Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The approximate composition of soda glass is :

Answer»

`SiO_2 75%, Na_2O 15%,CAO 8%,Al_2O_3 2%`
`SiO_2 45%,Na_2O 4%,CaO 3%,K_2O 4%,PBO 44%`
`SiO_2 80%,Na_2O 4%,CaO 0.5%,K_2O 0.5%,B_2O_3 12%,Al_2O_3 3%`
None of the above

Answer :A
2.

Approximate atomic weight of an element is 26.89. If its equivalent weight is 8.9, the exact atomic weight of element would be

Answer»

26.89
8.9
`26.70`
17.8

Answer :C
3.

The appropriate reagent for the following transformation is

Answer»

ZN - Hg/HCl
`H_2N-NH_2`KOH /ethylene glycol
`Ni//H_2`
`NaBH_4`

Solution :
Both Zn- Hg/HCI and `NH_2 NH_2OH^(-)`can REDUCE group but in case of zn-Hg/HCI , HCI will bring about substitution of `OH^(-)`by `CI^(-)`therefore , the most effective regent is `NH_2NH_2OH^(-)`.
4.

The appropriate reagent for the following transformation

Answer»

`Zn(Hg),HCL`
`H_(2),Ni`
`NH_(2)-NH_(2),overset(ӫ)(O)H`
`NaBH_(4)`

Solution :`[PT(H_(2)O)_(4)(OX)][CuCl_(4)]:`Exhibits COORDINATION isomerism
5.

The appropriate formula ofdichloridobis(ethane-1, 2-diamine)platinum(IV) nitrate is :

Answer»

`[PtCl_(2)(en)_(2)](NO_(3))_(2)`
`[PT(en)_(2)Cl_(2)](NO_(3))_(2)`
`[Pt(en)_(2)Cl_(2)]NO_(3)`
`[PtCl_(2)(en)_(2)]NO_(3)`

Solution :N//A
6.

The appreciable radioactivity of uranium minerals is mainly due to

Answer»

An uranium isotope of mass NUMBER 235
A thorium isotope of mass number 232
Actinium
Radium

Solution :RA CONTAMINATED with uranium MINERAL SHOWS appreciant radioactivity
7.

The appearance of colour in solid alkali halides is generally due to

Answer»

SCHOTTKY defect
Frenkel defect
Interstitial POSITION
F-centres

Answer :D
8.

The apparatus used for measuring the heat changes of a reaction is called

Answer»

a thermometer
a calorimeter
BAROMETER
NONE of these.

Solution :barometer
9.

The apparatus shown consits of three temperature jacketed 1 litre bulbs connected by stop cocks. Bulb A contains a mixture of H_(2)O(g) , CO_(2)(g)and N_(2)(g) at 27^(@)C and a total pressure of 547.2 mmHg. Bulb Bis empty and is held at a temperature - 23^(@)C. Bulb C is also empty and is held at a temperature of - 173^(@)C. The stopcocks are closed and the volumes of lines connecting the bulbs is zero. Givn : CO_(2)(g) converted into CO_(2)(s) at - 78^(@)C,N_(2)(g)converted into N_(2)(s) at - 196^(@)C &H_(2)O converted into H_(2)O at 0^(@)C. [Use R =0.08 atm-litre // mole.k ] (a) The stopcock between A &B is opened and the system is allowed to come to equilibrium. The pressure in A & B is now228 mmHg.What do bulbs A& B contain? ( b) How many moles of H_(2)O are in system ? ( c ) Both stopcocks are opened and the systemis again allowed to equilibrium.The pressure throughout the system is 45.6 m Hg. What do bulbs A,B and C contain? (d) How many moles of N_(2) are in the system ?

Answer»


Answer :(a) BULB A `: N_(2)(g) , CO_(2)(g)`
Bulb `B : N_(2)(g) , CO_(2)(g) , H_(2)O(s)`
(b) No. of mole of `H_(2) = 0.0025 `
( c ) Bult `A : N_(2)(g)`
Bulb B `: N_(2)(g) , H_(2)O(s)`
Bulb C `: N_(2)(g) , CO_(2)(s)`
( d) TOTAL no of mole of `N_(2)` in system = 0.013
10.

