Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Isomerismshownby aminesis / are

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chain
position
FUNCTIONAL
all of these

ANSWER :D
2.

KCl crystallizes in the same type of lattice as does NaCl. Given that (""^rNa^(+))/(""^rCl^(-))=0.5 and (""^rNa^(+))/(""^rK^(+))=0.7

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ANSWER :1.143,B1.172
3.

Isomerism exhibited by [Cr(NH_(3))_(2) (H_(2)O)_(2)Cl_(2)]^(+) are :-

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IONISATION, optical
Hydrate, optical
Geometrical, optical
Coordinate, geometrical

Answer :C
4.

KCl Crystallizes in the same type of lattice as does NaCl.Given that, (r_(Na^(+)))/(r_(Cl^(-)))=0.5and (r_(Na^(+)))/(r_(K^(+)))=0.7Calculate : (a)The ratio of the side of unit cell for KCl to that for NaCl and (b) The ratio of density of NaCl to that for KCl.

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ANSWER :(a) 1.143,(B) 1.172
5.

KCl crystallizes in the same type of lattice as does NaCl. Given that r_(Na+)//r_(Cl-) = 0.55 and r_(Na+)//r+_(K-) = 0.74. Calculate the ratio of the side of the unit cell for KCl to that for NaCl.

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1.125
1.624
1.414
0.732

Answer :A
6.

Isomerism exhibited by ethylene glycol is ________.

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POSITION isomerism
chain isomerism
functional isomerism
both (a) and ( C)

ANSWER :C
7.

KCl crystallises in the same type of lattice as does NaCl. Given (r_(Na^(+)))/(r_(Cl^(-)))=0.5 and (r_(Na^(+)))/(r_(K^(+)))=0.7The ratio of the side of the unit cell for NaCl to that for KCl is

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`1:1.172`
`1:1.1143`
`1:1.1413`
`1:1.732`

SOLUTION :NACL crystallises in the face centred cubic unit cell such that
`r_(NA^(+))+r_(Cl^(-))=(a)/(2)`
Given,`(r_(Na^(+)))/(r_(Cl^(-)))=0.5,(r_(Na^(+)))/(r_(K^(+)))=0.7`
Thus we have ,`(r_(Na^(+))+r_(Cl^(-)))/(r_(Cl^(-)))=1.5`
`(r_(K^(+)))/(r_(Cl^(-)))=(r_(K^(+)))/(r_(Na^(+))//0.5)=(0.5)/(r_(Na^(+))//r_(K^(+)))=(0.5)/(0.7)`
Therefore,`(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.2)/(0.7)xx(1)/(1.5)`
`:.(a_(KCl//2))/(a_(NaCl//2))=(1.2)/(0.7xx1.5)=(a_(KCl))/(a_(NaCl))=1.143`
or`(a_(NaCl))/(a_(KCl))=1:1.143`
8.

KCl cannot be used as a salt bridge for all the cell Cu(s) | CuSO_(4) (aq) | | AgNO_(3) (aq) |Ag(s) because

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`CuCl_(2)` gets PRECIPITATED
`Cl_(2)` gas is evolved
`AgCl` gets precipitated
None of the above .

SOLUTION :KCl reacts with `AgNO_(3)` to form a PPT. of AgCl.
9.

KCl cannot be used as a salt bridge for the cell Cu(s) abs(CuSO_(4)(aq))abs(AgNO_(3)(aq)) Ag(s) because:

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`CuCl_(2)` GETS precipitated
`Cl_(2)` gas is evolved
`AGCL` gets precipitated
None of these

Answer :C
10.

Isomerism exhibited by acetic acid and methyl formate is:

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Functional
Chain
Geometrical
OPTICAL

ANSWER :A
11.

KCl cannot be used as a salt bridege for the cell Cu(s)|CuSO_(4)(aq.)||AgNo_(3)(aq.)|Ag(s) because

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`Cl_(2)` gas is evolved
`CuCl_(2)` GETS precipitated
`SO_(2)` gas is evolved
`AgCl` gets precipitated

Solution :In this notation, the anode (or OXIDATION half-cell) is always written first on the lect white the cathode (or reduction half-cell) is always written last on the rifht. The other components appear in the order in which we would encounter them in moving form the anode to the cathode. The two electrodes are electrically connected by means of a slat bridge, denoted by two by vertical bars.
The cell terminals are at the extreme ends in this cell notation. and a single cerical bar indicates a phase boundary-sat between a SOLID terminal and the electrode solution. for example, the zinc electode is a solild while the `Zn^(2+)` ions (form `ZnSO_(4)`) are in solution. thus, we draw a line between `Zn` and `Zn^(2+)` to show the phase boundries. Note that there is also a line between the `ZnSO_(4)` solution and the `KCl` solution in the salt bridge because these two solutions are not mixed physically and therefore constitute two separate phases.
12.

