94420 + Interview Questions in Chemistry in Class 12

1.	If the radius of the octahedral void is r and radius of the atoms in close-packing is R, derive relation between r and R.
Answer» Solution :The relation between R and R for OCTAHEDRAL void is derived as under : A sphere fitting into an octahedral void is shown in the Fig. For CLARITY, the spheres above and below have been REMOVED. ABC is a right angled triangle. `therefore""BC^(2)=AB^(2)+AC^(2)` `"or"(2R)^(2)=(R+r)^(2)+(R+r)^(2)=2(R+r)^(2)` `"or"((2R)^(2))/(2)=(R+r)^(2)` `"or"(2sqrt2R)^(2)=(R+r)^(2)` `"or"R+r=sqrt2R` `"or"r=sqrt2R-R` `"or"r=R(sqrt2-1)` `"or"r=0.414R`

Discussion

2.	If the radius of the first Bohr orbit is r, then the deBroglie wavelength in the third bohr orbit is
Answer» ANSWER :D

Discussion

3.	If the radius of the bromide ion is 0.182 nm, how large a cation can fit in each of the tetrahedral holes ?
Answer» Solution :For a tetrahedral hole, `(r_(+))/(r_(-))= 0.225` `:. r_(+)` (radius of tetrahedral hole) = `0.225 xx r_(-) =0.225 xx 0.182 NM= 4.01 xx 10^(-2)` nm Therefore, CATION having radius of `4.01 xx 10^(-2)` nm will just FIT in the tetrahedral hole.

Discussion

4.	If the radius of Mg2+ ion, Cs^(+) ion, O^(2–) ion, S2^(–) ion and Cl^(–) ion are 0.65 Å, 1.69 Å, 1.40 Å, 1.84 Å, and 1.81 Å respectively. Calculate the co-ordination numbers of the cations in the crystals of MgS, MgO and CsCl.
Answer» ANSWER :4,6,8

Discussion

5.	If the radius of K^(+) and F^(-) are 133 pm and 136 pm respectively, the distance between K^(+) and F^(-) in KF is......... pm
Answer» 269 134.5 136 3 Answer :A

Discussion

6.	If the radius of first Bohr orbit is r, the wavelength of an electron in the third orbit of a hydrogen atom is equal to
Answer» `6PI R` `2PI r` `9pi r` 3r Answer :A

Discussion

7.	If the radius of an octahedral void is r and the radius of atom is close packing is R, derive the relationship between r and R.
Answer» Solution :The RADIUS of the sphere representing an octahedral void can be CALCULATED by considering the cross-section through void. The cross-section of the octahedron is a square and it is shown in FIG. Let the radius of octahedral void is r and the radius of sphere is R. In the isosceles TRIANGLE ABC, `(AC)/(AB)= (sqrt(2))/(1)` Now, AB = 2R AC = R + 2r +R `:.(2R+ 2r)/(2R)= (sqrt(2))/(1)` or `1+ (r)/(R)= (sqrt(2))/(1)` or ` (r)/(R)= sqrt(2)-1= 0.414` orr= 0.414 R Thus, for an atom to occupy an octahedral void, its radius must be 0.414 TIMES the radius of the sphere.

Discussion

8.	If the radius of an octahedral void is r and the radius of atom in close packing is R, then the relation between r and R is :
Answer» R = 0.414r r = 0.732R r = 0.414R r = 0.532R ANSWER :D

Discussion

9.	If the quantum numbers n,l,m and s were defined as: R=shell number =1,2,3,4,. . . . In integral steps. l=Type of subshell =0,1,2,3,. . .To n in integral steps. m=Number of orbitals corresponding to any subshell =-(l+1)to+(l+1), in integral steps, incuding zero. s= Spin quantum number =-(1)/(2) or +(1)/(2) The l-values correspond to the subshells as actual representations, like l=0 (s-subshell). l=1(p-subshell),l=2(d-subshell),and so on. In the modern long form of periodic table, the 2nd period should (Assume that (n+l)rule is perfectly obeyed).
Answer» 8 elements 12 elements 16elements 18elements Solution :For n=3 `m=-(l+1)"to" +(l+1)` `=0m=-1,0,+1=3` orbital =1 m=02,01,0,+1,+2=5 orbital =2 m=-3,-2,-1,0,+1,+2,+3=7 orbital =3 m=-4,-3,-2,-1,0,+1+2,+1,+4=9 orbital ltbr. Total ORBITALS =3+5+7+9=24 orbitals `s=-(1)/(2) "or" +(1)/(2)` (i.e. two electrons) Total electrons =24xx2=48 electrons (ii) lr 2nd PERIOD Given: n=2,l=0,1,2 l=0 l=0s in n=1,l=0,1 l=0,1 l=1 p l=2 d Now `1s^(2)1P^(6)2S^(6)2p^(6)=16` electron (as electron will not enter in 2d)

