Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the formation of metal carbonyls, which orbitals are involved in the overlap ?

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Solution :(i) Filled bonding `pi_(2p)` orbital of CO with empty metal d-orbital RESULTING in `SIGMA`-bond between metal atom and carbon atom of CO.
(II) Filled metal d-orbital with empty antibonding `pi_(2p)*` orbital of CO resulting in additional `PI`-bond between the metal and same CO MOLECULE (back bonding).
2.

In the electrolytic purification of copper some gold is found in the

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Cathode
Cathode mud
Anode mud
Electrolyte

Answer :C
3.

In the electrorefining of copper, some gold is deposited as :

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Cathode
Cathode mud
Anode mud
None

ANSWER :C
4.

In the formation of intersitital compounds by transition metals, identify the correct statements

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Melting points of interstial carbides are more than those of respective pure metals
Densities of interstial hydrides are less than those respective pure metals
Electrical conductivity is LOST in the formation of interstial COMPOUND from a metal
Interstitial borides are very HARD in NATURE and less reactive than the parent metals

Solution :N//A
5.

In the formation of N_2^+ from N_2, the electron is lost from:

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A `SIGMA`- ORBITAL
A `PI`- orbital
A `sigma^**` - orbital
A `pi**` - orbital

Answer :A
6.

In the formation of HBr from H_2 & Br_2following mechanism is observed. (A)Br_2hArr2Br. Equilibrium step (B)H_2+Br.toHBr+H. slow step ( C)H.+Br_2toHBr+Br. Fast step Calculate the rate of reaction, if concentration of hydrogen is twice that of bromine and the rate constant is equal to one rutherford.Concentration of bromine is 1M.

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`2xx10^6` DPS
`10xx10^9` dps
`20.2xx10^10` dps
`4xx10^2` dps

Solution :1-Rutherford=`10^6` dps
RATE =`K[H_2]^1[Br_2]^(1//2)`
Rate = `10^6[2]^1[1]^(1//2)=2xx10^6` dps
7.

In the electrolytic process for the extraction of aluminium the electrolyte is :

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`Al (OH)_3` in `NaOH` solution
An aqueous solution of `Al_2 (SO_4)_3 `
A MOLTEN MIXTURE of `Al_2O_3` and `Na_3AlF_6`
A molten mixture of `Al_2O_3` and `Al(OH)_3`

ANSWER :C
8.

In the formation of ether, one of the compound is alcohol another is

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R-O NA
`CH_2N_2`
R-O AG
R-OK

Answer :B
9.

In the electrolytic process for the extraction of aluminium, the electrolyte is :

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`AL(OH)_(3)` in NaOH solution
An aqueous solution of `Al_(2)(SO_(4))_(3)`
A MOLTEN mixture of `Al_(2)O_(3) " and " Na_(3)AlF_(6)`
A molten mixute of `Al_(2)O_(3) " and " Al(OH)_(3)`

Solution :Electrolyte is molten mixture of `Al_(2)O_(3)` (alumina) and `Na_(3)AlF_(6)` (cryolite)
10.

In the electrolytic method of obtaining aluminium from purified bauxite, cryolite is added to the charge in order to

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minimise the heat LOSS due to radiation
protect aluminium produced from oxygen
 dissolve bauxite and render it conductor of electricity
 lower the melting POINT of bauxite.

Solution :(i) Pure alumina is a bad conductor of electricity
(ii) The fusion temperature of pure alumina is about `2000^(@)C` and at this temperature when the electrolysis is carried of FUSED mass, the metal formed EVAPORATES as the boiling point of aluminium is `1800^(@)C`.The above difficulties are overcome by using a mixture of alumina, cryolite and fluorspar.
11.

In the formation of Compounds bromine undergoes sp^(3)d^(2) hybridisation in

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Ground state
1st excited state
2 ND excited state
3 nd excited state

Solution :SECOND excited stateBr under GOES `SP^(3)d^(2)` HYBRIDISATION
12.

In the formation of Al_2O_3 large amount of heat is evolved. This property is used in :

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Deoxidation
Confectionary
Indoor PHOTOGRAPHY
THERMITE welding

Answer :D
13.

In the electrolytic cell , flow of electrons is from

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cathode to ANODE in solution
cathode to anode through EXTERNAL supply
cathode to anode through internal supply
anode to cathode THROUGHT internal supply.

Answer :C
14.

In the form of dichromate , Cr(VI) is a strong oxidising agent in acidic medium but Mo(VI) in MoO_(3) andW(VI) in WO_(3) are not because "…...............".

