Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In nucleotide phosphate group is attached to

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C-1
C-2
C-4
C-5

Answer :D
2.

In nucleoside , a base is attached at1' position of sugar moiety. Nucleotide is formed by linking of phosphoric acid unit of the sugar unit of nucleoside. At which position of sugar unit is the phosphoric acid linked in a nucleoside to give a nucleotide ?

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SOLUTION :Phosphoric acid unit is linked at 5' -position of SUGAR moiety of nucleoside to FORM a nucleotide.
3.

In nucleoside adenine is attached to

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C-2
C-1
C-3
C-4

Answer :B
4.

In nucleoside base unit is attached at

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position ONE of PENTOSE sugar unit
position TWO of pentose sugar unit
position THREE of pentose sugar unit
position of four of pentose sugar unit

Answer :A
5.

In nucleosidea base is attachedat 1 position of sugar moiety . Nucleotide is formedbylinkingof phospheric acidunit ofnucleoside . At whichposition of sugarunitsis thephosphoricacid linked in a nucleoside to givea nucleotide ?

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SOLUTION :Phosphoricacidis linked at 5 - POSITION of sugarmoiety of nucleosideto GIVEA nucleotide .
6.

In nucleophilic substitution reaction aryl chloride resembles

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ethyl chloride
BENZYL chloride
ALLYL chloride
VINYL chloride

ANSWER :D
7.

In nucleophilic alphatic substitution , the nucleophilies are generally

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Acids
Bases
Salts
Neutral MOLECULES

Solution :The nucleophiles are GENERALLY beases.
8.

In nucleic acids, the sequence is represented as

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PHOSPHATE - BASE - SUGAR
Sugar - base - phosphate
Base - sugar - phosphate
Base - phosphate - sugar

Answer :C
9.

In nucleic acids, the sequence is

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PHOSPHATE - BASE - SUGAR
sugar- base-phosphate
base- sugar - phosphate
base- phosphate - sugar

Answer :C
10.

In nucleic acids, the sequence is :

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Phosphate-sugar-base
Sugar-base-phosphate
Base-sugar-phosphate
Base-phosphate-sugar

Answer :C
11.

Nucleic acids are :

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Phosphate-base-sugar
Sugar-base-phosphate
Base-sugar-phosphate
Base-phosphate-sugar

Answer :C
12.

In nucleic acids, the nucleotides are linked to one another through

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HYDROGEN bond
Peptide bond
Glycosidic linkage
Phosphate GROUPS 

ANSWER :D
13.

In nucleic acids the nucleotide sub units linked by hydrogen bond b) Nucleic acids control heredity at molecular level (c) DNA is a dinucleotide and RNA is oligo- nucleotide The correct statement is

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all
a,C
b only
a only

Answer :C
14.

In nucleic acids, the nucleotides are joined together by

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phosphoester LINKAGE
PHOSPHODIESTER linkage
PHOSPHODISULPHIDE linkage
sulphodiester linkage.

Answer :B
15.

In nucleic acid the sequence is

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base-phosphate-sugar
base-sugar-phosphate
sugar-base-phosphate
phosphate-base-sugar

Answer :B
16.

In nucleicacid , the correctsequence is ……….. .

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BASE - PHOSPHATE SUGAR
phosphate- base-sugar
sugare - base- phosphate
base - sugar - phosphate

ANSWER :D
17.

In nuclear reactors, the moderator is :

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CADMIUM
Uranium-235
Uranium-238
Heavy water.

Answer :D
18.

In nuclear fission, 0.01% mass is converted into energy. The energy released by the fission of 100 kg mass will be:

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`9 xx 10^(15) j`
`9 xx 10^(11) KJ`
`9 xx 10^(17) j`
`9 xx 10^(13) J`

Solution :`Delta m = 100 xx (0.01)/(100) = 0.01 kg`
`E = Delta mc^(2) = 0.01 xx (3 xx 10^(8))^(2) J`
`= 9 xx 10^(14) J = 9 xx 10^(11) kJ`
19.

Compreshension-II In non-ideal solutions, at one of the intermediate compostions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapouriese at this point and vapours are condensed, teh condensate contains same compositon as present in original liquid mixture. it means at this point liquid behaves like a pure liquid and is called an Azeotropic mixture. Which of the following cannot form low boiling point azeotrope ?

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n-heptane & n-hexane
Acetone & aniline
Both (a) & (b)
`CHCI_(3)&C_(2)H_(5)OH`

SOLUTION :it is corrct answer.
20.

In non polar molecular solids, molecules are held together by …………….............

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London FORCES
WEAK VANDERWAALS forces
Strong electrostatic forces
strong cohesive forces

SOLUTION :London forces
21.

In non polar molecular solids constituent molecules held together are by …………………

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SOLUTION :LONDON FORCES
22.