Discussion

10.	If the radius of Bohr's 4th orbit is a, then the radius of Bohr's first orbit is
Answer» 4a a/4 `a^(2)//16` a/16 Answer :D

Discussion

11.	If the quantum numbers n,l,m and s were defined as: R=shell number =1,2,3,4,. . . . In integral steps. l=Type of subshell =0,1,2,3,. . .To n in integral steps. m=Number of orbitals corresponding to any subshell =-(l+1)to+(l+1), in integral steps, incuding zero. s= Spin quantum number =-(1)/(2) or +(1)/(2) The l-values correspond to the subshells as actual representations, like l=0 (s-subshell). l=1(p-subshell),l=2(d-subshell),and so on. The maximum number of electrons is 3^(rd) shell should be:
Answer» 18 48 24 32 Solution :For n=3 `m=-(l+1)"to" +(l+1)` `=0m=-1,0,+1=3` orbital =1 m=02,01,0,+1,+2=5 orbital =2 m=-3,-2,-1,0,+1,+2,+3=7 orbital =3 m=-4,-3,-2,-1,0,+1+2,+1,+4=9 orbital LTBR. Total orbitals =3+5+7+9=24 orbitals `s=-(1)/(2) "or" +(1)/(2)` (i.e. two electrons) Total electrons =24xx2=48 electrons (ii) lr 2nd period Given: n=2,l=0,1,2 l=0 l=0s in n=1,l=0,1 l=0,1 l=1 p l=2 d Now `1s^(2)1p^(6)2s^(6)2P^(6)=16` ELECTRON (as electron will not enter in 2d)

Discussion

12.	If the pressure of hydrogen gas is increased from 1 atm. To 100 atm, keeping the hydrogen ion concentration constant at 1 M, the reduction potential of the hydrogen half cell is at 25^(@)C will be
Answer» 0.059 V `-0.059V` `0.295V` `0.118V` Solution :`E_(H_(2)//H^(+))=-(0.0591)/(1)log_(10)((sqrt(pH_(2)))/([H^(+)]))`,`H^(+)+e^(-)to(1)/(2)H_(2)`

Discussion

13.	If the pressure of hydrogen gas is increased from 1atm to 100atm, keepimng the hydrogen ion concentratioin constant at 1M, the new reduction potential of the hydrogen half cell is at 25^(@)C will be:
Answer» `0.059V` `-0.059V` `0.295V` `0.118V` ANSWER :B

Discussion

14.	If the pressure of a given mass of a gas is reduced to half and temperature is doubled simultaneously, the volume will be
Answer» same as before TWICE as before FOUR TIMES as before one FOURTH as before Answer :C

Discussion

15.	If the pressure of a given mass of gas is reduced to half and temperature is doubled simultaneous the volume will be
Answer» same as before twice as before `1//4`TH as before NONE of the above Answer :D

Discussion

16.	If the pressure of 2 litres of an ideal gas is 4 atm then what will be the pressure of the gas if the volume is reduced to one- fourth of its present value?
Answer» Solution :`P_(1)V_(1) = P_(2)V_(2)`. As per the data GIVEN, `4 XX 2 = P × (0.5)`. So, `P = 16"atm"`.

