Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Nickelocene, [Ni(eta^(5)-C_(5)H_(5))_(2)] is a bright green reactive solid conveniently prepared by adding a solution of NiCl_(2) in dimethyl sulphoxide to a solution to a of KC_(5)H_(5) in 1, 2 dimethoxyethane. What is the E.A.N of Ni in above complex ?

Answer»

35
36
38
NONE of these

Solution :`"EAN"=28-2+12=38`
Discussion
2.

Nickelocene, [Ni(eta^(5)-C_(5)H_(5))_(2)] is a bright green reactive solid conveniently prepared by adding a solution of NiCl_(2) in dimethyl sulphoxide to a solution to a of KC_(5)H_(5) in 1, 2 dimethoxyethane. What is the oxidation state of nickel in the above complex ?

Answer»

0
`+3`
`+2`
None of these

Solution :`[OVERSET(+2)(Ni)(ETA^(5)-C_(5)H_(5))_(2)]`
Discussion
3.

Nickeloy is an alloy containing :

Answer»

NI + CU +Cr
Al + Cu +Cr
Ni+Al+Cu
None of the above

Answer :C
Discussion
4.

Nicker crystallizes in an fcc unit cell with a cell-edge length of 0.3524nm. Calcualte the radius of the nickel atom

Answer»

0.1624nm
0.1246nm
0.2164nm
0.1426nm

Solution :For an fcc LATTICE, `d_("face")=asqrt(2)`
or `4r_(Ni)=asqrt(2)`
`r_(Ni)=(asqrt(2))/(4)=sqrt(2)/(4)xx0.3524=0.1246` NM
Discussion
5.

Nickel (Z= 28) combines with a uninegative monodentate ligand X^(-) to form a paramagnetic complex [Nix_(4)]^(2-). The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively :

Answer»

ONE, tetrahedral
TWO, tetrahedral
one, square planar
two, square planar

Solution :`[NiX_(4)]^(2-)`
`d^(8) , sp^(3) , 2` unpaired electron
Discussion
6.

Nickel steel is used in making

Answer»

Cycles
Alensils
CUTTING TOOLS
Cables

Answer :D
Discussion
7.

Nickel metal is in highest oxidation state in:

Answer»

`Ni(CO)_4`
`K_2NiF_6`
`[Ni(NH_3)_6](BF_4)_2`
`K_4[Ni(CN)_6]`

Answer :B
Discussion
8.

Nickel is purified by thermal decomposition of its

Answer»

Hydride
Chloride
Azide
CARBONYL

Solution :Nickel is PURIFIED by THERMAL DECOMPOSITION of nickel carbonyl
`Ni(CO)_(4) overset("Heat") to Ni+4CO`.
Discussion
9.

Nickel is purified using the concept of complex compounds. The complex related is

Answer»

`Ni(CO)_6`
`[Ni(NH_3)_4]^(2+)`
`Ni(CO)_4`
`[Ni(NH_3)_6]^(2+)`

ANSWER :C
Discussion
10.

Nickel is purified by….

Answer»

MOND process
Van-Arkel method
Zone refining
Electrolytic refining

Answer :A
Discussion
11.

Nickel is purified by thermal decomposition of its :

Answer»

HYDRIDE
Chloride
Azide
Carbonyl

Answer :D
Discussion
12.

Nickel formate is best used as a catalyst in:

Answer»

PRESERVATION of fruits
esterification
dyeing wool and COTTON FABRICS
HYDROGENATION of oils

Answer :D
Discussion
13.

Nickel (II) tetracyanide complex has …..geometry:

Answer»

Linear
Tetrahedral
Square planar
None

Answer :C
Discussion
14.

Nickel combines with a uninegative monodentate ligand X to form a paramagnetic complex [NiX_4]^(2-) .The number of unpaired electron/s in the nickel and geometry of this complex ion are respectively

Answer»

TWO, SQUARE PLANAR
ONE, tetrahedral
two, tetrahedral
one, square planar

Answer :C
Discussion
15.

Nickel chloride, when treated with dimethyl gyloxime in presence of ammonium hydroxide, a bright red precipitate is obtained Answer the following (a) Draw the structure of the complex showing H-bonds (b) Give oxidation state of nickel and its hybridization (c) Predict the magnetic behaviour of the complex

Answer»

SOLUTION :Oxidation state of nickel is +2 and hybridization is `DSP^(2) mu_(s) =sqrt( n(ni+2)) BM n = 0 .therefour mu_(s) = 0`
(b) `+2, dsp^(2)
(c)` diamagnetic
Discussion
16.

