Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

For the test of halides, the soda extract is acidfied with

Answer»

DIL `H_(2)SO_(4)`
Dil. `HNO_(3)`
Dil. HCl
none of the three

Solution :SODIUM carbonate EXTRACT is treated with dil. `HNO_(3)` to destroy `CO_(3)^(2-)` ION and `CN^(-)` ions (if present ) since both INTERFACE with the test.
2.

For the system A_((g))+2B_((g))hArrC_((g)), the equlibrium concentrations are (A) 0.06 mole/litre (B) 0.12 mole/litre (C ) 0.216 mole/litre. The K_(eq) for the reaction is

Answer»

250
416
`4XX10^(-3)`
125

Solution :For reaction `A+2BhArrC`
`K=([C])/([A][B]^(2))=(0.216)/(0.06xx0.12xx0.12)=250.`
3.

For the system at equlibrium, which of the following are correct

Answer»

`LOGK=(1)/(2.303R)(DeltaS-(DeltaH)/(T))`
On increasing the temperature of an endothemic reaction, the equlibrium shifts in forwared DIRECTION because Q decreases
On increasing the temperture of an endothermic reaction, the equilibrium shifts in forward direction because K increase
On increasing the temperature of an endothemic reaction, the conncentration in moles per LITRE of the reactants increase

Solution :`DeltaG=DeltaH-TDeltaS=-2.303RTlogK`
`TDeltaS-DeltaH=2.303RTlogKimplies`
`(TDeltaS-DeltaH)/(2.303RT)=logKimplies(1)/(1.303R)[DeltaS-(DeltaH)/(T)]=logK`
Hence choice (a) is correct.
On changing temperatue K changes and not Q.
Also `LOG""(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
For endothemic reactions on increasing T, K increase hte concentration of products. Thus choice (c) is correct while (b) and (d) are not correct.
4.

For the system 3A+2BhArrC, the expression for equilibrium constant is

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`([3A][2B])/(C)`
`([C])/([3A][2B])`
`([A]^(2)[B]^(2))/([C])`
`([C])/([3A]^(3)[2B]^(2))`

Solution :Equlibrium CONSTANT for the reaction, `3A+2BhArrC isK=([C])/([A]^(3)[B]^(2)).`
5.

For the synthesis of Laevorotatory solution, the only correct combination is :

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(IV)(iv)(Q)
(II)(III)(S)
(III)(ii)(P)
I(iii)(S)

Solution :On hydrolysis with DILUTE acids sucrose yields an equimolar mixture of D(+) GLUCOSE and D(-) Fructose. Since D(-) Fructose has a GREATER specific ROTATION than D(+) Glucose, the resulting mixture is laevorotatory.
6.

For the synthesis of ammonia by the reaction N_(2)+3H_(2)iff2NH_(3) in the Haber process, the attainment of equilibrium is correctly predicted by the curve

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SOLUTION :concentrations of `H_(2)` and `N_(2)` DECREASE while that of `NH_(3)` increases with time and after equilibrium, all of them REMAIN constant.
7.

For the synthesis of ammonia by the reaction N_(2)+3H_(2)hArr hNH_(3) in the Haber process the attainment of equilibrium is correctly predicted by the curve

Answer»




ANSWER :C
8.

For the synthesis of ammonia at 300 K : N_2(g)+3H_2(g)to2NH_3(g) Calculate the value of DeltaG^@ in Kcal and give your answer in magnitude by using the following data : {:(( ),N_2,H_2,NH_3),(DeltaH_f(Kcal//"mole"),0,0,-10),(S^@(Cal//"K-mole"),40,30,45):}

Answer»


SOLUTION :`DeltaH_R^@=2xxDeltaH_(f(NH_3))^@-3xxDeltaH_(f_(H_2))^@-DeltaH_(f_(N_2))^@=-20 KCAL`
`DeltaS_R^@=2xxS_(NH_3)^@-3xxS_(H_2)^@-S_(N_2)^@=2xx45-3xx30-40=-40` Cal/K
`DeltaG^@=DeltaH^@-TDELTAS^@= - 20 - (300xx(-40))/1000=-20+12=-8 Kcal`
9.

