3+NaOH rarrNaPO_3 RARR (NaPO_3)_(6) implies6` times polymerisation
Discussion
40.

HPO_3 + H_2O overset(Heat)rarr ? The product is:

Answer»

`H_4P_2O_7`
`H_3PO_3`
`H_3PO_4`
`P_2O_5`

ANSWER :C
Discussion
41.

HPO_3 act as

Answer»

REDUCING AGENT
Oxidation agent
HYDROLYTIC agent
Bleaching agent

Answer :B
Discussion
42.

Howmany of the following compounds are dissolve in aqeous solution of NaOH (i) Phenol (ii) Cyclohexanol (iii) 2, 4-di nitro phenol (iv) Benzoic (v) Benzene sulphonic acid (vi) P-cresol (vii) P-methoxy phenol (viii) alpha- naphthol (ix) N-methyl aniline

Answer»


ANSWER :3
Discussion
43.

Howmany of the following compounds are dissolve in aqeous solution of NaOH (1) Phenol (2) p-cresol (3) Benzoic acid (4) Benzene sulphonic acid (5) Aniline (6) P-toluedine (7) Picric acid (8) Squaric acid

Answer»


ANSWER :6
Discussion
44.

Howw many of the following are ores of zinc : Ainc red Calamine , Willemite ,Hemimorphite,Siderite ,phyrolusite ,olivine ,Anglesite

Answer»


ANSWER :5
Discussion
45.

Howmany metals are present in the ore chalcopyrite, from which 80% of the world's copper production comes.

Answer»


SOLUTION :There are two metals are PRESENT in the ore CHALCOPYRITES `(CuFeS_(2))` one is CU and other is Fe.
Discussion
46.

How many of the following alloys contain 'Al' metal Magnalium , Duralumin , Brass , Bronze , Rolled gold , Nickeloy, Nickel steel, Invar, Alnico, Solder

Answer»


SOLUTION :Mangnalium , DURALUMIN, ALNICO
Discussion
47.

Howmany metals are commercially extracted by pyrometallurgy from the given metals?( Cu, Fe, Sn, Au, K, Na )

Answer»


Solution :CU, FE, SN can be commercially EXTRACTED by pyrometallurgy
Discussion
48.

Name any two ores of zinc. How is zinc extracted from zinc oxide?

Answer»

SOLUTION :When zine oxide is HEATED with COKE at 1673 K, coke REDUCED zinc oxide to zinc `ZnO + C rarr Zn + CO`.
Discussion
49.

How XeF_4 is prepared ?

Answer»

Solution :It is prepared by heating a 1:5 mixture of XENON and fluorine in a NICKEL tube heated to `400^@` C and 6 ATMOSPHERIC PRESSURE for a few hours
Discussion
50.

How XeF_2is prepared?

Answer»

SOLUTION :It is PREPARED by heatinh a mixture of XENON and FLUORINE using light from mercury lamp
`Xe+ F_2 rarr XeF_2`
Discussion