Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Phenoland benzoicacid may bedistinguishedby theirreaction with .

Answer»

aqueousNaOH
AQUEOUS `NaHCO_(3)`
neutral `FeCl_(3)`
aqueous `NH_(3)`

Answer :B::C
2.

Phenol and benzoic can be separated by

Answer»

`NaHCO_(3)`
`NaOH` SOLUTION
`FeCl_(3)` solution
All of these

Solution :Phenol does not react with `NaHCO_(3)`whereas benzoic acid will react to form sodium salt which can be hydrolysed to GET benzoic acid back.
(b) Both will react with NaOH, THEREFORE `NAOH` cannot be used for SEPARATION.
(c )Phenol forms complex with `FeCl_(3)` from which phenol cannot be recovered, therefore cannot be used.
(d ) is not possible,
3.

phenol and benzoic acid may be distinguished their reaction with

Answer»

aqueous NaOH
aqueous `NaHCO_(3)`
NEUTRAL `FeCl_(3)`
`Br_(2)-H_(2)O`

Answer :B::C::D
4.

Phenol and benzoic acid can be distinguished by

Answer»

Conc. `H_(2)SO_(4)`
Aqueous NaOH
Aqueous `Na_(2)CO_(3)`
Aqueous `NaHCO_(3)`

Answer :D
5.

Phenoland benzoic acid is distinguished by

Answer»

NaOH
`NaHCO_(3)`
`Na_(2)CO_(3)`
`H_(2)SO_(4)`

Answer :B
6.

Phenetole is …..

Answer»

DIPHENYL ether
ETHOXY BENZENE
Methoxy benzene
DIETHYL ether

Solution :Ethoxy benzene
7.

phenol act as

Answer»

analgesc
antiseptic
disimfectant
both 'B' and 'C'

ANSWER :D
8.

Phenetole react with cold HI gives

Answer»

`C_6H_5-I+C_2H_5-OH`
`C_2H_5-I+C_6H_5-OH`
`C_6H_5CH_2-OH+C_2H_5-I`
`C_6H_5-OH + CH_3-CH_2-CH_2OH`

ANSWER :B
9.

Phenol and benzoic acid are separated by:

Answer»

`NaHCO_(3)`
NaOH
NA
`NaNH_(2)`

Solution :`PhOh+NaHCO_(3)rarr"No reaction "`
`PhCOOH+NaHCO_(3)rarrPhCOunderset(("salt"))overset(Θ)O Na^(o+)+H_(2)O+CO_(2)`
10.

Phenol.

Answer»

Solution :(1) Phenol is USED in the preparation of phenol-formaldehyde polymer which is used in a plastic BAKELITE.
(2) It is used in the preparation of phenol-phthalein-an indicator and in certain dyes.
(3) It is used in the preparation of drugs such as SALOL, aspirin, etc.
(4) It is used in the preparation of DETTOL, which is an antiseptic.
(5) It is used in the preparation of 2,4-dichlorophenoxy acetic acid which is used as selective weed killer.
(6) It is used to prepare picric acid which is used as explosive.
11.

phenelzine is used in

Answer»

DEPRESSION
HIGH fever
hyperacidity
high inflammation

Answer :A
12.

Phenelzin is used as an

Answer»

ANALGESIC
ANTISEPTIC
ANTIPYRETIC
ANTIDEPRESSANT

ANSWER :D
13.

PhCOOH, PhCH_3 can be separated by

Answer»

`KMnO_4`
AQ. `NaHCO_3` + n-hexane
`H_2O`
NONE of these

SOLUTION :PhCOOH DISSOLVES in aq. `NaHCO_3` solution.
14.

Phenacetin is used as

Answer»

ANTIPYRETIC
ANTISEPTIC
antimalarial
Analgesic

ANSWER :A
15.

Phenacetin is used as :

Answer»

Antipyretic
Antiseptic
Antimalarial
Analgesic

ANSWER :A
16.

PhCOOC_(2)H_(5)+C_(2)H_(5)-COOHC_(2)H_(5) overset(NaNH_(2))(to) Number of condensated products (including stereoisomer)

Answer»


SOLUTION :
17.

PhCOCH_(2)CH_(2)NH_(2) and PhNHCH_(2)COCH_(3) can be distinguished by

Answer»

Carbylamine TEST
Tollen's test
Hinsberg's test
Iodoform test

Solution :`1^(@)` amines GIVE this `"REA"^(N)`
18.

