Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Draw the structure of XeF_4.

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SOLUTION :
2.

Draw the structure of XeF_(4).

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SOLUTION :
3.

During the test of halogens by silver nitrate test, the sodium extract is first boiled with a few drops of conc. HNO_3 to

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decompose sodium halides present
decompose sodium cyanide if present
decompose sodium SULPHIDE if present
acidify the sodium extract.

Solution :Boiling sodium extract with a few drops of conc. `HNO_(3)` decompose `NaCN` (if present ) and `Na_2 S` (if present)
`NaCN + HNO_(3) overset(Delta)(to) HCN UARR NaNO_(3)`
`Na_(2) S+ 2 HNO_(3) overset(Delta)(to) H_(2) S uarr + 2 NaNO_(3)`
Nitric acid also acidify the sodium extract . An alkaline sodium extract will give a white PPT. AgOH and `AgNO_3` solution .
`NaOH + AgNO_(3) to AgOH darr+ NaNO_(3)`
4.

During the test of N in an organic compound by Lassaigne's extract, prussian blue colour is obtained. This is due to :

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`Fe_4[Fe(CN)_6]_3. xH_2O `
`[Fe(CN)_5NOS]^(4-)`
`[Fe(SCN)_2]^(+) `
`[Fe(SCN)]^(2+)` .

ANSWER :A
5.

Draw the structure of XeF_(2)

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SOLUTION :`XeF_2` has a LINEAR STRUCTURE
6.

During the study of rate of reaction between H_2O_2, and iodide ion, the reaction involves :

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OXIDATIONOF `I^(-)` by `H_2O_2`
OXIDATION of `H_2O_2` by `I^(-)` ION
REDUCTION of `I^(-)` by `H_2O_2` to `I^(+)` ion
oxidation of `I^(-) " to " I^(+) `

ANSWER :A
7.

Draw the structure of XeF_(2) molecule.

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SOLUTION :`XeF_(2):`
8.

During the smelting of roasted copper pyrites in blast furnace, why Cu_(2)S formed but not FeS?

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Solution :Copper has greater affinity to SULPHUR than oxygen and iron has greater affinity to oxygen than to sulphur. Hence `Cu_(2)S and FeO` are formed in BLAST FURNACE.
9.

During the reaction of carboxylic acid with NaHCO_2 the carbon of the CO_2 produced comes from NaHCO_3

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ANSWER :1
10.

During the recharging of lead storage cell,_________.

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CONCENTRATION of lead is decreased
lead SULPHATE concentration is increased
concentration of `H_(2)SO_(4)` is increased
concentration of `PbO_(2)` is decreased

Answer :C
11.

Draw the structure of XeF_2and XeO_3. Write their shapes and hybridisation.

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SOLUTION :
12.

During the reaction of Benzene diazonium chloride with para-cresol the substitution occurs at_____position of p-cresol.

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ANSWER :2
13.

Draw the structure of XeF_2 molecule.

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SOLUTION :The STRUCTURE of `XeF_2` is DRAWN as under :
14.

During the reaction of 2 -bromopentane with sodium ethoxide the correct statement is

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Trans-2-pentene is the MAJOR PRODUCT
1-pentene is the major product
cis-2-pentene is not the major product
All of the above

SOLUTION :All of them CORRECT
15.

Draw the structure of white phosphorus and red phosphorus. Which one of these two type of phosphorus, is more reactive and why? Or Which allotrope of phosphorus is more reactive and why? Or Why is red phosphorus less reactive than white phosphorus. Or Draw the structural difference between white and red phosphorus.

