Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The amine which reacts with NaNO_2 and dil. HCl to give yellow oily compound is___________.

Answer»

ETHYLAMINE
isopropylamine
SEC- BUTYLAMINE
dimethylamine

ANSWER :D
Discussion
2.

The amine which can react with C_(6)H_(5)-SO_(2)-Cl to form a product insoluble in alkali shall be

Answer»

Primary AMINE
Secondary amine
TERTIARY amine
Both primary and secondary amines.

Solution :`C_(6)H_(5)SO_(2)Cl` is called Hinsberg's reagent they react with secondary amine to FORM a product insoluble in alkalines. This reaction used to separate `1^(@),2^(@)` and `3^(@)` amine form their mixture.
Discussion
3.

The amine which liberate nitrogen on reaction with nitrous acid is

Answer»

ISOPROPYL amine
N - METHYL aniline
Isobutyl amine
tert-butylamine

SOLUTION :`1^(@)` amines GIVES this `"Rea"^(n)`
Discussion
4.

The amine that does not form hydrogen bonds is

Answer»

Isopropyl amine 
NEOPENTYL amine 
TERTIARY butyl amine 
N, N - DIMETHYL AMINO ethane

Answer :D
Discussion
5.

The amine 'A' when treated with nitrous acid give yellow only substance. The amine A is

Answer»

triethylmine
trimethylamine
aniline
methylphenylamine

Solution :`(2^(@))` Secondary amines `overset("Nitrous acid")to` yellow OILY substance (Nitroso compound).
`CH_(3)NHC_(6)H_(5) overset(HNO_(2))underset("cold") to CH_(3)-underset(C_(6)H_(5))underset(|)(N)-N=0 + H_(2)O`
Discussion
6.

The amide contains

Answer»

DATIVE bond
Sigma bond only
Sigma bond and a `PI`-bond
` 2 pi`-bonds and sigma bond

Answer :C
Discussion
7.

The amide contains :

Answer»

SIGMA BOND only
Sigma bonds and a `(pi)`-bond
DATIVE bond
2`(pi)`-bonds and sigma bond

Answer :B
Discussion
8.

The alpha-particle is identical with

Answer»

HELIUM nucleus
Hydrogen nucleus
Electron
Proton

Solution :`alpha`-PARTICLE is IDENTICAL with `._(2)He^(4)`, helium nucleus
Discussion
9.

The alpha-hydrogen atom attached to the carbonyl group is acidic in nature because the carbanion which is left gets resonance stabilished. As a result, these compounds take part in the aldol condensation reactions. The carbanion acts as a nucleophile in these reactions. The compounds in which alpha-hydrogen is not acidic take part in the Cannizzaro's reaction. In this reaction, one molecule of the carbonyl compound under consideration is reduced to primary alcohol while the other is oxidised simutaneously to the carboxylic acid. A mixture of cinnamaldehyde and crotonaldehyde is treated with concentrated alkali. C_(6)H_(5)overset(beta)(C)H=overset(alpha)(C)HCHO+overset(gamma)(C)H_(3)overset(beta)(C)H=overset(alpha)(C)HCHOoverset(OH^(-))rarr Which statement is true about the above reaction ?

Answer»

Aldol condensation takes place and `alpha`-carbon atom of crotonaldehyde provides the CARBANION
Aldol condensatin takesplace and `beta`-carbon atom of crotonaldehyde provides the carbanion
Aldol condensation takes place and `gamma`-carbon atom of crotonaldehyde provides the carbanion
Aldol condensation takes place and `alpha`-carbon and cinnamicaldehyde provides the carbanion.

Solution :Removal of `gamma`-hydrogen of crotonaldehyde provides more STABLE allylic carbanion. Hene `gamma`-carbon (not `alpha`) provides the carbinion (NUCLEOPHILIC) for the carbonyl carbon of CINNAMALDEHYDE
Discussion
10.