For the structure given below the sign marked as S is an:

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TETRAHEDRAL VOID
CUBIC void
Octahedral void
Trigonal void

Answer :C
10.

For the strong electrolytes NaOH, NaCl and BaCl_2 the molar ionic conductivities at infinite dilution are 248.1xx10^(-4),126.5xx10^(-4) and 280.0xx10^(-4) mho cm^2 mol^(-1) respectively. Calculate tmolar conductivity of Ba(OH)_2 at infinite dilution.

Answer»


ANSWER :A::B::C::D
11.

For the standard cell Cu(s)|Cu^(2+)(aq)||Ag^(+)(aq)|Ag(s). [E_((Cu^(2+))/(Cu))=0.3V and E_((Ag^(+))/(Ag))^(0)=0.80V] Write the reaction taking place at the electrodes.

Answer»

SOLUTION :At cathode `AG^(+)+E^(-) to Ag`
At ANODE `Cu to Cu^(2+)+2e^(-)`
12.

For the standard cell Cu(s)|Cu^(2+)(aq)||Ag^(+)(aq)|Ag(s). [E_((Cu^(2+))/(Cu))=0.3V and E_((Ag^(+))/(Ag))^(0)=0.80V] Identify the cathode and the anode as the current is drawn from the cell.

Answer»

SOLUTION :Cathode is `Ag^(+)//Ag and" ANODE is "CU^(2+)//Cu`
13.

For the square coplanar complex [Pt(NH_(3))(NH_(2)OH)P_(Y)(Cl)]^(+), how many geometrical isomers are possible? Draw them.

Answer»

SOLUTION :Three isomers are possible. Any other possible CONFIGURATION WOULD MERELY be a ROTATION or reflection of one of these.
14.

For the sequential first order reaction: A overset(k_(1)) rarr B overset(k_(2)) rarrC t=0 [A_(0)] 00 Match the following lists: {:(,"List-I",,"List-II"),("(P)","Time for" (+(d[C])/dt)_(max)when k_(1)=k_(2)=k,,(1)1/k),("(Q)","Time for" (+(d[C])/dt)_(max)when k_(1)nek_(2),,(2)(l nk_(2)-l nk_(1))/(k_(2)-k_(1))),("(R)",[B]when k_(1)=k_(2)(d[B])/(dt)=0 and (d^(2)[B])/dt^(2)=-ve,,(3)[A_(0)]/e),("(S)",[B]when k_(1) ne k_(2)(d[B])/(dt)=0 and (d^(2)[B])/(dt^(2))=-ve,,[A_(0)](k_(2)/k_(1))^(k_(2)/(k_(1)-k_(2)))):}

Answer»

`{:("PQRS"),("1234"):}`
`{:("PQRS"),("2143"):}`
`{:("PQRS"),("2413"):}`
`{:("PQRS"),("4321"):}`

ANSWER :A
15.

For the simultaneous reactions:2A to B, -(d[A])/(dt) =(0.04min^(-1)).[A] 3A to 2C, -(d[A])/(dt) =(0.03min^(-1)).[A] Which of the following statement(s) is/are incorrect regarding the reactions?

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The overall rate constant for the disappearance of 'A' is `0.17min^(-1)`.
The molar ration of 'B' and 'C' after 10min from the START of reaction is 2:3
The mole percent of 'B' in the total product formed upto 20 min form the start of reaction will be 50.
Half LIFE for the disappearance of 'A' is 10min, if In 2=0.7.

Answer :A::B
16.

For the solution of the gasesW, X, Yandzinwaterat298 K , theHenryslawconstants(K _ H )are 0.5, 2, 35 and40 kbar,respectively. Thecorrectplotfor the givendata is:

Answer»





Solution :`P_("gas")=K_(H).X_("gas")`
`P_("gas")=K_(H).(1-X_(H_(2)O))`
`P_("gas")=K_(H)-K_(H).X_(H_(2)O)`
`y=C+mx`
For higher `K_(H)` SLOPE will be more negative
17.