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Solution :Both white and red phosphorus consist of `P_(4)` tetrahedra. In white phosphorus, the various `P_(4)` molecules are held together by weak van der Waals FORCES of attraction. In each `P_(4)` molecule, the PPP ANGLE is only `60^(@)` which is much smaller than the normal tetrahedral angle of `109^(@)-28`'. As a result, there is considerable angle strain. Due to weaker forces of attraction and considerable angle strain, white PHOSPORUS is very reactive.
In contrast, in red phosphorus, these `P_(4)` tetrahedra are joined together through covalent bonds to GIVE polymeric structure
Since it is difficult to break strong covalent bonds as compared to weak van der Waals forces of attraction, therefore, white phosphorus is more reactive than red phosphorus.
16.

Draw the structure of the monomer for the following polymer : Polypropene.

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SOLUTION :`CH_(2)=CH-CH_(3)` (PROPENE).
17.

During the reaction of alcohols with KI, why sulphuric acid is not used?

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SOLUTION :In the conversion of alcohol to alkyl iodide, `H_(2)SO_(4)` cannot be used SINCE it converts KI to CORRESPONDING HI and then oxidises it to iodine.
18.

Draw the structure of the monomerof each of the followingpolymers : (i) Poly vinylchloride (PVC)(ii) Nylon 6.

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Solution :Structures of the MONOMERSOF twopolymers are GIVEN below:
(i) `underset("Vinyl chloride")(CH_(2)=CHCL)`
(ii)
19.

During the reaction : CH_(3) - C -= CH + H_(2) overset("Catalyst")rarr CH_(3) - CH = CH_(2) The catalyst is :

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Ni
`LiAlH_(4)`
Pt
Pd POISONED with `BaSO_(4)` and QUINOLINE

Answer :D
20.

Draw the structure of the semicarbazone of ethanal.

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SOLUTION :Reaction OCCURS through the more nucleophilic `NH_(2)` (ATTACHED to NH) and not through `NH_(2)` attached CO group. Thus,
`underset("Ethanol")(CH_(3)-CH=O)+underset("Semicarbozide")(H_(2)N NHCOCH_(2)) overset(pH" "3.5)to underset("ETHANAL semicarbazone")(CH_(3)-CH=N NHCOCH_(2))+H_(2)O`
21.

During the reaction, CH_(3)CONH_(2)overset(P_(2)O_(5))(to)CH_(3)CN. the hybridisation state of carbon changes from

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`SP^(3)` to `sp`
`sp^(3)` to `sp^(2)`
`sp^(2)` to `sp^(3)`
`sp^(2)` to `sp`.

ANSWER :D
22.

Draw the structure of the monomer for each of the following polymers: (i) Nylon 6 (ii) Polypropene

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Solution :(i) MONOMER of NYLON 6
(ii) Monomer of POLYPROPYLENE.
23.

During the race of complex compounds, finish line is fixed achieving EAN value equal to the atomic number of corresponding inert gas. Then which of the following complex is present at the finish line ?

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`[Co(NO_(2))_(6)]^(4-)`
`[MN(CO)_(5)]`
`K_(4)[Fe(CN)_(6)]`
`Fe_(3)[Fe(CN)_(6)]_(2)`

Solution :`K_(4)[Fe(CN)_(6)] IMPLIES 26-2+12=36`
24.

Draw the structure of thefollowingpolymers: (i) Polythene(ii) PVC (iii) Teflon.

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Solution :(i) Polythene .
Thestructure of the MONOMER ofpolythene is`underset("Ethene")(CH_(2) = CH_(2))`
(ii) PVC (POLYVINYL Chloride)
Thestructureof monomer of PVC is given below :
`underset("Vinly chloride")(CH_(2) = CH-Cl)`
(iii) Teflon
Thestructure of themonomer of teflonis :
`underset("Tetrafluoroethen")(CF_(2) = CF_(2))`
25.

