This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Gibbs free energy G , enthalpy H and entropy S are interrelated as in |
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Answer» G = H + TS |
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| 2. |
Fructose is ketose sugar even then it gives red precipitate with Fehling solution because : |
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Answer» Ketones are oxidised by Fehling solution |
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| 3. |
Gibbs energy of formation triangleG_(f)^(G) of MgO (s) and CO (g) at 1273 K and 2273 K are given below : triangleG_f[MgO (s)]= -941"kJ mol"^(-1)" at 1273 K" triangleG_f [CO (g)]=-439"kJ mol"^(-1)" at 1273 K" triangleG_f [MgO (s)] =-314"kJ mol"^(-1)" at 2273 K" triangleG_f[CO (g)] =-628"kJ mol"^(-1)" at 2273 K" On the basis of above data, predict the temperature at which carbon can be used as a reducing agent for MgO (s). |
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Answer» Solution :For the reaction, `MgO(s)+C(s) to Mg(s)+CO(g)` At 1273 K, `triangleG_(r)=triangleG_(r) [CO(g)]-triangleG_(f) [MgO(s)]=-439-(-941)"kJ mol"^(-1)=502"kJ mol"^(-1)`. At 2273 K, `triangleG_(r)=-628-(-314)kJ mol^(-1)=-314"kJ mol"^(-1)`. The TEMPERATURE is 2273 K. |
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| 4. |
Fructose has a specific rotation -92.4^(@). An aqueous solution of Fructose has an observed rotation of -27.7^(@), when placed in a polarimeter tube of 10 cm long. How much amount of Fructose is dissolved in 100 ml of aqueous solution ? |
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Answer» 3.0 GM |
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| 5. |
Gibbs free energy change for the electrolysis process is expressed by ………………… . |
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Answer» `DELTAG^(@)=-NFE^(@)` |
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| 6. |
Fructose is not oxidised by bromine water indicates |
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Answer» the PRESENCE of ALDEHYDIC GROUP |
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| 7. |
Gibbs free energy can be related to cell emf as follows: |
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Answer» `DELTA G^@ = -nFE_("CELL")` |
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| 8. |
Fructose is a functional isomer of glucose. |
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Answer» glucose |
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| 9. |
Gibbs energies for the oxidation of Fe and C around 1400""^(@)" are "-341 kJ mol^(-1)" and "-447 kJ mol^(-1). Will C be a suitable reducing agent in the metallurgy of Fe? Give reason. |
| Answer» Solution :YES. This is because `triangle_(r )G^(0)` for the oxidation of C is more NEGATIVE. | |
| 10. |
Gernera method for the extration of metal from oxide ore is |
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Answer» CARBON REDUCTION |
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| 11. |
Fructose, fruit sugar, milk sugar, levulose, ketohexose. |
| Answer» SOLUTION :MILK sugar. It is the NAME of lactose. All OTHERS areindicatingfructose only . | |
| 12. |
Fructose gives the silver mirror test because it |
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Answer» Contains an aldehyde group |
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| 13. |
Germinated Barley (an enzyme ) is a source of enzyme : |
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Answer» ZYMASE |
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| 14. |
Fructose contains a keto group but still it reducess Tollens 'reagent. Explain. |
| Answer» Solution :Under the basic conditions ofTollens' reagent , fructoseundergoes Lobry DE Bruyn van Eikenstein REARRANGEMENT (refer to ' Supplement Your Knowledge for Competitions ').As a result, fructose GIVES a equilibrium mixture of fructose and mannose . Since both GLUCOSE and mannose CONTAIN `-CHO` group , therefore , they reduce Tollen's reagent. | |
| 15. |
Germanium is an example of |
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Answer» intrinsidc SEMICONDUCTOR |
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| 16. |
Ge (II) compounds are powerful reducing agents whereas Pb(IV) compound are strong oxidants. It can be due to |
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Answer» More POWERFUL INERT pair effect in Pb than Ge |
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| 17. |
Fructose form hemiketal between gtC=O group and -OH group of |
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Answer» C-3 |
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| 18. |
German silver is an alloy of copper and : |
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Answer» ZN and Ni |
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| 19. |
Germanium can be made n-type semi conductor by doping with |
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Answer» SILICON |
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| 20. |
Frothing agents used to separate ZnS from PbS is…… |
| Answer» ANSWER :A | |
| 21. |
German silver is an alloy of… |
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Answer» Copper, Zinc, SILVER |
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| 23. |
German Silver is an alloy of Copper and: |
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Answer» Copper, ZINC and NICKEL |
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| 24. |
Fructose contains |
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Answer» 5OH groups |
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| 26. |