The alpha-hydrogen atom attached to the carbonyl group is acidic in nature because the carbanion which is left gets resonance stabilished. As a result, these compounds take part in the aldol condensation reactions. The carbanion acts as a nucleophile in these reactions. The compounds in which alpha-hydrogen is not acidic take part in the Cannizzaro's reaction. In this reaction, one molecule of the carbonyl compound under consideration is reduced to primary alcohol while the other is oxidised simutaneously to the carboxylic acid. Compound A (molecular formula C_(3)H_(8)O) is treated with acidified dichromate to form a product B (molecular formula C_(3)H_(6)O). Bforms shining silver mirror on warning with ammoniacl silver nitrate. B when treated with an aqueous solution of H_(2)NCOHNH_(2)HCl and sodium acetate gives a product C. The structure of C is :

Answer»

`CH_(3)CH_(2)CH = N NHCONH_(2)`
`(CH_(3))_(2)C=N NHCONH_(2)`
`(CH_(3))_(2)C = NCONHNH_(2)`
`CH_(3)CH_(2)CH = NCONHNH_(2)`.

SOLUTION :The data suggests that the COMPOUND [A] is an ALIPHATIC ketone butanone `(CH_(3)CH_(2)COCH_(3))`.
Discussion
11.

The alpha-hydrogen atom attached to the carbonyl group is acidic in nature because the carbanion which is left gets resonance stabilished. As a result, these compounds take part in the aldol condensation reactions. The carbanion acts as a nucleophile in these reactions. The compounds in which alpha-hydrogen is not acidic take part in the Cannizzaro's reaction. In this reaction, one molecule of the carbonyl compound under consideration is reduced to primary alcohol while the other is oxidised simutaneously to the carboxylic acid. An organic compound 'A' of the molecular formula C_(5)H_(10)Cl_(2) is hydrolysed to compound 'B' C_(5)H_(10)O which gives an oxime with hydroylamine and yellow precipitate with a mixture of iodine and sodium hydroxide. The compound 'A' should be :

Answer»

`CH_(3)CH_(2)C Cl_(2)CH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)C Cl_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)CH_(2)CHCl_(2)`
`CH_(3)CH_(2)CH_(2)CHClCH_(2)CL`.

SOLUTION :
Discussion
12.

The alpha- and beta-forms of glucose are

Answer»

ISOMERS of D(+) glucose and L(-) glucose respectively
diastereomers of glucose
anomers of glucose
isomers which differ in the CONFIGURATION of C-2

Answer :C
Discussion
13.

The alpha-helical structure of protein is stabilized by

Answer»

dipeptide bond
glycosidic bond
intramolecular HYDROGEN bond between-NH and CARBONYL oxygen
Intermolecular hydrogen bond between -NH and carbonyl oxygen

Answer :C
Discussion
14.

The alpha-amino acid which does not give purple colour in the ninhydrin test is

Answer»

proline
glycine
PHENYLALANINE
aspartic acid

Solution :NINHYDRIN test is HIGHLY specific for primary amines. Proline being a secondary amine GIVES a yellow orange colour with Nlnhydrin whereas all other `alpha`-amino acids give a blue purple colour with Ninhydrin.
Discussion
15.

The alloy which contains nickel is :

Answer»

Brass
Bell metal
Bronze
German SILVER

ANSWER :D
Discussion
16.

The alloy used in dental filling contains

Answer»

 AG and SN
 Ag and Sb
HG. Ag and Sn
Hg. Ag and Sb

Answer :C
Discussion
17.

Which one of the following is used to remove moisture from ammonia?

Answer»

TYPE METAL
Devarda's metal
WOOD's metal
SOLDER metal

Solution :Devarda.s metal
Discussion
18.

The alloy used in preparation of balance beam and light instruments:

Answer»

Copper
Magnalium
Aluminium bronze
Nickeloy

Answer :A
Discussion
19.

The alloy of steel that is used for making automobile parts and utensils is :

Answer»

STAINLESS STEEL
NICKEL steel
Tungsten steel
Chromium steel

ANSWER :A
Discussion
20.

The alloy containing highest percentage composition of copper is

Answer»

GERMAN SILVER
ALUMINIUM BRONZE
Bell METAL
Brass

Solution :Aluminium Bronze
Discussion
21.

The allotrope of sulphur stable below 90^@ C is:

Answer»

ORTHO RHOMBIC sulphur
Monoclinic sulphur
Plastic sulphur
Flowers of sulphur

Answer :A
Discussion
22.