PhCHO+(CH_3CO)_2Ooverset(CH_2COONa)toAoverset(HBr)toB The product B is

Answer»

`PhCH=CHCH_2Br`
`Phundersetunderset(Br)(|)CH-CH_2-COOH`
`PhCH_2CH(Br)COOH`
PhCH=CH-COBr

Solution :PERKIN's reaction + Markownikov's addition of HBR.
19.

PhCH_(2)CH_(2)COOH overset(Ag_(2)O)to PhCH_(2)CH_(2)COOAg overset(Br_(2))to PhCH_(2)CH_(2)Br+CO_(2)+AgBr The reaction is known as Hunsdiecker reaction. Choose incorrect statement(s) regarding the Hunsdiecker reaction.

Answer»

A more convenient WAY to preform the Hunsdiecker REACTION is the use of a mixture of acid and mercuric oxide.
Reaction involves radical intermediates.
The yield of bromide increases as `1^(@) "ALKYL" lt 2^(@) "alkyl" lt 3^(@) "alkyl"`.
The reaction starts with decarboxylation.

Solution :Yield increases as `3^(@) "alkyl" lt 2^(@) "alkyl" lt 1^(@) "alkyl"`. Decarboxylation takes place, but in the propagation STEP
20.

PhCHO +(CH_(3)CO)_(2)O overset((1)CH_(3)COONa)underset((2)"hydrolysis", Delta)toA overset(HBr)toB B The product B is

Answer»

`PhCH=CHCH_(2)Br`
`Phunderset(Br)UNDERSET(|)(C)H-CH_(2)-COOH`
`PhCH_(2)CH(Br)COOH`
`PhCH=CH-COBr`

Solution :Perkin REACTION
`underset("(A)")(Ph-CH=CH-COOH) overset(HBR)to Ph-underset(Br)underset(|)(C)H-CH_(2)-COOH`
21.

Ph(CH_2)_3 -oversetoverset(O)(||)C-Cloverset(AlCl_3)to(X)overset(Na_2Cr_2O_7. H^(+)"heat")to(Y)overset("heat")to(Z)

Answer»




SOLUTION :
22.

PHBV is prepared from

Answer»

glycolic ACID
3 -HYDROXY BUTANOIC acid and 3-hydroxy pentanoic acid
GLYCINE and `omega` AMINO caproic acid
glycine and 3 -hydroxy butanoic acid

Answer :B
23.

PhC-=CPh overset(Hg^(2+)+H^(o+))to(A). The compound (A) is The compound (A) is:

Answer»

a.
b.
c.
d.

Solution :
HENCE the ANSWER is `(a)`.
24.

PHBV is of which class polymer ?

Answer»

POLYESTER
POLYAMIDE
Polycynide
Polyethene

Solution :Polyester
25.

PHBV is a biodegradable polymer and is obtained by copolymerization of ....................with ...................

Answer»


ANSWER :3-hydroxybutanoic ACID , 3-hydroxypentanoic acid
26.

Phase transitions are ubiquitous in nature. We are all familiar with the different phase of water (vapour, liquid and ice) and with the change from one to another, the change of phase are called phase transitions. There are six ways a substance can change between these three phase, melting, freezing, evaporating, condensing sublimation and decomposition. At 1 atm pressure vaporisation of 1 mole of water from liquid (75^(@)C) to vapour (120^(@)C). C_(v)(H_(2)O,l)=75 J "mole"^(-1)K^(-1), C_(p)(H_(2)O,g)=33.3J"mole"^(-1)K^(_1) Delta H_(vap) at 100^(@)C=40.7KJ//"mole" Calculate change in internal energy when Water vapour at 100^(@)C to 120^(@)C ?

Answer»

`666 J`
`2998 J`
`499.72 J`
`166.28 J`

SOLUTION :N//A
27.

Phase transitions are ubiquitous in nature. We are all familiar with the different phase of water (vapour, liquid and ice) and with the change from one to another, the change of phase are called phase transitions. There are six ways a substance can change between these three phase, melting, freezing, evaporating, condensing sublimation and decomposition. At 1 atm pressure vaporisation of 1 mole of water from liquid (75^(@)C) to vapour (120^(@)C). C_(v)(H_(2)O,l)=75 J "mole"^(-1)K^(-1), C_(p)(H_(2)O,g)=33.3J"mole"^(-1)K^(_1) Delta H_(vap) at 100^(@)C=40.7KJ//"mole" Calculate change in internal energy when Water liquid at 100^(@)C to vapour at 100^(@)C ?

Answer»

`40700 J`
`37598.878 J`
`43801.1J`
`31012.J`

SOLUTION :N//A
28.

