Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Among the following compounds C_(5)H_(7)NH_(2),NH_(3),CH_(3)NH_(2),C_(2)H_(5)NH_(2) and C_(6)H_(5)NH, the least basic compound is

Answer»

`C_(3)H_(7)NH_(2)`
`NH_(3)`
`CH_(3)NH_(2)`
`C_(6)H_(5)NH_(2)`

Solution :`C_(6)H_(5)NH_(2)` is least basic compound DUE to RESONANCE by which the lone PAIR of nitrogen TAKES part in resonance `&` due to unavailability of lone pair on N. Aniline become less basic. The lone pair of N is delocalized into benzene ring by resonance
Discussion
2.

Among the following compound which one is planar in shape

Answer»

methane
Acetylene
BENZENE
isobutane

Solution :All 6 CARBONS of Benzene are `sp^2`- hybridised so it is PLANAR
Discussion
3.

Among the following compound, the weakest acid is-

Answer»

`HC-=CH`
`C_(6)H_(6)`
`C_(2)H_(6)`
`CH_(3)OH`

ANSWER :C
Discussion
4.

Among the following compound. (a) Number of compounds which are aromatic = w (b) Number of compounds which are non-aromatic = x (c) Number of compounds which are anti-aromatic = y (d) Number of compounds which readily undergo Dimerzation at room temperature = z Sum of w + x + y + z =....

Answer»


Solution :`w rArr a, B, f, h, I, j`
`x rArr d, E, g, l`
`y rArr c, K`
`d rArr c, k`
SUM of `w + x + y + z = 14`
Discussion
5.

Among the following compound the reactivity order is (1)H - CHO""(2) CH_(3) - CHO (3) CH_(3) - overset(O)overset(||)(C) - CH_(3)""(4) C_(2)H_(5)-COCH_(3)

Answer»

` 1 gt 2 gt 4 gt 3`
`4 gt 3 gt2 gt 1 `
` 1 gt 2 gt 3 gt 4`
` 1 gt 3 gt 4 gt 2`

ANSWER :C
Discussion
6.

Among the following compound s that is bothparamagnetic and colouredis

Answer»

`K_(2)Cr_(2)O_(7)`
`(NH_(4))_(2)[TiCl_(6)]`
`VOSO_(4)`
`K_(3)[Cu(CN)_(4)]`

Solution :For a compoun to be coloured, the CENTRAL atom should have INCOMPLETELY filled d-orbital and to be a pramagnetic , there should be at least one unpaired electron Here, we have
`{:("Compound","Central atom","Electronic config."),(K_(2)Cr_(2)O_(7),._(24)Cr(VI),3s^(2)3p^(6)),((NH_(4))_(2)[TiCl_(6)],._(22)Ti(IV),3s^(2)3p^(6)),(VOSO_(4),._(23)V(IV),3s^(2)3p^(6)3d^(1)),(K_(3)[Cu(CN)_(4)],._(29)Cu(I),3s^(2)3p^(6)3d^(10)):}`
Discussion
7.

Among the following compound. (a) Number of compounds which are aromatic = P (b) Number of compounds which are anti-aromatic = Q (c) Number of compounds which are non-aromatic = R (d) Number of compounds which readily undergo dimerization at room temperature = S (e) Number of compound which reacts with active metal = T Sum of P + Q + R + S + T=

Answer»


SOLUTION :`P + Q + R = 12`
`S = (B + d) = 2`
`T = (b + d + f + I + 1) = 5`
Sum of `P + Q + R + S + T = 19`
Due to STERIC hindarance dimerization does not take place.
Discussion
8.

Among the following complexes the one which shows Zero crystal field stabilization energy (CFSE) is

Answer»

`[Ni(CO)_(4)]` and `[NiCl_(4)]^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is paramagnetic
`[NiCl_(4)]^(2-)` and `[Ni(CN)_(4)]^(2-)` are diamagnetic and `[Ni(CO)_(4)]` is paramagnetic
`[Ni(CO)_(4)]` and `[Ni(CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagnetic
`[Ni(CN)_(4)] ` is diamagnetic while `[NiCl_(4)]^(2-)` and `[Ni(CN)_(4)]^(2-)` are paramagnetic .