Compreshension-II In non-ideal solutions, at one of the intermediate compostions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapouriese at this point and vapours are condensed, the condensate contains same compositon as present in original liquid mixture. it means at this point liquid behaves like a pure liquid and is called an Azeotropic mixture. A and B forms non-ideal solution showing positive deviation. Boiling pointof pure A and B is 350 K and 380 K respectively. The solution will bpoil at (approximate)

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`250 K`
`380 K`
`GT 380 K`
`lt 350 K`

Solution :it is CORRCT ANSWER.
23.

In non-ideal solutions, at one of the intermediate compositions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapourises at this point and vapours are condensed, the condensate contains same composition as present in orginal liquid mixture. It means that at this point liquid behaves like a pure and is called asAzeotropic mixture. Choose the correct answer : Choose the correct statemnent

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Ideal solutions connot be separated into their components by frectional DISTILLATION
For ideal solution, entghalpy of mixing is always greater than zero
Only non-ideal solution showing positive devialtion cannot be separeated out by FRATION distillation.
Non-ideal solution showing both positive and ngative deviation cannot be separated out by FRACTIONAL distillation.

Solution :it is CORRCT answer.
24.

In NO_(3)^(-) ion, the nitrogen atom involves :

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sp hybridisation
`sp^(2)` hybridisation
`sp^(3)` hybridisation
`DSP^(2)` hybridisation

ANSWER :B
25.

In NO_(3)^(-) ion number of bond pairs and Ione pairs of electrons on nitrogen atom are

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2,2
3,1
1,3
4,0

Answer :D
26.

In nitroprusside ion the iron and NO exist as Fe^(II) and NO^(+) rather than Fe^(III) and NO.These forms can be differntiated by :

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estimating the CONCENTRATION of iron
measuring the concentration of `CN^(-)`
measuringthe SOLID state magnetic moment
theremally decomposing compound

Answer :C
27.

In nitroprusside ion, the iron and NO exist asFe^(II) and NO^(+) rather than Fe^(III) and NO. These forms can be differentiated by

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ESTIMATING the concentrationof iron
MEASURING the concentration of`CN^(-)`
measuring the solidestate magnetic moment
thermally decomposig the compound.

Solution :Magnetic moment HELPS to find the NUMBER of unpaired electrons.
28.

In nitroprusside ion, the iron and NO exist as Fe^(II) and NO^(+) rather than Fe^(III) and NO. These forms can be differentated by :-

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Estimating the CONCENTRATION of iron
Measuring the concentration of `CN^("ϴ")`
Measuring the SOLID state MAGNETIC moment
Thermally DECOMPOSING the compound

Answer :C
29.

In nitrogen molecule, the two atoms of nitrogen are joined by

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ONE SIGMA BOND and one pi bond
Two sigma BONDS and one pi bond
One sigma bond and two pi bonds
Three sigma bonds

Answer :3
30.

In nitroprusside ion, the iron and NO exist as Fe^(II) and NO^+ rather than Fe^(III) and NO. These forms can be differentiated by

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estimatinng the concentration of iron
measuring the concentration of `CN^-`
measuring the SOLID state magnetic MOMENT
thermally DECOMPOSING the compound

Answer :C
31.

In nitroprusside ion, iron and NO exist as Fe (II) and NO^(+) rather than Fe (III) and NO. These forms can be differentiated by

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estimating the concentration of iron
measuring the concentration of `CN^(-)`
measuring the solid STATE magnetic MOMENT
thermally DECOMPOSING the compound

Solution :In nitroprusside ion, Fe (II) has `d^(6)` configuration, i.e., 4 unpaired electrons which pair up for `d^(2)sp^(3)`-hybridisation and `NO^(+)` has also no unpaired electron. Hence, its magnetic moment is zero, i.e., it is diamagnetic. On the other HAND, Fe (III) has `d^(5)` configuration and NO has unpaired electron. Even after pairing up, unpaired electrons are present and it would have net magnetic moment.
32.

In nitrogen cycle, the main products are

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`NO and NO_(2)`
`NO_(2) and N_(2)O_(3)`
`NO and N_(2)O_(3)`
`N_(2)O_(3) and N_(2)O_(5)`

ANSWER :A
33.

In nitro alkanes -NO_2 group is converted to -NH_2 group by the reaction with

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`Sn"/"HCL`
ZN DUST
`Zn"/"NH_2`
`Zn"/"NAOH`

Answer :A
34.

In nitrogen family the H-M-H bond angle in the hydrides MH_3 gradually becomes closer to 90^0 on going from N to Sb. This shows that gradually:

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The BASIC strength of the HYDRIDES increases
Almost PURE p-orbitals are used for M-H bonding
The bond ENERGIES of M-H bond increases
The bond pairs of electrons become farther APART from the central atom

Answer :D
35.

In nitriding process of steel

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Steel is heated in an ATMOSPHERE of ammonia
Steel is MADE red hot and then cooled
Steel is made red hot and then plunged into oil for cooling
none of these

Solution :The proccess of producing a HARD coating of IRON nitride on steel is called nitriding.
36.