The apparatus generally used for measuring heat changes is:

Answer»

Voltameter
Voltmeter
Calorimeter
Coulometer

Answer :C
11.

The antisterility or anti reproductive vitamin is:

Answer»

B
C
D
E

Answer :D
12.

The antisptic whicha are used in soap are

Answer»

PERHYDROL
bithionla
chlorine
iodine

Answer :B
13.

The antiseptic used in good quality soaps is

Answer»

Lysol
Bithional
BORIC acid
Salol

ANSWER :B
14.

The antiseptic present in dettol is

Answer»

Codine
Chloroxylenol
BITHIONAL
IODINE

ANSWER :B
15.

The antiseptic dettol is a mixture of _______and _______in a suitable solvent

Answer»


ANSWER :CHLOROXYLENOL, `ALPHA`-terpineol
16.

The antiseptic character of iodoform is due to:

Answer»

Its poisonous NATURE
UNPLEASANT smell
liberation of free iodine
None

ANSWER :C
17.

The antiseptic action of Dettol is due to

Answer»

CHLOROBENZENE
CHLOROXYLENOL
CHLOROQUINE
Chloramphenicol

ANSWER :B
18.

The anticodon transfer RNA for the messenger RNA codon GCA is

Answer»

TGA
GUT
AGT
CGU

Solution :According to base - pairing principle, ADENINE (A) always APPEARS against uracil (U), guanine (G) against CYTOSINE (C) in RNA molecules. Therefore , ANTICODON of GCA is CGU.
19.

The antibodies necessary to protect new born babies from infection are derived from:

Answer»

COW's milk
Pasteurised milk
Mother's milk
Honey

Answer :C
20.

The antibiotic streptomycin is specific against :

Answer»

TUBERCULOSIS
TYPHOID
MALARIA
AIDS

Answer :A
21.

The antibiotic which kills the has microrganism is /are

Answer»

oflaxacin
penicillin
Chloramphenicol
all of these

Answer :D
22.

The antibioticwhich is effective againstcertain strains of cancer cells

Answer»

DYSIDAZIRINE
sulphanilamide
vancomycin
OFLOXACIN.

Solution :Dysidazirine is supposed to be toxic againstcertain STRAINS of cancer CELLS.
23.

The antibiotic Streptomycin is obtained from

Answer»

TUBERCULOSIS
TYPHOID
MALARIA
AIDS

Answer :A
24.

The antibiotic having Beta-Lactam ring.

Answer»

Pencillin
Chloramphenicol
STREPTOMYCIN
Ciproflaxacin

ANSWER :A
25.

The anti oxidants for wine are

Answer»

`SO_2 & SO_3^(-2)`
`BHT & BHA`
CITRIC acid
Tetrazine

ANSWER :A
26.

The answer to the correct scientific notation of the following given expression frac{2.320}{3.694} X 0.050 is,

Answer»

0.03
`3.1X10^-2`
0.031
`0.31X10^-1`

ANSWER :B
27.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : In neutral or faintlyalkaline solution , 8 moles of permanganateanion quantitatively oxidize thiosulphate anios to produce X moles ofsulphur containing product . The magneticof X is

Answer»

SOLUTION :`8MnO_(4)^(-) + 3S_(2)O_(3)^(2-) +H_(2)O rarr 8 MnO_(2) + 6SO_(4)^(2-) + 2OH^(-)`
`:. `Molesof `SO_(4)^(2-)` formed from 8 moles of `MnO_(4)^(-) = 6`
28.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : Consider the following list of reagents : Acidified K_(2)Cr_(2)_(7),alkalineKMnO_(4), CuSO_(4), H_(2)O_(2), Cl_(2),O_(3), FeCl_(2) , HNO_(3) andNa_(2)S_(2)O_(3) . The total number of reagents that can oxidize aqueous iodide to iodine is

Answer»

