Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

On heatingthe salt with NHO_(3) and ammonium molybdate , formationof yellow ppt indicates thepresence of (a)_____or (b) _____.

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Answer :a.`AsO_(4)^(3-) `b.`PO_(4)^(3-)`
2.

On heating to 400-500^@C, relatively unstable hydrides and carbonates decompose. Which of the following will decompose when heated to 400-500^@C

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`II, III`
`I,II, III`
`I, III`
`III, IV`

ANSWER :A
3.

When sodium metal heated in dry ammonia, the compound formed is:

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SODIUM nitrate
Sodium HYDRIDE
Sodium AMIDE
Sodium azide

Answer :C
4.

on heating sodium as well as sulphur can be melted molten sodium and molten sulphur are used as:

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MEDIUM for EXTRACTING metals
Catalyst
Metal refiners
Electrodes in batteries

Answer :D
5.

On heating sodium acetate with sodium hydroxide, the gas evolved will be

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Acetylene
Methane at 298 K
Ethane
Ethylene

Answer :B
6.

On heating salicylic acid with soda lime the productobtained is

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Benzene
Phenol
BENZOIC ACID
TOLUENE

ANSWER :B
7.

On heating propanamide with "SOCI"_(2) the productformed as :

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PROPANOL
PROPYL CHLORIDE
proponoyl chloride
prolanal

ANSWER :C
8.

On heating potassium dichromate, it decomposes to give …..… and molecular oxygen.

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SOLUTION :Chromium(III) oxide - `Cr_(2)O_(3)`
9.

On heating potassium permanganate, one of the following compound is not obtained :

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`MnO_(2)`
`O_(2)`
`K_(2)MnO_(4)`
MNO.

ANSWER :D
10.

On heating, peroxides are _______

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stable
UNSTABLE
DECOMPOSES violently
both B and c

ANSWER :D
11.

On heating ozone its volume

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DECREASES to half
Becomes double
Increases to 3/2 times
Remains unchanged

Answer :C
12.

On heating orthoboric acid to red hot, the reidue is :

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Boron
Meta boric acid
Boron oxide.
Borax.

Solution :`UNDERSET("Orthoboric acid")(H_(3)BO_(3))overset(100^(@)C)rarr HBO_(2) overset(160^(@)C)rarr H_(2)B_(4)O_(7)overset("Red HOT")rarr B_(2)O_(3)`
13.

On heating NaCl + K_(2)Cr_(2)O_(7) +H_(2)SO_(4) conc., the gas comes out

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`CrO_(2)Cl_(2)`
`CrOCl_(2)`
`Cl_(2)`
`O_(2)`

ANSWER :A
14.

On heating magnesium boride with HCl a mixture of volatile. …………….. Are obtained.

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ANSWER :borones
15.

On heating MgCl_(2). 2H_(2)O at 350^(@)C in the presence of anhydrous MgC_(2), is formed

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DRY HCl
CO GAS
`SO_(2)`
Air

Answer :A
16.

On heating, lead nitrate forms oxides of nitrogen and lead. The oxides formed are _____.

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`N_2O,PBO`
`NO_2,PbO`
`NO,PbO`
`NO,PbO_2`

Solution :`Pb(NO_3)_2` on HEATING GIVE `NO_(2),PbO and O_2 "" 2PB(NO_3)_2 rarr 2PbO + 4NO_2 + O_2`
17.

On heating, lead nitrate forms oxides of nitrogen and lead. The oxides formed are:

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`N_2O,PbO`
`NO_2,PbO`
`NO,PbO`
`NO,PbO_2`

SOLUTION :`PB(NO_3)_2` on heating GIVE `NO_(2),PbO and O_2 "" 2Pb(NO_3)_2 RARR 2PbO + 4NO_2 + O_2`
18.

On heating lead (II) nitrate gives a brown gas "A". The gas "A" on cooling changes to colourless solid "B". Solid "B" on heating with no changes to a blue solid 'C'. Identify 'A', 'B' and 'C' and also write reactions involved and draw the structures of 'B' and 'C'.

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Solution :The gas A is `NO_2`.
The reactions are explained as under :
`2Pb(NO_3)_2 UNDERSET(673K) overset(Delta)to 2PbO + underset(" A(Brown colour)")(4NO_2) + O_2`
`2NO_2 overset("On cooling ")to underset("(Colourless SOLID)")(N_2O_4)`
`2NO+ underset(B)(N_2O_4) overset(250K)to underset("C (Brown colour solid )")(2N_2O_3)`
STRUCTURE of B `(N_2O_4)` :
19.

On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are.......

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`N_(2)O, PbO`
`NO_(2), PbO`
NO, PbO
NO, `PbO_(2)`

Solution :`2Pb(NO_(3))_(2) OVERSET(DELTA)to 2PbO(s) + 4NO_(2)(G) + O_(2)(g)`
20.