For the sequential reaction: A.overset(k_(1)=0.2"min"^(-1))(to)Boverset(k_(2)=0.2"min"^(-1))(to)C t= 0 a M ""0""0 The time (in min) at which concentration of B becomes maximum is :

Answer»


ANSWER :5
18.

Forthe sequential first order reactions: {:(,Aoverset(k_(1)=2xx10^(-4)s^(-1))to,Boverset(k_(2)=10s^(-1))to,C),(t=0,0.4M ,0,0):} the time after which the concentration of C cecomes 0.3 M is:

Answer»

`(In2)/(k_(1))`
`(In4)/(k_(1))`
`(In2)/(k_(2))`
`(In4)/(k_(2))`

Answer :B
19.

For the sequence of reactions, RC_6 H_5 NO_2 overset(HNO_3) underset(H_2 SO_4) to A overset((NH_4)_2 S) to B, the compound Bis

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ANILINE
m- DINITROBENZENE
m- NITROANILINE
m- diaminobenzene

Solution :
20.

For the second order reaction , A + B toProducts When a moles of A reacts with b moles of B , the rate equation is given by k_(2) t= (1)/((a-b)) "ln" (b(a-x))/(a(b-x)) When a gt gt b , the rate expression becomes that of

Answer»

First ORDER
Second order
Unchanged , second order
Third order

Solution :`k_(2) t = (1)/((a-b))` ln `(b(a-x))/(a(b-x))`
` GT gt b` means (a-x) = a and (a-b) =a
i.e., `k_(2) t = (1)/(a)` ln `(ba)/(a(b-x)) implies k_(2) t = (1)/(a)` ln `(b)/((b-x))`
(SINCE 'a' being very large , may be treated as constant after the change) . Thus , the reaction FOLLOWS first order kinetics .
21.

For the second order reaction t_((1)/(2))prop

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`(1)/(a^(2))`
`(1)/(a)`
CONSTANT
a

ANSWER :B
22.

The rate constant for a second order reaction is k=(2.303)/(t(a-b))log""(b(a-x))/((b-x)) where a and b are initial concentrations of the two reactants A and B involved. If one of the reactants is present in excess, it becomes pseudo unimolecular. Explain how ?

Answer»

first order w.r.t. A
zero order w.r.t. A
first order w.r.t.B
overall zero order

Solution :[B](=b), being present in LARGE EXCESS, does not CHANGE practically. The RATE BECOMES independent of [B], i.e., order -0 w.r.t. B.
23.

For the same metal, stabilisation energies of tetrahedral and octahedral complexes are related as

Answer»

`Delta_t = Delta_0`
`Delta_t XX 4 = Delta_0 xx 6`
`Delta_t xx 9 =Delta_0 xx 4`
`Deltatxx 6 = Delta_0 xx 4`

ANSWER :C
24.

For the same alkyl (or) aryl group, boiling point, is more for

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RI
RBr
RCI
RF

Answer :A
25.

For the salt of weak acid and strong base, the hydrolysis constant is given by the expression :

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`K_(H)=(K_(W))/(K_(B))`
`K_(h)=(K_(w))/(K_(a)K_(b))`
`K_(h)=K_(a)`
`K_(h)=(K_(w))/(K_(a))`

ANSWER :D
26.

For the reversible vapourisation of water at 100^(@)C and 1 atmospheric pressure. DeltaG is equal to?

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`DELTAH`
`DELTAS`
ZERO
`DeltaH//T`

ANSWER :C
27.

For the reversible vaporisation of water at 373 K and 1 atmosphere pressure, Delta G is equal to

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`DELTA H`
`Delta S`
ZERO
`(Delta H)/(T)`

ANSWER :C
28.

