Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

HF is a weaker acid than HCl why?

Answer»

SOLUTION :SINCE `H-F` bond is STRONGEST, hence it is weakest ACID AMONG all the halogen acids.
2.

Heating a mixture of ethyl alcohol acetic acid in presence of conc. H_2SO_4produces a fruity smelling compounds A . Then A is

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ETHER
ESTER
Aldehyde
KETONE

ANSWER :B
3.

HF is a weak acid but HCl is a strong acid because

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HF ATTACKS glass but HCl does not
HF is less ionic than HCl
Electron affinity of fluorine is LOWER than chlorine
BOND energy of HF is higher than HCl

Solution :Bond energy of H-F is higher than HCl
4.

Heat treatment alters the properties of steel due to

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chemical reaction on heating
partial rusting
change in the RESIDUAL energy
change in the lattice STRUCTURE due to differential rate of cooling

Solution :Heat treatment alters the PROPERTIES of STEEL due to rearrangement of its grain structure.
5.

Hexane dioic acid in obtained by oxidation of

Answer»

BENZENE
CYCLOHEXANE
CYCLOHEXENE
cyclohexane carbaldehyde

ANSWER :C
6.

Heat required to raise the temperature of 1 mol of a substance by 1^(@)C is called

Answer»

SPECIFIC HEAT
MOLAR heat CAPACITY
Water EQUIVALENT
Specific gravity

Solution :It is molar heat capacity.
7.

Heat produced in calories by the combustion of one gram of carbon is called

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Heat of COMBUSTION of CARBON
Heat of FORMATION of carbon
CALORIFIC value of carbon
Heat of production of carbon.

Solution :It is the definition of calorific value.
8.

Hexane, C_(6)H_(14), is immiscible with water and ethanol. Water and ethanol are miscible. C_(6)H_(14)has the lowes density. Which diagram represents the results when equal volumes of these three liquids are placed in a test tube and shaken?

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1
2
3
4

Answer :D
9.

Heat of transition is the heat evolved or absorbed when a substance is converted from

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Solid to liquid
Solid to vapour
Liquid to vapour
One ALLOTROPIC form to another allotropic form

SOLUTION :It is the definition of heat of TRANSITION.
10.

Calculate the entropy change involved in the conversion of one mole of water at 373 K to vapour at the same temperature.(Latent heat of vaporisation of water at this temperature , Delta H_vap = 2.257 kJg^-1)

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ANSWER :C
11.

Hexamethylenediamine and adipic acid are monomers of ……………………

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SOLUTION :NYLON - 6, 6
12.

Heat of reaction of which of the following equation expresses the bond energy of HCl :-

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`HCl(G)toH(g)+CL(g)`
`2HCl(g) to H_(2)(g)+Cl_(2)(g)`
`HCl(g)to(1)/(2)H_(2)(g)+(1)/(2)Cl_(2)(g)`
`HCl(g)toH^(+)(g)+Cl^(-)(g)`.

Answer :A
13.

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemical equation. The amount of energy released during a chemical change depends upon the state of reactants and products, the conditions of pressure and volume at which reaction is carried out, and temperature. The variation of heat of reaction (Delta H or Delta E) with temperature is given as DeltaH_(2) - Delta H_(1) = Delta C_(p) [T_(2) - T_(1)] or Delta E_(2) - Delta E_(1) = Delta C_(v) (T_(2) - T_(1)) . Standard heat enthalpy of elements in their most stable state is assumed to be zero whereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atm pressure and 25^(@)C . Oxidation of N_(2) to N_(2) O , NO , NO_(2) showsabsorption of energy whereas heat of combustion of N_(2) is exothermic like other heat of combustion. The specific heat of I_(2) in vapour and solid state are 0.031 and 0.55 cal/ g-^(@) C respectively . If heat of sublimation of iodine is 6.096 kcal mol^(-1) at 200 ^(@) C , the heat of sublimation of I_(2) at 250^(@) C is :

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`5.8 KCAL MOL^(-1)`
`2.28 kcal mol^(-1)`
`4.8 kcal mol^(-1)`
`3.8 kcal mol^(-1)`

ANSWER :A
14.

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemical equation. The amount of energy released during a chemical change depends upon the state of reactants and products, the conditions of pressure and volume at which reaction is carried out, and temperature. The variation of heat of reaction (Delta H or Delta E) with temperature is given as DeltaH_(2) - Delta H_(1) = Delta C_(p) [T_(2) - T_(1)] or Delta E_(2) - Delta E_(1) = Delta C_(v) (T_(2) - T_(1)) . Standard heat enthalpy of elements in their most stable state is assumed to be zero whereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atm pressure and 25^(@)C . Oxidation of N_(2) to N_(2) O , NO , NO_(2) showsabsorption of energy whereas heat of combustion of N_(2) is exothermic like other heat of combustion. Heat of vaporisation of H2O is 627.78 cal/g. If heat of formation of H_(2) O_((l)) is -68.3 kcal , heat of formation of H_(2) O_((g)) is :

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`-57.0` KCAL
`559.5` kcal
`676.73` kcal
Can not be CALCULATED

ANSWER :A
15.