On heating, lead (II) nitrate gives a brown gas 'A'. The gas 'A' on cooling changes to colourless solid 'B'. Solid 'B' on heating with NO changes to a blue solid 'C'. Identify 'A', 'B' and 'C' and also write reactions involved and draw the structures of 'B' and 'C'.

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Solution :(i) Since lead (II) NITRATE on heating gives a brown gas 'A', therefore, gas 'A' must be nitrogen dioxide `(NO_(2))`.
`UNDERSET("Lead (II) nitrate")(2Pb(NO_(3))_(2)) overset(DELTA, 673 K)RARR 2 PbO + underset("Brown gas (A)")(4 NO_(2))+O_(2)`
(ii) Thre brown gas 'A' on cooling dimerises to give a colourless solid 'B', therefore 'B' must be `N_(2)O_(4)` (dinitrogen tetroxide).
`2 NO_(2) underset("On heating")overset("On cooling")(hArr) underset("Colourless solid (B)")(2N_(2)O_(4))`
(iii) Since colourless solid 'B' on heating with NO, gives a blue solid 'C', therefore 'C' muct be dinitrogen trioxide.
`2 NO + underset("Colourless (B)")(N_(2)O_(4)) rarr underset("Blue solid (C)")(2 N_(2)O_(3))`
Thus, `A = NO_(2), B = N_(2)O_(4) and C = N_(2) O_(3)`.
21.

On heating lead (II) nitrate gives a brown gas "A". The gas "A" on cooling changes to colourless solid "B". Solid "B" on heating with NO changes to a blue solid «C. Identify 'A', 'B' and 'C and also write reactions involved and draw the structures of 'B' and 'C\

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SOLUTION :`2PB(NO_(3))_(2) overset(Delta)UNDERSET(673 K) to 2PbO + underset(A)(4NO_(2)) + O_(2)`
`2NO_(2)(g) overset("COOLING")underset("Heating") `2NO + N_(2)O_(4) overset(Delta)underset(250 K)to underset("Blue SOLID")underset(C )(N_(2)O_(4)(s))`
22.

Onheatinglead (II)nitrategives a brown gas 'A' . Thegas 'A' on coolingchanges to colourisess solid 'B'. Solid 'B' on heatingwith NO changeto a bluesolid 'C'. Identify 'A' ,'B' and 'C' and alsowritereactions involvedand draw the structures of 'B' and 'C'.

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Solution :`2Pb(NO_(3))_(2) underset(673K)overset(Delta)to 2PbO + 4NO_(2) (A)`(brown)+ `O_(2)`
`2NO_(2)underset("Heating")overset("On cooling")hArr N_(2)O_(4)` (B) (brown) + `O_(2)`
`2NO_(2) + N_(2)O_(4) overset(Delta 250K)to underset("(C)")2N_(2)O_(3)` (bluesolid)
STRUCTUREOF `N_(2)O` :
Structure of `N_(2)O_(3)` :
23.

On heating in following compound an allyl group will migrate to which possition.

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ANSWER :3
24.

On heating K_(2)Cr_(2)O_(7) with NaCl and conc. H_(2)SO_(4), the gas liberated is

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`CrO_(2)Cl_(2)`
`CrCl_(3)`
`Cr_(2)O_(3)`
`CrOCl_(2)`

ANSWER :A
25.

On heating K_(4)[Fe(CN)_(6)] with conc. H_(2)SO_(4) gives the gas

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`SO_(2)`
`CO_(2)`
`CO`
`NO_(2)`

SOLUTION :`K_(4)[FE(CN)_(6)]+6H_(2)SO_(4)+6H_(2)Orarr2K_(2)SO_(4)+FeSO_(4)+(NH_(4))_(2)SO_(4)+6CO`
26.

On heating in excess supply of air, K, Rb and Cs form superoxides rather than oxides and peroxides?

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SOLUTION :`K^(+)`,`Rb^(+)` and `Cs^(+)` are larger cations which stabilize`O_(2)^(-)` (superoxide) the larger ANION. Thus when `MO_(2)` is formed, it is stabilized hence FORMATION is preferred to OXIDES and PEROXIDES.
27.

On heating in air, 0.12 g of metal gave 0.20 g of its oxide. The carbonate and nitrate of the metal were found to contain 28.5% and 16.2% of the metal respectively. Calculate by applying law of constnat proportions, the masses of oxide of the metal that will be obtained by heating 10 g each of the carbonate and the nitrate.