Solution :c)it is the CORRECT answer.
Discussion
9.

Among the following componds which have more than one type of hybridisation for carbon atom (i)CH_3CH_2CH_2CH_3 (ii)CH_3-CH=CH-CH_3 (iii)CH_2=CH-C-=CH (iv)H-C-=C-H

Answer»

(II) and (III)
(ii)
(iii) and (IV)
(iv)

ANSWER :A
Discussion
10.

Among the following complexes which one shows zero CFSE ?

Answer»

`[Mn(H_(2)O)_(6)]^(3+)`
`[FE(H_(2)O)_(6)]^(3+)`
`[CO(H_(2)O)_(6)]^(2+)`
`[Co(H_(2)O)_(6)]^(3+)`

Answer :B::C
Discussion
11.

Among the following complexes the one which shows zero crystal field stabilisation energy is

Answer»

`[MN(H_2O)_6]^(3+)`
`[Fe(H_2O)_6]^(3+)`
`[Co(H_2O)_6]^(2+)`
`[Co(H_2O)_6]^(3+)`

Answer :B
Discussion
12.

Among the following complexes, the one which shows zero crystal field stabilization energy (CFSE) is

Answer»

`[Mn(H_(2)O)_(6)]^(3+)`
`[Fe(H_(2)O)_(6)]^(3+)`
`[Co(H_(2)O)_(6)]^(2+)`
`[Co(H_(2)O)_(6)]^(3+)`

Solution :`H_(2)O` is a weak field LIGAND. Hence,
`Delta_(0) lt` PAIRING ENERGY.
CFSE = `(-0.4x+0.6y) Delta_(0)`
where x and y are no. of electrons OCCUPYING `t_(2g)` and `e_(g)` orbitals respectively.
For `[Fe(H_(2)O)_(6)]^(3+)` complex ion, `Fe^(3+)(3d^(5)) = t_(2g)^(3) e_(g)^(2)`
`therefore CFSE=-0.4xx3+0.6xx2=0Dq`
Discussion
13.

Among the following complexes (K - P) : K_(3) [Fe(CN)_(6)] - K , [Co(NH_(3))_(6)]Cl_(3)- L , Na_(3)[Co("oxalate")_(3)]-M , [Ni(H_(2)O)_(6)]Cl_2 - N, K_(2) [Pt(CN)_(4)]-O and [Zn(H_(2)O)_(6)] (NO_(3))_(2)-P, the diamagnetic complexes are

Answer»

K , L , M , N
K , M , O , P
L , M , O, P
L , M , N , O

Solution :For COMPLEXES L and M , i.e, `[Co(NH_(3))_(6)]^(3+)` and `[Co("OX")_(3)]^(3-)`
`Co^(3+) (3D^(6)) is d^(2) sp^(3)` hybridised .

For complex K , i.e, `[Fe(CN)_(6)]^(3-) , Fe^(3+) (3d^(5)) is d^(2) sp^(3)` hybridised .

For complex O i.e., `[PT(CN)_(4)]^(2-)` ,
`Pt^(2+) (5d^(8)) is DSP^(2)` hybridised.

For complexP , i.e, `[Zn(H_(2)O)_(6)]^(2+)`
`Zn^(2+) (3d^(10)) is sp^(3) d^(2)` hybridised .

For complex N, i.e., `[Ni(H_(2)O)_(6)]^(2+)` ,
`Ni^(2+) (3d^(8)) is sp^(3) d^(2)` hybridised .

Hence , complexes L, M , Oand P are diamagnetic .
Discussion
14.

Among the following complexes (K-P) K_(3)[Fe(CN)_(6)] (K), [Co(NH_(3))_(6)]Cl_(3) (L), Na_(3)[Co("oxalate")_(3)] (M), [Ni(H_(2)O)_(6)]Cl_(2) (N), K_(2)[Pt(CN)_(4)](O) and [Zn(H_(2)O)_(6)](NO_(3))_(2)(P) the diamagnetic complexes are

Answer»

<P>K, L, M, N
K, M, O, P
L, M, O, P
L, M, N, O

Solution :K : `K_(3)[Fe(CN)_(6)],Fe^(3+)=3d^(5), d^(2)sp^(3)` HYBRIDIZATION, number of unpaired ELECTRONS = 1, paramagnetic.
L : `[Co(NH_(3))_(6)]Cl_(3), Co^(3+)=3d^(6), d^(2)sp^(3)` hybridization, number of unpaired electrons = 0, diamagnetic.
Discussion
15.