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Cr(VI) is more stable than Mo(VI) and W (VI)
Mo(VI) and W (VI) are more stable than Cr(VI).
HIGHER oxidation states of heavier members of group-6 of transition SERIES are more stable.
Lower oxidation states of heavier members of group -6 of TRANSITIONSERIES are more stable.

Answer :b,C
15.

In the electrolytic cell, flow of electrons is from

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Cathode to anode in solution
Cathode to anode through external supply
Cathode to anode through INTERNAL supply
Anode to cathode through internal supply

Solution :In an ELECTROLYTIC CELL, ELECTRONS do not flow themselves. It is the migration of ions towards oppositely charged electrons that INDIRECTLY constitutes the flow of electrons from cathode to anode through internal supply.
16.

In the electrolytic cell flow of electronsis form

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cathodeto anode in solution
CATHODE to anode through EXTERNAL SUPPLY
cathode to anode through internal supply
anode to cathode through internal supply

Solution :In ELECTROLYTIC cell FLOW of electronis possiblefromcathode to anodethrough internal supply
17.

In the electrolytic cell, flow of electrons is from:

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cathode to anode in solution
cathode to anode through EXTERNAL supply
cathode to anode through internal supply
anode to cathode through internal supply

Solution :CURRENT FLOWS from anode to cathode in electrolytic cell. Thus ELECTRONS flow from cathode to anode through internal supply.
18.

In the electrolytic cell electrons flow from:

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CATHODE to ANODE in solution.
cathode to anode through EXTERNAL circuit.
cathode to anode through INTERNAL circuit.
anode to cathode through external circuit.

Answer :A
19.

In the electrolysis of which solution, OH^- ions are discharged in preference to CI^- ions:

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DILUTE NaCI
Very dilute NaCI
Fused NaCI
Solid NaCI

Answer :B
20.

In the form of dichromate, Cr(VI) is a strong oxidising agent in acidic medium but Mo(VI) in MoO_(3) and W(VI) in WO_(3) are not because -

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Cr(VI) is more stable than Mo(VI) and W(VI).
Mo(VI) and W(VI) are more stable than Cr(VI).
HIGHER oxidation STATES of heavier members of gr. - 6 transition series are more stable.

Solution :Higher oxidation states of heavier members of transition elements BELONGING to the same GROUP are more stable.
21.

In the electrolysis of which solution, OH^(-) ion are discharged in preference to Cl^(-) ions?

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Dilute NaCl
very dilute NaCl
fused NaCl
solid NaCl

SOLUTION :In very dilute solution of `NaCl`, the following REACTIONS TAKE place on electrolysis:
Anode: `2OH^(-)toH_(2)O+(1)/(2)O_(2)+2e^(-)`
Cathode: `2H^(+)+2e^(-)toH_(2)`
22.

In the form of dichromate, Cr(VI) is a strong oxidising agent in acidic medium but Mo(VI) in MoO_(3) and W(VI) and WO_(3) are not because______. (i) Cr (VI) is more stable than Mo(VI) and W (VI).(ii) Mo (Yl) and W(VT) are more stable ll1an Cr(Vl).(ili) Higher oxidation states of heavier members of group-6of transition series are more stable.(iv) Lower oxidation states of heavier members of group-6of transition series are more stable.

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(i) and (II)
(ii) and (III)
(i) and (IV)
(ii) and (iv)

ANSWER :B
23.

In the electrolysis of water, one faraday of electrical energy would evolve

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ONE mole of OXYGEN gas
one gram atom of oxygen
8 g of oxygen
`22.4 L` of oxygen atoms

Answer :C
24.

In the folowing reaction, we start with 2 mol of N_(2) and 5 mol of H_(2) exerting a total pressure of 7 atm, at a given temperature in a closed vessel. When 50 % of N_(2) is converted into NH_(3) N_(2)+ 3H_(2) rarr 2NH_(3) Partial pressure of NH_(3) is:

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2.8 ATM
2 atm
3.2 atm
4 atm

Answer :B
25.

In the electrolysis of H_(2)SO_(4), 9.72 litres and 2.35 litres of H_(2) and O_(2) were liberated. Number of equivalent of persulphuric acid (H_(2)S_(2)O_(8)) produced is

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0.448
0.224
0.868
0.42

Solution :REACTIONS are `2H_(2)SO_(4) RARR H_(2)S_(2)O_(8) + H_(2)`
`2H_(2)O rarr 2H_(2) + O_(2)`
26.

In the form of dichromate, Cr(VI) is a strong oxidising agent in acidic medium but Mo (VI) in MoO_(3) and W(VI) in WO_(3) are not because….