Phase transitions are ubiquitous in nature. We are all familiar with the different phase of water (vapour, liquid and ice) and with the change from one to another, the change of phase are called phase transitions. There are six ways a substance can change between these three phase, melting, freezing, evaporating, condensing sublimation and decomposition. At 1 atm pressure vaporisation of 1 mole of water from liquid (75^(@)C) to vapour (120^(@)C). C_(v)(H_(2)O,l)=75 J "mole"^(-1)K^(-1), C_(p)(H_(2)O,g)=33.3J"mole"^(-1)K^(_1) Delta H_(vap) at 100^(@)C=40.7KJ//"mole" Calculate change in internal energy when Water liquid at 75^(@)C to 100^(@)C ?

Answer»

`1875 J`
`13125 J`
`-1875 J`
`-13125 J`

SOLUTION :N//A
29.

PHBV is

Answer»

polyester POLYMER
polyamide polymer
polymer of GLYCOLIC ACID
polymer of glycolic acid

Answer :A
30.

PH_(4)I +KOH to underset(("gas"))(A) +underset(("salt"))(B) +H_(2)O Incorrect statement :-

Answer»

.A. is INFLAMMABLE gas
.B. is SALT of (SB + SA)
.A. follows Drago.s rule
A. is a weaker lewis BASE than `NH_(3)`

Answer :A
31.

Pharmaceutical products are highly effective in which of the following form ?

Answer»

EMULSION
Gel
Sol
All of above 

SOLUTION :Emulsion
32.

PH_4I + NaOH forms

Answer»

`PH_3`
`NH_3`
`P_4O_6`
`P_4O_10`

ANSWER :A
33.

[(Ph_3P)_3RhCl]is a familiar catalyst used in

Answer»

HYDROGENATION of oils
hydrogenation of alkenes
dehydration of alcohols
dehydration of aldehydes

Answer :B
34.

(Ph_3P)_3RhCl is

Answer»

ZIEGLAR nutta catalyst
Wilkinsons catalyst
Developer in photography
Bio catalyst

Answer :B
35.

[(Ph_(3)P)_(3)RhCI], a rhodium complex is used for the hydrogenation of alkenes.

Answer»


ANSWER :1
36.

PH_3 produces smoky rings when it comes in contact with air this is because:

Answer»

It is inflammable
It COMBINES with WATER vapours
It combines with nitrogen
It CONTAINS IMPURITY of `P_2H_4`

Answer :D
37.

PH_3 has lower boiling point than NH_3. Why ?

Answer»

SOLUTION :Unlike `NH_3, PH_3` molecules are not ASSOCIATED through HYDROGEN bonding in liquid STATE. That is why the BOILING point of `PH_3` is lower than `NH_3`.
38.

PH_3 forms bubbles when passed slowly in water but NH_3 dissolves. Explain why ?

Answer»

Solution :`NH_3` forms hydrogen bonds with WATER because of high electronegativity of nitrogen hence it gets soluble in water. PHOSPHORUS, HOWEVER cannot form hydrogen bonds hence it forms BUBBLES in water.
39.

PH_3 forms bubbles when passed slowly in water but NH_3 dissolves. Explainwhy ?

Answer»

Solution :` NH_3` forms HYDROGEN bonds with water. THEREFORE it is soluble in water but `PH_3` cannot FORM hydrogen BOND with water. Therefore it ESCAPES as gas.
40.

PH_3 can be obtained by heating

Answer»

White phosphorus with not concentrated alkali
Heating phosphinic acid `(H_3PO_2)`
Heating phosphinic acid `(H_3PO_3)`
Heating phosphinic acid `(H_3PO_4)`

SOLUTION :a) `P_(4)+3NaOH+3H_(2)Oraarr3NaH_(2)PO_(2)+PH_(3)uarr`
b) `2H_(3)PO_(2)overset(DELTA)rarr3H_(3)PO_(4)+PH_3`
C) `4H_(3)PO_(3)overset(Delta)rarr3H_(3)PO_(4)+PH_3`
41.

PH_(3) can be obtained by :

Answer»

heating hypophosphorus acid
heating orthophosphorus acid
reacting WHITE phosphorus with HOT CONC. NaOH
all

Solution :(c) `P_(4)+3NaOH + 3H_(2) rarr 3NaH_(2)PO_2 +PH_3`
While heating oxyacids YIELDS oxides and water.
42.

pH values of HCl and NaOH solutions each of strength (N)/(100) will be respectively

Answer»

2 and 3
2 and 12
12 and 2
2 and 10

Solution :`(N)/(100) = 0.01 N HCL, [H^(+)] = 10^(-2) M , pH =2`
`[OH] = 10^(-2) M` for NAOH
`pH + pOH = 14, pH =14-2, pH = 12`.
43.