Isomerisation exhibited by [Cr(NH_(3))_(2)(H_(2)O)_(2)Cl_(2)]^(+) are :

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ionisation, optical
HYDRATE, optical
geometrical, optical
Coordination, geometrical

ANSWER :C
13.

KCl can be used in salt bridge as an electrolyte in which of the following cells ?

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`Zn| ZnCl_2 ||AgNO_3 |Ag`
`Pb|Pb(NO_3)_2 ||CU (NO_3)_2|Cu`
` CU|CuSO_4||AuCl_3|Au`
` Fe|FeSO_4||Pb(NO_3)_2)|Pb`

Solution :KCl can MAKE pereiptiate with ` AgNO_3, Pb(NO_3)_2` so can`t be USED ALONG these electrolytes.
14.

KCIO_(3) on reaction with SO_(2) gives (A) and on reactionwith conc. H_(2)SO_(4) gives (B).(A) and (B) are

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`KCI,HCI_(4)`
`CI_(2),CIO_(2)`
`KCI,HCIO_(3)`
`CI_(2),HCIO_(4)`

Solution :`KCIO_(3)+3SO_(2)+3H_(2)O rarr KCI+3H_(2)SO_(4)` (A)
`3KCIO_(3)+3H_(2)SO_(4)rarr 3KHSO_(4)+3HCIO_(3)`
`2HCIO_(3)rarr 2CIO_(2)+H_(2)O+[O]`
`HCIO_(3)+[O]rarr HCIO_(4)`
`3KCIO_(3)+3H_(2)SO_(4)rarr 3KHSO_(4)+UNDERSET((B)Product)HCIO_(4)+H_(2)O`
15.

Isomeric amines of formula C_(7)H_(9)N that contain a benzene ring are

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ANSWER :5
16.

Isomerism among compounds due to the migration of a proton is known as:

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Geometrical
chain
Tautomerism
Position

Answer :C
17.

Isomer which are non super imposable mirror image are known as,

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antimeter
metamer
racemate
all

Answer :A
18.

Isoleucine is :

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Protein
Nucleic ACID
Phospholipid
Carbohydrate.

Answer :A
19.

KCIO_3 on heative decomposes into KCI and O_2. If some MnO_2 is added the reaction goes much faster because :

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`MnO_2` DECOMPOSES to give OXYGEN
`MnO_2` PROVIDES heat by reacting
Better contact is PROVIDED by `MnO_2`
`MnO_2` acts as a catalyst

Answer :D
20.

Isoelectric point of a protein is related to :

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pH
volatility
MELTING POINT
PHYSIOLOGICAL activity.

Answer :A
21.

KCI + "conc" H_(2)SO_(4) + K_(2)Cr_(2)O_(7) overset(Delta) to (X) overset(NaOH) to(Y),(X)isreddishbrown coloured gassolublein NaOH forming (Y),(X) and (Y) are

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`Cr_(2)OCI_(2)Na_(2)CrO_(3)`
`Cr_(2)O_(2)CI_(2)Na_(2)CrO_(3)`
`CrO_(2)CI_(2)Na_(2)CrO_(6)`
`CrO_(2)CI_(2)Na_(2)CrO_(4)`

Answer :d
22.

KCl (aq) cannot be used as a salt bridge for the cell Cu(s)|CuSO_4(aq)||AgNO_3(aq)|Ag(s) because :

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`CuCI_2` is PRECIPITATED
`CI_2` gas is GIVEN out
`AgCI` is precipitated
All

Answer :C
23.

Isoelectric point is a

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SPECIFIC temperature
Suitable concentration of amino acid
Hydrogen ion concentration that does not allow migration of amino acid under electric field
Mp of an amino acid under the influence of electric field

Solution :ISOELECTRIC point is a PH at which zwitter ions do not MIGRATE towards any of the ELECTRODE.
24.

K,Ca and Li metals may be arranged in the decreasing order of their standard electrode potentials as …………… .

