Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

For the half-cell raction, 2H_(2)O+2e^(-)toH_(2)+2OH^(-),E^(@)=-0.8277V at 298K. Autoprotolysis constant of water calculted from this value will be

Answer»

`1xx10^(-10)`
`1xx10^(-12)`
`1xx10^(-13)`
`1xx10^(-14)`

Solution :AUTOPROTOLYSIS constant of `H_(2)O=[H^(+)][OH^(-)]=K_(w)`
Redn. Half reaction:
`2H_(2)O+2e^(-)toH_(2)+2OH^(-),E^(@)=-0.8277V`
`underset("Ox. Half reaction:"H_(2)to2H^(+)+2e^(-),E^(@)=0.0)`
Cell reaction: `2H_(2)OhArr2H^(+)+2OH^(-),E^(@)=-0.8277V`
`E=E^(@)-(0.0591)/(2)"log"[H^(+)]^(2)[OH^(-)]^(2)`
At EQUILIBRIUM, E=0. Hence,
`E^(@)=(0.0591)/(2)log[H^(+)]^(2)[OH^(-)]^(2)`
`therefore-0.8277=0.0591log[H^(+)][OH^(-)]^(2)`
`=0.0591logK_(w)`
or `logK_(w)=14` or `K_(w)=10^(-14)`.
Discussion
2.

For the half cell, +2H^(+)2e^(-).E^(0)= 1.30 V. At pH = 2, electrode potential of the given quinhydrone half cell is :

Answer»

`1.36V`
`1.30V`
`1.42V`
`1.20V`

ANSWER :C
Discussion
3.

for the graph below, select correct order of temperture ?

Answer»

`T_(1)gtT_(2)GT T_(3)`
`T_(2)gtT_(3)gt T_(1)`
`T_(3)gtT_(2)gt T_(1)`
`T_(1)gtT_(2)gt T_(3)`

Answer :c
Discussion
4.

For the given set of complexes : (P) [Co(CN)_(6)]^(3-)" and "[Co(H_(2)O)_(6)]^(3+) (Q) [Co(H_(2)O)_(6)]^(3+)" and "[Rh(H_(2)O)_(6)]^(3+) (R ) [Co(H_(2)O)_(6)]^(2+)" and "[CoF_(6)]^(3-) (S) [Co(NH_(3))_(6)]^(3+)" and "[CoF_(6)]^(3-) Select the correct order for Delta_(0):

Answer»

`[Co(CN)_(6)]^(3-)"GT "[Co(H_(2)O)_(6)]^(3+)`
`[Co(H_(2)O)_(6)]^(2+)"gt "[CoF_(6)]^(3-)`
`[Co(H_(2)O)_(6)]^(3+)"gt "[Rh(H_(2)O)_(6)]^(3+)`
`[Co(NH_(3))_(6)]^(3+)"gt "[CoF_(6)]^(3-)`

Solution :`Delta_(0)" of "Co^(3+) gt Co^(2+)` complexes
`Delta_(0)" of "CN^(-) gt NH_(3) gt H_(2)O gt F^(-)` complexes
Discussion
5.

For the graph below, select correct order of temperature?

Answer»

`T_(1)gtT_(2)gtT_(3)`
`T_(2)gtT_(3)gtT_(1)`
`T_(3)gtT_(2)gtT_(1)`
`T_(1)=T_(2)=T_(3)`

SOLUTION :Tempt`uarr` EXTENT of ADSORPTION`darr`
Discussion
6.

For the following three reaction 1, 2 and 3, equilibrium constants are given: (1) CO_((g)) + H_(2)O_((g))hArrCO_(2(g)) + H_(2(g)), K_(1) (2) CH_(4(g)) + H_(2)O_((g))hArrCO_((g)) + 3H_(2(g)), K_(2) (3) CH_(4(g)) + 2H_(2)O_((g))hArrCO_(2(g)) + 4H_(2(g)), K_(3) Which of the following relations is correct ?

Answer»

`K_(2)K_(3)=K_(1)`
`K_(3)=K_(1)K_(2)`
`K_(3).K_(2)^(3)=K_(1)^(2)`
`K_(1)sqrt(K_(2))=K_(3)`

SOLUTION :`K_(3)=K_(1)K_(2).`
Discussion
7.

