Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Instead of principal quantum number (n), azimuthal quantum number (l) & magnetic quantum number (m), a set of new quantum number s, t & u was introduced with similar logic but different values as defined below s = 1, 2, 3,.......oo all positive integral values. t = (s^(2) - 1^(2)), (s^(2) - 2^(2)), (s^(2) - 3^(2)).........No negative value u = - ((t + 1))/(2) "to" + ((t + 1))/(2) (including zero, if any) in integral steps. Each orbital can have maximum four electrons. (s + t) rule is defined, similar to (n + l) rule. Number of electrons that can be accommodated in s = 2 and s = 3 shell.

Answer»

`14, 38
28, 76
8, 28
None of these

Solution :`{:(s = 1,t = 0,u = - (1)/(2)","(1)/(2),),(s = 2,t = 0,u = - (1)/(2)","(1)/(2),),(,t = 3,u = - 2"," -1"," 0","+1","+2 ,),(s = 3,t = 0,u = - (1)/(2)","(1)/(2),),(,t = 5,u = -3"," -2"," -1"," 0"," +1"," +2"," +3,),(,t = 8,u = - (9)/(2) "," - (7)/(2)"," - (5)/(2)"," - (3)/(2)"," - (1)/(2)"," (1)/(2)"," (3)/(2)"," (5)/(2)"," (7)/(2)"," (9)/(2),):}`
According to `(s + t)` RULE INCREASING ORDER of energy
1s 2s 3s 4s 2F 5s
`{:((i),"Number of electron in " s = 2,7 xx 4 = 28,,),(,"Number of electron in " s = 3,19 xx 4 = 76,"Hence (B)",):}`
`{:((ii),"For " Z = 24,1s^(8) 2s^(8) 3s^(8) " i.e. number electrons (s) in " s = 2,t = 3 ""[2f^(@)] = 0,),(,"Hence" (C),,,):}`
2.

Instrument in which fuel energy is converted into electrical energy is known as. . . . . .

Answer»

Voltmeter
Electrochemical CELL
electrolytic cell
FUEL cell

Solution :Fuel cell.
3.

Inspite of long range order in the arrangement of particles why are the crystals usually not perfect?

Answer»

Solution :This is because when crystallization TAKES place at EITHER fast or moderate rates, these particles MAY not get sufficient time to arrange themselves in a perfect order. Hence, crystals are not perfect.
4.

Inspired by Alfred Werner (1866-1919), a KOTA student decided to reconduct a similar experiment on unknown salt samples of MCl_(3).xNH_(3). The student found that some of the chloride ions could be prdipitated as AgCl on adding silver nitrate solution. He found that this salt was of 4 years (based on colour). He labelled these complexes as A (yellow complex) B( purple complex), C (Green complex), D (violet complex). He found that moles of AgCl precipitated (per mole of salt) in one case was 3, one case it was 2, and in two cases it was one. He then measured the electrical conductivity of various salt solutions and found that D had the lowest value. He then measured the boiling point of solutions of A, B, C, D and found that B had the 2nd highest boiling point, Based on the above information, answer the following questions. The student took 2.675 g sample of A (Atomic weight of central atom=59) and dissolved it in water to form 1 L solution whose molar conductance was found to be 200" "Omega^(-1)cm^(2)mol^(-1) What is the specific conductance of the solution ?

Answer»

`2xx10^(-3) Omega^(-1)cm^(-1)`
`2xx10^(-4) Omega^(-1)cm^(-1)`
`0.2" "Omega^(-1)cm^(-1)`
`0.4" "Omega^(-1)cm^(-1)`

SOLUTION :`A implies "M.W".=59+17xx6+35.5xx3=267.5`
`M=((2.675)/(267.5))/(1)=0.01" M",Lambda_(m)=kxx(1000)/(M)`
`K=(2000xx0.01)/(1000)=2xx10^(-3)`
5.