The alkyne which will react with KMnO_(4) to give pyruvic acid is :

Answer»

ETHYNE
Propyne
Butyne
2-Pentyne

Solution :`underset("Propyne")(CH_(3) - C -= CH) underset(O)OVERSET(KMnO_(4))rarr underset("Pyruvic acid")(CH_(3) - underset(O)underset(||)(C) - COOH)`
Discussion
23.

The alkyne which gives pyruvic acid (CH_3COCOOH) on oxidation with alk KMnO_4 is:

Answer»

`CH-=CH`
`CH_3C-=CH`
`CH_3C-=C-CH_3`
`CH_3-CH_2-C-=CH`

ANSWER :B
Discussion
24.

The alkyl halides required to prepare by Wurtz reaction are

Answer»




Solution :(c): In Wurtz REACTION, an ethereal solution of an alkyl halide FORMS SYMMETRICAL alkane when HEATED with metallic sodium. Tertiary halides do not undergo this reaction.
Discussion
25.

The alkyl halides required to prepare by wurtz reaction are

Answer»




SOLUTION :
Discussion
26.

The alkyl halides are best prepared from ……….

Answer»

ALCOHOLS
ALKENES
ETHERS
ALKANES

ANSWER :A
Discussion
27.

The halide which does not give a precipitate with AgNO_3 is:

Answer»

ETHYL CHLORIDE
ALLYL chloride
ISOPROPYL chloride
vinyl chloride

ANSWER :D
Discussion
28.

The alkyl halide that undergoes S_(N)I reaction more readily is :

Answer»

ethyl bromide
isopropyl bromide
vinyl bromine
t-butyl bromide

Solution :Since the reaction follows `S_(N)1` mechanism the alkyl halide giving most STABLE carbocation will be the most reactive.
`H_(3)C-underset("t-Butyl bromide")underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-BrrarrH_(3)C-underset(3^(@)" carbocation")underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C^(+))+Br^(-)`
Ethyl bromide and n-propyl bromide give primary carbocation, isopropyl bromide gives SECONDARY carbocation, t-butyl bromide gives `3^(@)` carbocation. ORDER of stability of carbocation is `3^(@)gt2^(@)gt1^(@)`. HENCE t-butyl bromide is the most stable.
Discussion
29.

The alkyl group of Grignard reagent acts as:

Answer»

FREE radical
Carbonium ion
Carbanion
None

Answer :C
Discussion
30.

The alkyl cyanides when hydrolysed to the corresponding acid, the gas evolved is

Answer»

`N_(2)`
`O_(2)`
`NH_(3)`
`CO_(2)`

Answer :C
Discussion
31.

The alkene which on reductive ozonolysis yields acetone is:

Answer»

`CH_2 = CH_2`
`CH_3-CH = CH_2`
`(CH_3)_2C = C(CH_3)_2`
`CH_3`-CH = CH-`CH_3`

ANSWER :C
Discussion
32.

The alkene which on ozonolysis yields acetone is:

Answer»

`CH_2 = CH_2`
`CH_3 - CH = CH_2`
`(CH_3)_2C=C(CH_3)_2`
`CH_3 - CH = CH - CH_3`

ANSWER :C
Discussion
33.

The alkene which on oxidation with acidified KMnO_(4) gives acetic acid is :

Answer»

Ethylene
Propylene
1-Butene
2-Butene

Solution :`UNDERSET("2-Butene")(CH_(3) - overset(H)overset(|)(C) = overset(H)overset(|)(C) - CH_(3)) overset(KMnO_(4))RARR underset("Acetic acid")(2CH_(3) overset(OH)overset(|)(C) = O)`
Discussion
34.

The alkene that will give the same product with HBr in the absence as well as in the presence of peroxide is

Answer»

2-butene
1-butene
Propene
1-hexene

Solution :The ADDITION of HBR to symmetrical alkenes is not affected to by presence or ABSENCE of PEROXIDE
Discussion
35.

The alkene that exhibits geometrical isomerism is:

Answer»

PROPENE
2-methyl propene
2-butene
2-methyl-2-butene

ANSWER :C
Discussion
36.

The alkene limonene has the following structure, Which product results from the reaction of limonene and 1 molar equivalent chlorine water ?

Answer»




Solution :HIGHLY rich `pi` ELECTRON bond will be ATTACKED by first in eletrophilic ADDITION reaction.
Discussion
37.