Discussion

17.	If the pressure of a gas contained in a closed vessel is increased by 0.4 % when heated by 1°C then its initial temperature must be
Answer» 250 K 250°C 25°C 25 K Answer :A

Discussion

18.	If the pressure is halved and absolute temperature doubled the volume of the gas will be :
Answer» 4 2 Same 8 Answer :A

Discussion

19.	If the pressure and temperature of 2 litre of CO_2are doubled, the volume of CO_2 would become :
Answer» 5 litre 4 litre 8 litre 2 litre Answer :D

Discussion

20.	If the pressure and density of CO_(2) gas in adiabatic process changes from (P^(1)d) to (P^(1).d^(1)) where P=32 P^(1) than d/d_(1) is equal to
Answer» <P>`(1/32)^(1.33)` `(1/32)^(1/1.33)` `(32)^(1/1.33)` `(32)^(1/1.4)` Solution :`PV^(1) = "constant" RARR PV^(y) = P^(1)(V^(1))^(Y) rArr P/P^(1) = (V^(1)V)^(y) = (32 XX P^(1))/P^(1) = (d/d^(1))^(y)` (As `V propto 1/d`) `rArr 32 = (d/d^(1))^(y) rArr d/d^(1) = (32)^(1/y) = (32)^(1/1.33)` Hence, ( c) is the correct option.

Discussion

21.	If the position of Na^+ and Cl^- are interchanged in NaCl, the crystal Iattice with respect toNa^+ and Cl^- is :
Answer» Both fcc Both bcc fcc and bcc bcc and fcc Answer :A

Discussion

22.	If the Planck's constant is h=6.6xx10^(-34)J ,the de Broglie wavelength ofa particle having momentum of 3.3xx10^(-24)kgms^(-1) will be
Answer» `0.02Å` `0.5Å` `2Å` `500Å` Solution :`lamda=h/(MV)=(6.6xx10^(-34)JS)?(3.3xx10^(-24)kgms^(-1))` `=2xx10^(-10)m=2Å`

Discussion

23.	If the Planck's constant, h= 6.6xx10^(-34) Js, the de Broglie's wavelength of a particle having momentum of 3.3xx10^(-24) kg m s(-1)will be:
Answer» 0.02 `OVERSET@A` 0.5`overset@A` 2 `overset@A` 500`overset@A` ANSWER :C

Discussion

24.	If the pH value is 4.5 for a solution then what is the value of H^(+) concentration
Answer» `3.162 XX 10^(-5)` mol/L `31.62 xx 10^(-5)` mol/L `0.3162 xx 10^(-5)` mol/L `3.162 xx 10^(-8)` mol/L Solution :`[H^(+)] = 10^(-pH)` `= 10^(-4.5) mol//K, = 10^(0.5) xx 10^(-5)` `= sqrt(10) xx 10^(-5)` `3.162 xx 10^(-5) mol//L`.

Discussion

25.	If the pH of a solution of an alkali metal hydroxide is 13.6, the concentration of hydroxide is
Answer» Between 0.1 M and 1M More than 1 M Less than 0.001 M Between 0.01 M and 1 M Solution :`pH = 13.6` POH = 14 - 13.6 = 0.4 `[OH^(-)]` = Antilog (0.4) = 0.3979. So the value of `[OH^(-)]` between 0.1 M and 1 M.

Discussion

26.	If the pH of a solution is increased from 3 to 6, then H^+ ion concentration of the solution will be
Answer» INCREASED by 1000 times Reduced to half Reduced by 100 times Reduced by 1000 times Answer :D

Discussion

27.	If the pH of a solution is 4.0 a 25^(@)C, its pOH would be (K_(w) = 10^(-14))
Answer» `4.0` `6.0` `8.0` `10.0` SOLUTION :PH + POH = 14, pH = 4.0 pOH = 14 - pH , pOH = 14 - 4.0 = 10.0.

Discussion

28.	If the pH of a solution is 2, its normality will be
Answer» 2N `(1)/(2)N` 0.01 N None of these Solution :`pH = 2, pH = -LOG[H^(+)] , 2 = -log [H^(+)]` `[H^(+)] = 10^(-2) = 0.01 N`.