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K, CA, LI
Ca, K, Li
Li, Ca, K
Ca, Li,K

ANSWER :B
25.

Isoelctric point is defined as the pH at which :

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An amino acid BECOMES acidic
An amino acid becomes basic
Zwitter ION has POSITIVE charge
Zwitter ion has zero charge

Answer :D
26.

K_c for A + B ⇌ C + D is 10 at 25^o C. If a container contains 1,2,3,4 mole per litre of A,B,C, and D respectively at 25^o C , the reaction shall :

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PROCEED from RIGHT to left
Proceed from right to left
Be at equilibrium
None of these

Answer :A
27.

KBr,on reaction with cone H_(2)SO_(4) give reddish brown gaswhich bleaches moistlimus paper .The evolved gas is

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Bromine<BR>Mixture of bromineand HBR
`HBr`
`NO_(2)`

Solution :`KBr + H_(2)SO_(4) RARR KHSO_(4) + HBr`
`2HBr +H_(2)SO_(4) rarr Br_(2) + 2H_(2)+S O_(2)`
28.

Isocyanide test is used for the derection of :

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PRIMARY ALCOHOLS
Primary amines
Secondary amines
Secondary alcohols

ANSWER :B
29.

Isocyanide test is used to detect:

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PRIMARY alcohols
Primary AMINES
SECONDARY amines
Secondary alcohols

Answer :B
30.

KBr undergoes 80% dissociationin its 0.5M aqueoussolution.Calculatethe osmotic pressureof thissolutionat 287^(@)C.

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<BR>

Solution :KBR DISSOCIATES as
`KBr to K^(+) + Br^(-)`
If `alpha` is the degree of dissociation , then
`alpha= (i-1)/(m-1)`
m = 2 , `alpha = 80% = 0.80`
` 0.80 = (i-1)/(2-1)`
` i=1 = 0.80`
`i=0.80 + 1 = 1.80`
` pi = icRT`
` = 1.80 xx 0.5 xx 0.0821 xx300`
` = 22.167 ` ATM
31.

Isocyanidetest is usedfor the dectectionof

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primary ALCOHOLS
secondary alcohols
primary AMINE
secondary amine

ANSWER :C
32.

KBr is 80% dissociated in aqueous solution of 0.5 m concentration (Given K_(f)=1.86 " K kg" mol^(-1)). The solution freezes at :

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271.326 K
272 K
270.5 K
268.5 K.

Solution :`ALPHA=(i-1)/(n-1)or 0.8=(i-1)/(2-1)
i=1.28, DeltaT_(F)=iK_(f)m`
` =1.28xx(1.86 K KG mol^(-1))xx(0.5 mol kg^(-1))`
=1.674 K.
f.p. of solution=(273-1.674) = 271.326 K
33.

Isobutyric acid is obtained by oxidation of

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butanal
2- methyl PROPANAL
2- methylpropen -1-ol
both B and c

Answer :D
34.

KBr is 80 % dissociated in solution. The freezing point of a 0.5 molal solution is (K_(f) "water" = 1.86^(@)C/m)

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273 K
277 K
271.326 K
269 K

Solution :For KBR,`i = 1 + alpha = 1 + 0.80 = 1.80`
`Delta T_(F) = i K_(f) m = 1.80 XX 1.86 xx 0.5 = 1.674^(@)`
`T_(f) = 273 - 1.674 = 271.326 K.`
35.

Isobytyl magesium bromide with dry ether and absolute alcohol gives :

Answer»




SOLUTION :N//A
36.

KBr is 80% dissociated in aqueous solution of 0.5M concentration (Given K_(f) for water =1.86 K kg mol^(-1)). The solution freezes at

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271.326 K
272 K
270.5 K
268.5 K

ANSWER :D
37.

Isobutylene reacts with HBr by peroxide effect gives

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`CH_(3)CH_(2)-CH_(2)-CH_(2)Br`
`CH_(3)-CHBrCH_(2)-CH_(3)`
`(CH_(3))_(2)CH-CH_(2)-Br`
`(CH_(3))_(3)C-Br`

ANSWER :C
38.

KBr contains 32,9 % potassium by mass. If 6.40 g of Br_(2) is made to react with 3.60 g of potassium, the actual mass of potassium which reacted with Br_(2) is

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3.14 g
1.76 g
3.6 g
None of these

Solution :% of BROMINE in KBR `= 100-32.9=67.1%`
67.1 g of bromin react with potassium = 32.9 g
6.40 g of bromine react with potassium
`=((32.9)XX(6.40g))/((67.2g)) = 3.138 g = 3.14 g`
39.