In nitric oxide (NO) the oxidation state of nitrogen is :

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`-2`
`+1`
`-1`
`+2`

ANSWER :D
37.

In [Ni(en)_(3)]Cl_(2),the coordination number of Fe^(2+) is………. .

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ANSWER :`6`
38.

In NH_(4)OH is added to a solution containing Al_(2)(SO_(4))_(2) and MgSO_(4), which of the following will precipitate?

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`Al(OH)_(3)` only
`Mg(OH)_(2)`only
`Al(OH)_(3)` and `Mg(OH)_(2)`
`Fe^(3+), CR^(3-)`

ANSWER :C
39.

In nickel-cadmium storage cell , the electrolyte is

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moist KOH
dil `H_(2) SO_(4)`
AQUEOUS `NH_(4)Cl`
`Ni (OH)_(3)` (aq)

Answer :A
40.

In NH_(3) and PH_3, the common is

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Odour
Combustibility
BASIC nature
None of these

Solution :`OVERSET(••)NH_(3) and overset(••)PH_3` both are basic because of the presence of lone parir of ELECTRONS.
41.

In NH_(4)NO_(2), the oxidation number of nitrogen will be

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`+3`
`+5`
`-3` and +3
`+3` and +5

Solution :`{:(NH_(4)NO_(2),hArr,overset(**)(N)H_(4)^(+),+,overset(**)(N)O_(2)^(-)),("(OXIDATION number)",,x+4=+1,,x-4=-1),(,,x=1-4=-3,,x=+3):}`
42.

In neutral or faintly alkaline medium, thiosulphate is quantitatively oxidized by KMnO_(4) is

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`SO_(3)^(2-)`
`SO_(4)^(2-)`
`SO_(2)`
`SO_(5)^(2-)`

SOLUTION :In neutral or faintly ALKALINE medium THIOSULPHATE is quantitatively oxidized by `KMnO_(4)` to `SO_(4)^(2-)`
`8KMnO_(4)+3Na_(2)S_(2)O_(3)+ H_(2) O to 3K_(2)SO_(4)+8MnO_(2)+3Na_(2)SO_(4)+2KOH`
43.

In neutral or faintly alkaline solution, 8 moles of permagnate anion quantitatively oxidize thiosulphate anions to produce X moles of a sulphur containing product. The magnitude of X is:

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Solution :The INVOLVED reaction is:
`8MnO_(4)^(-)+3S_(2)O_(3)^(2-)+H_(2)Orarr8MnO_(2)+6SO_(4)^(2-)+2OH^(-)`
8 MOLES of permangnate ion will give 6 mole of sulphur CONTAINING PRODUCT.
44.

In neutral or basic solutions, glycosides do not show mutarotation. However, if the solutions are made acidic, glycosides show mutarotation. Explain.

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Solution :Because glycosides are acetals, they UNDERGO HYDROLYSIS in aqueous ACID to form cyclic hemiacetals that then undergo mutarotation. Acetals are stable to BASE, and therefore in basic solution they do not show mutarotation.
45.

In Nernst equation, the constant 0.0592 at 298 K represents the value of

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`(RT)/(nF)`
`(RT)/(F)`
`(2.303 RT)/(nF)`
`(2.303RT)/(F)`

Answer :B::C::D
46.

In Nernst equation the constant 0.0591 represents the value of

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`(2.303RT)/(NF)`
2.303`(RT)/(F)`
`(RT)/(nF)`
`(2.303RT)/(nF)logQ^(0)`

Answer :B
47.

In Nef- Carbonylsynthesis of 2- nitropropane ontreatmentwith strongalkali andfollowedbyacificationwith 50% H_(2)SO_(4)givesa product , whichwill gives.

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TOLLEN's TEST
Haloformtest
Hinsbergtest
CARBYL AMINE reaction

Answer :B
48.

In Nef - Carbonyl synthesisof 1^(0)- nitroalkane treatmentwith NaOHfollowedbyacidificationwith 50% H_(2) SO_(4)gives.

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ALDEHYDES
ESTERS
KETONES
CARBOXYLICACIDS

ANSWER :A
49.

In nature a decay chain series starts with ""_90^232Th and finally terminates at ""_82^208Pb. A thorium ore sample was found to contain 8 xx 10^(-5) mL of helium at STP and 5xx10^9-7)g of ""^232Th . Find the age of the ore sample assuming the source of helium to be only the decay of ""^232Th . Also, assume complete retention of helium within the ore. Half-life of""^232Th= 1.39 xx 10^10years.

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SOLUTION :`""_90^232Th to ""_82^208Pb + 6""_2^4He + 4 ""_(-1)^0 e`
` 4.89 XX 10^9` years
50.

In NaCl, the Cl^- ions occupy the place in a fashion of:

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fcc
bcc
Both
None

Answer :A