Discussion

29.	If the pH of a solution is 2 , its normality will be
Answer» 0.5 N 0.01 N 2 N NONE of these Answer :D

Discussion

30.	If the Pb^(2+) concentration is maintained at 1.0M what is the [Cu^(2+)] , when the cell potential drops to zero ?E_("cell")^@ = 0.473V, Pb(s) // Pb^(2+) // Cu^(2+) // Cu(s)
Answer» `1 XX 10^(-16) M` `1 xx 10^15 M` `1 xx 10^(-14)M` `1 xx 10^14 M` ANSWER :A

Discussion

31.	If the partition is removed the average molar mass of the sample will be (Assume ideal behaviour).
Answer» `1/2` g/mol `10/3` g/mol `3/2` g/mol `5/3` g/mol Solution :`:.` We KNOW `PV=nRT` `:.N=(RT)/(PV)` Moles of `H_(2)=(3xx16.42)/(0.0821xx300)=2` Moles of `D_(2)=(6xx16.42)/(0.0821xx300)=4` AVERAGE moleclar weight `=(2xx2+4xx4)/(4+2)=10/3`

Discussion

32.	If the oxidation potential be defined with reference to Ag \|Ag^(+) half cell (for which oxidation potential is taken to be zero) , which of the following will give the correct value of oxidation potential of Cu \| Cu^(2+) half cell (Given that Cu \| Cu^(2+) = -0.34V and Ag \| Ag^(+) = -0.80 V )
Answer» `-0.46` VOLTS `-1.14` volts `1.14` volts 0.46 volts Solution :For the cell reaction , `Cu + 2 Ag ^(+) to Cu^(2+) + 2 Ag` `E_(cell)^(@) = E_(Ag^(+) \|Ag)^(@) - E_(Cu^(2+)\|Cu)^(@)` = `0.80 - 034 = 0.46` V . This is the difference of reduction POTENTIALS of Ag and Cu electrodes . Taking ELECTRODE potential of Ag = 0 and `E_(Cu^(2+)\| Cu)^(@) = - 0.46` V or `therefore E_(Cu\| Cu^(2+))^(@) = 0.46` V .

Discussion

33.	If the osmatic pressure of human blood is 7.53 atm at 37^@C. Calculate the concentration non electrolytic solutes in the blood ?
Answer» 0.296 MOL `L^(-1)` 0.592mol `L^(-1)` 1.12mol `L^(-1)` 1MOL `L^(-1)` ANSWER :A

Discussion

34.	If the organic compound contains more than two similar terminal groups and all of them are directly attached to the principal chain, then none of them forms a part of the principal chain. Special suffixes are used to name these. {:("Functional group", "Suffix"),(-CONH_(2), "Carboxamide"),(-CN, "Carbonitrile"),(-CHO, "Carbaldehyde"),(-COOH, "Carboxylic acid"):} Carbon atoms of these terminal groups are not counted in the principal chain. If any one of these terminal groups is not directly attached to the parent chain and forms the part of side chain, then the longest chain is selected containing two such similar groups at its two ends. The groups present in the side chain are treated as substituents and are indicated by suitable prefixes. Indicate whether the following IUPAC name are true (a) or false (b). {:("""Compound",, ""IUPAC " Name"),(""CONH_(2),,),(""\|,,),(H_(2)NOC - CH_(2) - CH - CH_(2) - CONH_(2),, """Propane-1,2,3-tricarboxamide"),("""True (a)",, """False (b)"):}
Answer» ANSWER :a

Discussion

35.	If the organic compound contains more than two similar terminal groups and all of them are directly attached to the principal chain, then none of them forms a part of the principal chain. Special suffixes are used to name these. {:("Functional group", "Suffix"),(-CONH_(2), "Carboxamide"),(-CN, "Carbonitrile"),(-CHO, "Carbaldehyde"),(-COOH, "Carboxylic acid"):} Carbon atoms of these terminal groups are not counted in the principal chain. If any one of these terminal groups is not directly attached to the parent chain and forms the part of side chain, then the longest chain is selected containing two such similar groups at its two ends. The groups present in the side chain are treated as substituents and are indicated by suitable prefixes. Indicate whether the following IUPAC name are true (a) or false (b). {:("""Compound",, ""IUPAC " Name"),(""CH_(2)CHO,,),(""\|,,),(OHC - CH_(2) - CH - CH_(2) - CHO,, """3-(formylmethyl)pentane-1,5-dial"),("""True (a)",, """False (b)"):}
Answer» ANSWER :a