Inspired by Alfred Werner (1866-1919), a KOTA student decided to reconduct a similar experiment on unknown salt samples of MCl_(3).xNH_(3). The student found that some of the chloride ions could be prdipitated as AgCl on adding silver nitrate solution. He found that this salt was of 4 years (based on colour). He labelled these complexes as A (yellow complex) B( purple complex), C (Green complex), D (violet complex). He found that moles of AgCl precipitated (per mole of salt) in one case was 3, one case it was 2, and in two cases it was one. He then measured the electrical conductivity of various salt solutions and found that D had the lowest value. He then measured the boiling point of solutions of A, B, C, D and found that B had the 2nd highest boiling point, Based on the above information, answer the following questions. The order of electrical conductivity for the 4 complexes will be :

Answer»

`B GT A gt C gt D`
`C= B gt D gt A`
`C gt D GTB = A`
`A gt B gt C = D`

Solution :`B implies [Co(NH_(3))_(5)Cl]Cl_(2),"Order" to A gt B gt C=D`
6.

Inspired by Alfred Werner (1866-1919), a KOTA student decided to reconduct a similar experiment on unknown salt samples of MCl_(3).xNH_(3). The student found that some of the chloride ions could be prdipitated as AgCl on adding silver nitrate solution. He found that this salt was of 4 years (based on colour). He labelled these complexes as A (yellow complex) B( purple complex), C (Green complex), D (violet complex). He found that moles of AgCl precipitated (per mole of salt) in one case was 3, one case it was 2, and in two cases it was one. He then measured the electrical conductivity of various salt solutions and found that D had the lowest value. He then measured the boiling point of solutions of A, B, C, D and found that B had the 2nd highest boiling point, Based on the above information, answer the following questions. What is the relationship between C and D (if C, had the lowest boiling point )?

Answer»

Ammoniated isomers
Structural isomers
Both (a) and (B)
Geometrical isomers

Solution :C and `D implies [M(NH_(3))_(4)Cl_(2)]CL` (cis-trans isomerism)
7.

Inspired by Alfred Werner (1866-1919), a KOTA student decided to reconduct a similar experiment on unknown salt samples of MCl_(3).xNH_(3). The student found that some of the chloride ions could be prdipitated as AgCl on adding silver nitrate solution. He found that this salt was of 4 years (based on colour). He labelled these complexes as A (yellow complex) B( purple complex), C (Green complex), D (violet complex). He found that moles of AgCl precipitated (per mole of salt) in one case was 3, one case it was 2, and in two cases it was one. He then measured the electrical conductivity of various salt solutions and found that D had the lowest value. He then measured the boiling point of solutions of A, B, C, D and found that B had the 2nd highest boiling point, Based on the above information, answer the following questions. If atomic number of M is 27, then number of N-M-N bond angles in A will be :

Answer»

21
15
10
6

Solution :`A implies[CO(NH_(3))_(6)Cl_(3)`
8.

Inspired by Alfred Werner (1866-1919), a KOTA student decided to reconduct a similar experiment on unknown salt samples of MCl_(3).xNH_(3). The student found that some of the chloride ions could be prdipitated as AgCl on adding silver nitrate solution. He found that this salt was of 4 years (based on colour). He labelled these complexes as A (yellow complex) B( purple complex), C (Green complex), D (violet complex). He found that moles of AgCl precipitated (per mole of salt) in one case was 3, one case it was 2, and in two cases it was one. He then measured the electrical conductivity of various salt solutions and found that D had the lowest value. He then measured the boiling point of solutions of A, B, C, D and found that B had the 2nd highest boiling point, Based on the above information, answer the following questions. If all the complexes taken by the student were cystalline, then, what is the possible molecular formula of the complex having least boiling point?

Answer»

`MCl_(3).6NH_(3)`
`MCl_(3).5NH_(3)`
`MCl_(3).4NH_(3)`
`MCl_(3).2NH_(3)`

Solution :`[M(NH_(3))_(4)Cl_(2)]Cl` has i=2 while (a) and (b) have i=4 and i=3respectively. Hence, (C ) has least elevation in B.P.
9.