The alkene that exhibits geometrical isomerism is :

Answer»

PROPENE
2-Methylpropene
2-Butene
2-Methyl-2-butene

Answer :C
Discussion
38.

The alkene formed as a major product in the above elimination reaction is

Answer»


`CH_(2)=CH`

Solution :

During Hofmann ELIMINATION more ACIDIC `beta`-hydrogen is eliminated.
Discussion
39.

The alkene C_6H_10 producing OHC-(CH_2)_4-CHO on ozonolysis is

Answer»

Hexene-1
Hexene -3
Cyclohexene
1-methylcyclohexene-1

Answer :C
Discussion
40.

The alkane,(a) C_(5)H^(12)and(B) C_(8) h_(18), on treatmentwithchorine give only one monochloride ,Givethe structuresof eachalkane and itscholride .

Answer»

Solution :`(a) (CH_(3))_(4)Cto (CH_(3))_(3)C-CH_(2)Cl,`
`(B)(CH_(3))_(3)C-(CH_(3))_(3)to (CH_(3))_(2)CH_(2)Cl]`
Discussion
41.

The alkane which does NOT undergo nitration is ___________.

Answer»

butane
methane
propane
ethane

Answer :B
Discussion
42.

The alkaline hydrolysis of fats to give glycerol is known as …………………… .

Answer»

ESTERIFICATION
HYDROBORATION
HYDRATION
SAPONIFICATION

SOLUTION :Saponification
Discussion
43.

The alkaline hydrolysis of fats gives glycerol and the reaction is known as …………………….. .

Answer»

SOLUTION :SAPONIFICATION
Discussion
44.

The alkaline hydrolysis of fats to give glycerol is known as ……… .

Answer»

Esterification
Hydroboration
Hydration
Saponification

Answer :D
Discussion
45.

The alkaline hydrolysis of ethyl acetate is represented by the equation CH_(3) COOC_(2)H_(5) + NaOH to CH_(3) COONa + C_(2)H_(5) OH Experimentally it is found that for this reaction (dx)/(dt) = k [CH_(3)COOC_(2)H_(5)][NaOH] Then the reaction is

Answer»

Bimolecular and of FIRST ORDER
Bimolecular and of SECOND order
PSEUDO-bimolecular
Pseudo- unimolecular

Solution :It is an bimolecular and second order reaction .
Discussion
46.

The alkaline earth mrtals are:

Answer»

NA and K
Mg and Ca
Cu and Ag
Al and Fe

Answer :B
Discussion
47.

Thealkalinehydrolysisofesteris knownas

Answer»

dehydrogenation
DEHYDRATION
ESTERIFICATION
saponification

SOLUTION :The alkalinehydrolysisof esteris KNOWN assaponification. WhenesterisheatedwithaqueousNaOH,sodiussaltofacidandalcoholareformed.
` R -overset(O) overset("||") Cunderset( "easter") (- O ) - R '+ NaOHoverset (H_ 2 O )to `
`R - overset (O )overset( "||") C underset("sodium carboxylate")( - O ^ (- ) )- Na ^(+ )+underset ( "alcohol")(R'OH )`
Discussion
48.

The alkaline earth metals forming predominantly covalent compounds is:

Answer»

BARIUM
Strontium
Calcium
Beryllium

Answer :D
Discussion
49.

The alkaline earth metals Ba,Sr,Ca and Mg may be arranged in the order of their decreasing first ionisation potential as

Answer»

Mg,CA,Sr,BA
Ca,Sr,Ba,Mg
Sr,Ba,Mg,Ca
Ba,Mg,Ca,Sr

Solution :`{:("ELEMENT-","Mg","Ca","Sr","Ba"),("I.E.",737,590,549,503):}`
Discussion
50.

The alkaline earth metal with least density is

Answer»

MG
Be
Sr
Ca

Solution :As the nuclear charge increases and size decreases, density increases. But density slightly decreases upto CLACIUM and then increases considerably upto radium due to a hard difference in the crystal STRUCTURE of these elements.
`{:(,"Be","Mg","Ca","Sr","BA","Ra"),("Density (g/mL)",1.84,1.74,1.55,2.63,3.59,5.5):}`
Discussion