Discussion

36.	If the organic compound contains more than two similar terminal groups and all of them are directly attached to the principal chain, then none of them forms a part of the principal chain. Special suffixes are used to name these. {:("Functional group", "Suffix"),(-CONH_(2), "Carboxamide"),(-CN, "Carbonitrile"),(-CHO, "Carbaldehyde"),(-COOH, "Carboxylic acid"):} Carbon atoms of these terminal groups are not counted in the principal chain. If any one of these terminal groups is not directly attached to the parent chain and forms the part of side chain, then the longest chain is selected containing two such similar groups at its two ends. The groups present in the side chain are treated as substituents and are indicated by suitable prefixes. Indicate whether the following IUPAC name are true (a) or false (b). {:("""Compound",, ""IUPAC " Name"),(""CH_(2)-COOH,,),(""\|,,),(HOOC - CH_(2) - CH - CH_(2) - COOH,, """3-(carboxymethyl)pentane-1,5-dioic acid"),("""True (a)",, """False (b)"):}
Answer» ANSWER :a

Discussion

37.	If the organic compound contains more than two similar terminal groups and all of them are directly attached to the principal chain, then none of them forms a part of the principal chain. Special suffixes are used to name these. {:("Functional group", "Suffix"),(-CONH_(2), "Carboxamide"),(-CN, "Carbonitrile"),(-CHO, "Carbaldehyde"),(-COOH, "Carboxylic acid"):} Carbon atoms of these terminal groups are not counted in the principal chain. If any one of these terminal groups is not directly attached to the parent chain and forms the part of side chain, then the longest chain is selected containing two such similar groups at its two ends. The groups present in the side chain are treated as substituents and are indicated by suitable prefixes. Indicate whether the following IUPAC name are true (a) or false (b). {:("""Compound",, ""IUPAC " Name"),(""CN,,),(""\|,,),(NC - CH_(2) - CH - CH_(2) - CN,, """3-cyanopentane-1,5-dinitrile"),("""True (a)",, """False (b)"):}
Answer» ANSWER :B

Discussion

38.	If the organic compound contains more than two similar terminal groups and all of them are directly attached to the principal chain, then none of them forms a part of the principal chain. Special suffixes are used to name these. {:("Functional group", "Suffix"),(-CONH_(2), "Carboxamide"),(-CN, "Carbonitrile"),(-CHO, "Carbaldehyde"),(-COOH, "Carboxylic acid"):} Carbon atoms of these terminal groups are not counted in the principal chain. If any one of these terminal groups is not directly attached to the parent chain and forms the part of side chain, then the longest chain is selected containing two such similar groups at its two ends. The groups present in the side chain are treated as substituents and are indicated by suitable prefixes. Indicate whether the following IUPAC name are true (a) or false (b). {:("""Compound",, ""IUPAC " Name"),(""COOH,,),(""\|,,),(HOOC - CH_(2) - CH - CH_(2) - COOH,, """Propane - 1,2,3-tricarboxylic acid"),("""True (a)",, """False (b)"):}
Answer» ANSWER :a

Discussion

39.	If the orders of reduction potential isthen :
Answer» Y will oxidize X only Y will oxidize Z only Z will oxidize both X and Y Z will reduce both X and Y Solution : `E_(Z)^(@)` is HIGHEST `Rightarrow` strongest oxidising AGENT . `Rightarrow E_(X)^(@)Rightarrow` Strongest oxidising agent . `Rightarrow Y` will oxidising X but not Z. ALSO , Z will oxidise both X and Y.

Discussion

40.	If order of reaction A+B overset(hv)rarrAB is zero. It means that
Answer» Reaction is INDEPENDENT of temperature Formation of activated complex is ZERO Reaction is independent of the CONCENTRATION of reacting SPECIES Decomposition of activated complex is zero Solution :In photochemical reactions the rate of reaction is independent of the concentration of reacting species .

Discussion

41.	If the number of values of m is seven, the value of azimuthal quantum number should be:
Answer» 3 4 2 1 Solution :(A)`m=(2l+1):.7=2l+1` or `l=3`.