Among the following complexes : K_(3)[Fe(CN)_(6)],[Co(NH_(3))_(6)]Cl_(3) , Na_(3)[Co ( o x )_(3)],[Ni(H_(2)O)_(6)]Cl_(2),K_(2)[Pt(CN)_(4)] and [Zn(H_(2)O)_(6)(NO_(3))_(2)] The diamagnetic are .

Answer»

K, M, O, P
K, L, M, N
L, M, N, O
L, M, O ,P

Answer :D
Discussion
16.

Among the following complexes , how many have 'spin only' magnetic moment of 2.83 B.M. ? [Ni(CO)_4],[Ni(CN)_4]^(2-),[NiCl_2( P Ph_3)_2], [NiCl_4]^(2-),[NiF_6]^(2-),[NiF_6]^(4-),[Ni(NH_3)_6]^(2+),[Ni(en)_3]^(2+),[Ni(H_2O)_6]^(2+)

Answer»


SOLUTION :
Discussion
17.

Among the following chemical reactions, the one representing homogenous catalysis is :-

Answer»

`N_(2)(g) + 3H_(2) (g) overset(Fe) to2NH_(3)(g) `
`2 SO_(2)(g) + O_(2)(g) overset(2NO) to2 SO_(3) (g)+2NO(g) `
CO(g) + 2H2(g) `overset(Ni)to ` CH4(g) + H2O
2 SO2(g) + O2(g) `overset(V_(2) O_(5))to` 2SO3(g)

Answer :B
Discussion
18.

Among the following, chain transfer reagent(s) is/are

Answer»

CARBON tetrachloride
benzoyl peroxide
benzoquinone
carbon tetrabromide.

Solution :Carbon tetrachloride and carbon tetrabromide ACT as chain TRANSFER reagents in VINYL polymerisation.
Discussion
19.

Among the following cells Leclanche cell (I) Nickel-cadmium cell (II), Lead storage battery (III) and Mercury Cell (IV), primary cells are …………. .

Answer»

I & II
I & III
II & III
I & IV

Answer :D
Discussion
20.

Among the following cells Lechanche cell (I), Nickel-cadmium cell (II), Lead storage battery (III), Mercury (IV), primary cells are

Answer»

I and II
I and III
II and III
I and IV

Solution :Leclanche cell and MERCURY CELLS are PRIMARY cells.
Discussion
21.

Among the following cells I. Leclanche cell "" II. Nickel - Cadmiun cell III. Lead storage battery "" IV. Mercury cell Primaru cells are ………….. .

Answer»

I and IV
I and III
III and IV
II and III

Answer :A
Discussion
22.

Among the followingcellsi) Leclanche cell II) Nickel - Cadmium cell (iii) Leadstoragebattery (iv) Mercury cell Primarycellsare

Answer»

I and IV
I and III
III and IV
II and III

SOLUTION :(iv) , (i) , (ii) , (iii)
Discussion
23.

Among the following cells I) Leclanchecell II) Nickel - Cadmium cell III) Lead storage battery (IV) Mercury cell Primary cells are

Answer»

I and IV
I andIII
III and IV
II and III

Answer :A
Discussion
24.

Among the following carbocations : "(I) "Ph_(2)C^(+)CH_(2)Me"(II) "PhCH_(2)CH_(2)CH^(+)Ph "(III) "Ph_(2)CHCH^(+)Me"(IV) "Ph_(2)C(Me)CH_(2)^(+) The order of stability is

Answer»

`IVgtIIgtIgtIII`
`IgtIIgtIIIgtIV`
`IIgtIgtIVgtIII`
`IgtIVgtIIIgtII`

ANSWER :B
Discussion
25.