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Solution :Mass of oxygen in metal oxide
=(0.20-0.12)=0.08g
So, the ratio of masses of metal and oxygen in metal oxide
100gof metal CARBONATE contain metal =28.5g
10 G of metal carbonate contain metal `=(28.5)/(100)xx10=2.85g`
If x g of oxygen combine with 2.85 g of metal, the ratio of masses of the metal and oxygen should be 3:2 as the LAW of constant proportions is true.
`(2.85)/(x)=(3)/(2)` or `x=1.9g`
Mass of metal oxide obtained from 10G metal carbonate
=Mass of metal +Mass of oxygen `=(2.85+1.9)=4.75g`
100g of metal NITRATE contain metal =16.2g
10g of metal nitrate contain metal `=(16.2)/(100)xx10=1.62g`
If y g oxygem combine with 1.62 g of metal, the ratio of masses of the metal and oxygen should be 3:2.
`(1.62)/(y)=(3)/(2)` or `y=1.08g`
Mass of metal oxide obtained from 10g metal nitrate
=Mass of metal+Mass of oxygen.
=(1.62+1.08)=2.70g
28.

On heating glycerol with conc. H_(2)SO_(4) a compound is obtained which has a bad odour. The compound is :

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Glycerol sulphate
Acrolein
Formic acid
Allyl alcohol

Solution :`{:(CH_(2)-OH""CH_(2)),(|""||),(CH-OHunderset(H_(2)SO_(4))OVERSET("Conc.")to CH-+2H_(2)O),(|""|),(CH_(2)OH""underset("Acrolein")(CHO)):}`
29.

On heating glycerol with .KHSO_4, compound is obtained which has bad odour. The compound is :

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Acrolein
Formic acid
Allyl alcohol
Methyl isocyanide

Answer :A
30.

On heating glucose with Fehling solution, we get a precipitate whose colour is

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Orange
Red
BLACK
White

ANSWER :B
31.

on heating forms______membred ring transition state.

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ANSWER :6
32.

On heating ethyl bromide with an alloy of lead-sodium, we get :

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ETHYL LEAD BROMIDE
Butane
Tetraethyl lead
Propane

Answer :C
33.

On heating ethanol with exess of concentrated H_(2)SO_(4) " to " 170^(@)C, the product obtained is

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ethyne
ethane
ethene
ethoxy ethane

Solution :On HEATING ETHANOL with excess of concentrated `H_(2)SO_(4)` to `170^(@)C`, ethene is the product.
`CH_(3)CH_(2)OH + H_(2)SO_(4) rarr underset(underset(C_(2)H_(4) + H_(2)SO_(4))(darr 170^(@)C))(CH_(3) CH_(2)HSO_(4)) + H_(2)O`
34.

On heating ethanol with excess of conc. H_2SO_4 at 443 K, product obtained is

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ethene
ethane
ethyne
ethoxy ethane

Answer :A
35.

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 moles of hydrogen (H_2) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Identify compounds (A) to (D) and also give necessary equations of all the steps involved.

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Solution :(A): `NH_(4)NO_(2), ` (B) : `N_(2)`
( c) : `NH_(3)`, (D) : `HNO_(3)`
(i) `underset(A)(NH_(4)NO_(2)) overset(Delta)to underset(2H_(2)O)`
(ii) `N_(2)(g) + 3H_(2)(g) overset(Fe)to 2NH_(3)(g)`
(iii) `4NH_(3)(g) + 5O_(2)(g) to 4NO(g) + 6H_(2)O(l)`
(iv) `2NO(g) + O_(2)(g) to 2NO_(2)(g)`
(v) `3NO_(2)(g) + H_(2)O(l) to underset(D)(2HNO_(3)) + NO(g)`
36.

On heating diethyl ether with conc. HI, 2 moles of which of the following is formed ?

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Ethanol
Iodoform
Ethyl iodide
Methyl iodide

Answer :C
37.

On heating copper nitrate strongly______is finally obtained.

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COPPER
Copper oxide
Copper nitrite
Copper nitride

Answer :B
38.

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 mol of hydrogen (H_(2)) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Identify compounds (A) to (D) and also give necessary equations of all the steps involved.

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Solution :(i) Since gas 'B' on heating with 3 moles of HYDROGEN in presence of a catalyst, gives a gas 'C' which is basic in nature, therefore, 'C' must be ammonia `(NH_(3))` and gas (B) must be `N_(2)`
`underset((B))(N_(2))+3H_(2) overset(Delta, "Catalyst")rarr underset("Ammonia (C)")(2 NH_(3))`
(ii) Since gas 'B' (i.e., `N_(2)`) is obtained by heating compound (A), therefore, compound (A) must be EITHER ammonium NITRITE or ammonium dichromate
`underset((A))(NH_(4))NO_(2) overset(Delta)rarr underset((B))(N_(2))+2H_(2)O or underset((A))((NH_(4))_(2))Cr_(2)O_(7) overset(Delta)rarr underset((B))(N_(2))+Cr_(2)O_(3) + 4 H_(2) O`
(iii) Since gas 'C', (i.e., `NH_(3)`) on further oxidation in moist conditions gives compound (D) which is a part of acid rain, therefore, compound (D) must be nitric acid `(HNO_(3))`.
`{:(underset((C))(4NH_(3))+5O_(2) overset("Oxidation")rarr 4 NO + 6 H_(2)O),(2 NO + O_(2) rarr 2 NO_(2)"," " "3 NO_(2) + H_(2)O rarr underset((D))(2HNO_(3))+NO):}`
Thus, `A = NH_(4)NO_(2) or (NH_(4))_(2) Cr_(2) O_(7), B = N_(2), C = NH_(3) and D = HNO_(3)`.
39.

