Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The reaction of WCl_6with Al at about 400^@Cgives black crystals of a compound that contains only tungsten and chlorine. A sample of this compound, when reduced with hydrogen gives 0.2232 g of tungsten metal and hydrogen chloride, which is absorbed in water. Titration of the hydrochloric acid thus produced required 46.2 mL of 0.1051-M NaOH to reach the end point. What is the empirical formula of the black tungsten chloride?

Answer»

SOLUTION :`WCl_4`
2.

The reaction of toluene with CLl_(2) in presence of FeCl_(3) gives X and reaction in presence of light gives Y. thus, X and Y are:

Answer»

X=benzyl CHLORIDE, Y=m-chlorotoluene
X-benzal chloride, Y=o-chlorotoluene
X-m-chlorotoluene, Y=p-chlorotoluene
X=o- and p-chlorotoluene, Y=trichloromethylbenzene.

Solution :
THUS, OPTION (d) is CORRECT.
3.

The reaction of water with sodium and potassium is:

Answer»

Reversible
Irreversible and endothermic
Exothermic
Endothermic

Answer :C
4.

The reaction of toulene with Cl_2 in presence of FeCl_3 gives predominently

Answer»

<P>m-Chloro TOLUENE
BENZOYL chloride
Benzyl chloride
o-&p- Chloro toulenes

Answer :D
5.

Toluene reacts with Cl_2 in presence of FeCl_3 giving

Answer»

<P>m-chlorotoluene
benzoyl chloride
o- and p- chlorotoluene
benzal chloride

Answer :C
6.

The raction of toluene with CI_(2) in presence of FeCI_(3) gives X and reaction in presence of light gives Y Thus X and Y are .

Answer»

<P>X=benzyl CHLORIDE , Y=m-CHLOROTOLUENE
X=benzyl chloride , Y=o-chlorotoluene
X=m-chlorotoluene, Y=p-chlorotoluene
X=o- and p- chlorotoluene, Y=trichloromethyl BENZENE

SOLUTION :
7.

The reaction of toluene with Cl_(2) in presence ofFeCl_(3) gives predominantly.

Answer»

<P>m-CHLOROTOLUENE
Benzoyl chlordie
p-chlorotoluene
o- and p- chlorotoluene

Solution :CL being o, p-directing GIVES a mixture of o - and p - chlorotoluene.
8.

The reaction of toluene with chlorine in the presence of iron and in the absence of light yields______

Answer»




MIXTURE (B) and (c)

Solution :CL is o, p-directing, i.e., OPTION (d) is correct.
9.

The reaction of toluene with chlorine in the presence of iron and in the absence of light yields …….. .

Answer»




MIXTURE of (B) and (C )

SOLUTION :
10.

The reaction of toluene with Cl_(2) in presence of FeCl_(3) gives predominantly :

Answer»

BENZYL CHLORIDE
o- and p-chlorotoluene
m-chlorotoluene
BENZOYL chloride

SOLUTION :
11.

the reaction of toluence with Cl_(2) in presence of FeCl_(3) gives 'X' and reaction in presence of light gives 'Y'. Thus, 'X' and 'Y' are:

Answer»

<P>X= Benzal CHLORIDE, Y = o-Chlorotoluene
X= m-Cblorotoluene, Y = p -Chlorotoluene
X = o -and p-Chlorotoluene, Y = TRICH loromethylbenzene
X= Benzyl chloride, Y = m-Chlorotoluene

SOLUTION :
12.

The reaction of toluene with chlorine in the presence of FeCl_(3) gives predominantly

Answer»

BENZYL CHLORIDE
BENZAL chloride
m-chloro TOLUENE
o-and p-chloro toluene

ANSWER :D
13.

The reaction of toluene with chlorine in the presence of ferric chloride gives mainly

Answer»

<P>BENZOYL CHLORIDE
m-chlorotoluene
Benzyl chloride
o and p chlorotoluene

Solution :
14.

The reaction oftoluene withchlorine in thepresence of ferricchloride givesprodominantly

Answer»

BENZYL CHLORIDE
m-chlorotouene
benzyoly chloride
o-andp- CHLORO TOLUENE

ANSWER :D
15.

