Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

{:("Column "1,"Column "2),((A)"Soap in water",P. "Associated colloid"),((B)"Starch gelatin",Q. "Lyoptrilic colloid" ),((C) "Gold sol" ,R."Collodion"),((D)"Cellulose nitrate in alcohol",S. "Lyophobic colloid "):}

Answer»

A-R, B-S, C-Q, D-P
A-P, B-Q, C-S, D-R
A-R, B-S, C-P, D-Q
A-P, B-Q, C-R, D-S

Answer :B
2.

Colourless transition metal ion is:

Answer»

`ZN^(2+)`
`Cu^+`
`Ti^(3+)`
`All`

ANSWER :D
3.

Colourless solutions of the following four salts are placed separately in four different test tubes and a strip of copper is dipped in each one of these. Which solution will turn blue ?

Answer»

`KNO_3`
`AgNO_3`
`ZN(NO_3)_2`
`ZnSO_4`

ANSWER :B
4.

Colourless solutions of the following four salts are placed separately in four different test tubes and a strip of copper is dipped in each one of these. Which solution turn blue.

Answer»

`KNO_3`
`AgNO_3`
`ZN(NO_3)_3`
`ZnSO_4`

ANSWER :B
5.

Colourless transition metal ion is

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`ZN^(2+)`
`TI^(3+)`
 `CR^(3+)`
`V^(2+)`

Answer :A
6.

Colourless solution of (A) gives while ppt (B) with AgNO_(3)soluble in aqueous NH_(3) (a) also while given ppt (C ) with NaOH soluble is extrable in excess of it forming (D),(D) gives ppt .(E) with H_(2)S identify (A),(B),(C ),(D) and (E ).

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SOLUTION :(A) `ZnCI_(2)` (B) `AgCI`
(C ) `ZN(OH)_(2)` (D) `NaZnO_(2)`
(E ) `ZNS`
7.

Colourless salt (X) overset(Delta) to (Y) overset(Cu^(2+),Delta) to colouredhead (Z) ,(X) can be

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BORAX
Microcostric salt
Copper sulphate
None of these

Answer :a,B
8.

Colourless salt (X) overset(Delta) to (Y) overset(Cu^(2+),Delta) tocoloured head (Z) (X) can be

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BORAX
MICRO cosamic SALT
both
none

Answer :C
9.

Colourless salt (A) gives apple- green flame with cone. HCI (A) on reaction with dil H_(2)SO_(4) give light brown flame (D) turning KI -strach paper blue. (A) + CH_(3)COOH + K_(2)CrO_(4) rarr yellow ppt(B) (A) + H_(2)SO_(4) rarr (C ) ("white ppt") + (D) (D) + CH_(3)NH_(2) + CH_(3)OH + H_(2)O + gas (E ) (E ) + Mg overset(Delta)to (F) (F) + H_(2)O rarr NH_(3) Identify (A) to (F) and explain reaction.

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Solution :(A) `BA(NO_(2))_(2)` (B) `BaCrO_(4)` (C ) `BaSO_(4)`
(D) `HNO_(2)` (E ) `N_(2)` (F)`Mg_(2)N_(2)`
10.

Colourless salt (A) overset(dil. HCI)rarr White ppt. (B) Iidentify (A),(B),(C ) and (D)

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Solution :(A) `PB(NO_(3))_(2)` (B) `PbCI_(2)`
(C ) `PbI_(2)`(D) `[FE(H_(2)O)_(3)NO]^(2+)`
11.

Coloured salts are formed by

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Alkali metals
Lanthanides
ACTINIDES
TRANSITION metals

Solution :Due to PRESENCE of vacant d-orbitals and they SHOW d-d transition.
12.

Coloured ion among the following is

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`Zn^(2+)`
`Mn^(2+)`
`CU^(1+)`
`TI^(4+)`

Solution :`Mn^(2+)`
13.

Coloured complexes absorb radiation in the

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VISIBLE REGION
INFRARED region
U.V. region
far IR region

Solution :visible region
14.

Colour of transition metal complexes can be explained by:

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COMPLETELY FILLED d-orbitals
Vacant d-orbitals
d-d transition
None

Answer :C
15.

Colouration of Br_(2)//C Cl_(4) will be discharged by

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Cinnamic acid<BR>Benzoic acid
o-phthalic acid
Acetophenone

Solution :Cinnamic acid reacts with bromine in carbon tetrachloride to give dibromocinnamic acid.
`C_(6)H_(5)CH=CHCOOH+Br_(2) overset(C Cl_(4))to UNDERSET("Dibromocinnamic acid")(C_(6)H_(5)-overset(Br)overset(|)(CH)-overset(Br)overset(|)(C)HCOOH)`
16.

