Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.	Glyptal is a polymer of
Answer» malonic ACID + ETHYLENE GLYCOL phthalic acid + ethylene glycol maleic acid + formaldehyde ACETIC acid + phenol . Solution :

2.	Glyptal is a polymer of :
Answer» ETHYLENE GLYCOL and PHTHALIC ACID Ethylene glycol and adipicacid Ethylene glycol and terephthalic acid CAPROLACTUM and formaldehyde Answer :A

3.	Glypltal or alkyds is polymer of:
Answer» ETHYLENE GLYCOL and PHTHALIC ACID Ethylene and phathalic acid Phthalic acid and acetylene None of these Answer :A

4.	Glyoxal is
Answer» `CH_(2)O-CH_(2)O` `{:(CH_(2)OH),(\|),(CH_(2)OH):}` `{:(CHO),(\|),(CHO):}` `{:(CH_(2)OH),(\|),(CHO):}` Answer :C

5.	Glyoxal is :
Answer» `CH_2OH-CHO` `CH_2=OH` `CHO-CHO` `CH_2=CHCHO` ANSWER :C

6.	Glyeogen is
Answer» Structurally similar to AMYLOPECTIN but extensively branched Structurally very much similar to amylopctin a STRUCTURAL polysacharide a polymer of `beta`- D- glucose UNITS. Solution :Glycogen is called animal starch because its structure is similar to that of amylopectin, the main difference between glycogen and amylopectin is that amylopectin chains consists of about 20 - 25 GLUCOSEUNITS but glycogen charins are much shorter and consists of about 10 - 14 glucose units, i.e., glycogenis highly brached.

7.	Glycosidiclinkage is present in :
Answer» SUCROSE STARCH glucose fractose Solution :N//A

8.	Glycoside linkage is :
Answer» An ACETAL linkage An ETHER linkage An ESTER linkage An AMIDE linkage Answer :A

9.	Glycolic acid and lactic acid on polymerisation gives
Answer» ORLON DEXTRON DACRON PHBV Answer :B

10.	"Glycol" overset(773 K) to 'A'. Identify 'A'
Answer» ANSWER :A

11.	Glycol reacts with PCI_3 and gives ethylene dichloride . What will be the product, if it reacts with P+I_2:
Answer» ETHYLENE iodide Ethylene iodohydrin Ethylene None Answer :C

12.	Glycol oon intramolecular Cannizzaro reaction in presenncof strong alkali gives:
Answer» glycol glycollic acid glycine glucose ANSWER :B

13.	Glycol on heatingwith PI_(3)mainly given Aglycol on heating with HI mainly gives B A and B are :
Answer» `CH_(2)=CH_(2)" and "CH_(3)CH_(2)-I` `CH_(2)=CH_(2)" and "CH_(2)CH_(2)` `CH_(3)=CH_(2)-i-I" and "CH_(3)CH_(2)-I` `CH_(3)=CH_(2)-I" and "CH_(2)CH_(2)` SOLUTION :N//A

14.	Glycol on oxidation with _______ gives oxalic acid :
Answer» ACIDIC `KMnO_4` Acidic `K_2Cr_2O_7` NITRIC ACID `HIO_4` ANSWER :C

15.	Glycol is
Answer» MONOHYDRIC ALCOHOL dihydric alcohol TRIHYDRIC alcohol polyhydric alcohol ANSWER :B

16.	Glycol is prepared industrially by the following reactions:
Answer» None Answer :D

17.	Glycol forms diethylene glycol on heating with
Answer» ANHY, `ZnCl_2` CONC. `H_2SO_4` Anhy. `AlCl_3` `H_3PO_4` ANSWER :D

18.	Glycogen is present in
Answer» kidney liver intestine BLOOD ANSWER :B

19.	Glycogen on hydrolysis gives :
Answer» STARCH Amylopectin Amylose Glucose Answer :D

20.	Glycogen is closely related with
Answer» polyethene teflon bakelite STARCH SOLUTION :Both glycogen and starch are NATURAL POLYMERS (ALSO can be biopolymer) while otherare syntheticpolymers.