Hexamethylene tetramine is used as an:

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ANALGESIC
Antipyretic
Urinary antiseptic
All

Answer :C
16.

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemical equation. The amount of energy released during a chemical change depends upon the state of reactants and products, the conditions of pressure and volume at which reaction is carried out, and temperature. The variation of heat of reaction (Delta H or Delta E) with temperature is given as DeltaH_(2) - Delta H_(1) = Delta C_(p) [T_(2) - T_(1)] or Delta E_(2) - Delta E_(1) = Delta C_(v) (T_(2) - T_(1)) . Standard heat enthalpy of elements in their most stable state is assumed to be zero whereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atm pressure and 25^(@)C . Oxidation of N_(2) to N_(2) O , NO , NO_(2) showsabsorption of energy whereas heat of combustion of N_(2) is exothermic like other heat of combustion. Which statements regarding the formation of NO and NO_(2) respectively from N_(2) and O_(2) are correct : (A) Heat of formation of NO is exothermic (B) Heat of formation of NO_(2) is exothermic (C) The oxidation of N_(2) to NO and NO_(2) is favoured at high temperature. (D) If heat of formation of NO and NO_(2) are 21.55 and 8.50 kcal, heat of reaction for NO + (1)/(2) O_(2) to NO_(2) is -13.05 kcal

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1, 2
3 , 4
1 ,2 , 4
1, 2 , 3

ANSWER :B
17.

Hexagonal close packing is found in crystal lattice of :

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Na
Mg
Al
None of these

Answer :A
18.

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemical equation. The amount of energy released during a chemical change depends upon the state of reactants and products, the conditions of pressure and volume at which reaction is carried out, and temperature. The variation of heat of reaction (Delta H or Delta E) with temperature is given as DeltaH_(2) - Delta H_(1) = Delta C_(p) [T_(2) - T_(1)] or Delta E_(2) - Delta E_(1) = Delta C_(v) (T_(2) - T_(1)) . Standard heat enthalpy of elements in their most stable state is assumed to be zero whereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atm pressure and 25^(@)C . Oxidation of N_(2) to N_(2) O , NO , NO_(2) showsabsorption of energy whereas heat of combustion of N_(2) is exothermic like other heat of combustion. Standard heat enthalpy has been assumed to be zero for :

Answer»

GRAPHITE
DIAMOND
CHARCOAL
LAMP black

Answer :A
19.

Hexamethylene tetramine is commonly known as _____.

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UROTROPINE
Methenamine
Hexamine
All of the above

Solution :Urotropine
20.

Heat of reaction for, CO(g) 1/2 O_(2)(g) rarr CO_(2)(g) at constant V is -67.71 kcal at 17^(@)C. The heat of reaction at constant P at 17^(@)C

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`+68.0` KCAL
`-67.42` kcal
`-68.0` kcal
None

Answer :C
21.

Hexaflurocobaltate (III) ion is found to be high spin complex, the probable hybrid state of cobalt in it is:

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`d^2sp^3`
`sp^3`
`sp^3d`
`sp^3d^2`

ANSWER :D
22.

Heat of reaction at constant volume is measured in the apparatus

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Bomb calorimeter
Calorimeter
Pyknometer
Pyrometer

Solution :Both calorimeter is USED to MEASURE HEAT of REACTION.
23.

'Heat ofneutralisation of a strong dibasic acid in dilute solution by NaOH is'

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`-27.4 cal/equ
`-13.7 cal/equ
`+13.7 cal/equ
`-13.7 cal/mol

Answer :B
24.

Heat of neutralization of the acid-base reaction is 57.32 kJ for

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`HNO_(3)+LIOH`
HCOOH+KOH
`HCl+NH_(4)OH`
`CH_(3)COOH+NaOH`

SOLUTION :Strong ACID `(HNO_(3))` and strong base (LiOH).
25.

Heat of neutralization will be minimum for which of the following combination

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`NaOH+H_(2)SO_(4)`
`NH_(4)OH+CH_(3)COOH`
`NaOH+HCl`
`NaOH+CH_(3)COOH`

SOLUTION :Heat of neutralization is the heat liberated when one mole acid is neutralized by base. For strong acid-strong base neutralization, its VALUE is 57kJ/mol. For weak acid or base its value is less than this value. Hence, the heat of neutralization will be MINIMUM for `CH_(3)COOH+NH_(4)OH`.
26.