For the reversible reaction the initial concentrations of A and B are Am and bm,and the equillibrium concentrations are (a-x)M and (b+x) respectively. The value of x is:

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`(K_(1)a+K_(2)B)/(K_(1)+K_(2))`
`(K_(1)a-K_(2)b)/(K_(1)+K_(2))`
`(K_(1)+K_(2))/(K_(1)a+K_(2)b)`
`(K_(1)+K_(2))/(K_(1)a-K_(2)b)`

ANSWER :B
29.

For the reversible vaporisation of water at 100^@C and 1 atmospheric pressure, triangleG is equal to:

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`TRIANGLEH`
`TRIANGLES`
ZERO
`triangleH/T`

ANSWER :C
30.

For the reversible reaction N_(2(g))+3H_(2(g))iff2NH_(3(g)) At 500^(@)C, the value of K_(p) is 1.44xx10^(-5) when partial pressure is measured in atmospheres. The corresponding value of K_(c) with concentration in mole "litre"^(-1), is

Answer»

<P>`1.44xx10^(-5)//(0.082xx500)^(-2)`
`1.44xx10^(-5)//(8.314xx773)^(-2)`
`1.44xx10^(-5)//(0.082xx773)^(2)`
`1.44xx10^(-5)//(0.082xx773)^(-2)`

Solution :`Deltan_(g)=2-4=-2,K_(C)=K_(p)//(RT)^(DELTAN)`
`=1.44xx10^(-5)//(0.082xx773)^(-2)`
31.

For the reversible reaction N_2(g) + 3H_2(g) = 2NH_3(g) at 500^@C the value of K_p is 1.44 xx 10^-5 when partial pressure measured in atmosphere The corrosponding value of K_c with concentration is mole/lit. IS :

Answer»

`(1.44xx10^(-5))/ (0.082xx500)^(-2)`
`(1.44xx10^(-5))/ (8.314xx773)^(-2)`
`(1.44xx10^(-5))/ (0.082xx773)^(-2)`
`(1.44xx10^(-5))/ (0.082xx773)^(-2)`

ANSWER :D
32.

For the reversible reaction : A(s)+B(g)iffC(g)+D(g) : DeltaG^(@)=-350 kj.Which one of the following statements is true

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The ENTROPY CHANGE is NEGATIVE
Equilibrium constant is greater than ONE
The REACTION should be instantaneous
The reaction is thermodynamically nto feasible

Solution :`DeltaG` has negative value. So, the reaction is feasible in forward direction. So, equilibrium constant will have value greater than one.
33.

For the reversible reaction : Aounderset(K_(2))overset(K_(1))hArrB ,k_(1)=0.02"min"^(-1) and k_(2)=0.03"min^(-1) . The reaction is statedwith A only .If the half life of suchreaction is defined as the time in which halfof the equilibrium amount of B is formed , then , what is the half life of reaction ?

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34.65 min
23.10 min
13.86 min
Infinite

Answer :C
34.

For the reversible reaction. A(s)+B(g) Leftrightarrow C(g)+D(g), triangleG^(@)=-350kJ Which one of the following statement is true?

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The REACTION is thermodynamically non-feasible
the entropy CHANGE is negative
Equilibrium constant is greater than one
The reaction should be instantaneous

Answer :C
35.

For the reversible reaciton, N_(2(g))+3H_(2(g))hArr2NH_(3(g)) at 500^(@)C, the value of K_(p) is 1.44xx10^(-5) when partial pressure is measured in atmospheres. The conrresponding value of K_(c) with concentration in mole "littre"^(-1), is

Answer»

`1.44xx10^(-5)//(0.082xx500)^(-2)`
`1.44xx10^(-5)//(8.314xx773)^(-2)`
`1.44xx10^(-5)//(0.082xx773)^(2)`
`1.44xx10^(-5)//(0.082xx773)^(-2)`

SOLUTION :`underset(4)(H_(2)+3H_(2))hArrunderset(2)(2NH_(3))`
`Deltan=2-4=-2`
`K_(p)=K_(c)[RT]^(Deltan),K_(p)=K_(c)[RT]^(-2)`
`K_(c)=(K_(p))/([RT]^(-2))=(1.44xx10^(-5))/([0.082xx773]^(-2))`
36.