Insoluble component of starch in water constituting 80% to 85% of starch is composed of –

Answer»

`beta-D-` GLUCOSE, `C_(1)-C_(4)` and `C_(2)-C_(6)` linkages
`ALPHA -D-` glucose, `C_(1)-C_(4)` and `C_(2)-C_(6)` linkages
`beta -D-` glucose, `C_(1)-C_(4)` and `C_(1)-C_(6)` linkages
`alpha - D-` glucose, `C_(1)-C_(4)` and `C_(1)-C_(6)` linkages

SOLUTION :
STRUCTURE of Amylopectin which MAKE the starch insoluble.
10.

In______process, work is done at the expense of internal energy.

Answer»

Isothermal
isochoric
adiabatic
isobaric

Solution :We know, that `DeltaE=q+W` ltBrgt For adiabatic PROCESS, q=0
`THEREFORE DeltaE=W`
i.e., WORK is DONE at the expenseof only INTERNAL energy and Q= for adiabatic process.
11.

Insecticide Gammexane is

Answer»

DDT
BHC
Chloral
None of the above

Solution :
12.

Inpresenceof conc. Alkali formaldehyde undergoes

Answer»

ALDOL condensation
Cannizzaro's reaction
Esterification
Wurtz reaction

Solution :Aldehydes turn LACKING an `alpha` HYDROGEN undergoes self OXIDATION reduction ( DISPROPORTIONATION reaction ), also known as Cannizzaro's reaction.
13.

Inorganic benzene reacts with HCl to form a compound B_(3)N_(3)H_(9)Cl_(3) . The protonation occurs at :-

Answer»

B-atom
First at N-atom, then REARRANGES into B-atom
N-atom
First at B-atom, then rearranges into N-atom

Answer :C
14.

In..........oxidation number of sulphur is +7.

Answer»

`H_(2)SO_(4)`
`SO_(2)`
`H_(2)S`
NONE of above

ANSWER :D
15.

Inorganic graphite and graphite have many similarties. Choose among the following, the property which is dissimilar.

Answer»

Layered structure, where LAYERS are INTER connected by weak van DER Waals' forces
Slippery nature
Hybridisation of all ATOMS in the layer is `sp^(2)`
Good conductor of electricity

Solution :Inorganic graphite is BAD conductor of electricity.
16.

In..........oxoacid of sulphur has lone pair of electron on sulphur atom.

Answer»

`H_(2)SO_(3)`
`H_(2)S_(2)O_(7)`
`H_(2)SO_(4)`
`H_(2)S_(2)O_(8)`

SOLUTION :
17.

Inorganic benzene is :

Answer»

BN
`BF_4`
`B_2H_6`
`B_3N_3H_6`

ANSWER :D
18.

Innumerable number of galvanic cells can be constructed on the pattern of Daneill cell by taking combination of different half cells. Write the use of above cell

Answer»

Solution :SHE is USED as the reference electrode to DETERMINE the electrode potential of other ELECTRODES.
19.

Innumerable number of galvanic cells can be constructed on the pattern of Daneill cell by taking combination of different half cells. Write the name of the half represented by Pt(s)/H_2(g)/ H^+(aq)

Answer»

SOLUTION :STANDARD HYDROGEN ELECTRODE (SHE)
20.

Innumerable number of galvanic cells can be constructed on the pattern of Daneill cell by taking combination of different half cells. What is the potential of the above half cell at all temperatures?

Answer»

SOLUTION :The POTENTIAL of SHE is ZERO.
21.

Inner layer of blast furnace is made of ___________.

Answer»

GRAPHITE bricks
silica bricks
fire-clay bricks
basic bricks

Answer :C
22.

Inner complexes are formed when __________ orbitals are used for hybridisation.

Answer»

ND
(n-1)d
(n+1)d
(n-2)d

Answer :B
23.

Inner complex is also called

Answer»

SPIN FREE complex
low spin complex
WEAK FIELD complex
ionic complex

Answer :B
24.

Inks, paints are considered as ..........

Answer»

LIQUID in SOLID
solid in liquid
GAS in gas
solid in solid

Solution : solid in liquid
25.

Ink stains can be removed from clothes by treating them with which acid?

Answer»


ANSWER :D
26.

