Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Draw the structure of the following compounds. (a) Sulphuric acid (b) Marshall's acid.

Answer»

SOLUTION :(a) STRUCTURE of SULPHURIC acid : `HO-OVERSET(O)overset(||)underset(O)underset(||)S-OH`
(b)`underset("(Peroxodisulphuric acid)")("Structure of Marshall.s acid"):HO-overset(O)overset(||)underset(O)underset(||)S-O-O-underset(O)underset(||)overset(O)overset(||)S-OH`
Discussion
2.

During the extraction of aluminium by Hall-Heroult process at which electrode oxygen gas is liberated.

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Solution :(ii) `2Al_(2)O_(3)+3C rarr 4Al+3CO_(2)`
`Al_(2)O_(3)overset ("Electrolysis ") to 2Al^(3)+3O^(2)`
At Anode : `Al^(3+)+ 3E^(-) to Al`
At Cathode : `C+O^(2-) +2E^(-)to CO_(2)`
`CO+O^(2-)+2e ^(-) to CO_(2) uarr`
(iii) Oxygen gas is not liberated ,
Discussion
3.

Draw thestructure of surcose .

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Solution :Sucrose `C_(12)H_(22)O_(11)`ISA DISACCHARIDE.
Discussion
4.

During the extraction of aluminimum by Hall - He'rault process, i) Write neat labelled diagram of elecctrolytic cell. ii) Write over all cell reaction. iii) At which electrode oxygen gas is liberated?

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Solution :i.
II. `2Al_(2)O_(3)+3C rarr 4Al+3CO_(2)`
iii. ANODE.
Discussion
5.

Draw the structure of the compound whose IUPAC name is 4 - chloropentan -2- one.

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SOLUTION :`CH_(3)-overset(Cl)overset(|)CH-CH_(2)-overset(O)overset(||)C-CH_(3)`
Discussion
6.

During the extraction of Ag and Au using a KCN solution, cyanide ions react with metal ions as

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a reducing AGENT
a complexing agent
and oxidizing agent
a lewis BASE

Solution :`CN^(ѳ)` is strong ligand so act as complexing agent that’s why a Lewis base.
Discussion
7.

Draw the structure of the compound named 4-methyl pent-3-en-2-one.

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SOLUTION :`CH_(3)-UNDERSET(CH_(3))underset(|)(C)=CH-underset(O)underset(||)(C)-CH_(3)`
Discussion
8.

During the evaporation of liquid

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The temperature of the liquid
The temperature of the liquid will fall
May RISE or fall depending on the nature
The temperature remains unaffected

Solution :In the PROCESS of EVAPORATION, high energy molecules leave the surface of liquid, HENCE average kinetic energy and CONSEQUENTLY the temperature of liquid falls.
Discussion
9.

Draw the structure of sucrose.

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SOLUTION :SUCROSE `C_(12)H_(22)O_(11)` is a disaccharide
Discussion
10.

During the estimation of nitrogen by Kjeldahl's method, copper sulphate is added to :

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raise the BOILING POINT of `H_(2)SO_(4)`
absorb water FORMED
catalyse the reaction
form ammonium sulphate

Answer :C
Discussion
11.

Draw the structure of SO_(3)^(2-).

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SOLUTION :In `SO_(3)^(2-)` ion, S is `sp^(3)`-HYBRIDIZED. Due to the presence of a lone PAIR of ELECTRONS, `SO_(3)^(2-)` has a pyramidal SHAPE as shown :
Discussion
12.

During the emission of a positron from a nucleus, the mass number of the daughter element ramains the same but the atomic number

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is decreased by 1 unit
is decreased by 2units
is increased by 1 unit
REMAINS unchanged.

Solution :`""_(Z)^(A)X to ""_(Z - 1)^(A)Y + ""_(+1)^(0)E^(-)`
So , atomic number is decreased by 1 unit.
Discussion
13.

Draw the structure of saccharin. How many times is it sweeter than cane sugar ?

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SOLUTION :
It is 550 TIMES sweeter than cane SUGAR.
Discussion
14.

During the electroytic refining of zinc, which of the following statement is true?

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The IMPURE metal is at the cathode
Graphite is at the anode
The metal ions GET reduced at anode
Acidified zinc SULPHATE is the electrolyte

Answer :D
Discussion
15.

Draw the structure of [Pt(Cl_(3))(C_(2)H_(4))]

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SOLUTION :The COMPLEX is KNOWN as Zeises SALT.
Discussion
16.