German silver is an alloy of |
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Answer» COPPER, zinc and nickel |
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| 27. |
Frothing agent used in froth floatation process is …………… |
| Answer» Solution :pine oil | |
| 28. |
Frothers (used in Froth floatation process) are |
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Answer» MOLECULES with HYDROPHILIC HEAD and HYDROPHOBIC TAIL. |
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| 30. |
German silver is a alloy of …… metal. |
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Answer» ZN, SN, Ni |
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| 31. |
German silver does not contain |
| Answer» Solution :German SILVER is an alloy of copper (Cu), zinc (Zn) and nickel (Ni) in the ratio `2 : 1 : 1` . Thus , Sn is not PRESENT in it . | |
| 32. |
German silver contains ____ % of silver. |
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Answer» 90 |
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| 33. |
Froth stabilizers in froth floatation process is... |
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Answer» CRESOL |
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| 35. |
Froth flotation |
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Answer» is a physical method of separating MINERAL from the GANGUE |
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| 36. |
Geometry of XeOF_4 molecule is: |
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Answer» SQUARE Planar |
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| 37. |
Geometry of the given compound |
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Answer» CIS |
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| 38. |
Geometry of orbitals around the transition metal ion in hexacyanoferrate |
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Answer» SQUARE planar ARRANGEMENT |
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| 40. |
Geometry of ether is |
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Answer» linear |
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| 41. |
Geometry of orbitals around the transition metal ion in haem of haemoglobin is |
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Answer» SQUARE PLANAR ARRANGEMENT |
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| 42. |
Froth floatation process is suitable for concentrating _____ores. |
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Answer» oxide |
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| 43. |
Geometrical shapes of the complexes (p),(q),(r) formed by the following reactions respectively are : Cu^(2+)(aq)+KCN(aq)("excess")to"complex"(p) Co^(2+)(aq)+KNO_2(s)+H^+ (aq)to"complex"(q) Zm^(2+)(aq)+NaOH(aq)("excess")to"complex"(r) |
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Answer» Tetrahedral , octahedral and SQUARE PLANAR `[Cu(CN)_4]^(3-)-3d^(10)` electron configuration and , therefore , `sp^3` hybridisation and tetrahedral geometry. (B)`Co^(2+)(aq)+3K^(+)(aq)+7NO_2^(-)(s)+2H^(+)(aq)toK_3[Co(NO_2)_6]darr (Q)+NOuarr+H_2O` `[Co(NO_3)_6]^(3-)-3d^(6)` electron configuration and , therefore , `d^2sp^3` hybridisation and octahedral geometry. (C )`Zn^(2+)(aq)+4OH^(-)(aq)("excess")to[Zn(OH)_4]^(2-)(r)` `[Zu(OH)_4]^(2-)3d^10` electron configuration and , therefore , `sp^3` hybridisation and tetrahedral geometry. |
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| 44. |
Geometrical shapes of the complexes formed by the reaction of Ni^(2+) with Cl^(-), CN^(-) and H_(2)O respectively are |
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Answer» octahedral, tetrahedral and SQUARE planar `Ni^(2+)+CN^(-)to[Ni(CN)_(4)]^(2-), dsp^(2)` hybridisation it is square planar. `Ni^(2+)+H_(20Oto[Ni(H_(2)O)_(6)]^(2+), sp^(3)d^(2)` hybridisation, it is octahedral. |
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| 45. |
Geometrical shapes of the complexes formed by the reaction of Ni^(2+) with Cl^(-), CN^(-)and H_2O, respectively, are |
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Answer» OCTAHEDRAL, TETRAHEDRAL and SQUARE planr |
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| 46. |
Froth floatation process is used for the benefication of : |
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Answer» OXIDE ore |
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| 47. |
Geometrical shapes of the complexes formed by the reaction of Ni^(2+) with Cl^(-), CN^(-) and H_(2)O, respectively, are |
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Answer» Octahedral, TETRAHEDRAL and square planar `Ni^(2+)+4CN^(-)rarr[Ni(CN)_(4)]^(2-)`, square planar, `DSP^(2)` hybridization `Ni^(2)+6H_(2)Orarr[Ni(H_(2)O)_(6)]^(2+)`, octahedral, `sp^(3)d^(2)` hybridization. |
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| 48. |
Froth floatation process is based on |
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Answer» SPECIFIC gravity of the ore particle |
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| 49. |
Geometrical shapes of the complexes formed by the reaction of Ni^(2+) with (Cl^(-) CN^(-) and H_(2)0, respectively, are |
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Answer» octahedral, tetrahedral and SQUARE PLANAR `[Ni(CN)_(4)]^(2-) to Square planar` `[Ni(H_(2)O)_(6)]^(2+) to Octahedral` |
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| 50. |
Geometrical shapes of the complexes formed by the reaction of Ni^(2+) with Cl^-, and CN^-, respectively are |
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Answer» OCTAHEDRAL, tetrahegral and SQUARE PLANAR |
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