Among the following carbocations : (I) Ph_(2) C^(+) CH_(2) Me(II) PhCH_(2) CH_(2) CH^(+)Ph (III)Ph_(2) "CHCH"^(+) Me(IV) Ph_(2) "C(Me)CH"_(2)^(+)the order of stability is

Answer»

`IV gt II gt I gt III `
`I lt II lt III lt IV`
`II gt I gt IV gt III`
`I gt IV gt III gt II`

SOLUTION :
Stability of carbocation DEPENDS upon NUMBER of resonating structures and extent of +1, -I effect.
Discussion
26.

Among the following bonds which has the most polar character :

Answer»

C-O
C-Br
C-F
C-S

Answer :C
Discussion
27.

Among the following anions overset-CH_3 overset-NH_2 OH^- F^-, the order of basicity is:

Answer»

agtbgtcgtd
bgtagtcgtd
cgtbgtagtd
cgtagtbgtd

Answer :A
Discussion
28.

Which of the following is an acidic salt ?

Answer»

`NaH_(2)PO_(2)`
`NaH_(2)PO_(3)`
`Na_(2)HPO_(3)`
`Na_(3)PO_(4)`

ANSWER :2
Discussion
29.

Among the following amino acids, the (R)-enantiomer is represented by:

Answer»




ANSWER :B
Discussion
30.

Among the following amines, the strongest Bronsted base is….

Answer»


`NH_3`

Solution : Aniline is a weaker base than NH, due to delocalization of lone pair of electrons on the N ATOM into the benzene ring. Pyrrole (c)is not at all basic because the lone pair of electrons on the N-atom is DONATED towards aromatic sextet formation. Therefore, PYRROLIDINE (d) has a strong TENDENCY to accept a proton and is hence it is the strongest Bronsted base.
Discussion
31.

Among the following amines, the strongest Bronsted base is

Answer»

`NH_(3)`


Solution :In (c), electrons on the N ATOM are delocalized over two double bonds but in (d), electrons are more strongly delocalized over the benzene RING but in (b), electrons are not delocalized at all, therefore, it is the strongest BASE. Further, being a `2^(@)` amine, it is more basic than EVEN `NH_(3)`. THUS, option (b) is correct.
Discussion
32.

Among the following amines, the strongest Bronsted base is____

Answer»


`NH_(3)`

ANSWER :D
Discussion
33.

Among the following actinide pairs, the maximum oxidation states is shown by

Answer»

U and NP
Np and PU
Pu and An
U and Pa

Solution :Both Np and Pu show HIGHEST oxidation state of `+7`
Discussion
34.

Among the following amines the correct order of decreasing basic strength is:

Answer»

IVltIIltIIIltI
IltIIltIIIltIV
IIltIltIIIltIV
IIIltIIltIltIV

Answer :A
Discussion
35.

Among the following acids which has the lowest pK_a value

Answer»

`CH_3 COOH`
`HCOOH`
`(CH_3)_2 CH - COOH`
`CH_3CH_2 COOH`

Answer :B
Discussion
36.

Among the following acidic strength is (1) CH_(3) - CH_(2) - COOH ""(2) CH_(3) - underset(CN) underset(|) (CN) - COOH (3)CH_(3) - underset(Cl) underset(|) (CH) - COOH""(4) CH_(3) - underset(NO_(2))underset(|) (CH) - COOH

Answer»

`4 gt 1 gt 2 gt 3`
` 3 gt 4 gt 2 gt 1`
` 4 gt 2 gt 3 gt 1`
` 4 gt 3 gt 2 gt 1`

Answer :C
Discussion
37.

Among the following acids, the one which can form an anhydride most easily is :

Answer»

`{:(COOH),(|),(COOH):}`
`{:(CH_(2)CH_(2)COOH),(|),(CH_(2)CH_(2)COOH):}`

ANSWER :C
Discussion
38.

Among the following acids, which has the lowest pK_a value-

Answer»

`(CH_3)_2CHCO_2H`
`C_2H_5CO_2H`
`CH_3CO_2H`
`HCO_2H`

ANSWER :D
Discussion
39.

Among the following, achiral amino acid is'

Answer»

GLYCINE
ALANINE
PROLINE
TRYPTOPHAN

ANSWER :A
Discussion
40.