Heat of neutralization of the reaction, NaOH+HCl rarr NaCl + H_(2)O is 57.2"kJ mol"^(-1). What will be the heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl

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28.6 kJ
57.1 kJ
14.3 kJ
22.5 kJ

Answer :C
27.

Heat of neutralization of strong acid and weak base is

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57.1 kJ `mol^(-1)`
13.7 kJ `mol^(-1)`
Less than 13.7 kcal `mol^(-1)`
More than 13.7 kcal `mol^(-1)`

Solution :HEAT of neutralization of strong ACID and WEAK BASE is less than 13.7 kcal `mol^(-1)`.
28.

Heat of neutralisation of strong acid and strong base under 1 atm and 25^@C is -13.7 kcal. If standard Gibbs energy change for dissociation of water to H^+ and OH^- is -19.14 kcal, the change in standard entropy for dissociation of water is:

Answer»

18.25
110.2
`-18.25`
NONE of these

Answer :B
29.

Heat of neutralization of strong acid against strong base is constant and is equal to

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13.7 KCAL
57 kcal
`5.7xx10^(4)` J
All of the above

Solution :13.7 kcal = 57 KJ = `5.7xx10^(4)J`.
30.

Heat of neutralization of an acid by a base is highest when

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Both the acid and BASE are WEAK
Both the acid and base are STRONG
The acid is strong and the base is weak
The acid is weak and the base is strong

Solution :When both acid and base are strong than heat of neutralization is `57.1 KJ mol^(-1)`.
31.

Heat of neutralization of strong acid by a strong base is a constant value due to:

Answer»

Salt FORMED does not hydrolyse
Only `H^(+)` and `OH^(-)` IONS react in EVERY case
The STRONG base and strong acid react completely
The strong base and strong acid react in aqueous solution

Solution :In neutralization of a strong acid and base only `H^(+)` and `OH^(-)` ions react.
32.

Hexafluorocobaltate (III) ion is found to be high spin complex, the probable hybrid state of cobalt in it is:

Answer»

`d^2sp^3`
`sp^3`
`sp^3d`
`sp^3d^2`

ANSWER :D
33.

Heatof neutralization of HF is

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` GT 57.32J`
`LT 57.32 J`
`57.23 J`
NONE

ANSWER :A
34.

Heat of neutralisation of weak acid and strong base is less than the heat of neutralisationof strong acid and strong base due to

Answer»

Energy has to be SPENT for the total dissociation of WEAK ACID
Salt of weak acid and strong base is not stable
Incomplete dissociation of weak acid
Incomplete neutralisation of weak acid

SOLUTION :Energy has to be spent for the total dissociation of weak acid.
35.

Heat of neutralization (DeltaH) of NH_(4)OH and HF are -51.5 and -68.6 kJ respectively. Calculate their heat of dissociation? (i) HCl (aq)+NaOH(aq) rarr NaCl (aq)+H_(2)O, ""DeltaH= -57.3 kJ (ii) HCl (aq)+underset("(weak base)")(NH_(4)OH (aq)) rarr NH_(4)Cl (aq)+H_(2)O, ""DeltaH= -51.5 kJ

Answer»

Solution :`:.` The HEAT of DISSOCIATION of `NH_(4)OH`,
`DELTAH=-51.5-(-57.3)=5.8 kJ`
SIMILARLY we have
`HF(aq) +NAOH(aq) rarr NaF(aq)+H_(2)O, DeltaH=-68.6 kJ`
`:.` The heat of diffociation of `HF`,
`DeltaH =-68.6-(-57.3)=-11.3 kJ`
36.

Hexafluorferrate(III)ion is an outer orbital complex. The number of unpaired electrons present in.it is:

Answer»

1
5
4
Unpredictable

ANSWER :B
37.

Heat of neutralisation of weak acid and strong base is less than the heat of neutralisation of strong acid and strong base due to

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A) energy has to be spent for the total dissociation of WEAK acid
B) SALT of weak acid and strong base is not stable
C) incomplete dissociation of weak acid
D) incomplete neutralisation of weak acid

Solution :Heat of neutralisation is the change in enthalpy when one gram equivalent of an acid is neutralised by a base or vice versa. All strong acids and bases are almost completely ionised to enthalpy of neutralisation of all strong acids by strong bases are same. weak acids do not undergo complete ionisation IMMEDIATELY on dissolution in WATER. these GET ionised during the reaction of neutralisation. a part of heat evolved during neutralisation is consumed in causing complete ionisation of weak acid. as a result the heat of neutralisation of weak acid with a strong base is less than the heat of neutralisation of stong acid with strong base.
38.

Hexaamminenickel(II) hexanitrocobaltate (III) can be written as :-

Answer»

`[NI(NH_3)_6[Co(NO_2)_6]`
`[Ni(NH_3)_6]_3[Co(NO_2)_6]_2`
`[Ni(NH_3)_6][Co(NO_2)_6]`
`[Ni(NH_3)_6(NO_2)_6]Co`

ANSWER :B
39.