For the reversible reaction A =+ 2B harr C+ Heat the forward raction will proceed at

Answer»

LOW TEMPERATURE and low pressure
low pressure
HIGH pressure and low temperature
high pressure and high temperature

Solution :For the reversible reaction `A+2BhArr C+Delta`, FORWARD reaction will proceed at high pressure and low temperature.
37.

For the reversible reaction : A_(s) + B_(g) hArr C_(g) + D_(g) : Delta G^(@) = - 350 kJ Which one of the following statements is true ?

Answer»

The ENTROPY CHANGE is negative
Equilibrium CONSTANT is greater than one
The REACTION should be instantaneous
The reaction is thermodynamically not feasible

Answer :B
38.

For the reversible reaction 2H_2S_((g)) hArr 2H_(2(g))+S_(2(g)) The equilibrium concentrations, are [H_2S]=0.5 mole/litre [H_2]=0.4 mole/litre [S_2]=0.4 mole/litre The value of 'K' would be

Answer»

`0.004` mole/litre
`0.08` mole/litre
`0.016` mole/litre
`0.16` mole/litre

Answer :C
39.

For the reduction of silver ions with copper metal, the standard cell potential was found to be +0.46V at 25^(@)C. Thevalue of standard Gibbs energy, DeltaG^(@) will be (F=96500Cmol^(-1))

Answer»

`-98.0kJ`
`-89.0kJ`
`-89.0J`
`-44.5kJ`

SOLUTION :`2AG^(+)+Cuto2Ag+Cu^(2+)`
`n=2`
`DeltaG=-nFE_(CELL)`
`DeltaG=-2xx96500xx0.46` joul
`DeltaG=-88.78kJ=-89kJ`.
40.

For the reduction of silver ions with copper metal, the standard cell potential was found to be +0.46V at 25^(@)C. The value of standard Gibbs energy, DeltaG^(@) will be (F=96500" C "mol^(-1))

Answer»

`-98.0kJ`
`-89.0kJ`
`-89.0J`
`-44.5kJ`

SOLUTION :`Cu+2AG^(+)TOCU^(2+)+2Ag,E_(CELL)^(@)=0.46V`
`DeltaG^(@)=-nFE_(cell)^(@)=-2xx96500xx0.46J=-88780J=-89kJ`
41.

For the relief of post operative pains, cardiac pains, suitable analgesic is________

Answer»

Codeine
Aspirin
Ibuprofen
Any NON - ADDICTIVE ANALGESICS

ANSWER :A
42.

For the reduction of NO_(3)^(-) ion in an aqueous solution, E^(@) is +0.96V. Values of E^(@) for some metal ions are given below V_((aq))^(2+)2e^(-)toV""E^(0)=-1.19V Fe_((aq))^(3+)+3e^(-)toFe""E^(@)=-0.04V Ag_((aq))^(3+)+3e^(-)toAu""E^(0)=+1.40V Hg_((aq))^(2+)+2e^(-)toHg""E^(o)=+0.86V The pair(s) of metals that is (areO oxidized by NO_(3)^(-) in aqueous solution is(are)

Answer»

V and HG
Hg and FE
Fe and Su
Fe and V

Solution :The species having less reduction potential with respect to `NO_(3)^(-)(E^(o)=0.96V)` will be OXIDIZED by `NO_(3)^(-)`
These species are V, FE, Hg.
43.