For the given reactions: (a) C_(x)H_(y) +(x+(y)/(4))O_(2) rarr xCO_(2)+(y)/(2)[R] (b) N_(2)+3H_(2) underset(200 " atm " 500^(@)C) overset( Fe+Mo) rarr [S]_("gas") (c ) P_(4) +NaOH +H_(2)O overset ("boil")rarr[T]_(gas) The % ratio of valence electron of central atom vs total valence shell electrons is 62.5% is [S} and 27.77% in[T] and central atom of [S] and [T] belongs to same group then what is the correct order of increasing bond angle of [R]=1, [S]=2 and [T]=3? ,brgt [If your answer is 1 lt 2 lt 3 then write 0123.]

Answer»


SOLUTION :`{:(SrarrNH_(3),R rarrH_(2)O, TrarrPH_(3)),(""~107^(@)," "~104.5^(@),""~92^(@)):}`
Discussion
8.

For the given reactions, which of the following statements are true? underset("(excess)")(KI +K_3 ) [Fe (CN)_6]underset(H_2 SO_4 ) overset("dilute ") tounderset("darrZn SO_4)(" Brownishyellowsolution ") whiteprecipitate+{:(ubrace("Brownish yellow filtrate")),(""darr Na_2 S_2 O_4),("colourlesssolution"):}

Answer»

The first reaction is a redox reaction.
White precipitate is of `Zn_3 [Fe(CN)_6]_2`
Addition of starch solution to FILTRATE gives blue colour.
White precipitate is soluble in NAOH solution.

Solution :`2KI^(-1)+2K_3 overset(III)([Fe(CN)_6]overset(dilH_2SO_4) to2 K_4 [Fe(CN)_6 ]+overset(0)I_2`
` I_2+ KIto KI_3`
` K_4 [Fe (CN) _6] + 2 ZnSO_4toZn_2 [Fe (CN) _6 ] +2K_2 SO_4 `
`UNDERSET("Brownishyellow filtrate ") ( KI_3+ 2Na_2 S_2O_3tounderset("COLOURLESSSOLUTION ") (Na_2S_4O_6+ 2KI+KI`
`Zn_2[Fe(CN)_6 ]+8NaOHto2Na_2underset("Soluble ")([Zn (OH)_4] )+Na_4 [Fe (CN)+6 ]`
Discussion
9.

For the given reaction, the major product obtained is (AAK_MCP_35_NEET_CHE_E35_019_Q01)

Answer»


No REACTION is possible

Answer :D
Discussion
10.

For the given reaction, R-underset(R_(2))underset(|)overset(R_(1))overset(|)(C )-x overset(HOH)(rarr) R-underset(R_(2))underset(|)overset(R_(1))overset(|)(C )-OH Which substrate will give maximum racemisation?

Answer»

`H_(5)C_(6)- underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)C-Br`
`CH_(2)-CH- underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)C-Br`

Solution :The substrate which can FORM most stable carbocation will give MAXIMUM racemisation
Discussion
11.

For the given reaction ,find the order of the reaction with respect to [H^(+)] 5Br_((aq))^(-)+BrO_(3(aq))^(-)hArr3Br_(2(aq))+3H_(2)O_(l)

Answer»

3
2
1
4

Answer :B
Discussion
12.

For the given plot, match the most appropriate graph for respective gases: (Among H_(2),He, CO, CH_(4))

Answer»

<P>`{:(P,Q,R,S),(H_(2),He,CO,CH_(4)):}`
`{:(P,Q,R,S),(He,H_(2),CH_(4),CO):}`
`{:(P,Q,R,S),(He,H_(2),CH_(4),CO):}`
`{:(P,Q,R,S),(CO,He,H_(2),CH_(4)):}`

Answer :C
Discussion
13.

For the given reaction

Answer»

`CH_(3)-underset(CH_(3)) underset(|) OVERSET (CH_(3)) overset(|) (C)-Br//AlBr_(3)`
`CH_(3)-underset(CH_(3)) underset(|) overset (CH_(3)) overset(|) (C)-OH//H^(0+)`
`CH_(3) -underset(CH_(3))underset(|)(C)=CH_(2)//H^(o+)`
`CH_(3)-underset(CH_(3))underset(|)(CH)-overset(CL) overset(|)(CH)-Ph`

SOLUTION :
Discussion
14.

For the given orbital in column 1, the only correct combination for any hydrogen like species is

Answer»

(2) (ii) (P)
(1) (ii) (S)
(4) (iv) (R )
(3) (iii)(P)

Answer :A
Discussion
15.