Hexa methylene tetramine is used as ............

Answer»

analgesic
antipyretic
URINARY ANTISEPTIC
all of these

SOLUTION :Urinary antiseptic
40.

Heat of neutralisation of a strong acid and strong base is always.

Answer»

13.7 kcal/mole
9.6 kacl/mole
6 kcal/mole
11.4 kacl/mole

Answer :A
41.

Heat of hydrogenation of cyclohexene to cyclohexane is -28.6 kcal/mol.The observed heat of hydrogenation of benzene to cyclohexane is -49.8 kcal/mol. Calculate the resonance energy of benzene in kcal/mole.

Answer»


SOLUTION :RESONANCE ENERGY =-49.8-(-3x28.6)=36 K cal/mol
42.

Hexa-2-ene-4-yne is

Answer»

`CH_(3)-CH_(2)-C-=C-CH = CH_(2)`
`CH_(3)-C-=C-CH=CH-CH_(3)`
`CH_(3)CH_(2)-CH=CH-C-=CH`
`CH_(3)-C-=C-CH_(2)-CH=CH_(2)`

SOLUTION :`UNDERSET("Hexa-2-ene-4-yne")(CH_(3)-C-=C-CH=CH-CH_(3))`
43.

Heat of formation of SO_(4) is -298 kJ. What is the heat of combustion of 4g of S

Answer»

`+37` KJ
`-37.25` kJ
`+298` kJ
18.6 kJ

Solution :`S+O_(2)rarrSO_(2), DeltaH=-298 kJ`
HEAT of formation of `SO_(2)` is also the heat of combustion of sulphur.
`because` heat of combustion of 32 g S = (-298) kJ
`THEREFORE` heat of combustion of 4g `S=((-298)xx4)/(32)=-37.25 kJ`.
44.

Heat of formation of SO_(2) is -298 kJ. What is the heat of combustion of 4 g of S?

Answer»

`+37kJ`
`-37.25 kJ`
`+298kJ`
`18.6kJ`

Solution :Heat of combustion is TOTAL heat changes accompanying when ONE mole of substance undergoes complete combustion in EXCESS of oxygen.
`S+O_(2) to SO_(2),DeltaH=298kJ`
`therefore`Heat of formation of `SO_(2)`=heat of combustion of `SO_(2)` atomic mass of S=32G
`because`Combustion of 32g of S(=1 mole of S) gives heat
=-298 kJ
`therefore `Combustion of 4g of S gives heat`=(-298)/(32)xx4=-37.25kJ`.
45.

Heteropolymer.

Answer»

Solution :A polymer made from more than one kind of repeating UNIT of monomers is called HETEROPOLYMER. The heteropolymers are also called co-polymers. E.g. Terylene, Nylon - 6, 6 , BUNA - S, Buna -N.
46.

Heteropoly acids are formed by:

Answer»

Be
Fe
Mo
Cr

Answer :C
47.

Heat of formation of SO_2 "is" -298 kJ. What is the heat of formation of 4 g of SO_2?

Answer»

`+37`KJ
`-37.15`kJ
`+298`kJ
`-18.6`kJ

Answer :D
48.

heat of formation ofH_(2)O is -188 kJ // mol and H_(2)O_(2) is -286 kJ // mol . The enthaply change for thereaction2H_(2)O_(2) to 2H_(2)O+O_(2) is

Answer»

196 kJ
`-196 kJ`
984 kJ
`-984 kj`

Solution :`H_(2)+1/2 O_(2)to H_(2)O,DeltaH=-188kJ mol^(-1)`
`H_(2) + O_(2) toH_(2)O_(2) , DeltaH =286 kJ mol ^(-1)`
multiply Eqs.(i) and (ii) by 2
`2H_(2)+O_(2) to 2H_(2)O, DeltaH=-376 kJ mol^(-1)`
`2H_(2)+2O_(2) to 2H_(2)O_(2) , DeltaH =- 572 kJ mol^(-1)`
Eq .(iii) - Eq.(iv)
`2H_(2)O_(2) to 2H_(2)O + O_(2), DeltaH_(r) =+196 kJ`
49.

Heterolytic cleavage of a covalent bond gives only:

Answer»

CATIONIC species
Anionic species
Both of the above
Free radicals

Answer :C
50.

Heterolytic bond dissociation energy of alkyl halides follows the sequence

Answer»

`R-F GT R -Cl gt R -BR gt R -I`
`R - I gt R - Br gt R - Cl gt R - F`
`R - I gt R - F gt R - Br gt R - Cl`
`R - Cl gt R - Br gt R- I gt R - F`

Solution :`R-I gt R - Br gt R - Cl gt R - F`