Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Ferrous sulphate forms Turnbulls blue with:

Answer»

KCN
`NH_4SCN`
`K_3[Fe(CN)_6]`
`K_4[Fe(CN)_6]`

Answer :C
2.

Ferrous sulphate forms Turn bull's blue with

Answer»

KCN
`NH_(4)SCN`
`K_(3)[Fe(CN)_(6)]`
`K_(4)[Fe(CN_(6))]`

Solution :`3FeSO_(4)+K_(3)[Fe(CN)_(6)]toFe_(3)[Fe(CN)_(6)]_(2)+3K_(2)SO_(4)`, Ferraferric cyanide
3.

Ferrous salts slowly convert to ferric salts on exposure to air. Why?

Answer»

Solution :`Fe^(2+)` state is OXIDIZED to `Fe^(3+)` which is more stable ELECTRONIC configuration i.e., `3d^(5)`-half FILLED configuration
4.

Ferrous ion changes to 'X' ion, on reacting with acidified hydrogen peroxide. The number of d-electrons present in 'X' and its magnetic moment are

Answer»

6 and 6.93 B.M.
5 and 5.92 B.M.
5 and 4.9 B.M.
4 and 5.92 B.M.

Solution : 5 and 5.92 B.M.
5.

Ferromagnetismis maximum in

Answer»

FE
Ni
CO
None

Solution :Ferromagnetism is MAXIMUM is Fe out of F,Co and Ni .
6.

Ferrosilicon is used in steel industry as

Answer»

A flux
Scavenger of hydrogen
A REDUCING agent
Alloying agent

Answer :D
7.

Extent of Ferromagnetism is maximum in

Answer»

fe
`NI^(2+)`
`CO_(3+)`
C`Cu^(2+)`

Answer :A
8.

Ferromagnetism is exhibited only below

Answer»

842 K
1042 K
742 K
642 K

Answer :B
9.

Ferromagnetism arises becases of the sponteneous alignment of the magnetic moments due to unpaired electrons as

Answer»

uparrowuparrowuparrowuparrowuparrow
uparrowuparrowuparrowdownarrowdownarrow
uparrowdownarrowuparrowdownarrow
uparrowuparrowdownarrowuparrowuparrow

Answer :A
10.

Ferrochrome, an iron chromium alloy used in making stainless steel, is produced by reducing chromite (FeCr_(2)O_(4)) with coke : FeCr_(2)O_(4)(s) + 4C (s) rarr underset("Ferrochrome")(underbrace(Fe(s) + 2Cr(s))) + 4CO(s) (i) How many kilograms of chromium can be obtained by the reaction of 236 kg of chromite with an excess of coke ? (ii) How many litres of CO at 25^(@)C and 740 mm Hg are obtained as a by-product ?

Answer»

Solution :(i) `FeCr_(2)O_(4)(s) + 4C(s) rarr Fe(s) + 2Cr(s) + 4CO(s)`
224 KG of chromite gives = 104 kg of Cr
236 Kg of chromite gives `= (104 XX 236)/(224)` kg of Cr
= 109.57 kg Cr
(ii) 224 kg chromite gives = 112 Kg CO
Thus 236 kg chromite gives `= (112 xx 236)/(224)` kg CO
`rArr` 118 kg CO = 4214.2857 mol.
As PV = nRT
T = 298 K
`P = (740)/(760)` atm
`therefore""V = (nRT)/(P) = (4214.28 xx 0.0821xx 298 xx 760)/(740)`
`= 105.89 xx 10^(3)` litre
11.

Ferrocene is diamagnetic in nature. According to valence bond theory the hybride state assumed by Fe in ferrocene is

Answer»

`sp^2`
`sp^3d^2`
`d^2sp^3`
`sp^3d`

ANSWER :C
12.

Ferromagnetic substances have

Answer»

ZERO magneticmoment
SMALL magnetic moment
large magnetic moment
any valueof magneticmoment

ANSWER :C
13.

Formula of ferrocene is:

Answer»

`Fe(eta^5-C_5H_5)_2`
`Fe(eta^2-C_5H_5)_2`
`CR(eta^5-C_5H_5)_5`
`Os(eta^5-C_5H_5)_2`

ANSWER :A
14.

Ferrocene is:

Answer»

`Fe(eta^5-C_5H_5)_2`
`Fe(eta^2-C_5H_5)_2`
`CR(eta^5-C_5H_5)_5`
`Os(eta^5-C_5H_5)_2`

Answer :A
15.

Ferrimagnetic substances lose ferrimagnetism on heating and become ______________

Answer»


ANSWER :PARAMAGNETIC
16.

Ferrimagnetic is converted into ferromagnetic at :

Answer»

300 K
400 K
600 K
850 K

Answer :D
17.

Ferric sulphate on heating gives:

Answer»

`SO_2` and `SO_3`
`SO_3` only
`SO_3` only
S only

Answer :C
18.

Ferric oxide in furnance is reduced by

Answer»

C
`H_2`
CO
`CO_2`

ANSWER :C
19.

Ferric oxide in blast furnance is reduced by :

Answer»

C
`H_2`
CO
`CO_2`

ANSWER :C
20.