Duringthe quation analysis of a mixturecontainingCu^(2+) and Zn^(2+) ions H_(2)S gas ispassed theroughan acidifiedsolutioncontainingthese ions in order to test Cu^(2+) aloneexplane

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SOLUTION :`H_(2)S hArr 2H^(o+) +S^(2-)`
`HCI rarr H +CI^(Theta)`
`K_(sp) `(SOLUBILITY product) of `CuS` is lessthan `K_(sp)` of `ZnS `.Due tocommonion EFFECT ,the ionisation of `H_(2)S` is sappressed and the `S^(2-)` concentration decreases
Onlythose metalsulphides getprecipitate whichhave low `K_(sp)` so ZnS is notprecipitate.
26.

Draw the structure of the following species BrO_4^(-).

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SOLUTION :
27.

During the process of electrolytic refining of copper, some metals present as impurity settle as "anode mud." These are ......

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`Sn and Ag`
`PB and ZN `
`Ag and AU `
`Fe and NI `

Answer :C
28.

During the process of electrolytic refining of copper some metals present as impurity settle as 'anode mud' . These are :

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SN and Ag
Pb and Zn
Ag and Au
Fe and Ni

Answer :C
29.

Draw the structure of the following molecules/ions XeOF_(4)

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30.

During the process of electrolytic refining of copper some metals present as impurity settle as 'anode mud'. These are

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Sn and Ag
Pb and ZN
Ag and Au
FE and Ni

Solution :In the electrolytic refining of copper the more electropositive like Fe, Zn , Ni , Co etc. DISSOLVE in the solution and less electropositive impuritis such as Ag, Au and Pt COLLECT below the anode in the form of ANODIC mud.
31.

Draw the structure of the following molecules/ions XeO_(3)

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32.

During the process of digestion, the proteins present in food materials are hydrolysed to amino acids. The two enzymes are involved in the process.Proteins overset(" Enzyme - A")rarr polypeptides overset(" Enzyme - B ")rarr amino acids are respectively.

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PEPSIN and trypsin
invertase and zymase
amylase and maltase
diastase and lipase

Answer :A
33.

Draw the structure of the following molecules/ions XeF_(5)^(+)

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34.

During the process of digestion, the proteins present in food materials are hydrolysed to amino acids. The two enzymes involved in the process are: overset("Enzyme (A)")(rarr) Polypeptides underset("Enzyme (B)")(rarr)Amino acids

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invertase and zymase
amylase and maltase
diastase and lipase
PEPSIN and TRYPSIN

Solution :Proteins `underset("proteases")overset("pepsin")to ` Polypeptides `underset("chemotrypsin")overset("trypsin")to ` AMINO ACIDS.
35.

Draw the structure of the following molecules/ions XeF_(4)

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36.

During the process of digestion, the proteins present in food materials are hydrolysed to amino acids. The two enzymes involved in the process Proteinsoverset("Enzyme(A)")to" Polypeptides" overset("Enzyme (B)")to Amino acids, are respectively.

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PEPSIN and TRYPSIN
INVERTASE and Zymase
Amylase and Maltase
Diastage and lipase

Answer :A
37.

Draw the structure of the following molecules/ions XeF_(5)^(-)

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38.

During the process of digestion, the proteins present in food materials are hydrolysed to amino acids. The two enzymes A and B, involved in the process proteins overset"Enzyme (A)"topolypeptides overset"Enzyme (B)"to amino acids, respectively are

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amylaseand maltase
diastase and lipase
pepsin and trypsin
invertase and zymase

Solution :In the process of DIGESTION , the proteins PRESENT in food material are HYDROLYSED to amino acid . In this process, two enzymes pepsin and trypsin are involved as FOLLOWS
Protein `underset"(ENZYME A)"overset"Pepsin"to` Polypeptide `underset"(Enzyme B)"overset"Trypsin"to` Amino acid
39.

Draw the structure of the following molecules/ions SO_(4)^(2-)

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40.

During the preparation of glucose from starch chalk powder is added to the reaction mixture to_______.

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accelerate the RATE of reaction
decolourise the filtrate
neutralise excess of SULPHURIC acid
obtain CRYSTALS of glucose

Answer :C
41.