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 mol of hydrogen (H_2) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Identify compounds (A) to (D) and also give necessary equations of all the steps involved.

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Solution :Compound (A) to (D) are as FOLLOWS :
(A) = `NH_4NO_2` (B) `=N_2`
(C) `=NH_3` (D)`=HNO_3`
The reactions are GIVEN as under :
(i) `NH_4NO_2 OVERSET(DELTA)to N_2 + 2H_2O `
(ii) `N_2 + 3H_2 to 2NH_3`
(iii) `4NH_3 + 5O_2 to 4NO + 6H_2O `
`2NO + O_2 to 2NO_2 `
`3NO_2 + H_2O to 2HNO_3 + NO`
40.

On heating colourless solid A, gas B (liquid at room temp.) and gas C are formed . A is decomposed by NaOH on heating to form gas D giving white fumes with HCl. Gas C occupies 800ml//g at N.T.P. Hence A is -

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`NH_(4)NO_(3)`
`NaNO_(3)`
`NH_(4)Cl`
`NH_(4)NO_(2)`

ANSWER :4
41.

On heating, chloride acid decomposes to

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`HCIO_(4), CI_(2), O_(2)` and `H_(2)O`
`HCIO_(2), CI_(2), O_(2)` and `H_(2)O`
`HCIO, CI_(2)O` and `H_(2)O_(2)`
`HCI, HCIO, CI_(2)O` and `H_(2)O`

Solution :`underset("Chloric acid")(3 HClO_3) overset(Delta)(rarr) HClO_(4) + Cl_2 + 2O_(2) + H_(2)O`
42.

On heating chloroform with silver powder , which of the following is formed ?

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ETHANOL
ETHANE
ETHYNE
Ethene

Answer :3
43.

On heating calcium acetate and calcium formate , the product formed is

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`CH_(3)COCH_(3)`
`CH_(3)CHO`
`HCHO + CaCO_(3)`
`CH_(3)CHO+CaCO_(3)`

Answer :D
44.

On heating aniline with fuming sulphuric acid at 180^(@)C, the compound formed will be

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ANILINE disulphate
Aniline 2, 4, 6-trisulphonic acid
Sulphanilic acid
None

Solution :
45.

On heating aniline with alcoholic CS_(2) in the presence of HgCl_(2) gives :

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<P>p - aminobenzene sulphoric acid
Phenyl cyanide
Phenyl isothiocyanate
Phenyl isocyanide.

Solution :`C_(6)H_(5)NH_(2)+CS_(2)rarr UNDERSET("Phenyl isothiocyanate")(C_(6)H_(5)NCS)`
46.

On heating anhydrous Na_(2)CO_(3),..... is evolved

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`CO_(2)`
Water vapour
CO
No gas

Solution :ANHYDROUS from of `Na_(2)CO_(3)` does not DECOMPOSE on heating even to redness. It is an amorphous powder called soda ASH.
47.

On heating an ethanolic amine with chloroform and ethanolic KOH, the organic compound formed is

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an alky CYANIDE
an ALKYL ISOCYANIDE
an alkanol
an alkanediol

Answer :B
48.

On heating an aliphatic primary amine with chloroform and ethanolic potassium hydroxide, the organic compound formed is

Answer»

ALKYL isocyanide
an alkanol
an alkanediol
an alkyl cyanide

Solution :In CARBYLAMINE REACTION, alkyl ISOCYANIDES are FORMED.
49.

On heating an aliphatic primary amine with chloroform and ethanolic potassium hydroxide, the organic compound formed is :

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an alkanol
an alkanediol
an alkyl cyanide
an alkyl ISOCYANIDE

Solution :`UNDERSET(1^(@) "amine")(R-overset(..)(N)H_(2)+CHCl_(3))overset(C_(2)H_(5)OH\\KOH)rarrunderset("Isocyanide")underset("alkyl")(R-overset(o+)(N)-=overset(Θ)(C)):`
50.

On heating ammonium dichromate, the gas evolved is :

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OXYGEN
Ammonia
Nitric ACID
Nitrogen

Answer :D