21.	Glycogen is called animal starch
Answer»

22.	Glycogenis anexample of :
Answer» POLYSACCHARIDE Disaccharide MONOSACCHARIDE protein ANSWER :C

23.	Glycogen is an example of :
Answer» Polysaccharide Disaccharide Monosaccharide Protein Answer :A

24.	Glycogen is a branched chain polymer of alpha-D-glucose units in which chain is formed by C1-C4 glycosidic linkage whereas branching occurs by the formation of C1-C6 glycosidic linkage. Structure of glycogen is similar to ………….
Answer» AMYLOSE CELLULOSE AMYLOPECTIN GLUCOSE SOLUTION :Amylopectin

25.	Glycogen is a branched chain polymer of alpha-D-glucose units in which chain is formed by C_(1)-C_(4) glycosidic linkage whereas branching occurs by the formation of C_(1)-C_(6) glycosidic linkage. Structure of glycogen is similar to______________ .
Answer» AMYLOSE Amylopectin Cellulose Glucose Answer :B

26.	Glycogen is a branched polymer of :
Answer» `ALPHA` GLUCOSE `BETA` glucose `alpha` fructose None ANSWER :A

27.	Glycogen is a branched chain polymer of alpha-D-glucose units in which chain is formed by C_1-C_4 glycosidic linkage whereas branching occrus by the formation of C_1-C_6 glycosidic linkage. Structure of glycogen is similar to ..........
Answer» Amylose Amylopectin Cellulose Glucose Solution :AMYLOPECTION is a BRANCHED POLYMER , amylose and cellulose are linear poylmers while glucose is the MONOMER.

28.	Glycogen is
Answer» a strutcural polysaccharide structurally similar to amylopectin but EXTENSIVELY BRANCHED a polymer of `beta-D` - glucose UNIS structually very MUCH similar to amylopectin SOLUTION :Glycogen is structurally similar to amylopectin but extensively branched.

29.	Glycogen is :
Answer» A polysaccharide FOUND in both ANIMALS and PLANTS Polysaccharide found in plants A polysaccharide found in animals A polysaccharide found in HONEY Answer :C

30.	Glycogen is _______.
Answer» a POLYMER of -------D-glucose units a structural polysaccharide structurally very much similar to AMYLOPECTIN structurally similar to amylopectin but extensively branched Answer :D

31.	Glycogen also known named as
Answer» PLANT starch animal starch cellulose Dextrin Answer :B

32.	Glycogen and amylopectin have :
Answer» Same structure Similar structure but differ in BRANCHING of glucose chain Similar structure but differ in their solubility in WATER Similar structure but they are stored in different parts of the body Answer :B

33.	Glycogen , a naturally occurring polymerstored in animals is a
Answer» MONOSACCHARIDE DISACCHARIDE TRISACCHARIDE POLYSACCHARIDE ANSWER :D

34.	Glycine reacts with nitrous acid to give :
Answer» Glycine NITRITE Methyl ALCOHOL and methylamine GLYCOLIC ACID Ethyl GLYCINATE. Answer :C

35.	Glycine is optically inactive. Why?
Answer» SOLUTION :Glycine is DENOTED by the FORMULA, `H_2N-CH_2-COOH`. Glycine has no ASYMMETRIC CARBON, so it is optically inactive.

36.	Glycine may be classed as all of the following except
Answer» A base An acid A zwitter ion OPTICALLY active acid Solution :Glycine do not have the CHIRAL carbon so it is not optically active acid. `underset(("Glycine"))(H_(2)N-underset(H)underset(\|)OVERSET(H)overset(\|)(C)-COOH)`

37.	Glycine (H_(2)N-CH_(2)-COOH) is one of the proteinogenic amino acid. Find moles of glycine in it's 7.5 gm
Answer» ANSWER :`(##ALN_NC_CHM_MC_E01_008_A01##)` 0.1 MOLE

38.	Glycine is :
Answer» ARHENIUS acid Lewis base Simplest AMINO acid All of the above Answer :D

39.	Glycine exists as (H_3N+ CH_2COO-) while anthranilic acid (P-NH_2-C_6H_4-COOH) does not exist as dipolar ion.
Answer» Solution :`-COOH` is too weakly acidic to TRANSFER `H^+` to the weakly basic `-NH_2` attached to the electron withdrawing benzene ring. When attached to an aliphatic carbon, the `-NH_2` is sufficiently basic ACCEPT `H^+` from `-COOH` group.