For the reduction of NO_(3)^(-) ion in an aqueous solution , E^(0) is + 0.96 V , the values of E^(0) for some metal ions ar given below : i) V_((aq))^(+2) + 2e^(-) to V,E^(0) = 1.19V ii) Fe_((aq))^(+3) + 3e^(-) to Fe , E^(0) = -0.04 V iii) Au_((aq))^(+3) + 3e^(-) to Au , E^(0) = + 1.40 V iv) Hg_((aq))^(+2) + 2e^(-) to Hg , E^(0) = +0.86 V The pair(s) of metals that is/are oxidizd by NO_3^(-) in aqueous solution is /are

Answer»

FE and AU
Hg and Fe
V and Hg
Fe and V

SOLUTION :`V^(+2)//V(-1.19V) , Fe^(+3)//Fe-(0.04V),Hg^(+2)//Hg (+0.86V) , NO_3^(-) // NO_2^(-) (+0.9V) ,Au^(+3)//Au (+1.40)`
44.

For the reduction of Feo at the temperature corresponding to point D, which of the following statements is correct?

Answer»

`DeltaG^(@)` value for the overall reduction reaction with carbon monoxide is ZERO
`DeltaG^(@)` value for the overall reduction reaction with a mixture of 1 mol carbon and 1 mol oxygen is positive.
`DeltaG^(@)` value for the overall reduction reaction with a mixture of 2 mol carbon and 1 mol oxygen will be positive.
`DeltaG^(@)` value for the overall reduction reaction with carbon monoxide is NEGATIVE.

Solution :At POINT `D, DeltaG_((CO","CO_2))^(@) = Delta_(f)G_((Fe","FeO))^(THETA)`
Thus overall value of `DeltaG^(@)` will be zero.
45.

For the reduction of FeO at the temperature corresponding to point D, which of the following statements is correct ?

Answer»

`DeltaG` value for the OVERALL reduction REACTION with carbon MONOXIDE is ZERO.
`DeltaG` value for the overall reduction reaction with a mixture of 2 mol carbon and 1 mol oxygen is POSITIVE.
`DeltaG` value for the overall reduction reaction with a mixture of 2 mol carbon and 1 mol oxygen will be positive.
`DeltaG` value for the overall reduction reaction with carbon monoxide is negative.

Solution :It is the correct answer.
46.

Forthe redox reacton Cr_2 O_(7)^(2+)+H^(+) +NIto Cr^(3+) +NI^(2+)+H_2 O the correctcoefficientsof thereactantsfor thebalancedreaction areCr_2 O_(7)^(2-)NIH^+

Answer»

1314
2314
1116
331 2

Solution :Thebalancedequation is :`Cr_2O_(7)^(2-) + 14 H^++3Ni to 2Cr^(3+) + 7H_2 O + 3Ni^(2+)`
47.

For the redox reaction Zn_((s))+Cu^(2+)(0.1M)toZn^(2+)(1M)+Cu_((s)) taking place in a cell, E_(cell)^(o) is 1.10 volt, E_(cell) for the cell will be (2.303(RT)/(F)=0.0591)

Answer»

2.14 VOLT
1.80 volt
1.07 volt
0.82 volt

Solution :`E=E^(@)-(0.059)/(n)"log"([ZN^(++)])/([Cu^(++)])=1.10-(0.059)/(2)"log"(1)/(0.1)`
`=1.10-0.0295log10=1.07` volt
48.

For the redox reaction Zn(s) + Cu^(2+) (0.1M) rarr Zn^(2+) (1M) + Cu(s) that takes place in a cell, E^(o)""_(cell) is 1.10 volt. E_(cell) for the cell will be:

Answer»

`2.14` VOLT
`1.80` volt
`1.07` volt
`1.82` volt

Answer :C
49.

For the redox reaction Zn+NO_(3)^(-)rarr Zn^(2+)+NH_(4)^(-) is basic medium, coefficients of Zn, NO_(3)^(-) and OH^(-) in the balanced equation respectively are :

Answer»

4, 1, 7
7, 4, 1
4, 1, 10
1, 4, 10

Answer :C
50.

For the redox reaction :Zn(s) + Cu^(2+) (0.1M) to Zn^(2+) (1M) + Cu(s)taking place in a cell, E_("cell")^@is 1.10 volt. E_("cell") for the cell will be

Answer»

2.14 VOLT
1.07 volt
1.80 volt
0.82 volt

Answer :C