Colour of Ti^(4+) (3d^(0)) metal ion is

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PURPLE.
BLUE.
green.
colourless.

ANSWER :D
17.

Colour of the Cu_(2)O is due to

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d-d TRANSITION
p-p transition
CHARGE TRANSFER
f-f transition

ANSWER :C
18.

Colour of solid zinc is __________.

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REDDISH brown
green
silvery white
bluish white

Answer :D
19.

The colour of iodine solution is discharged by shaking it with aqueous solution of:

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`H_2O_2`
SODIUM sulphide
Sodium thiosulphate
Sodium sulphate

Answer :C
20.

Colour of osazone of glucose is :

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Red
Brown
Yellow
Orange

Answer :C
21.

Colour of iodine solution is disappeared by shaking it with aqueous solution of

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`H_(2)SO_(4)`
`Na_(2)S`
`Na_(2)S_(2)O_(3)`
`Na_(2)SO_(4)`

SOLUTION :`2Na_(2)S_(2)O_(3) +I_(2) to 2NaI + Na_(2)S_(4) O_(6)`
22.

Colour of Cu_(2)O is due to

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d-d transition
CHARGE transfer
f-f transition
geometry of `Cu_(2)O`

ANSWER :B
23.

Colour of compounds occurs due to phenomenon of polarisation, charge transfer, d-d transitionand H.O.M.O.L.U.M.O transition. Most of the transition metal transition metal complex compound are coloured either due to d-d electrons transition or charge transfer and ionic compounds are coloured due to polarisation of anion. Q. Which of the following is correct about KFE^(II)[underset(II)(Fe)(CN_(6))] and KFE^(III)[underset(III)(Fe)(CN_(6))] complex compounds?

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Both are blue COLOURED compounds because colour arisesdue to d-d ELECTRONS transition in Fe cation present outside the complex ion.
Both are blue coloured compounds because colour arisesdue to transfer of electron between `Fe^(II) and FE^(III)` cation
Both are blue coloured compounds because in complexes `Fe^(II)` cation shows same d-d transition bond
Complex (I) has blue colour becouse (II) has BROWN colour

Answer :B
24.

Colour of compounds occurs due to phenomenon of polarisation, charge transfer, d-d transitionand H.O.M.O.L.U.M.O transition. Most of the transition metal transition metal complex compound are coloured either due to d-d electrons transition or charge transfer and ionic compounds are coloured due to polarisation of anion. Q. Choose incorrect statement.

Answer»

Halogens are coloured due to HOMO-LUMO TRANSITION
During charge TRANSFER, OXIDATION state of ATOMS changes
Higher the POLARISATION, more is colour intensity
Comple compound having no unpaired electron can not undergo d-d transition and therefore it is colourless

Answer :D
25.

Colour of compounds occurs due to phenomenon of polarisation, charge transfer, d-d transitionand H.O.M.O.L.U.M.O transition. Most of the transition metal transition metal complex compound are coloured either due to d-d electrons transition or charge transfer and ionic compounds are coloured due to polarisation of anion. Q. If MCl_(4) salt is white, then comment on colour of its iodine salt.

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Coloured
White
MAY be or coloured
Black

Answer :C
26.

Colour of cobalt chloride solution is

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PINK
Black
Colourless
Green

SOLUTION :`CoCl_(2)` solution is pink.
27.

Colour of bromine in CS_2 is:

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Green
Orange
Yellow
Red

Answer :A
28.

Colour is imparted to glass by mixing:

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SYNTHETIC dyes
Metal oxides
Oxides of non-metal
Coloured salt

Answer :B
29.

Colour is imparted to glass by mixing

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SYNTHETIC dyes
Metaloxide
Oxides of non-metal
Coloured salt

SOLUTION :Metal oxides or some salts are fused with GLASS to IMPARTED COLOUR of glass.
30.

Colour in transition metal compounds is due to

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small SIZED METAL ions
absorption of light in UV REGION
complete ns sub-shell
d-d transition

Answer :D
31.

Colour imparted by Co(II) compounds to glass is…..

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Green
Brown
Violet
Blue

Answer :D
32.

Colour in transition metal compounds is attributed to :

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Small SIZE metal IONS
ABSORPTION of LIGHT in the UV region
Complete ns-subshell
d-d transition

Answer :D
33.