Initiators that can be used in cationic polymerization is/are (a) KNH_(2) (b) H_(2)SO_(4) (c) BF_(3) with little amount of H_(2)O (d) t-butyl peroxide The correct answer is

Answer»

All are CORRECT
Only a
Only B and C
Only a and d

Answer :C
27.

Initiators that can be used in anionic polymerisation is/are (a) Potassium amide (b) n-butyl lithium (c) AlCl_(3) (d) H_(2)SO_(4) The correct answer is

Answer»

only a 
only a and B 
only C and d 
all a, b, c and d 

ANSWER :B
28.

Initially, the root mean square ( rms) velocity of N_(2) molecules at certain temperature is u. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the rms velocity will be:

Answer»

2u
14u
4u
u/2

Solution :`rms(N_(2))=SQRT((3RT)/28)`
After dissociation, u. = `sqrt((3Rxx2T)/14)`
`u/(u.)=sqrt(1/4),u/(u.)=1/2,u.=2u`
29.

Initial volume of H_(2) gas saturated with water vapour is confined under a piston in a container is 10 litres as shown in the given figure. the container also contains some liquid water. The total pressure over liquid water is 80cm of Hg. If now the piston is removed such that volume of container is doubled, then final total pressure over liqid water in the container is P. The vapour pressure of water is 20cm of Hg and volume of liquid is negligible. Calculate P//10.........

Answer»


Solution :`P_(1)V_(1)=P_(2)V_(2)`
`P_(2)=` Pressure of `H_(2)` gas `=(60xx10)/20`
`P_(2)=30cm` of `Hg`
Final total pressure over liquid water `(P)=30+20=50 cm` of `Hg`
`P/10=50/10=5`
30.

Initial mass of a radioactive element is 40 g. How many grams of it would be left after 24 years, if its half-life period is 8 years

Answer»

2
5
10
20

Solution :`N = (N_(0))/(2^(n)) and n = (24)/(8) = 3`
`N = (40)/(2^(3)) = (40)/(8) = 5`
31.

Initial concentration of the reactant is 1.0 M. The concentration becomes 0.9 M, 0.8 M and 0.7 M in 2 hours, 4 hours and 6 hours respectively. Then the oerder of reaction is

Answer»

`2`
`1`
ZERO
`3`

Answer :C
32.

Initial concentration of reaction for nth order reaction is 'a' . Which of the following relations is correct about t_(1//2) of the reaction ?

Answer»

`LN t_(1//2)=ln("constant")-(n-1)log_(e)a`
`ln t_(1//2)=ln("constant")-ln a`
`t_(1//2)ln n=ln("constant")+ln a_(0)`
`ln t_(1//2)=nln a_(0)`

SOLUTION :`t_(1//2) prop (1)/(a^(n-1))`
`t_(1//2)-k(1)/(a^(n-1))`
`ln t_(1//2)=ln k -(n-1) log_(e)a`.
33.

Initial chemical reaction A_(2)underset(K_(-1))overset(K_(1))hArr2A, then (d[A])/(dt)…………

Answer»

`k_(1)[A]_(2)-k_(-1)[A]^(2)`
`2k_(1)[A_(2)]-k_(-1)[A]^(2)`
`2k_(1)[A]_(2)-2k_(-1)[A]^(2)`
`k_(1)[A_(2)]+k_(-1)[A]^(2)`

Solution :Rate=`(-d[A_(2)])/(DT)=(1)/(2)(d[A])/(dt)`
Rate =`k_(1)[A_(2)]-k_(-1)[A]^(2)`
`THEREFORE (1)/(2)(d[A])/(dt)=k_(1)[A_(2)]-k_(-1)[A]^(2)`
`therefore (d[A])/(dt)=2k_(1)[A_(2)]-2k_(-1)[A]^(2)`
34.

InH_(2)-O_(2) fuel cell, at cathode the reduction takes place of the specie, which is

Answer»

`O^(-)`
`O_(2)^(-)`
`H_(2)O`
`O_(2)`

SOLUTION :`O_(2)+4E^(-) to 2O^(--)`
35.

Information regarding the sequence of nucleotides in the chain of a nucleic acid is called its secondary structure.