Ferric oxide crystallises in a hexagonal close packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Answer»

SOLUTION :Number of oxide ION per unit cell = 6
`therefore` Total number of OCTAHEDRAL VOIDS = 6
Number of ferric ion present `= 2/3 xx 6 = 4`
`therefore ` Ratio of `Fe^(3+)` ions to `O_("ions")^(2-)= 4 : 6 = 2:3`
Hence formula of oxide is `Fe_2O_3`
21.

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Answer»

Solution :Let the number of `O^(2-)` IONS in the packing= N
Number of octahedral holes (voids) =N
Voids occupied by `FE^(3+)= (2N)/(3)`
Ratio of `Fe^(3+) : O^(2-)= (2N)/(3): N`
`=2:3`
Formula of ferric OXIDE = `Fe_(2)O_(3)`
22.

Ferric ion forms a prussiann blue coloured ppt. due to

Answer»

`K_(4)Fe(CN)_(6)`
`Fe_(4)[Fe(CN)_(6)]_(3)`
`KMnO_(4)`
`Fe(OH)_(3)`

Solution :`4FeCl_(3)++3K_(4)[Fe(CN)_(6)]tounderset("Prussian Blue colour")(Fe_(4)[Fe(CN)_(6)])+12KCl`
23.

Ferric ion forms a prussian blue coloured precipitate with K_(4)[Fe(CN)_(6)]a due to the formation of

Answer»

`K_(3)Fe(CN)_(6)`
`Fe_(4)[Fe(CN)_(6)]_(3)`
`Fe(OH)_(3)`
`KFE[Fe(CN)_(6)]`

SOLUTION :`Fe_(4)[Fe(CN)_(6)]_(3)`
24.

Ferric ion forms a prussian blue precipitate due to the formation of

Answer»

`K_(4)[FE(CN)_(6)]`
`K_(3)[Fe(CN)_(6)]`
`Fe(CNS)_(3)`
`Fe_(4)[Fe(CN)_(6)]_(3)`

Solution :Prussian blue precipitate is `Fe_(4)[Fe(CN)_(6)]_(3)`
25.

Ferric hydroxide sol is prepared by

Answer»

treating ferric chloride with dilute sodium hydroxide SOLUTION
treating ferric chloride with dilute ammonium hydroxide solution
adding ferric chloride solution to BOILING water
any onhe of the above methods

Answer :C
26.

Ferric hydroxide sol is positively charged colloid. The coagulating power of NO_3^-, SO_4^(2-) and PO_4^(3-) ions would be in the order

Answer»

`NO_3^(-) GT SO_4^(2-) gt PO_4^(3-)`
`SO_4^(2-) gt NO_3^(-) gt PO_4^(3-)`
`PO_4^(3-) gt SO_4^(2-) gt NO_3^-`
`NO_3^(-) = SO_4^(2-) =PO_4^(3-)`

ANSWER :C
27.

Ferric hydroxide sol is more readily coagulated by Na_3PO_4 in comparison to KCl.

Answer»

Solution :Ferric hydroxide SOL is positively charged and to CAUSE its coagulation, ions carrying negative charge are needed. Since `PO_4^(3-)` ions have HIGHER negative charge than `Cl^–` ions therefore, `Na_3PO_4` COAGULATES the ferric hydroxide sol most efficiently.
28.

Ferric hydroxide sol can be prepared from freshly perpared ferric hydroxide precipitate. It can also be prepared by adding ferric chloride solution to boilling water. In both cases the sol particles are positively charged. Name the above two methods of preparation of ferric hydroxide sol.

Answer»


ANSWER :PEPTIZATION and HYDROLYSIS RESPECTIVELY.
29.

Ferric chloride forms both positively and negatively charged sols. Explain.

Answer»

Solution :When `Fecl_(3)` is added to excess of HOT water , a positively chargedsol of hydrated FERRIC oxide is FORMED due to adsorption of ferric ions.
`Fe_(2)O_(3).xH_(2)O //Fe^(3+)`is a positively charged sol.
When `FeCl_(3)` is added to alkali solution , a NEGATIVELY charged sol of ferric oxide is formed due to adsorption of hydroxyl ions. `Fe_(2)O_(3).xH_(2)O //OH^(-)` is a negatively charged sol.
30.

Ferric chloride on rubbing to a bleeding wound causes

Answer»

COAGULATION
peptisation
emulsification
de-emulsification

Answer :A
31.

Ferric chloride is applied to stop bleeding due to cut because :

Answer»

`Fe^(3+)` ion Caogulates BLOOD which is a negatively charged sol.
`Fe^(3+)` ion Coagulates blood WHICHIS a POSITIVELY charged sol.
`Cl^(-)` ion Coagulates blood which is a positively charged sol.
`Cl^(-)` ion Coagulates blood which is a negatively charged sol.

Solution :`Fe^(3+)` ion coagulate the SOLUBLE PROTEIN ( Present in blood plasma ) which are negatively charged.
32.