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Cr(VI) is more stable than MO(VI) and W(VI)
Mo(VI) and W(VI) are more stable than Cr(VI)
Higher oxidation STATES of heavier members of group -6 of transition series are more stable
Lower oxidation states of heavier members of group -6 of transition series are more stable

Solution :Cr(VI) in acidic medium act as a good OXIDIZING agent because of higher STABILITY of chromium in lower oxidation state to which it is reduced. i.e., `d^(3)` CONFIGURATION
27.

In the electrolysis of NaCl when Pt electrode is taken then H_(2), is liberated at cathode while with Hg cathode sodium amalgam is formed, this is because:

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Hg is more inert than PT
More voltage is required to reduce `H^(+)` at Hg than at Pt
Na dissolves in Hg but it does not dissolve in Pt
Concentration of `H^(+)` ions is more when Pt electrode is taken

Answer :B
28.

In the fopllowingreaction, identifythecompound / rteactioncondition represented by A and B PbS overset("Heat in air") to A + PbS overset(B) to Pb + SO_(2)

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Solution :`PbS OVERSET("Heat in air")(to) PbO + PbS`
`PbO + PbSoverset("Heat in the OBSENCE of air")(to) Pb + SO_(2)`
29.

In the electrolysisof H_(2)SO_(4) , 0.2 gram of hydrogen is produced, hence the weight of another substance produce is

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1.6 gram
3.2 gram
6.1 gram
19.2 gram

Solution :`W_("hydrogen")/E_("Hydrogen") =W_("OXYGEN")/(E_("oxygen")) therefore (0.2)/(1) = W_("oxygen")/(16//2)`
`therefore W_("oxygen") =0.2xx(16)/(2) =1.6`
30.

In the followingreactions (a) 6NH_(3)+3Cl_(2)to6NH_(4)Cl+'x'NH_(3)+3Cl_(2)to'y'+3HCl xand y respectively are :

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`HCL and N_(2)`
`N_(2) and HCl`
`N_(3)HandHCl`
`N_(2)andNCl_(3)`

ANSWER :D
31.

In the electrolysis of H_(2)SO_(4) 0.2 gram hydrogen is produced, hence the weight of another substance produced is

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1.6 gram
3.2 gram
6.1 gram
19.2 gram

Solution :In the electrolysis of dil. `H_(2)SO_(4)` the electrolysis TAKES place as
`H_(2)O HARR H^(+)+OH^(-)`
At anode `"" 2OH^(-) to H_(2)O+[O]+2e^(-)`
At CATHODE `"" 2H^(+)+2e^(-) to 2[H]`
`THEREFORE W+[O]:W+2[H^(+)] therefore 16:2 therefore 8:1`
32.

In the electrolysis of CuSO_(4) , the reaction Cu^(2+) + 2 e^(-) to Cu , takes place at

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anode
cathode
in solution
NONE

Solution :REDUCTION ALWAYS occurs at cathode during electrolysis .
33.

In the following which is the strongest acid?

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`CH_3 OH`
`CH_3 CH_2 OH`
`(CH_3)_2 CHOH`
`(CH_3)_3 COH`

ANSWER :A
34.

In the electrolysis of dilute H_(2)SO_(4) using platinum electrode

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`H_(2)` isliberated at CATHODE
`O_(2)` is produced at cathode
`Cl_(2)` is produced at cathode
`Cl_(2)` is OBTAINED at ANODE.

Solution :`H_(2)` is liberated at cathode while `O_(2)` is liberated at anode.
35.

In the following which is not glyceride

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Fats
Oils
Phospholipids
Soaps

Solution :GLYCERIDES are the TRIESTERS of glycerol with LONG chain fatty acids.
36.

In the following which is not coloured ?

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`FeCl_(3)`
`CrCl_(3)`
`TiCl_(3)`
`HgI_(2)`

Answer :D
37.

In the electrolysis of H_(2)O, 11.2 litres of H_(2) was liberated at cathode at NTP. How much O_(2) will be liberated at anode under the same conditions ?

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11.2 litres
22.4 litres
32 g
5.6 litres

Answer :D
38.

In the electrolysis of CuCl_(2) solution (aq) with Cu electrodes, the weight of cathode increased by 3.2 g. In the anode,

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0.05 mole of `Cu^(2+)` will go into the solution
560 of `O_(2)` will be LIBERATED
112 ML of `Cl_(2)` will be liberated
3.2 mole of `Cu^(2+)` will go into the solution

Answer :A
39.

In the electrolysis of CuCI_2 solution using Cu electrodes the mass of cathode increases by 3.18 g. What happened at the other electrode:

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`0.05` mble of `CU^(+2)` IONS passed into SOLUTION
`0.112`LITRE of `CI_2` was liberated
`0.56` litre `O_2` was liberated
`0.1` mole of `Cu^(2+)` ions passed into the solution

Answer :A
40.