Answer»


ANSWER :FALSE
36.

Information regarding the sequence of nucleotides in the chain of a nucleic acid is called

Answer»

PRIMARY Structure
SECONDARY structure
TERTIARY structure
Quaternary structure

Solution :Primary structure
37.

Information -1 : Principlal quantun number 'n' is defined as 1, 2, 3…. Information -2 : Azimaathal quantum number 'l' is defined as 0 to (n + 1) in integral steps of 1 Information -3 : Magnetic quantum number 'm' is defined as - l //2 to + l//2 Information -4 : Spin quantum number 's' has five possible values -2, -10, +1, +2 Information -5 : The sub-shell corresponding to l = 1, 2, 3, 4, 5..... designated as P, Q, R, S, T, U.... respectively. Information -6 : The values of m for a given value of l give the number of orbitals in a sub-shell Information -7 : The principles for filling electron in teh shells remains unchanged. On the basic of above informations, answer the following questions. The nuber of orbitals & the maximum of electrons that can be filled in a T sub-shell are respectively.

Answer»

`5,30`
`6,30`
`5,25`
`6,35`

Solution :`n = 1, 2, 3`………
`{:(n = 1,n = 2,n = 3,),(l = 0"," 1"," 2,l = 0","1","2","3,l = 0","1","2","3","4,):}`
Possible subshells -
`{:(,1P,1Q,1R,2P,2Q,2R,2S,3P,3Q........,),(n + l =,1,2,3,2,3,4,5,3,4........,):}`
Inceasing order of energy
Each orbital has 5 ELECTRONS.
`{:(,1P,1Q,2P,1R,2Q,3P,2R........),("Total electrons",5,10,5,15,10,5,):}`
`{:("Type of subshell",1P,1Q,2P,1R,2Q,),("NUMBER of electrons accomodate by the given subshell",10,15,10,20,15,):}`
Sol.(i) `II^(nd)` period will be start from atomic number 16 (Sulphur)
Sol. (ii) Last electron from `Z = 50` to `Z = 65` will ENTER in 2R subshell
Sol. (iii) For T subshell `l = 4`. Number of possible VALUES of `m = 5`, Total electron `= 25`
38.

Information -1 : Principlal quantun number 'n' is defined as 1, 2, 3…. Information -2 : Azimaathal quantum number 'l' is defined as 0 to (n + 1) in integral steps of 1 Information -3 : Magnetic quantum number 'm' is defined as - l //2 to + l//2 Information -4 : Spin quantum number 's' has five possible values -2, -10, +1, +2 Information -5 : The sub-shell corresponding to l = 1, 2, 3, 4, 5..... designated as P, Q, R, S, T, U.... respectively. Information -6 : The values of m for a given value of l give the number of orbitals in a sub-shell Information -7 : The principles for filling electron in teh shells remains unchanged. On the basic of above informations, answer the following questions. For the element having atomic number 51, last electron enters in

Answer»

2Q
2R
3Q
3S

Solution :`N = 1, 2, 3`………
`{:(n = 1,n = 2,n = 3,),(l = 0"," 1"," 2,l = 0","1","2","3,l = 0","1","2","3","4,):}`
Possible subshells -
`{:(,1P,1Q,1R,2P,2Q,2R,2S,3P,3Q........,),(n + l =,1,2,3,2,3,4,5,3,4........,):}`
Inceasing order of energy
Each orbital has 5 electrons.
`{:(,1P,1Q,2P,1R,2Q,3P,2R........),("TOTAL electrons",5,10,5,15,10,5,):}`
`{:("Type of subshell",1P,1Q,2P,1R,2Q,),("Number of electrons accomodate by the given subshell",10,15,10,20,15,):}`
SOL.(i) `II^(nd)` period will be start from atomic number 16 (Sulphur)
Sol. (ii) Last electron from `Z = 50` to `Z = 65` will ENTER in 2R subshell
Sol. (iii) For T subshell `l = 4`. Number of possible values of `m = 5`, Total electron `= 25`
39.