The reaction of the diene shown below with dry HCl can lead to four products. Provide structural formula of all the products.

Answer»


SOLUTION :N//A
16.

The reaction of t-Butylbromide with sodium methoxide produces mainly

Answer»

Isobutane
Isobutylene
t-Butyl METHYL ether
Sodium tert-butoxide

Solution :
17.

The reaction of tert, butyl bromide with sodium methaoxide produces mainly :

Answer»

Isobutane
ISOBUTYLENE
t-Butyl METHYL ether
Sodium tert, butoxide

Solution :`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-Br+Na^(+)barOC_(2)H_(5)rarrCH_(3)-underset("Isobutylene")underset(CH_(3))underset(|)(C)=CH_(2)+C_(2)H_(5)OH+NaBr`
18.

The reaction of t-butyl bromide with aq. KOH us represented as (CH_(3))_(3)-C-Brunderset("StepI")to(CH_(3))_(3)C^(delta+).........Br^(delta-)underset("StepII")overset(-Br^(-))to(CH_(3))_(3)C^(+)underset("StepIII")overset(OH^(-))to(CH_(3))_(3)C-OH In above reaction which is the fast step?

Answer»

Step -I
Step-II
Step-III
All STEPS TAKES place with EQUAL and ease

Answer :C
19.

The reaction of sulphur powder with phenylmaggnesium bromide followed by hydrolysis gives_____.

Answer»

Solution :`C_(6)H_(5)SH` (THIOPHENOL)
20.

The reaction of t-butyl chloride and sodium ethoxide gies mainly :

Answer»

t-butyl ethyl ether
2, 2-dimethylbutane
2-methyl prop-1-ene
isopropyl-n-propyl ether

Solution :The nucleophile `-OC_(2)H_(5)` cannot attack at the carbon of `-UNDERSET(|)OVERSET(|)(C)-Cl` BOND due to steric hindrance. Hence,ELIMINATION reactionoccurs.
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-Cl+C_(2)H_(5)barONa^(+)rarrunderset("2-Methylprop-1-ene")(CH_(3)-underset(CH_(3))underset(|)(C)=CH_(2))+CH_(3)CH_(2)OH+NaCl`
21.

The reaction of sunflower oil with NaOH can be called___.

Answer»

cracking
saponification
 polymerization
esterification

ANSWER :B
22.

The reaction of sodium with water is highly exothermic. The rate of reaction is lowered by:

Answer»

LOWERING the temperature
Mixing with alcohol
Mixing with ACETIC acid
Making an amalgam

Answer :D
23.

The reaction of sodium methoxide with ethyl bromide follows …………… .

Answer»

`SN^1` MECHANISM
`SN^2` mechanism
`E_1` REACTION
`E_2` reaction

SOLUTION :`SN^2` mechanism
24.

The reaction of sodium sulphate with I_(2) gives

Answer»

Sodium Iodide
Sodium Sulphate
Sodium sulphite
Sodium TETRA thionate

Solution :`UNDERSET("Sodium sulphate ")(2Na_(2)S_(2)O_(2)) + I_(2) rarr underset( "Sodium h")(Na_(2)S_(4)O_(6)) + underset("Sodium ioditionate")(2NaI)`
25.

The reaction of sodium thiosulphate with I_2 gives:

Answer»

SODIUM sulphide
Sodium sulphite
Sodium sulphate
Sodium tetrathionate

Answer :D
26.

The reactionof sodiumacetateandsodalimegives

Answer»

butane
ETHANE
methane
PROPANE

Solution : `UNDERSET ("sodiumacetate")( CH_3COOH )+underset ( "sodalime")( NaOH)to underset ( "methane ") (CH_ 4 )+underset ( "SODIUMCARBONATE")( Na _2CO _ 3) `
27.

The reaction of sodium ethoxide with ethyl iodide to form diethyl ether is termed

Answer»

ELECTROPHILIC substitution
NUCLEOPHILIC substitution
electrophilic addition
radical substitution

Solution :Reaction of sodium ethoxide with ethyl iodide to produce diethyl ether is KNOWN as Williamson synthesis. It is a nucleophilic substitution reaction and proceeds VIA `SN_(2)` mechanism.
28.