Among the following a refrigirant is

Answer»

`CHCl_3`
`CH_2 F_2`
`C Cl_4`
`C Cl_4 F_2`

ANSWER :D
Discussion
41.

Among the following, a naturalpolymer is

Answer»

CELLULOSE
PVC
polyethylene
TEFLON

SOLUTION :Cellulose is a NATURAL POLYMER .
Discussion
42.

Among the folllowing the weakest lewis base is…….

Answer»

`H^-`
`OH^-`
`CL^-`
`HClO_3^-`

Solution :`Cl^-` is a CONJUGATE base of STRONG acid HCl.
Discussion
43.

Among the fluorides given which will further react with F_2 :

Answer»

NAF
`CaF_2`
`SF_6`
`IF_5`

ANSWER :D
Discussion
44.

Among the enlisted compounds, which one is used as a froth stabilizer in the froth floatation process?

Answer»

Aniline
Phenol
Benzaldehyde
Anisole

Answer :A
Discussion
45.

Among the elements from atomic number 1 to 36, the number of elements which have an unpairedelectron in their S subshell is

Answer»

4
7
6
9

Solution :`""_(1)H=1s^(1),""_(3)Li=2s^(1),""_(11)Na=3s^(1),""_(19)K=[Ar]`
`4s^(1)""_(24)Cr=[Ar]3D^(5) 4s^(1)""_(29)Cu=[Ar]3d^(10)4s^(1)`
Discussion
46.

Among the elements Ca, Mg, P and Cl, the order of increasing atomic radii is

Answer»

`MgltCaltClltP`
`CL ltPltMgltCa`
`PltCl ltCaltMg`
`CaltMgltPltCl`

SOLUTION :In a period SIZE decreases from left to RIGHT.
Discussion
47.

Among theelectrolytes Na_(2)SO_(4),CaCl_(2),Al_(2)(SO_(4))_(3)and NH_(4)Cl_(4), the mosteffective coagulating agent for Sb_(2)S_(3) sol is .

Answer»

`Na_(2)SO_(4)`
`CaCl_(2)`
`Al_(2)(SO_(4))_(3)`
`NH_(4)Cl`

SOLUTION :`Sb_(2)S_(3)` is a negative sol and according to HardySchulze rule:
(i)Ions carrying charge OPPOSITE to that of sol particles are effective in causing coagulation.
(ii) Coagulating power of an electrolyte is directly proportional to the valency of the active ions.
`therefore ` Outof the given options the mosteffective coagulatingagentis `Al_(2)(SO_(4))_(3) ` or `Al^(3+)` ion.
Discussion
48.

Amongthe electrolytes Na_(2)SO_(4),CaCl_(2),Al_(2)(SO_(4))_(3) and NH_(4)Cl, the most effective coagulating agent for Sb_(2)S_(3) sol is

Answer»

`Na_(2)SO_(4)`
`CaCl_(2)`
`Al_(2)(SO_(4))_(3)`
`NH_(4)Cl`

Solution :`Sbg_(2)S_(3)` is a negatively charged SOL. The most effective coagulating agent will be electrolyte with HIGHEST positive cfharge on the cartion, vz, `AL_(2)(SO_(4))_(3).` The order is
`Al^(3+)gt Ca^(2+)gt Na^(+)gt NH_(4)^(+).`
Discussion
49.

Amongthe electrolytes Na_2SO_4 , CaCl_2, Al_2(SO_4)_3 and NH_4Cl , the most effectivecoagulating agent for Sb_2S_3 sol is................

Answer»

`Na_2SO_4`
`CaCl_2`
`Al_(2)(SO_4)_3`
`NH_4Cl`

SOLUTION :`Al_(2)(SO_4)_3`
Discussion
50.

Among the electrolytesNa_(2)SO_(4) , CaCI_(2), AI_(2)(SO_(4))_(3) and NH_(4)CIthe most effctive oagulating agent for Sb_(2)S_(3) sol is

Answer»

`Na_(2)SO_(4)`
`CaCI_(2)`
`AI_(2)(SO_(4))_(3)`
`NH_(4)CI`

Answer :C
Discussion