Ph_(2)CH-overset(O)overset("||")C-OHoverset(1.SOCl_(2))underset(2.Et_(3)N,Delta)rarr

Answer»



`PH - OVERSET(O)overset("||")C-Ph`
NONE of these

Answer :A
44.

pH value of which one of the following is not equal to one

Answer»

`0.1 M HNO_(3)`
0.05 M `H_(2)SO_(4)`
`0.1 M CH_(3)COOH`
`50 cm^(3)` of `0.4 M HCl + 50 cm^(3)` of .2 NaOH

Solution :`PH = -log [H^(+)]`
(a) value of pH `= 0.1 M HNO_(3) = -log[0.1] = 1`
(b) Value of pH `= 0.05 H_(2)SO_(4) = -log [2 xx 0.05] = 1`
(c) Value of pH `= 0.1 M CH_(3)COOH != 1` as it is a weak acid so, will not undergo complete ionization.
(d) Milli-equivalent of acid `= 50 xx 0.4 = 20`
Milli-equivalent of BASE `= 50 xx 0.2 = 10`
Remaining acid `= 20 -10 = 10` milli-eq.
`[H^(+)] = (10)/(50+50) = (10)/(100) = 0.1`
`pH = -log[H^(+)] = 1`.
45.

pH value of which one of the following is NOT equal to one ?

Answer»

`0.1" M HNO"_(3)`
`0.05" M "H_(2)SO_(4)`
`0.1" M "CH_(3)COOH`
`50" cm"^(3)` of 0.4 M HCl + 50 `"cm"^(3)` of `0.2" M NAOH"`

Solution :`pH=-log[H^(+)]`
(a) VALUE of `pH=0.1" M HNO"_(3)=-log[0.1]=1`
(b) Value of `pH=0.05H_(2)SO_(4)=-log[2xx0.05]=1`
(c) Value of `pH=0.1"M "CH_(3)COOH!=1` as it is a weak acid so, will not undergo complete ionization.
(d) Milli - equivalent of acid `=50xx0.4=20`
Milli-equivalent of base `=50xx0.2=10`
Remaining acid `=20-10=10` milli-eq.
`[H^(+)]=(10)/(50+50)=(10)/(100)=0.1`
`pH=-log[H^(+)]=1`.
46.

Ph-underset(O)underset(||)(C)-NH_(2) overset(POCl_(3))to products is

Answer»

Benzonitrile
Benzamine
Chloro benzene
Aniline

Answer :A
47.

Ph-undersetunderset(OH)(|)oversetoverset(Me)(|)C-undersetunderset(OH)(|)oversetoverset(Me)(|)C-Et overset(conc.H_2SO_4,Delta)toProducts How many number of different type of carbonylproducts (only structural isomers ) can be formed (major or minor ) in this reaction, (considering all types of possible migrations)

Answer»


SOLUTION :`Ph-undersetunderset(OH)(|)oversetoverset(Me)(|)C-undersetunderset(OH)(|)oversetoverset(Me)(|)C-Et`
48.

Ph-undersetunderset(Me)(|)oversetoverset(OH)(|)C-undersetunderset(I)(|)oversetoverset(Me)(|)C-Phunderset(Delta)overset(AgNO_3)to? Major product is :

Answer»




None

Solution :
49.

Ph-underset(O)underset(||)(C)-CH_(3)overset(NaOCl)(to)A+ "salt" A+CH_(3)-underset(O)underset(||)(C)-CH_(3)toB 'B' is

Answer»

`CH_(3)-underset(O)underset(||)(C)-CH=underset(CH_(3))underset(|)(C)-PH`
`Ph-underset(O)underset(||)(C)-CH=CH-underset(O)underset(||)(C)-CH_(3)`

`CH_(3)-underset(CL)underset(|)overset(Cl)overset(|)(C)-CH_(3)`

Answer :C
50.

pH value of a solution, whose hydronium ion concentration is 6.2 xx 10^(-9) mol/l, is

Answer»

6.21
7.21
7.75
8.21

Solution :`[H_(3)O^(+)]` MEANS `[H^(+)] = 6.2 xx 10^(-9)` mol/l
`PH = -log (6.2 xx 10^(-9)) = 8.21`.