[NiC_(4)]^(2-)It is paramagnetic while Ni[CO_(4)] is diamagnetic though both are tetrahedral Why

Answer»

Solution :In `[Nicl_(4)]^(2-), Ni^(2+)`is co-ordinated with FOUR `Cl^(-)` ligands and follows `sp_(3)` HYBRIDIZATION with two unpaired electrons on `Ni^(2+)` whereas in `[Ni(CO)]_(4)`, the Ni atom is co-ordinated with four CO ligands follows `sp^(3)`hybridization having no unpaired electrons on Ni atom as `Cl(-)` is weak field ligand and CO is strong field.
Discussion
17.

Ni^(2+)is identified using alcoholic solution of dimethyl glyoxime.Write the structural formula for the rosy red precipitate of a complex formed in the reaction.

Answer»

Solution :Addition of an alcoholic solution of DIMETHYLGLYOXIME to an ammonical solution of Ni (II) gives rose-red preipitate` Ni (ONCC NOH]`_2` NICKEL Cis (dimethylglyoximate)
Discussion
18.

Ni^(2+) is identified using alcoholic solution of dimethyl glyoxime. Write the structural formula for the rosy and precipitate of a complex formed in the reaction.

Answer»

Solution :`(i) Ni^(2+)` ions present in Nickel chloride solution is ESTIMATED accurately for forming an INSOLUBLE complex called `[Ni(DMG)_(2)]`
`(II)` Nickel ion reacts with alocholic solution of `DMG` in the presence of ammonical medium, to give rosy RED PRECIPITATE of `[Ni(DMG)_(2)]` complex.
Discussion
19.

Niacin is ………………….

Answer»

Vitamin `B_(3)`
Vitamin `B_(6)`
Vitamin `B_(12)`
Vitamin `B_(2)`

SOLUTION :Vitamin `B_(3)`
Discussion
20.

Ni^(+) ion can be estimated by using dimethyl glyoxime and forms a cherry-red precipitate. The complex is stablized by:

Answer»

IOINC bonds
Coordinate COVALENT bonds
Dative `PI`-bonds
Hydrogenn bonds

Answer :D
Discussion
21.

Ni+H_(2)SO_(4) (hot and concentrated) to X(g) The liberated gas (select the correct statement)

Answer»

develops blue colour spots on the filter paper moistened with potassium iodate and strach solution
turns ACIDIFIED `K_(2)Cr_(2)O_(7)` solution green
produces black PRECIPITATE with LEAD acetate solution
reacts with `Cl_(2)` water to produce an acid which gives white fumes with ammonia.

Solution :(A)`5SO_(2)+2IO_(3)^(-)+4H_(2)O to I_(2)+5SO_(4)^(2-)+8H^(+) , I_(2)+` starch `to` blue colour.
(B)`2H^(+)+3SO_(2)+Cr_(2)O_(7)^(2-) to 2Cr^(3+) ("green")+3SO_(4)^(2-) +H_(2)O`
( C)`Pb^(2+)+SO_(3)^(2-) to PbSO_(3) darr `(white)
(D)`SO_(2)+2H_(2)O +CI_(2) to H_(2)SO_(4) + HCl`
`HCl+NH_(3) to NH_(4)Cl`
`NI+H_(2)SO_(4) +2H^(+) to Ni^(2+) +SO_(2) uarr [X] + 2H_(2)O`
With dilute `H_(2)SO_(4)`, hydrogen gas is liberated.
Discussion
22.

Ni (II) compounds are more stable than Pt (II) compounds. Give reason.

Answer»

SOLUTION :(1) The ionisation enthalpy values can be used to predict the thermodynamic stability of their compounds.
(ii) For NICKEL,`IE_(1)+ IE_(2)= 737+1753`
`=2490 kj MOL^(-1)`
for platinium`IE_(1)+ IE_(2)= 864+ 1791= 2655kj mol^(-1)`
Since, the ENERGY REQUIRED to form Ni2+ is less than that of P127, Ni(II) compounds are thermodynamically more stable than Pt(II) compounds.
Discussion
23.

Ni (II) compounds are thermodynamically…………. than Pt (II) compounds.

Answer»

SOLUTION :more STABLE
Discussion
24.