40.	Glycine exists as a zwitterion but o- and p- aminobenzonic acids do not. Explain.
Answer» Solution :In o- or p -aminobenzoic acids , the lone PAIR of ELECTRONS on the `NH_2` group is dontateed towards the benzene ring. As a result , acidic character of `-COOH` group and BASIC character of `-NH_(2)` group DECREASES. Therefore the weakly acidic `-COOH`group cannot transfer a `H^(+)` ion to the weakly basic `-NH_2` group. Thus, o-or p-aminobenoic acids do not exist as zwitterions. However , in glycine , no such electron -WITHDRAWING benzene ring is present . As a result , `-NH_2` group is sufficiently basic and hence accepts a proton form `-COOH` group to form a zwitterion. `underset("Glycine")(H_2N-CH_2-COOH) hArrH_(3)overset(+)N-CH_2-COO^(-)` .

41.	Glycine and e-amino caproic acid polymerises to give ............
Answer» glycyl amine NYLON 6,6 Nylon-2 Nylon 6 orlon SOLUTION :Nylon-2 Nylon 6

42.	Glycine, alanine, histidine, cultamine, proline, serine.
Answer» Solution :HISTIDINE. It is an essential amino acid WHEREAS others are non essential amino ACIDS.

43.	Glycinato ligand is:
Answer» BIDENTATE ligand Two DONOR SITES N and`O^-` All Answer :D

44.	Glycin has the structural formula NH_(2)-CH_(2)-COOH. Glycine has two dissociation constant for which K_(a)" and " K_(b) are 1.6xx10^(-10)" and "K_(b) is 2.5xx10^(12). Calculate the isoelectric point of glycine [Hint : If your answer is 5.12 then fill 0512 in OMR sheet. If your answer is 8.02 then fill 0802 in OMR sheet]
Answer» Solution :`pI=overset(pK_(A1)+pK_(a2))underset(2)_""pK_(a)=-logK_(a)` `=(9.7958+2.39)/2=6.09` `pK_(a1)=-logK_(a)""pK_(B1)=-logK_(b)` `pK_(a1)=-log1.6xx10^(-10)""pK_(b1)=-log2.5xx10^(-12)` `pK_(a1)=9.79""pK_(b1)=11.6` `pK_(a1)+pK_(b1)=14` `pK_(a2)+11.6=14` `pK_(a2)=2.3979`

45.	Glycinato ligand is :
Answer» BIDENTATE ligand Two DONOR SITES N and `O^(-)` All of these Answer :D

46.	Glyceryl ester of long chain fatty acids are called .........
Answer» SOAP detergent ANTISEPTIC ANTIBIOTIC SOLUTION :soap

47.	Glycerol was distilled with oxalic and crystals and the products were led into fehling solution and warmed . Cuprous oxide was precipitated . It is due to
Answer» CO HCHO `CH_(3)CHO` `HCOOH` SOLUTION :`HOOC-COOH UNDERSET("Decarboxylation")overset("Glycerol")to HCOOH + CO_(2)` `HCOOH +` Fehlingsolution `to underset("red ppt.")(Cu_(2))O+CO_(2)+H_(2)O`

48.	Glycerol was distilled with oxalic acid crystals and theproducts were led into Fehling solution and warmed. Cuprous oxide was precipitated. It is due to :
Answer» CO HCHO `CH_(3)CHO` HCOOH Answer :D

49.	Glycerol tristearate (stearin) can not undergo, which of the following reaction ?
Answer» Sponification Acid hydrolysis Hydrogenation none of these Answer :C

50.	Glycerol reacts with potassium bisulphate to produce
Answer» ALLYL iodide Allyl sulphate Acryl aldehyde Glycerol trisulphate Answer :C