For the given graph which of the following is correct : (n = mole of gas and P = Pressure)

Answer»

`P_(2) gt P_(1)` with n is CONSTANT
`P_(2) lt P_(1)` with n is constant
`P_(2) = P_(1)` with n is constant
can't compare `P_(1)` and `P_(2)`

SOLUTION :From the graph, it is clear that slope is not 1. Hence VOLUME will not increase as much as increase in mperature.
For or PV = NRT
P will ALSO increase, `P_(2) gt P_(1)` (n = constant)
Discussion
16.

For the given equlibrium : 2SO_(2)+O_(2)hArr2SO_(3)+ heat the equlibrium reaction proceeds in forward direction when

Answer»

OXYGEN is removed
`SO_(3)` is ADDED
Heat is added
Oxygen is added

SOLUTION :As per Le-Chatelier's principle.
Discussion
17.

For the given graph of real gas:What should be the pathto change a gas into a liquid or vice-versa in which always a single phase is present ?

Answer»

`A RARR F` VERTICALLY then `F rarr G` (isothermally) then `G rarr D`
`A rarrB` (isothermally) then `F rarr G` (isobarically), then `C rarr D` (isothermally)
`D rarr H rarr G` then `G rarr F` (isothermally) then `F rarr A` vertically
None of the above

Answer :A::C
Discussion
18.

For the given endothermic reaction, A(g) hArr 2B(g) The variation in concentration due to different changes is plotted. Neglect the slope of change in concentration. Changes are carried out very fast. Given the correct order of initials T (true) of F (false) for following statements. (P) Effect-I is decrease in temperature at constant volume (Q) Effect-II is decrease in total equilibrium pressure by changing volume. (R) Effect-III is addition of B only at constant volume

Answer»

FTT
TFT
TFF
TTT

Answer :D
Discussion
19.

For the given compounds in column (I), the only combination for any terminal alkyne is

Answer»

(I)(iv)(Q)
(I)(ii)(S)
(II)(i)(P)
(I)(iv)(S)

SOLUTION :`R-C=CH OVERSET("Tollens Reagent")to` WHITE PPT.
Discussion
20.

For the given conversion : Me-overset(O)overset(||)C-OH rarrMe-overset(O)overset(||)C-H Suitable options are :

Answer»

Reduction by `LiAIH_(4)`
REACTION with `SOCl_(2)` followed by `H_(2)//Pd-BaSO_(4)`
Catalytic reduction by `H_(2)//NI`
Reaction with `PCl_(5)` followed by DiBAL-H

Answer :B::D
Discussion
21.

For the given compound X, the total number of optically active stereoisomers is……..

Answer»


ANSWER :7
Discussion
22.

For the given compound CH_(3)-underset(overset(|)(OH))(CH)-CH=CH-CH_(3). (i) Total number of stereoisomers. (ii) Number of opticallly active stereoisomers. (iii) Total number of fractions on fractional distillation of all stereoisomers.

Answer»


Answer :(I)`CH_(3)-underset(OVERSET(|)(OH))(C)H-CH=CH-CH_(3)`
Number of STEREOCENTRES = 2 so TOTAL number of stereoisomers = `2^(2)` = 4
(II) All 4 isomers are optically active.(III) Total enantiomeric pairs are 2, hence number of FRACTION will be 2.
Discussion
23.

For the given complex [CoCl_(2)(en)(NH_(3))_(2)]^(+), the number of geometrical isomers, the number of optical isomers and total number of isomers of all type possible respectively are

Answer»

2, 2 and 4
2, 2 and 3
2, 0 and 2
0, 2 and 2

Solution :The octahedral complex of the type `[M(A A)X_(2)Y_(2)]`, i.e., `[CoCl_(2)(en)(NH_(3))_(2)]^(+)` will show two cis- and trans-geometrical isomers. Out of these, cis-isomer will be OPTICALLY active and shows two d- and l-forms. So the total number of possible isomers will be THREE.
Discussion
24.

For the given complex [Co(NH_(3))_(5)Br]SO_(4), write the IUPAC name and its ionisation isomer.

Answer»

Solution :Pentaamminebromido cobalt (III) SULPHATE `[CO(NH_3)_5 SO_4] BR.`
Discussion
25.