Ni^(+2) form a complex inon in water having the formula [Ni(H_(2)O)_(6)]^(+2). How many of the following statement are true for the complex ion ? (i) The complex is octahedral in shape(ii) The complex is diamagnetic in nature . (iii) Ni^(+2) has incompletely filled 3d subshell. (iv). Secodary valency of Ni^(+2) is 6 (v) All the bonds (metal-ligand ) are perpendicular to each other.(vi) All the 3d orbitals of Ni^(+2) are degenerate (vii) Total spin of the complex is 1.(viii) The hybridisation of Ni^(+2) is d^(2)sp^(3) (ix) The complex is more stable than [Ni(en)_(3)]^(+2) (x) Effective atomic number of Ni^(+2) is 36.

Answer»


ANSWER :4(i, III, IV, VII)
Discussion
25.

Ni^(+2) ion forms a searlet red ppt with DMG. It is a …………. Memberd ring.

Answer»


Solution :`HO-N=overset(CH_(3))overset(|)C-overset(CH_(3))overset(|)C=N-OH`
Dimethyl glyoxime (DMG)
The .N. atoms donate a LONE pair each to the metal atom and thus two 5-membered rings are formed through CHELATION in `[Ni(dmg)_(2)]` COMPLEX.
Discussion
26.

Ni is best used as catalyst in :

Answer»

Preservation of FRUITS
Esterification
Dyeing wool and cotton FABRIC
HYDROGENATION of oil

Answer :D
Discussion
27.

Ni + CO overset(330-350 K)to Ni(CO)_(4) No(CO)_(4) overset(450-470K) to Ni + 4CO This sequence of reactions are involved in

Answer»

VAN Arkel methalforrefiningof nickel
Mond's process for refiningofnickel
ZONE REFINING ofnickel
Refiningof nickelbydisstilation

Answer :B
Discussion
28.

How many unpaired electrons are there in Ni^(2+) ion ?

Answer»

DIAMAGNETIC
Pamagnetic Colourless
Colourless
None

Answer :B
Discussion
29.

Mn^(2+) ion is:

Answer»

DIAMAGNETIC
Pamagnetic
Colourless
None

Answer :B
Discussion
30.

NH_(4),SCN givesred colour with (s) ____ due to the formationof (b) _____.

Answer»


ANSWER :`FE^(2+)` ,B.`[Fe(SCN)]^(2+)`
Discussion
31.

[NH(CH_2)_4NHCO(CH_2)_4CO]_4 is a :

Answer»

ADDITION POLYMER
THERMOSETTING polymer
homopolymer
copolymer

Answer :D
Discussion
32.

NH_(4)SCN can be usedto test ion ormoreout of Fe^(3+) ,Co^(2+),Cu^(2+)

Answer»

`Fe^(3+) `only
`Co^(2+),CU^(2+)`
`Fe^(2+),Cu^(2+)`
all

Answer :d
Discussion
33.

NH_(4)SCN can be used to makedistanctionbetween Cu^(2+) and Co^(2+).

Answer»


Solution :`CaCI_(2) + 4NH_(2)SCN rarr underset(Blue colour)((NH_(4))_(2)[Co(SCN)_(4)]) + 2NH_(3)CI`
`CuCI_(2) + 2NH_(4)SCN rarr underset(Black ppt)(CU(SCN)_(2) + 2NH_(4)CI`
Discussion
34.

NH_(4)OH is a weak base because

Answer»

it has low vapour pressure
it is only partially ionised
it is COMPLETELY ionised
it has low density

Answer :B
Discussion
35.

NH_(4)COONH_(2(s))hArr2NH_(3(g))+CO_(2(g)) if eqilibrium prassure is 3 atm for the above reaction K_(p) for the reaction is

Answer»

<P>4
27
`4//27`
`1//27`

SOLUTION :`P_(NH_(3)):P_(CO_(2))=2:1`
`thereforeP_(NH_(3))=2ATM, P_(CO_(2))=1`
`K_(p)=[P_(NH_(3))]^(2).[P_(CO_(2))]=2^(2)xx1=4`
Discussion
36.

NH_(4)HF_(2) ionises in aqueous medium as

Answer»

`NH_(4)HF^(+)F^(-)`
`NH_(4)^(+)HF_(2)^(-)`
`NH_(3)HF^(-) H^(+)`
`NH_(4)F_(2)^(-) H^(+)`

ANSWER :B
Discussion
37.

NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant K_(p) ?

Answer»

`2500atm^(2)`
`50atm^(2)`
`100atm^(2)`
`200atm^(2)`

Solution :`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)`
`{:(1,0,0,"INITIALLY"),(1-alpha,alpha,alpha,"at equlibrium"):}`
ACCORDING to question at the equlibrium
`alpha+alpha=100impliesalpha=50` atm.
`thereforeK_(P)=P_(NH_(3))xxP_(H_(2)S)=50xx50=2500atm^(2)`
Discussion
38.