Information -1 : Principlal quantun number 'n' is defined as 1, 2, 3…. Information -2 : Azimaathal quantum number 'l' is defined as 0 to (n + 1) in integral steps of 1 Information -3 : Magnetic quantum number 'm' is defined as - l //2 to + l//2 Information -4 : Spin quantum number 's' has five possible values -2, -10, +1, +2 Information -5 : The sub-shell corresponding to l = 1, 2, 3, 4, 5..... designated as P, Q, R, S, T, U.... respectively. Information -6 : The values of m for a given value of l give the number of orbitals in a sub-shell Information -7 : The principles for filling electron in teh shells remains unchanged. On the basic of above informations, answer the following questions. The second period would begin with -

Answer»

Phosphorus
Sulphur
Chlorine
Titanium

Solution :`n = 1, 2, 3`………
`{:(n = 1,n = 2,n = 3,),(l = 0"," 1"," 2,l = 0","1","2","3,l = 0","1","2","3","4,):}`
Possible subshells -
`{:(,1P,1Q,1R,2P,2Q,2R,2S,3P,3Q........,),(n + l =,1,2,3,2,3,4,5,3,4........,):}`
Inceasing order of energy
Each orbital has 5 electrons.
`{:(,1P,1Q,2P,1R,2Q,3P,2R........),("TOTAL electrons",5,10,5,15,10,5,):}`
`{:("Type of subshell",1P,1Q,2P,1R,2Q,),("Number of electrons accomodate by the given subshell",10,15,10,20,15,):}`
Sol.(i) `II^(nd)` period will be start from atomic number 16 (Sulphur)
Sol. (ii) LAST electron from `Z = 50` to `Z = 65` will enter in 2R subshell
Sol. (iii) For T subshell `l = 4`. Number of possible VALUES of `m = 5`, Total electron `= 25`
40.

Informal, non-confrontationist and cooperative interaction among members of South East Asian Nations is also called----------.

Answer»

SOLUTION :ASEAN WAY
41.

Inert pair effect is shown by

Answer»

s-block
p-block
d-block
f-block

ANSWER :B
42.

Inertness of N_(2) gas is due to

Answer»

No vacant d-orbital
HIGH dissociation ENERGY
High ELECTRONEGATIVITY
None

ANSWER :A
43.

Inert pair effect is prominent character of

Answer»

Na
K
Mg
Al

Solution :IONISATION POTENTIAL `ALPHA` 1/size
44.

Inert gases such a helium behave like ideal gases over a wide range of temperature. However, they condense into the solid state at very low temperature It indicates that at very low temperature. It indicates that at very temperature there is a:

Answer»

WEAK ATTRACTIVE FORCE between the atoms
Weak REPULSIVE force between the atoms
strong attractive force between the atoms
Strong repulsive force betwwn the atoms

Answer :C
45.

Mixture of inert gases can be separated by

Answer»

Electrolysis of their COMPOUNDS
Fractional distillation of AIR
ADSORPTION and desorption by coconut CHARCOAL
Sublimation

Answer :B
46.

Inert gases are least reactive due to :-

Answer»

Completely filled valence SHELL ELECTRONIC configuration
High ionisation energy
More POSITIVE ELECTRON GAIN enthalpy.
All of these

Answer :D
47.

Industrially acetylene is prepared by the hydrolysis of :

Answer»

calcium CARBIDE
SODALIME
ETHYL BROMIDE
calcium carbonate

Answer :A
48.

Industrial production of ethanol is done by which method ?

Answer»

GRIGNARD REAGENT
FERMENTATION METHOD
Oxidation
None of these

Solution : Fermentation method
49.

Industrial production of acetaldehydes is done by

Answer»

OXIDATION of ethanol
redcution of ACETIC ACID
oxidation of ethylene
hydration of acetylene

Answer :C
50.

Industrial preparation of formic acid involves :

Answer»

Reaction of CO with AQUEOUS NaOH under pressure
Reaction of `CO_2` with aqueous NaOH under pressure
PASSING a MIXTURE of CO and `H_2` over heated copper at 473 K
Reaction of CO with METHANOL at 473 K

Answer :A