In the electrolysis of aqueous solution of CuSO_4 using copper electrodes , the process tha takes place at the anode is

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Solution :`Cu^(+)to2e^(-)toCu` (cathode)
`CutoCu^(2+)+2e^(-)` (anode)
In the electrolysis of aq.. `CuSO_(4)`, as the CURRENT flows, copper from anode dissolves while PURE copper is deposited on cathode.
41.

In the following unbalanced reaction A^(2+)+B^(3+)toA^(4+)+B The total number of e^(-) transferred during reaction is:-

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2
3
6
8

Solution :`A^(2+) to A^(+4)+2E^(-)xx3`
`3e^(-)+B^(3+)toBxx2`
TOTAL no. of `e^(-)` transferred=6 .
42.

In the following, thermosetting polymer is :

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BAKELITE
Polythene
Polyester
Buna –N

Answer :A
43.

In the following the number metal sulphides are not dissolve in yellow ammonium polysulphide. Hg^(+2), Pb^(+2), Bi^(+3), Cu^(+2), As^(+3), Sn^(+2) Sb^(+5)

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Solution :IIA GROUP = HgS, PbS, `B_(12)S_(3)`, CuS
44.

In the electrolysis of aqueous sodium chloride solution which of the half-cell reaction will occur at anode ?

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`Na_((aq))^(+)+e^(-) to Na_((S)),E_(cell)^(THETA)=-2.71V`
`2H_(2)O_((L)) to O_(2(g)) +4H_((aq))^(+)+4e^(-),E_(cell)^(Theta)=-1.23V`
`H_((aq))^(+)+e^(-)to(1)/(2)H_(2(g)),E_(cell)^(Theta)=0.00V`
`Cl_((aq))^(-) to (1)/(2)Cl_(2(g))+e^(-),E_(cell)^(Theta)=1.36V`

SOLUTION :`Cl_((aq))^(-) to (1)/(2)Cl_(2(g))+e^(-),E_(cell)^(Theta)=1.36V`
45.

In the electrolysis of aqueous sodium chloride solution which of the half cell reaction will occur at anode?

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`Na^(+)(aq)+e^(-)toNa(s),E_(Cell)^(Theta)=-2.71V`
`2H_(2)O(l)toO_(2)(G)+4H^(+)(aq)+4e^(-),E_(Cell)^(Theta)=1.23V`
`H^(+)(aq)+e^(-)to(1)/(2)H_(2)(g),E_(Cell)^(Theta)=0.00V`
`Cl^(-)(aq)to(1)/(2)Cl_(2)(g)+e^(-),E_(Cell)^(Theta)=1.36V`

SOLUTION :oxidatio occurs at anode. As (b) has HIGHER oxidation potential than (a), (b) occurs.
46.

In the following the most stable conformation of n-butane is :

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ANSWER :A
47.

In the following the most stable configuration of n - butane is

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ANSWER :B
48.

In the electrolysis of aqueous sodium chloride solution, which of the half cell reactions will occur at anode?

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`CI_(aq) to (1)/(2)CI_(2)+ e^(-), E_("cell")^(0)= 1.36 "VOLTS"`
`2H_(2)O_(l) to O_(2)+ 4H^(+)+ 4e^(-), E_("cell")^(0)= 1.23 "volts"`
`Na_(aq)^(+) e^(-) to Na_(s), E^(0)= -2.71 "volts"`
`H_(aq)^(+)+ e^(-) to (1)/(2)H_(2), E_("cell")^(0)= 0.00"volts"`

Solution :During electrolysis of aqueous NaCl FOLLOWING oxidation reaction are possible:
`Cl_(aq) to (1)/(2) Cl_(2(g))+e^(-)` , `E_("cell")^(o)=1.36 V` ...(i)
`2H_(2)O_(l) to O_(2(g))+4H_(aq)^(+)+4e^(-)`, `E_("cell")^(o)=1.23 V` ...(II)
The reaction at anode with lower value of `E^(o)` is preferred and therefore, water should get oxidised in preference to `Cl_(aq)^(-)`. However on account of overpotential of oxygen, reaction (i) is preferred.
Thus,
Cathode: `H_(2)O_(l)+e^(-) to (1)/(2) H_(2(g))+OH_(aq)^(-)`
Anode: `Cl_(aq)^(-) TI (1)/(2)Cl_(2(g))+e^(-)`
49.

In the following The major compound Y is

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SOLUTION :
50.

In the following the cations does not give flame test Ba^(+2), Li^(+), Ca^(+2), K^(+), Na^(+), Mg^(+2), Be^(+2)

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SOLUTION :`MG^(+2), Be^(+2)`