For the given cell, Mg|Mg^(2+)||Cu^(2+)|Cu

Answer»

MG is cathode
Cu is cathode
The CELL REACTION is `Mg+Cu^(2+)toMg^(2+)+Cu`
Cu is the oxidising agent.

Answer :B::C
Discussion
26.

For the given complex [CoCl_(2)(en) (NH_(3))_(2)]^(+), the number of geometrical isomers, the number of optical isomers and total number of isomers of all type possible respectively are :

Answer»

2, 2 and 4
2, 2 and 3
2, 0 and 2
0, 2 and 2.

Answer :A
Discussion
27.

For the given cell, Mg | Mg^(2+) || Cu^(2+) | Cu

Answer»

Mg is cathode
Cu is cathode
The CELL reaction is `Mg + Cu^(2+) to Mg^(2+) + Cu`
Cu is the oxidising AGENT.

ANSWER :B::C
Discussion
28.

For the given cell Cr_((s))abs(Cr_((aq))^(3+))abs(Cu_((aq))^(2+))Cu_((s)) which is correct?

Answer»

Cr is the anode
Cu is the anode
Overall CELL reaction is
`2Cr_((AQ))^(3+)+3Cu_((s)) rarr 2Cr_((s)) rarr 2Cr_((s))+3Cu_((aq))^(2+)`
Both (B) and (C)

Answer :A
Discussion
29.

For the given cel, Mg|Mg^(2+)||Cu^(2+)|Cu _____

Answer»

Mg is cathode
CU is cathode
The cell reaction is `Mg+Cu^(2+) to Mg^(2+)+Cu`
Cu is the oxidising agent

Solution :Left side of the cell represent oxidation half-cell and RIGHT side represent reduction half-cell. In galvanic cell, anode of Mg|`Mg^(2+)` is on left side, where oxidation reaction occur.
Oxidation : `Mg_((S)) to Mg^(2+)+2E^(-)`. .(i)
So, Option (A) is not right.
In this cell, cathode of `Cu^(2+)|Cu` is on right side, where reduction reaction occur.
Reduction : `Cu^(2+)+2e^(-) to Cu` . . .(ii)
Total reaction in cell (iii)=(i)+(ii)
(iii) Redox reaction :

So, option (C) is right.
* In this reaction oxidation of Mg and reduction of `Cu^(2+)` occur. So `Cu^(2+)` is oxidizing and Cu is not Oxidizing. So option (D) is wrong.
Discussion
30.

For the given aqueous reaction which of the statement(s) is (are) true?

Answer»

The first reaction is a redox reaction
White precipitate is `Zn_(3)[Fe(CN)_(6)]_(2)`
Addition of FILTRATE to starch solution GIVES a blue colour.
White precipitate is soluble in `NaOH` solution

Solution :
`(D)` with `NaOH`
`K_(2)Zn[Fe(CN)_(6)] + NaOH to [Zn(OH)_(4)]^(2-)(aq)+[Fe(CN)_(6)]^(4-)(aq)`
Discussion
31.

For the given aqueous reactions, which of the statement(s) is (are) true ?

Answer»

The first reaction is a REDOX reaction
White precipitate is `Zn_(3)[Fe(CN)_(6)]_(2)`
Addition of FILTRATE to STARCH solution GIVES bluecolour
White precipitate is soluble in NaOH solution.

Solution :(a,c,d)
`2KI+2K_(3)underset((Fe^(3+)))([Fe(CN)_(6)]) underset(H_(2)SO_(4))overset(dil.) to 2K_(4) underset((Fe^(2+))([Fe(CN)_(6)])+I_(2)`
`I_(2)+ underset("(Excess)")(KI to KI_(3))`
Discussion
32.

For the given aqueous reaction, which of the statement(s) is (are) true ?

Answer»

The FIRST reaction is a redox reaction
White precipitate is `Zn_(3)[Fe(CN)_(6)]_(2)`
Addition of filtrate to starch solution gives BLUE colour.
White precipitate is soluble in NAOH solution.

Solution :`underset("(EXCESS)")(KI)+K_(3)[Fe(CN)_(6)] overset("dil. "H_(2)SO_(4))(rarr) I_(2)+K_(4)[Fe(CN)_(6)]`
`I_(2)+KI hArr KI_(3)` (brown -yellow sol)'
`{:(Zn^(2+)+K_(4)[Fe(CN)_(6)] rarr K_(2)Zn_(3)[Fe(CN)_(6)]_(2)+K^(+)),("(white ppt)"),("or"),(""Zn_(2)[Fe(CN)_(6)]+K^(+)),("(white ppt)"):}`
Discussion
33.