The reactionof RMgX with a ketone, followed by treatment with H_(3)O^(+) forms

Answer»

`1^(0)` ALCOHOL
`2^(0)` alcohol
`3^(0)` alcohol
alkane.

SOLUTION :`RCOR + RMgX underset(H_(3)O^(+)) overset("dry ether") to R_(3) C - OH + MgXOH`
29.

Thereactionof RCONH_(2)withamixtureof Br_(2)and KOHgivesR - NH_(2)as a product . Theintermediatesinvolvedin this reactionare .

Answer»

`R - CONBr`
`R - N = C = O`
`- NHBR`

Answer :A::B
30.

The reaction of replacement of a hydrogen atom in benzene by alkyl group can be brought about with the following reagents:

Answer»

ALKYL chloride and `AlCl_(3)`
Alkene and `BF_(3),HF`
Alkanol and alkali
Alkanol and acid

Answer :A::B::D
31.

The reaction of R-overset(O)overset(||)(C)-NH_(2) With a mixture of Br_(2) and KOH gives R-NH_(2) as the main product. The intermediates (s) involved in this reaction is/are

Answer»




ANSWER :A::C
32.

The reaction of RCN with RMgX following by hydrolysis gives

Answer»

an aldehydes
an KETONES
`2^(0)` alcohols
`3^(0)` alcohols

Solution :`RCN + RMhX underset(H_(3)O^(+)) OVERSET("dryether") to RCOR + NH_(3) + MgXOH`
33.

The reaction of propene with HOCl(Cl_2+H_2O) proceeds through the intermediate

Answer»

`CH_3-CH^(+)-CH_2-Cl`
`CH_3-CH(OH)-CH_2^+`
`CH_3-CHCl-CH_2^+`
`CH_3-CH^+ CH_2-OH`

SOLUTION :`CH_3-CH^(+)-CH_2-Cl`
34.

The reaction of propene with HOCl(Cl_2+H_2O) proceedes through the intermediate-

Answer»

SOLUTION :
35.

The reaction of propene with HOCI proceeds via the addition of:

Answer»

`H^+` in the FIRST step
`CI^+` in the first step
`OH^-` in the first step
`CI^+ `and `OH^-` in the SINGLE step

Answer :B
36.

The reaction of primary alkyl halide with nitrile salt produces both RNO_(2) and RONO. Account for this behaviour.

Answer»

Solution :
NITRITE ion is an ambident nucleophile `[O^(-)-overset(. .)(N)=O]` tehrefore, it can attack as nucleophile through both oxygen and NITROGEN atoms and LEADS to the formation of two compounds.
37.

The reaction of phenol with air. The product is

Answer»

Anthraquinone
Benzophenone
Benzoquinone
Propiophenone

Answer :C
38.

The reaction of phenyl methanal and ethanal in the presence of dilute NaOH is known as

Answer»

CANNIZARO reaction
Aldol CONDENSATION
Claisen-schmidt condensation
PERKIN's reaction

Solution :Claisen-schmidt condensation
39.

The reaction of phenol with a diazonium salt in weakly alkaline medium is called_____.

Answer»

SOLUTION :COUPLING REACTION
40.

The reaction of p-HOC_(6)H_(4)COOH with excess Br_(2) forms

Answer»




ANSWER :D
41.

The reaction of p-aminophenol with one mole of acetyl chloride in presence of pyridine gives

Answer»




SOLUTION :
42.

The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by two step process shown below, O_(3)(g)+Cl(g) to O_(2)(g)+ClO(g)… (i) [K_(i)=5.2times10^(9) L*mol^(-1)*s^(-1) ClO(g)+O_(2)(g) to O_(2)(g)+Cl(g)…. (ii) [K_(ii)=2.6times10^(10)l*mol^(-1)*s^(-1)] The closet rate constant for the overall reaction O_(3)(g)+O(g) to 2O_(2)(g) is:

Answer»

`1.4times10^(20)l*mol^(-1)*s^(-1)`
`3.1times10^(10)l*mol^(-1)*s^(-1)`
`5.2times10^(9)l*mol^(-1)*s^(-1)`
`2.6times10^(10)l*mol^(-1)*s^(-1)`

Solution : On adding EQ. (i) and and eq.(ii) wer get `O_(3)(g)+O(g) to 2O_(2)(g)`
Hence overall rate CONSTANT=`K_(i)K_(n)=5.2times10^(9)times2.6times10^(10)=1.4times10^(2)mol^(-1)Ls^(-1)`
43.