Discussion

42.	If the number of moles of electrons involved in a reaction is doubled by multiplying all of the species appearing in the overall reaction by 2 then the potential is
Answer» HALVED DOUBLED unchanged squared Answer :C

Discussion

43.	If the number of silicon atoms is restricted to 23 only, what would be the number of oxygen atoms and magnitude of negative charges respectively in the structure of pyroxene (single chain silicate)? [If your answer are 11 and 12 respectively then write the answer as 1112.]
Answer» ANSWER :`7048`

Discussion

44.	If the number of Chiral carbon in camphor is X and total number of racemic form is Y then, report your answer is 4[X+Y]
Answer» SOLUTION :Each bridgehead carbon is CHIRAL CENTER and only one racemic form is KNOWN.

Discussion

45.	If the nitrogen atom had electronic configuration 1s^(7), it would have energy lower than that of the normal ground state configuration 1s^(2), 2s^(2) 2p^(3), because the electrons would be closer to the nucleus. Yet, 1s^(7) is not observed because it violates
Answer» HEISENBERG UNCERTAINTY principle Hund rule Pauli EXCLUSION principle Bohr postulate of stationary orbits Answer :C

Discussion

46.	If the nitrogen atoms are in a cyclic arrangement in hydrazoic acid, the oxidation states of N are
Answer» `+3, +3, +3` `0, 0-1` `0, 0, -1//3` `-1//3, -1//3, 0` ANSWER :B

Discussion

47.	If the nitrogen atom had electronic configuration is 1s^7, it would have energy lower than that of the normal ground state configuration1s^2 2s^2 2p^3 because the electrons would be closer to the nucleus. Yet 1s^7 is not observed. It violates:
Answer» HUND's rule Heisenberg's uncertainty principle Pauli's EXCLUSION principle Bohr postulate of STATIONARY orbits Answer :C

Discussion

48.	If the molecular weight of H_(3) PO_(3) is M, its equivalent weight will be
Answer» M M/2 M/3 2M Solution :DIBASIC ACID `E=M//2`

Discussion

49.	If the mole fraction of X in a solution of X and Y is 0.69, what is the mole fraction of Y?
Answer» SOLUTION :MOLE FRACTION of Y = 1 -0.69 = 0.31.

Discussion

50.	If themolarconductivityof a weakmonobasicacidat 0.1 Mand zeroconcentration are15.8 and226. 4 S cm^(2) mol^(-1) respectively calculatethe degree ofdissociationand thedissociationconstantfor acid
Answer» SOLUTION :`z= 0.06988 , K_(a) = 4.872 XX 10^(-4) `

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If the radius of the octahedral void is r and radius of the atoms in close-packing is R, derive relation between r and R.

If the radius of the first Bohr orbit is r, then the deBroglie wavelength in the third bohr orbit is

If the radius of the bromide ion is 0.182 nm, how large a cation can fit in each of the tetrahedral holes ?

If the radius of Mg2+ ion, Cs^(+) ion, O^(2–) ion, S2^(–) ion and Cl^(–) ion are 0.65 Å, 1.69 Å, 1.40 Å, 1.84 Å, and 1.81 Å respectively. Calculate the co-ordination numbers of the cations in the crystals of MgS, MgO and CsCl.

If the radius of K^(+) and F^(-) are 133 pm and 136 pm respectively, the distance between K^(+) and F^(-) in KF is......... pm

If the radius of first Bohr orbit is r, the wavelength of an electron in the third orbit of a hydrogen atom is equal to

If the radius of an octahedral void is r and the radius of atom is close packing is R, derive the relationship between r and R.

If the radius of an octahedral void is r and the radius of atom in close packing is R, then the relation between r and R is :

If the radius of Bohr's 4th orbit is a, then the radius of Bohr's first orbit is

If the pressure of hydrogen gas is increased from 1 atm. To 100 atm, keeping the hydrogen ion concentration constant at 1 M, the reduction potential of the hydrogen half cell is at 25^(@)C will be

If the pressure of hydrogen gas is increased from 1atm to 100atm, keepimng the hydrogen ion concentratioin constant at 1M, the new reduction potential of the hydrogen half cell is at 25^(@)C will be:

If the pressure of a given mass of a gas is reduced to half and temperature is doubled simultaneously, the volume will be

If the pressure of a given mass of gas is reduced to half and temperature is doubled simultaneous the volume will be

If the pressure of 2 litres of an ideal gas is 4 atm then what will be the pressure of the gas if the volume is reduced to one- fourth of its present value?