During the electrolytic reduction of alumina, the reaction at cathode is

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`2H_(2)O rarr O_(2) +4H+4e^(-)`
`3F rarr 3F+3e^(-)`
`AL^(3+) 3e^(-)rarr Al`
`2H^(+) rarr 2E^(-) rarr H_(2)`
Discussion
17.

Draw the structure of propane-1, 2, 3 tricarbaldehyde.

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SOLUTION :`UNDERSET(CHO)underset(|)CH_(2)-underset(CHO)underset(|)CH-underset(CHO)underset(|)CH_(2)`
Discussion
18.

During the electrolysis of molten NaCl solution, 230g of sodium metal is deposited on the cathode, then how many moles of chlorine will be obtained at anode

Answer»

10
3.48
35.5
`17.0`

SOLUTION :`(W_(1))/(W_(2))=(E_(1))/(E_(2))`
`(230)/(W_(2))=(33)/(35.5)`
`W_(2)=247.42`
`n=(247.42)/(71)=3.48` moles `Cl_(2)` gas.
Discussion
19.

Draw the structure of propofol? Mention its use.

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SOLUTION :Propofol structure:

It is USED during MINOR SURGICAL procedures.
Discussion
20.

During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 ampere is

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55 minutes
110 minutes
220 minutes
330 minutes

Solution :`2CL^(-)toCl_(2)(g)+2E^(-)`
To PRODUCE 1 mol of `Cl_(2)`, charge required
`=2F=2xx96500C`
`THEREFORE`To produce 0.1 mol of `Cl_(2)`, charge required
`=2xx96500xx0.1=19300C`
`Q=Ixxt`
`thereforet=Q=(19300)/(3)sec=(19300)/(3xx60)`min
`=107.22"min"cong110`min
Discussion
21.

Draw the structure of phosphinic acid (H_3PO_2).

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SOLUTION :Phosphinic ACID ( HYPOPHOSPHOROUS acid ) has the STRUCTURE :
Discussion
22.

During the electrolysis of Potassium acetate solution the anode products are

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`C_(2) H_(6) ,CO_(2)`
`C_(2) H_(6) , H_(2)`
`C_(4) H_(10) , CO_(2)`
`CH_(4) , C_(2) H_(6)`

Answer :A
Discussion
23.

During the electrolysis of fused PbBr_(2) the reaction that occurs at the cathode is :

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BROMIDE ions are OXIDIZED
bromide ions are reduced
lead ions are oxidized
lead ions are reduced

Solution :Reduction occurs at CATHODE as
`PB to Pb^(2+) + 2e^(-)`
Discussion
24.

Draw the structure of peroxodisulfuric acid.

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SOLUTION :`HO - OVERSET(O)overset(||)UNDERSET(O)underset(||)S-O-O-overset(O)overset(||)underset(O)underset(||)S-OH`
Discussion
25.

Draw the structure of perchloric acid (HClO_4)

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SOLUTION :
Discussion
26.

During the electrolysis of fusedNaCI, the reaction that occurs at the anode is :

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CHLORIDE IONS are oxidized
Chloride ions are oxidized
Sodium ions are oxidized
Sodium ions are reduced

Answer :A
Discussion
27.

Draw the structure of penicillin? Give its use.

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Solution :
Penicillin is USED to treat all TYPE of INFECTIONS PNEUMONIA, urinary tract infections.
Discussion
28.

During the electrolysis of fused sodium chloride, the anodic reaction is

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Reduction of SODIUM ions
OXIDATION of sodium ions
Reduction of chloride ions
Oxidation of chloride ions

Solution :`2NaCl overset("Electric CURRENT" ) to underset("Cation")(2Na^(+)) + underset("ANION")(2Cl^(-))`
Discussion
29.

Draw the structure of PCl_(3).

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SOLUTION :
Discussion
30.

During the electrolysis of fused potassium chloride at platinum electrodes, 0.25 gram atom of metal is liberated. What would be the volume of chlorine that can be collected in the experiment at STP?

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Solution :REACTION at cathode,
`K^(+)+e^(-) rarr K` and
at anode, `2Cl^(-) rarr 2e^(-) +Cl_(2)`.
For 0.25 GRAM ATOM of potassium liberated, moles of chlorinereleased `=0.125`.
Volume of chlorine released in the experiment at STP
`=0.125xx22.4=2.8 L`.
Discussion
31.

Draw the structure of PCI_(5). Or Solid PCI_(5) is ionic in nature.

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SOLUTION :In the solid state, `PCI_(5)` exists as `[PCI_(4)]^(+)[PCI_(6)]^(-)` in which `[PCI_(4)]^(+)` species is tetrahedral while `[PCI_(6)]^(-)` species is octahedral as SHOWN :
Discussion
32.