NH_4CO_2NH_2(s)

Answer»


ANSWER :SHIFTS TOWARDS LEFT
Discussion
39.

NH_4ClO_4 + NHO_3 to (A) + (B) oversetDeltato (C ) (neutral oxide) The summation of number of lone pairs and atomicities of compound B and C is .

Answer»


ANSWER :24
Discussion
40.

NH_(4)Cl(s) rarr NH_(3)(g)+HCl(g)when the above reaction occurs, the entropy

Answer»

Remains same
Decreases
INCREASES
None of the above

Solution :On occurrence of
`NH_(4)CL(s)rarrNH_(3)(g)+HCl(g)`
In above reaction, the disorder increases with the FORMATION of `NH_(3)` and HCl.
Discussion
41.

NH_(4)CI on heating with NaOH liberates

Answer»

NACL
`NH_(3)`
HCL
NaOCl

ANSWER :2
Discussion
42.

NH_(4)Cl+NaOH rarr "(Gas A)", NaCl+H_(2)SO_(4)rarr "(Gas B)" Discuss the acid-base nature of these gases, when dissolved in water. What is the product formed between these gases when mixed together?

Answer»

SOLUTION :`NH_(4)CL`
Discussion
43.

NH_(4)Cl is added along with NH_(4)OH is group (a)_____to (b)____ conecentration of (c ) ____.

Answer»


ANSWER :a.III ,b.Decrease, C. `OH^(THETA)`
Discussion
44.

NH_(4)Cl is acidic, because

Answer»

On HYDROLYSIS `NH_(4)Cl` gives WEAK base `NH_(4)OH` and STRONG acid HCl
Nitrogen donates a pair of electron
It is a salt of weak acid and strong base
On hydrolysis `NH_(4)Cl` gives strong base ad weak acid

Solution :`NH_(4)Cl + H_(4)O RARR NH_(4)OH + HCl`
`NH_(4)Cl` is a salt of weak base & strong acid so SODIUM will be acidic.
Discussion
45.

NH_4Cl is used to clean metal surfaces because:

Answer»

It dissociates into `NH_3` and HCL on HEATING
`NH_3` forms a soluble COMPLEX with the METAL.
`NH_4Cl` forms a volatile chloride
None of the above

Answer :A
Discussion
46.

NH_(4)CI can be replaced by (NH_(4))_(2)SO_(4) in group III.

Answer»


Solution :`NHCI` is used alongwith `NH_(4)OH` in group II to DECREASES ionicsationof `HN_(4)OH` by COMMON the effect (of `NH_(4)^(OPLUS)),(NH_(4))_(2)SO_(4)` is also a source of `NH_(4)^(Theta)` ionbut it common be usedsince`SO_(4)^(2-)` ionwillprecipitate `Zn^(2+),Ca^(2+)Ba^(2+),Sr^(2+)` astheir suilphate HENCE false
Discussion
47.

(NH_(4))_(2)Cr_(2)O_(7) on heating gives a gas which is also given by

Answer»

HEATING `NH_(4)NO_(2)`
Heating `NH_(4)NO_(3)`
`Mg_(3)N_(2)+H_(2)O`
`NA(comp.)+H_(2)O`

ANSWER :A
Discussion
48.

(NH_(4))_(2)Cr_(2)O_(7) on heating gives

Answer»

`Cr_(2)O_(3)`
`N_(2)`
`H_(2)CrO_(4)`
`NH_(3)`

Solution :`(NH_(4))_(2)Cr_(2)O_(7)overset(DELTA)rarr Cr_(2)O_(3)+N_(2)+4H_(2)O`
Discussion
49.

(NH_(4))_(2)Cr_(2)O_7on heating gives:

Answer»

`Cr_(2)O_3`
`N_2`
`H_(2)CrO_4`
`NH_3`

SOLUTION :`(NH_4)_(2)Cr_(2)O_(7)overset(DELTA)rarrul(N_2)+4H_2O+ul(Cr_(2))O_3`
Discussion
50.

(NH_(4))_(2).Cr_(2)O_(7) overset(Delta) to N_(2)(g) + 4H_(2)O(l) + X(s) Mention the substances 'X' in this reason.

Answer»

`Cr_(2)O_(3)`
`K_(2)CrO_(4)`
`NH_(3)`
`CrO_(4)`

ANSWER :A
Discussion