For the given aqaction , whichof the statement (s) is (are) true?

Answer»

The first reaction is a redoxreaction
Whiteprecipitate is `Zn_(4)[ Fe(CN)_(6)]_(2)`
ADDITIONOF fitrateto solutiongivesbluecolour
Whenprecipitate is solublein NqaOH solution

Solution :
Discussion
34.

For the gaseous reaction, say, A toproduct, the rate is often described in terms of d(P_A)//dt instead of d[A]//dt or d(n_A)//dt . What is the relation among these three expressions?

Answer»

SOLUTION :`(d(P_A))/(DT) = (RT)/(V) (d(n_A))/(dt) = RT (d[A])/(dt)`
Discussion
35.

For the gaseous reaction :N_(2)+3H_(2)hArr 2NH_(3)the partial pressure of H_(2) and N_(2) are 0.4and0.8 atm respectively.The total pressure of the entire system is 2.8 atm.What will be the value of K_(p)if all concentrations are given in atmospheres ?

Answer»

50
`0.02`
250
`31.25`

ANSWER :A
Discussion
36.

For the given complex [Co(NH_3)_5 Br]SO_4,write the IUPAC name and its ionisation isomer.

Answer»

SOLUTION :`(CO(NH_3)_5SO]BR` Pentaaminiesulphito COBALT (IH) bromide
Discussion
37.

For the gaseous reaction, N_(2)O_(4) rarr 2NO_(2)

Answer»

`DELTAH lt DeltaE`
`DeltaH = DeltaE`
`DeltaH = 0`
`DeltaH gt DeltaE`

Solution :`N_(2)O_(4)(g)rarr2NO_(2)(g)`
For this reaction `Deltan_(g)=2-1=1`
`Deltan_(g)` is positive is i.e., there is an INCREASE in the number of gaseous moles then `DeltaH gt DeltaE`.
Discussion
38.

For the gaseous reaction :A(g)to Products, the rate may be expressed as MethodI: -(1)/(V).(dn_(A))/(dt)-k_(1).C_(a)"^(n) Method II: -(dp_(A))/(dt)=k_(2).P_(A)"^(n) Wehre C_(A)=(n_(A))/(V)=molar concentration of A and P_(A) is the partial pressure of A at time 't' and 'n' is the order of reaction. The reaction is occurring at constant temperature, T=300 K Assume ideal behaviour of gas. Select the correct statement (s).

Answer»

`k_(1)=K_(2)` for any VALUE of `'n'`
`k_(1)=k_(2)` when `n=1`
`k_(1)=k_(2).(RT)`, when `n=0`
`k_(1)=k_(2)`.(RT)`,when `n=2`

ANSWER :B::D
Discussion
39.

For the gaseous reaction, H_(2)+Cl_(2) to 2HCl. If 40 ml of hydrogen completely reacts with chlorine then find out the the required volume of chlorine and volume of produced of HCl?

Answer»

Solution :According to GAY Lussac's Law:
`H_(2)+Cl_(2) to 2HCl`
`therefore` 1 ML of `H_(2)` will react will 1 ml of `Cl_(2)` and 2 ml of HCl will produce.
`therefore` 40 ml of `H_(2)` will react with 40 ml of `Cl_(2)` and 80 ml of HCl will produce REQUIRED vol. of `Cl_(2)=40` ml , produced vol. of HCl=80 ml
Discussion
40.

For the gaseous phase reacton 2NOhArrN_(2)+O_(2)DeltaH^(@)=+43.5"kcal mol"^(-1) Which statement is correct

Answer»

K VAIRES with addition of NO
K decrease at temperaturee decreases
K increases at tempereature decreases
K is independent of temperaturee

Solution :`2.303log""(K_(2))/(K_(1))=(DELTAH)/(R)([T_(2)-T_(1)])/(T_(1)xxT_(2))`
`DeltaH=+ve` for the REACTION
Discussion
41.