Draw the structure of the following molecules/ions SO_(3)^(2-)

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42.

During the preparation of colloidal sol by Bredig's are method , traces of alkali (NaOH " or " Na_2CO_3) is added to

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Homogenise the SOL
STABILIZE the sol
act as peptizing agentact
act as COAGULATING agent

ANSWER :B
43.

Draw the structure of the following molecules/ions XeF_(2)

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44.

Draw the structure of the following molecules/ions SnCl^(-)

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45.

During the preparation of arenediazonium salts, the excess of nitrous acid, if any, is destroyed by adding

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Aq. NaOH
Aq. `Na_(2)CO_(3)`
Aq. `NH_(2)CONH_(2)`
Aq. KI

Solution :Urea decompoes `HNO_(2)` to `N_(2),CO_(2)` and `H_(2)O`
`NH_(2)CONH_(2)+2HONO to 2N_(2) UARR +CO_(2) uarr+3H_(2)O`
46.

Draw the structure of the following molecules/ions SF_(4)

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47.

During the preparation of alkanes by Kolbe's electrolytic decarboxylatio of CH_3CH_2COONa , which of the following products are formed

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`CH_3CH_2CH_2CH_3`
`CH_2=CH_2`
`CH_4`
`CH_3CH_2OH`

Solution :The mechanism of KOLBE's electrolytic decarboxylation is as follows
`CH_3CH_2COONa to CH_3 CH_2COO^(-) + Na^(+)`
`H_2O to H^(+) + OH^(-)`
At anode as discharge POTENTIAL of `CH_3CH_2COO^-` is less than discharge potential of `OH^-`, HENCE discharging of `CH_3CH_2COO^-` TAKES place.
`CH_2CH_2-undersetunderset(O)(||)C-underset(ddot)overset(theta)O: to CH_3CH_2-undersetunderset(O)(||)C-overset(dot)O+e^-`
`CH_3CH_2-undersetunderset(O)(||)C-overset(dot)O to CH_3overset(dot)CH_2+CO_2`
`CH_3overset(dot)CH_2+overset(dot)CH_3 to CH_3CH_2CH_2CH_3`
`CH_3 overset(dot)CH_2 to CH_2=CH_2+overset(dot)H`
`CH_3overset(dot)CH_2+overset(dot)H to CH_3CH_3`
`CH_3CH_2-undersetunderset(O)(||)C-overset(dot)O -overset(dot)O + .^(dot)CH_2CH_3 to CH_3CH_2-undersetunderset(O)(||)C=O-CH_2-CH_3`
`CH_3CH_2-undersetunderset(O)(||)C-OCH_2CH_3 overset(OH^-)to CH_3CH_2COO^(-) + CH_3CH_2OH`
Hence , the various products formed at anode are `CH_3CH_2CH_2CH_3,CH_2=CH_2, CH_3CH_3 & CH_3CH_2OH`.
Hence, (a),(b), ( d) are correct while ( c) is INCORRECT.
48.

Draw the structure of the following molecules/ions SF_(6)

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49.

During the perparation of H_(2)S_(2)O_(s) (per disulphuric acid) O_(2) gas is also released at anode as byproduct. When 9.72 L of H_(2) releaseds at cathode and 2.35 L O_(2) at anode the weight H_(2)S_(2)O_(8) depostited at the cathode is .

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` 87. 12`
` 48. 65`
` 83. 42`
` 51. 74`

SOLUTION :` 2HSO_4^(-) RARR H_2S_2O_8 +2E`
` 20^(2-) rarr O_2 +4e`
`(2.35)/(22.5) =0. 105 0.42 mole`
`H^+ + 2e rarr H_2`
Mole of e for ` H_2 S_2O_8 =0. 87 - 0. 42 =0. 45 ` mole
` :.` Mole of ` H_2 S_2 OO_8 =0. 225"mole" = 43. 65 g`.
50.

Draw the structure of the following molecules/ions SF_(2)

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