The reaction of O_(2) and CO with haemoglobin gives

Answer»

only OXYGEN - HAEME COMPLEX
only CO-haeme complex
both but oxygen - haeme complex is more STABLE
both but CO-haeme complex is more stable.

Solution :Both but CO-haeme complex is more stable.
44.

The reaction of O_(2) and CO with hemoglobin gives

Answer»

only oxygen - HEME complex
only CO - heme complex
both , but oxygen heme complex is more stable
both , but CO- heme complex is more stable

ANSWER :D
45.

The reaction of o-chloroaniline with a mixture of HCl and NaNO_2 followed by cuprous bromide will give

Answer»




SOLUTION :
46.

The reaction of nitroprusside anion with sulphide ion gives purple colouration due to the formation of

Answer»

the tetranionic complex of IRON (II) coordinating to ONE `NOS^(-)` ION
the dianionic complex of iron (II) coordinating to one `NCS^(-)` ion
the trianionic complex of iron (III) coordinating to one `NOS^(-)` ion
the tetranionic complex of iron (III) coordinating to one `NCS^(-)` ion

Solution :`Na_2 S + underset("Sod. Nitroprusside")(Na_(2) [Fe(CN)_(5))NO] to Na_(4) underset("Violet COLOUR")([Fe(CN)_(5) ) NOS]`
`[overset(+2)(Fe) (C overset(-5)(N))_(5) NOS]^(-4) implies` Tetra-anionic complex of iron (II) coordinating to one `NOS^(-)` ion.
47.

The reaction of nitrogen with hydrogen to make ammonia has Delta H= -92 kJ. N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g) What is the value of Delta U ( in kJ) if the raction of correct out at a constant pressure of 40 bar and the volume changes is 1.25 litre.

Answer»


SOLUTION :N//A
48.

The reaction of nitrocompounds to primary amines occurs through the intermediate formation of nitroso compound and hydroxylamine catalytic hydrogenation of reduction of nitro compound with an active metal and concentrated hydrochloric acid always gives the corresponding primary amines. In the neutral medium, the nitro compounds are reduced to corresponding hydroxylamines. However, in the basic medium, bimolecular reduction products are obtained which redult through initial condensation of nitroso and hydroxyl amine intermediates followed by reduction to give different products depending upon the nature of the reducing agent used In the reduction of nitrobenzene, which of the following is the intermediate

Answer»

`C_(6)H_(5)-N=O`
`C_(6)H_(5)NH=NHC_(6)H_(5)`
`C_(6)H_(5)N=N-C_(6)H_(5)`
`C_(6)H_(5)-N=N-C_(6)H_(5)`.

Solution :In the reduction of nitro benzene, the INTERMEDIATE formed is `C_(6)H_(5) - N = OVERSET(O)overset(uarr)(N) - C_(6)H_(5)`
49.

The reaction of nitrocompounds to primary amines occurs through the intermediate formation of nitroso compound and hydroxylamine catalytic hydrogenation of reduction of nitro compound with an active metal and concentrated hydrochloric acid always gives the corresponding primary amines. In the neutral medium, the nitro compounds are reduced to corresponding hydroxylamines. However, in the basic medium, bimolecular reduction products are obtained which redult through initial condensation of nitroso and hydroxyl amine intermediates followed by reduction to give different products depending upon the nature of the reducing agent used The reagent that reacts with nitromethane to form methyl hydroxylamine is ?

Answer»

`Zn//HCl`
`Zn//NH_(4)CL`
`Zn//NaOH`
`Sn//HCl`

Solution :`CH_(3)NO_(2) + 2H overset(Zn(NH_(4)Cl)RARR CH_(3)NHOH`
50.

The reaction of nitrobenzene with zinc and alkali results in the formation of

Answer»

Aniline
Hydrazobenzene
Nitrosobenzene
Phenyl hydroxylamine

Solution :SEE REDUCTION of NITROBENZENE in the COMPREHENSIVE REVIEW.