For the gaseous phase reaction, 2NO ⇌ N_2 + O_2 , DeltaH^o = -43.5 Kcal mol^(-1) , Which statement is corrct for, N_2 (g) + O_2 (g) ⇌2NO(g):

Answer»

K is INDEPENDENT of TEMPERATURE
K INCREASES as temperature DECREASES
K decreases as temperature decreases
K varies with addition of NO

Answer :C
Discussion
42.

For the gas phase reaction 2NO(g)hArrN_(2)(g) + O_(2)(g) , DeltaH = -43.5 kcal,which one of the following is true for N_(2)(g) + O_(2)(g)2NO(g)

Answer»

K is INDEPENDENT of T
K decreases as T decreases
k increases as T decreases
K varies with addition of NO

Solution :The given reaction `N_(2)(g) + O_(2)(g)hArr2NO(g)` is endothermic.Therefore, according to Le-Chaltlier’s PRINCIPLE , HIGH TEMPERATURE favours forward reaction and hence K increase as T increase or K decrease as T decreases.
Discussion
43.

For the gas phase reaction, C_(2)H_(4)+H_(2)hArrC_(2)H_(6)(Deltah=-32.7kcal) carried out in a vessel, the equlibrium concentration of C_(2)H_(4) can be increased by

Answer»

Increasing the TEMPERATURE
Decreasing the PRESSURE
Removing some `H_(2)`
Adding some `C_(2)H_(6)`

Solution :(ABCD) The reaction is exothermic, hence increasing temperature will FAVOUR backward reaction (i.e., conc. Of `C_(2)H_(4)` increases). Again decreasing pressure, removing `H_(2)` and adding `C_(2)H_(6)` favours backward reaction.
Discussion
44.

For the gas phase reaction 2NO(g) hArr N_2(g) +O_2(g) ,DeltaH=-43.5 kcal, which one of the following is true for N_2(g) +O_2(g) hArr 2NO(g)

Answer»

K is independent of T
D decreases as T decreases
K INCREASES as T decreases
K VARIES with addition of NO

Answer :B
Discussion
45.

For the gas phase reaction, C_2H_4 +H_2 hArr C_2H_6,DeltaH=-136.8 kJmol^(-1) carried out in vessel the equilibrium concentration of C_2H_4 can be increases by

Answer»

INCREASING the temperature
decreasing the pressure
removing some `H_2`
ADDING some `C_2H_6`

ANSWER :A::B::C::D
Discussion
46.

For the gas phase exothermic reaction, A(g) + 2B(g)

Answer»

DECREASING the temperature
Increasing the pressure
Adding INERT yas at constant pressure
Removing C(G) at equilibrium

Answer :C
Discussion
47.

For the gas equation P = ( RT )/( V - b) - ( a)/( TV^(2)) , following conclusions are found true ( 1) lim ( RT - PV ) = 0, P rarr alpha, T rarr beta ( 2) lim (V) /( T ) = ( R )/( P ) , T rarr gamma Which is the correct set of the vlaues of alpha, betaand gamma?

Answer»

`OO, 0 ,oo`
`0,oo,0`
`oo,oo, 0`
`0,oo,oo`

ANSWER :D
Discussion
48.

For the gas - phase decomposition , PCI_(5)(g)overset(Delta)hArr PCI_(3)(g) + CI_(2)(g):

Answer»

`DeltaH LT 0, DeltaS lt 0`
`DeltaH gt 0, DeltaS gt 0`
`DeltaH gt 0, DeltaS lt 0`
`DeltaH lt 0, DeltaS gt 0`

Solution :Reaction is endothermic and no. of MOLES increases on decomposition.
Discussion
49.

For the galvanic cell: Zn(s) | Zn^(2+)(aq) (1.0 M) || Ni^(2+)(aq) (1.0 M) | Ni(s), E_cell^o will be [Given E_((Zn^(2+)) /(Zn))^0 = -0.76 V, [E_((Ni^(2+))/(Ni))^0= -0.25V]

Answer»

`-0.51V`
`-1.01V`
`0.51V`
`1.01V`

ANSWER :C
Discussion
50.

For the galvanticcell Pt(s)|Fe^(2+),Fe^(3+)"||"Fe^(2+)"|"Fe cell reaction is

Answer»

`3Fe^(2+)+Feto2Fe^(3+)`
`3Fe^(2+)TOFE+2Fe^(3+)`
`Fe+2Fe^(3+)to3Fe^(2+)`
`Fe+Fe^(2+)toFe^(3+)`

ANSWER :B
Discussion