During the electrolysis of dilute sulphuric acid, the following process is possible at anode.

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`2H_2O_((L)) to O_(2(g)) + 4H_((AQ))^(+) + 4e^(-)`
`2SO_(4(aq))^(2-) to S_2O_(8(aq)) + 2e^(-)`
`H_2O_((l)) to H_((aq))^+ + OH_((aq))^-`
`H_2O_((l)) + e^(-) to 1/2H_(2(g)) + OH_((aq))^-`

ANSWER :A
Discussion
33.

During the electrolysis of CrCl_(3), chlorine gas is evolved at the anode and chromium is deposited at the cathode. How many grams of Cr and how many litres of chlorine (at NTP) are produced, when a current of 6 amperes is passed for one hour ?

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SOLUTION :3.88 G, 2.507 LITRES
Discussion
34.

Draw the structure of optical isomers of (i) [PICl_(2)] (en)_(2)]^(2+) (ii). [Cr.(NH_(3))Cl_(2)(en)]^(+)

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Solution :Only cis-form will show optical ISOMERISM

(ii) Both cis and transforms will show optical isomerism: `cis - [Cr (NH_(3))_(2)Cl_(2)(EN)]`
Discussion
35.

During the electrolysis of cryolite, aluminium and fluorine are formed in .... molar ratio

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`1:2`
`2:3`
`1:1`
`1:3`

ANSWER :B
Discussion
36.

During the electrolysis of calcium chloride for the extraction of calcium, calcium fluoride is also added. The calcium fluoride :

Answer»

lowers the melting point of CALCIUM chloride
behaves as a medium
acts as an anode
make the FLOW of CURRENT fast

Answer :A
Discussion
37.

Draw the structure of O_3, molecule.

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SOLUTION :STRUCTURE of OZONE is :
Discussion
38.

During the electrolysis of aqueous solution of the following, molarity of the solution increaseswithout changing the chemical composition

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NaCl
HCl
`CuSO_(4)`
`H_(2)SO_(4)`

Discussion
39.

During the electrolysis of acidulated water, the mass of hydrogen obtained is 'x' times that of O_2 and the volume of H_2 is 'y' times that of O_2 .The ratio of 'y' and 'x' is

Answer»

16
8
0.125
0.25

Answer :A
Discussion
40.

During the electrolysis of a concentrated brine solution. Calculate the moles of chlorine gas produced by the passage of 4F electricity.

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SOLUTION :`2Cl^(-) to Cl_2 + 2e^(-) 2F to " 1 MOLE " , 4F to " 2 MOLES "`
Discussion
41.

Draw the structure of monomers of the following polymer : Teflon

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SOLUTION :`F_2C = CF_2` TETRAFLUOROETHENE
Discussion
42.

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 g mL^(-1) to 1.139 g mL^(-). Sulphuric acid of density 1.294 g mL^(-1) is 39% by weight and that of density 1.139 g mL^(-1) is 20% by weight. The battery hold 3.5 litre of acied and discharge. Calculate the no. of ampere hour for which the battery must have been used. The charging and discharging reactions are: Pb+SO_(4)^(2-) rarr PbSO_(4)+2e (charging) PbO_(2)+4H^(+)+SO_(4)^(2-)+2e rarr PbSO_(4)+2H_(2)O (discharging)

Answer»

Solution :The overall battery reaction is `Pb+PbO_(2) + 2H_(2)SO_(4) = 2PbSO_(4) + 2H_(2)O`
`because` two moles of electrons are involved for the reaction of two moles `H_(2)SO_(4)`.
`THEREFORE` eq. wt. of `H_(2)SO_(4)` = mol. Wt. of `H_(2)SO_(4) = 98`.
Following in the same WAY as in
no. of eq. of `H_(2)SO_(4)` present in 3.5 litres of solution of a charged battery
`= (39)/(98) xx (1.294)/(100) xx 3500`
`= 18.0235`
No. of equivalents of `H_(2)SO_(4)` present in 3.5 litres of solution after getting discharged `= (20)/(98) xx (1.139)/(100) xx 3500`
= 8.1357
Number of eq. of `H_(2)SO_(4)` lost = 18.0235 - 8.1357
= 9.8878
`therefore` moles of electric charge produced by the battery = 9.8878 F
`= 9.8878 xx 96500` coulombs
`= 9.8878 xx 96500` amp - seconds
`= (9.8878 xx 96500)/(60 xx 60)` amp - HOURS
=265 amp - hours.
Discussion
43.