Colour display in green houses can be made with discharge tubes. The gas that is very frequently used for the display is

Answer»

CHROMYL chloride
Neon
NITROUS OXIDE
Kerypton

ANSWER :B
34.

{:("Coloumn-I",,"Column-II"),("(Aqueous solution in standard condition)",,"(Product of electrolysis using inert electrode)"),((A)"KCl",,(P)"Metal discharged at cathode"),((B)H_(2)SO_(4),,(Q)H_(2) "discharged"),((C)CuSO_(4),,(R )O_(2)"discharged" ),((D)NaNO_(3),,(S)"Non- metal discharged at both electrodes"),(,,(T)"Net cell reaction is" :2H_(2)OrarrO_(2)+2H_(2) ):}

Answer»


ANSWER :(A)-(Q,S);(B)-(Q,R,S,T);(C )-(P,R);(D)-(Q,R,S,T)
35.

Colloids have many characterstic properites. Among these Tyndall effect is an optical property and coagulation is the process of setting of colloidal particles.What is Tyndall effect?

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ANSWER :The scattering of LIGHT by colloidal is known as TYNDALL effect.
36.

Colloids exhibit certain special properties Name the property of colloid involed in the construction of ultramicroscope.

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ANSWER :TYNDALL EFFECT
37.

Colloids exhibit certain special properties. Explain the above property.

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Answer :When a beam of light is PASSED through a colloidal solution, the path of the light beam becomes visible in the sol. This is DUE to scattering of light by COLLODIAL particles. This is CALLED Thndall EFFECT.
38.

Colloids are widely used in industry and in daily life. Write any four applications of colloids.

Answer»


ANSWER :REFER to SECTION 5.6
39.

Colloids are widely used in industry and in daily life. What are colloids?

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ANSWER :A colloid is a heterogeneous system in which the diameter of the PARTICLES of the disperse PHASE is between 1 and 1000 NM.
40.

Colloidal systems are

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Homogeneous
Heterogeneous
Suspensions
Transparent

Answer :B
41.

Colloidal system is free from which of the following effect?

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Effect of heat
Effect of applied electric field
Effect of ADDED electrolyte
Effect of GRAVITATIONAL 

SOLUTION :Effect of gravitational
42.

Colloidal sulphur is obtained when

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sulphur is HEATED GRADUALLY to high temperature
sulphur is heated with dilute sulphuric acid
hydrogen sulphide is passed through an AQUEOUS solution of nitric acid
sulphur is warned with carbon disulphide

Answer :C
43.

Colloidal sulphur is obtained by the action of HNO_3 on:

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`H_2S`
`HGS`
`CAS`
`CaS_2O_3`

ANSWER :A
44.

Colloidal sulphur is obtained by the action of HNO_(3) on _________.

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`H_(2)S`
`CaS_(2)`
`Na_(2)S_(2)O_(3)`
HgS

Answer :A
45.

Colloidal solutions of metals like gold can be prepared when their salt solutions react with certain substances like SnCl_(2) , formaldeyde, phenyl hydrazine , etc. 2AuCl_(3) + 3SnCl_(2) to 3SnCl_(4)+ underset("sol")(2Au)The above method is an example of

Answer»

reduction method
oxidation method
hydrolysis method
double decomposition method

Solution :Salt solution of gold is being REDUCED to gold by using a reducing AGENT LIKE `SnCl_(2)`
46.

Colloidal solutions of ink and graphite are prepared by ........... method.

Answer»

SOLUTION :mechanicaldispersion
47.

Colloidal solutions of metals like gold, silver and platinum are generally prepared by using:

Answer»

peptization
Bredig's are method
Exchange of solvent
Oxidation method

Answer :B
48.

Colloidal solution show Tyndall effect. Give two resasons.

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Solution :(i) The diameter of the dispersed particles is not much smalleer as COMPARED to the wavelength of light USED.
(ii0 There is a large DIFFERENCE in the REFRACTIVE indices of the dispersed phase and the dispersion medium.
49.

Colloidal solution of silver is prepared by

Answer»

BREDIG's are method
Peptization
Colloidal milk
Double DECOMPOSITION method

Answer :A
50.

Colloidal solution of silver is prepared by :

Answer»

COLLOIDAL milk
Double decomposition method
Bredig's method
Peptization

Solution :COLLIDAL sol of less REACTIVE mteal such as gold , silver platinum, copper, lead etc can be prepared by Bredig's method.