Solution :`6KI+ K_(2)Cr_(2)O_(7) +7H_(2)SO_(4) rarr 4K_(2)SO_(4) + Cr_(2)(SO_(4))_(3)+ 3I_(2) + 7H_(2)O`
`2CuSO_(4)+ 4KI rarr Cu_(2)I_(2)+ 2K_(2)SO_(4)+ I_(2)`
`H_(2)O_(2) +2KI rarr I_(2)+ 2KOH`
`Cl_(2)+ 2KI rarr 2KCl + I_(2)`
`O_(3)+ 2KI + H_(2)O rarr 2KOH + I_(2) O_(2)`
`2FeCl_(3) + 2KI rarr 2FeCl_(2)+ 2KCl + I_(2)`
`4HNO_(3) + 2KI rarr 2KNO_(3) + 2NO_(2)+ I_(2)+ 2H_(2)O`
29.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : The oxidation number of Mn in the porduct of alkanline oxidative fusion of MnO_(2) is

Answer»

Solution :`2MnO_(2)+ 4KOH + O_(2) RARR 2K_(2)MnO_(4) + 2H_(2)O`
OX. Stateof Mn in `OVERSET(+1)(K_(2))overset(x)(M)noverset(-2)(O_(4)): 2+x-8=0` or `x= + 6`
30.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : The number of metals collectivelycalled 'platinum metals ' in the transiton elements is

Answer»

Solution :The ELEMENTS of 2nd and 3RD triads of GROUPS 8,9 and 10 ( i.e., RU , Rh , Pd, OS, Ir, Pt) are collectivelycalledplatinum metals.
31.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : Th enumber of electrons present in the 4f-subshell ofTerbium( atomic no. = 65) is

Answer»

SOLUTION :Electronic configuration of TERBIUM (Z= 65) is `[Xe]^(54) 4f^(9) 5d^(0)6S^(2)`
32.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : The coefficient of H_(2)SO_(4) on balancing the equation K_(2)Cr_(2)O_(7) + H_(2)SO_(4) + KI rarrK_(2)SO_(4) + Cr_(2)(SO_(4))_(3) + H_(2)O+I_(2) is

Answer»

Solution :The balanced EQUATION is`:`
`K_(2)Cr_(2)O_(7) + 7H_(2)SO_(4) +6KI rarr 4K_(2)SO_(4)+ Cr_(2)(SO_(4))_(3)+ 3I_(2)+ 7H_(2)O`
33.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : Oxidation state of Cr in CrO_(5)is

Answer»

SOLUTION :`CrO_(5)` is aperoxo compound , `CrO(O_(2))_(2)` with the structure

`i.e., x+4 (-1)+ ( -2) = 0` or `x= +6`
34.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : The highest oxidationstate shown byany transition element is

Answer»

Solution :The highest oxidation STATE SHOWN by the TRANSITION element is `+8` viz. Ru in 4DSERIES and Os in 5dseries.
35.

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side :The magnetic moment of a transition metal ion is foundto be 5.92 B.M. The number of unpairedelectrons present in the species is

Answer»

SOLUTION :`MU = SQRT(N(n+2))` B.M.`mu5.92 ` B.M.Only when n=5
36.

The answer to each of the following question is a single digit integer, ranging from 0 to 9. if the correct answers to the question number A,B,C and D (say ) are 4,0,9 and 2 respectively. Then the correct correct darkening of bubbles should be as shownon the side.

Answer»

In MG-Al cell, the number of electrons involved in the cell reaction i s
0.25 mole of propane is subjected to combustion. If this reaction is used for MAKING a fuel,cell the number of moles of electrons involved in each HALF cell for this amount of propane will be
Three litres of 0.5M `K_(2)Cr_(2)O_(7)` solution have to be completely reduced in the acidic medium. The number of faradays of electricity required will be
For the Mg-Ag cell, how many times the difference between the EMF of the cell and its STANDARD EMF will change if concentration of `Mg^(2+)` ions changed to 0.1M and that of `Ag^(+)` ions is changed from 0.5M to 0.25M.

Answer :A
37.

The anomalous boiling point of water is due to

Answer»

van derWaals'forces
ionic bonding
covalent bonding
hydrogen bonding

Solution :The anomalous boiling point of `H_(2)O` is due to H - bonding which is not PRESENT in other hydrides of OXYGEN FAMILY members.
38.