Ferric chloride is applied to stop bleeding due to a cut because :

Answer»

`Fe^(3+)` ion coagulates blood which is a negatively CHARGED sol.
`Fe^(3+)` ion coagulates blood which is a POSITIVELY charged sol.
`Cl^(-)` ion coagulates blood which is positively charged sol.
`Cl^(-)` ion coagulates blood which is a negatively charged sol.

Solution :`Fe^(3+)` ions coagulate the solble proteins (present in blood plasma) which are negetively charged. (REMEMBER that when a blood vessel breaks, bleeding stops by itself afte rsometime. It is due to colustering together of platelest (blood particles) to from a plug).
33.

Ferric chloride (neutral) reacts with catechol to give :

Answer»

GREEN COLOUR
BLUE colour
BLACK colour
VIOLET colour.

Answer :A
34.

Ferric chloride is applied to stop bleeding because

Answer»

`Fe ^(3+)` ions coagulate blood which is a negatively CHARGED sol.
`Fe Cl_(3)` reacts with the CONSTITUENTS of blood to FORM a complex.
`Cl ^(+)` ions coagulate blood which is a positively charged sol.
Blood absorbs `FECL _(3).`

Answer :A
35.

Ferric alum has the composition (NH_(4))_(2)SO_(4). Fe_(2)(SO_(4)).xH_(2)O.x is

Answer»

7
24
6
15

Solution :Ferric ALUM is
`(NH_(4))_(2) SO_(4). Fe_(2)(SO_(4))_(3).24H_(2)O`
36.

Ferric chloride is applied to stop bleeding because:

Answer»

`FE^(3+)` ion coagulates blood, which is a NEGATIVELY charged SOL
`Fe^(3+)` ion coagulates blood, which is a POSITIVELY charged sol
`Cl_(–)` coagulates blood, which is a positively charged sol
`Cl^(–)` ion coagulates blood, which is a negatively charged sol

Answer :A
37.

Ferric alum gives red colour with NH_(4)SCN dueto formation of

Answer»

`AI(SCN)_(3)`
`[Fe(SCN)_(3)]^(THETA)`
`Fe(SCN)_(3)`
`Fe(SCN)_(3)]^(2+)``

ANSWER :C
38.

Ferric alum is the indicatein the tatration of Ag^(o+) with SCN^(Θ) when (a)_____colour apears of the end point .

Answer»


ANSWER :RED
39.

Ferric alum does not form precipitate with.

Answer»

NaOH
`BaCl_(2)`
`Na_(2)CO_(3)`
`H_(2)S" GAS"`

Solution :For maximum volume of 3M HCl solution 2M, 1L HCl solution should be USED completely.
`M_(1)V_(1)+M_(2)V_(2)=M_(F)V_(f)""2xx1+5xxV=3xx(1+V),V=(1)/(2)L,V_(f)=(3)/(2)l`
40.

table salt is:

Answer»

HF
`KHF_2`
NACL
`KClO_3`

ANSWER :B
41.

Fermentation of sugar with yeast gives :

Answer»

`CH_3OH`
HCHO
`C_2H_5OH`
`CH_3CH_2CH_2OH`

ANSWER :C
42.

Fermentationis an//a :

Answer»

ENDOTHERMIC REACTION
exothermic reaction
polymerisation reaction
condensation reaction

ANSWER :B
43.

Fermentation of starch solution to ethyl alcohol does not require

Answer»

Diastase
Invertase
Maltase
Zymase

Answer :B
44.

Fermentation of starch to give alcohol takes place in presence of:

Answer»

ENZYMES
`CO_2`
AIR
`N_2`

ANSWER :A
45.

Fermentation is an

Answer»

ENDOTHERMIC REACTION
Exothemic reaction
Reversible reaction
NONE of above

Answer :B
46.

Fermentation is a reaction called

Answer»

Endothermic
EXOTHERMIC
Isotemperature
Reversible

SOLUTION :FERMENTATION is exothermic REACTION.
47.

Fermentation is :

Answer»

Exothermic
Endothermic
Reversible
None

Answer :A
48.

Fe(OH)_(3) can be separated from Al(OH)_(3) by the addition of

Answer»

NACL SOLUTION
Dil. HCl solution
NaOH solution
`NH_(4)Cl` and `NH_(4)OH`

Solution :Due to common ion effect of `NH_(4)^(+)`, CONCENTRATION of `OH^(-)` decreases, as `K_(sp)Fe(OH)_(3) LT K_(sp)Al(OH)_(3)` thus `Fe(OH)_(3)` get precipitated first.
49.

Fe(OH)_3 can be separated from Al(OH)_3 by the addition of

Answer»

Dil.HCl
NaCl solution
NaOH solution
`NH_(4)Cl`+NHOH

Solution :NaOH DISSOLVES `Al(OH)_(3)` ppt. forming `NaAlO_2` LEAVING behind `Fe(OH)_(3)` as residue.
`Al(OH)_(3)(s)+NaOH (aq) toNaAlO_(2) (aq)+2H_(2)O(l)`
50.

Fe(OH)_(3) can be separated from Al(OH)_(3) by addition of:

Answer»

DIL. HCI
NACL solution
NaOH solution
`NH_(4)CI` and `NH_(4)OH`

Answer :C