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 to 1.139 g/mL. Supphuric acid of density 1.294 g/mL is 39% H_(2)SO_(4 )by weight and that of density 1.139 g/mL is 20% H_(2)SO_(4)by weight. The battery hold 3.5 L of the acid and the volume remained particlcally constant during the discharge.Calculate the number of ampere-hours for which the battery must have been used. The charging and discharging reactions are Pb+SO_(4)^(2-) = PbSO_(4) +2e^(-) (charging) PbO_(2)+ 4H^(+) + So+(4)^(2-) = PbSo_(4) + 2H_(2)O (discharging)

Answer»

Solution :For 1.0 L `H_2SO_4`:
INITIAL mass of `H_2SO_4=1294xx39/100=504.66g,` FINAL mass of `H_2SO_4=1139xx20/100=227.80g`
`implies H_2SO_4` Consumed/litres `=504.66-227.80=276 g`
`implies` Total `H_2SO_4` USED up `=276.86xx3.5=969.01 g=(969.01)/(98) m ol= 9.888 m ol`
Q 1 mole of `H_2SO_4` is associated with transfer of .0 mole of electrons, total of 9.888 mole ofelectrone tranfer has occured.
Ampere-hour `=(9.888xx96500)/(3600)=2.65Ah`
Discussion
44.

Draw the structure of monomers of the following polymer : Polythene

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SOLUTION :`H_2C = CH_2` ETHENE
Discussion
45.

Draw the structure of O_(3) molecule.

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SOLUTION :`O_(3)` MOLECULE.
Discussion
46.

Draw the structure of monomers of each of the polymer : PVC

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Solution :`H_2C-=underset("Vinyl CHLORIDE")underset(CL)underset(|)(CH)`
Discussion
47.

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 to 1.139 g.ml^(-1).H_(2)SO_(4) of density 1.294 gml^(-1) is 39% and that of density 1.139 g.ml^(-1) is 20% by weight. The battery holds 3.5 L of acid and the volume practically remains constant during discharge. Calcualte the number of ampere hours for which the battery must have been used. The discharging and charging reactions are: Pb + SO_(4)^(2-) rightarrow PbSO_(4) + 2e^(-) (Anodic reaction) PbO-92) + 4H^(+) + SO_(4)^(2-) + 2e^(-) rightarrow PbSo_94) + 2H_(2)O (Cathode reaction)

Answer»


ANSWER :265
Discussion
48.

Draw the structure of : {:((i)BrF_(3),(ii)XeOF_(4)):} (b) Explain giving reason in each case : (i) Why H_(2) Te is more acidic than H_(2)S? (ii) Why are halogens strong oxidising agents ? (iii) Why does nitrogen show catenation tendentcy less than phosphorus ?

Answer»

Solution :
(i) As the size of element increase down the group bond length increases and hence, bond dissociation energy decreases. Hence H-S bond dissociation energy is higher than that of H- Te bond dissociation energy and hence H- S bond breakes less EASILY than H- Te bond. Hence `H_(2)` Te is strong acid than `H_(2)S.`
(ii) See Q. 25, (or) (b) (i) Delhi Board (Comptt.) 2016.
(iii) N-N single bond is weaker than P - P single bond because Nitrogen has smaller size, due to that lone pair of electrons on TWO N-atom repel the bond of N-N bond and hence, it makes N-N single ond weakeer than P-P bond in which the lone pair of electrons FO not replel the bond pair electrons because bigger size of phosphorus. Consequently, Nitrogen shows the little tendency for CATENATION than PHOSPHOROUS.
Discussion
49.

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 g/m to 1.139 g/m. Sulphuric acid of density 1.294 g/m was 39% H_2SO_4 by wt. while acid of density 1.139 g/ m contains 20% acid by wt. The battery holds 3.5 L of acid and the value remianed practically same through the discharge. Catculate the number of amp hr. for which the battery must have been used. The charging and discharging reactions are : PbO_2 +SO_4^(2-) + 4H^++ 2e^(-)toPbSO_4 + 2H_2O (discharging ) PbSO_4 (s) +2eto Pb (s) + SO_4^(2-)(charging )

Answer»


ANSWER :[0.954 A HR]
Discussion
50.

During the discharge of a lead storage battery, density of H_2SO_4fell from 1.3 to 1.14 g/mL. Sulphuric acid of density 1.3g/ml is 40W% and that of 1.14g/mL is 20W%. The battery holds two litre of the acid and volume remains practically constant during discharging. The number of ampere-sec used from the battery is.

Answer»

`3 XX 96,500`
`6 xx 96,500`
`9 xx 96,500`
`12 xx 96,500`

Answer :B
Discussion