If the pressure of a gas contained in a closed vessel is increased by 0.4 % when heated by 1°C then its initial temperature must be

If the pressure is halved and absolute temperature doubled the volume of the gas will be :

If the pressure and temperature of 2 litre of CO_2are doubled, the volume of CO_2 would become :

If the pressure and density of CO_(2) gas in adiabatic process changes from (P^(1)d) to (P^(1).d^(1)) where P=32 P^(1) than d/d_(1) is equal to

If the position of Na^+ and Cl^- are interchanged in NaCl, the crystal Iattice with respect toNa^+ and Cl^- is :

If the Planck's constant is h=6.6xx10^(-34)J ,the de Broglie wavelength ofa particle having momentum of 3.3xx10^(-24)kgms^(-1) will be

If the Planck's constant, h= 6.6xx10^(-34) Js, the de Broglie's wavelength of a particle having momentum of 3.3xx10^(-24) kg m s(-1)will be:

If the pH value is 4.5 for a solution then what is the value of H^(+) concentration

If the pH of a solution of an alkali metal hydroxide is 13.6, the concentration of hydroxide is

If the pH of a solution is increased from 3 to 6, then H^+ ion concentration of the solution will be

If the pH of a solution is 4.0 a 25^(@)C, its pOH would be (K_(w) = 10^(-14))

If the pH of a solution is 2, its normality will be

If the pH of a solution is 2 , its normality will be

If the Pb^(2+) concentration is maintained at 1.0M what is the [Cu^(2+)] , when the cell potential drops to zero ?E_("cell")^@ = 0.473V, Pb(s) // Pb^(2+) // Cu^(2+) // Cu(s)

If the partition is removed the average molar mass of the sample will be (Assume ideal behaviour).

If the oxidation potential be defined with reference to Ag |Ag^(+) half cell (for which oxidation potential is taken to be zero) , which of the following will give the correct value of oxidation potential of Cu | Cu^(2+) half cell (Given that Cu | Cu^(2+) = -0.34V and Ag | Ag^(+) = -0.80 V )

If the osmatic pressure of human blood is 7.53 atm at 37^@C. Calculate the concentration non electrolytic solutes in the blood ?

If the orders of reduction potential isthen :

If order of reaction A+B overset(hv)rarrAB is zero. It means that

If the number of values of m is seven, the value of azimuthal quantum number should be:

If the number of moles of electrons involved in a reaction is doubled by multiplying all of the species appearing in the overall reaction by 2 then the potential is

If the number of silicon atoms is restricted to 23 only, what would be the number of oxygen atoms and magnitude of negative charges respectively in the structure of pyroxene (single chain silicate)? [If your answer are 11 and 12 respectively then write the answer as 1112.]

If the number of Chiral carbon in camphor is X and total number of racemic form is Y then, report your answer is 4[X+Y]

If the nitrogen atom had electronic configuration 1s^(7), it would have energy lower than that of the normal ground state configuration 1s^(2), 2s^(2) 2p^(3), because the electrons would be closer to the nucleus. Yet, 1s^(7) is not observed because it violates

If the nitrogen atoms are in a cyclic arrangement in hydrazoic acid, the oxidation states of N are

If the nitrogen atom had electronic configuration is 1s^7, it would have energy lower than that of the normal ground state configuration1s^2 2s^2 2p^3 because the electrons would be closer to the nucleus. Yet 1s^7 is not observed. It violates:

If the molecular weight of H_(3) PO_(3) is M, its equivalent weight will be

If the mole fraction of X in a solution of X and Y is 0.69, what is the mole fraction of Y?

If themolarconductivityof a weakmonobasicacidat 0.1 Mand zeroconcentration are15.8 and226. 4 S cm^(2) mol^(-1) respectively calculatethe degree ofdissociationand thedissociationconstantfor acid