The anodic solution of standard " Al-Ag" voltaic dilute by 100 times. The potential of the cell is increased by '0.01x' volts what is x ?

Answer»


Solution :`Al + 3 AG^(oplus) to Al^(+3) + 3Ag , E=E^(0) - (0.0591)/(3) LOG""([Al^(+3)])/([Ag^(+1)]^(3)) , E_1 = E^(0) - (0.06)/(3) log""(C)/([Ag^(+)]^(3))`
` in_2 = E^(0) - (0.06)/(3) log ""(((C)/(100)))/([Ag^(+1)]^(3)), DeltaE = (in_2 - in_1) = - 0.02 log [(C)/(100) xx (1)/([Ag^(+)]^(3)) xx ([Ag^(+)]^(3))/(e^(-))]`
`=-0.02 log 10^(-2) = - 0.02 xx (-2) log_(10)^(10) = 0.04 = 0.01 X = 0.04 , x =4 `
39.

The anode mud obtained during electro refining of Cu contains:

Answer»

Ag
Fe
Au
Zn

Answer :A::C
40.

The anode is a dry cell is

Answer»

graphite rod
copper rod
zinc container
carbon LEAD plates

Solution :ZN form OUTER BODY of cell which negatively CHARGED.
41.

The anode half-reaction occurring during the discharge of a lead storage battery is

Answer»

`Pb_((s))+SO_(2)+O_(2)toPbSO_(4(s))`
`Pb_((s))+SO_(4(aq))^(2-)toPbSO_(4(s))+2e^(-)`
`PbO_(2(s))+4H_((aq))^(+)+2e^(-)+SO_(4(aq))^(2-)hArrPbSO_(4(s))+2H_(2)O`
`Pb_((aq))^(2+)+SO_(4(aq))^(2-)+PbSO_(4(s))`

Answer :B
42.

The anode and cathode used in Leclanche cell are …………….. respectively.

Answer»

Zinc , GRAPHITE rod with `MnO_2`
Graphite rod in `MnO_2` and Zinc container
ZN container and COPPER rod
Copper container and Zinc rod

Answer :A
43.

The anions of A & B respectively are ______

Answer»

Chlorite & HYPOCHLORITE
CHLORIDE & hypochlorite
Chlorite & CHLORATE
Chloride & Chlorate

Answer :B
44.

The anionic sites occupied by unpaired electrons are called F-centres or colour centres . They impart __(X)__ colour to the crystals of NaCl. Excess of lithium makes LiCl crystals __(Y)__and excess of potassium makes KCl crystals _(Z)___. (X),(Y) and (Z) are

Answer»

yellow, GREEN and pink respectively
pink , yellow and violet (or lilac) respectively
yellow, pink and violet (or lilac ) respectively
red, yellow and pink respectively

Answer :C
45.

The anion formed by aluminium with alkali is

Answer»

Aluminide ion
ALUMINATE ion
Aluminous ion
Meta aluminate ion

SOLUTION :`Na^(+)AlO_(2)^(-)` -SODIUM meta aluminate
46.

The anhydride of pyrosulphuric acid is

Answer»

`SO_(2)`
`S_(2)O_(3)^(2-)`
`SO_(3)`
`S_(2)O_(7)^(2-)`

ANSWER :C
47.

The anhydride of hypochlorous acid is:

Answer»

`ClO_3`
`CL2O
`Cl_2O_5`
`ClO_3`

ANSWER :B
48.

The anhydride of orthophosphoric acid is:

Answer»

`P_4 O_10`
`P_2 O_5`
`P_4O_6`
`P_2 O_3`

ANSWER :A
49.

The anhydride of pyroslphuric acid

Answer»

`S_(2)O_(7)`
`S_(2)O_(3)`
`SO_(3)`
`SO_(2)`

ANSWER :C
50.

The anhydride of nitrous acid is:

Answer»

`N_2O_3`
NO
`N_2O`
`N_2O_4`

ANSWER :A