Isobutylene is obtanied when

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Sod. T-butaxide is treated with methyl iodide
t-Butyl bromide is treated with sodium methoxide
t-Butyl ALCOHOL is treated with CONC. `H_2SO_4`
t-Butyl methyl eter is HEATED with conc. `H_(2)SO_4`.

Solution :
40.

K_bfor the hydrolysis reaction : B^+ +H_2O hArr BOH +H^+ is 1.0xx10^(-6) the hydrolysis constant of the salt is :

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`10^(-6)`
`10^(-7)`
`10^(-8)`
`10^(-9)`

ANSWER :C
41.

Isobutyl n-butyl ether is reacted with cold conc. HI gives,

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`CH_3CH_2CH_2CH_2I+(CH_3)_2CHCH_2OH`
`CH_3CH_2CH_2CH_2OH + (CH_3)_2CHCH_2I`
`CH_3CH_2CH_2CH_2I + (CH_3)_2CHCH_2I`
`CH_3CH_2CH_2CH_2OH + (CH_3)_2CHCH_2OH`

ANSWER :B
42.

K_(b) for NH_(4)OH is 1.81xx10^(-5). The pH of 0.01 M NH_(4)Cl solution at 25^(@)C is :

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`4.82`
`3.93`
`5.63`
`4.26`

ANSWER :C
43.

K_b and K_f for water are respectively 0.52 and 1.80 kg "mol"^(-1)respectively. For an aqueous glycolic solution freezing point is 3.72^@ C. What is the boiling point of the solution ?

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Solution :DEPRESSION of freezing point =`Delta t_f =3.72^@C`
`DeltaT_f = K_f XX m` ,
MOLALITY `m=DeltaT_f //K_f` =3.72/1.86 =2 mol `kg^(-1)`
ELEVATION of BOILING point =`DeltaT_b=K_b xx m`
`=0.52xx2=1.04^@C`
Boiling point of the solution =100+1.04 =`101.04^@C`
44.

K_b for NH_4OH is 1.8 times 10^-5. Calculate the percentage of ionisation of 0.06 M ammonium hydroxide solution.

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Solution :`a=SQRT(K_b/C)=sqrt((1 .8 times10^-5)/(6 times10^-2))=sqrt(3 times10^-4)=1.732 times10^-2=1.732 times10^-2 times100=1.732%`
45.

Isobutyl magnesium bromide with dry ether and absolute alcohol gives:

Answer»




ANSWER :D
46.

K_(b) for "CC"l_(4) is 5.02. The boiling point of pure "CC"l_(4) is 76.8^(@)C. Calculate the boiling point of a 1 molal solution of naphthalene (C_(10)H_(8)) is "CC"l_(4)

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ANSWER :`81.8^(@)C`
47.

Isobutyl magnesiumbromidewithdry etherandabsoluteaocholgives :

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`(CH_(3))_(2)CH-CH_(2)Ohand CH_(3)CH_(2) MGBR`
`(CH_(3))_(2)CH-CH_(2)CH_(2)and Mg(OH)Br`
`(CH_(3))_(2) CH_(2),H_(2)C=CH_(2)and Mg(OH)Br`
`(CH_(3))_(3) CH and CH_(3)CH_(2)OM MgBr`

Answer :D
48.

K_b for diethylether is 2.16 K kg "mol"^(-1). Calculate the molar mass of solute when 0.4g of solute present in 40 g of ether, increased the boiling point of ether by 0.17 K.

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Solution :WEIGHT of solute =w=0.4 g,
Weight of solvent = W=40 g
`K_b=2.16 "K KG mol"^(-1) , DeltaT_b`=0.17 K
MOLAR mass of solute
`=(wxxK_bxx1000)/(WDeltaT_b)=(0.4xx2.16xx1000)/(0.17xx40)=127 "g mol"^(-1)`
49.

Isobutyl chloride is:

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`CH_3CH_2CH_2CH_2Cl`
`(CH_3)_2CHCH_2Cl`
`CH_3CH_2CHClCH_3`
`(CH_3)_3C-Cl`

ANSWER :B
50.

Isobutyl chloride and butyl chloride are:

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POSITION isomers
chain isomers
functional isomers
Metamers

Answer :B