Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Among the following the one that gives positive iodoform test upon reaction with I_(2) and NaOH

Answer»

`PhCHOHCH_(3)`
`C_(6)H_(5)CH_(2)CH_(2)OH`
`CH_(3)CH_(2)CH(OH)CH_(2)CH_(3)`
`CH_(3)CH(CH_(3))CH_(2)OH`

ANSWER :A
Discussion
2.

Among the following the number of elements showing only one non-zero oxidation stateis O, Cl, F, N, P, Sn, Tl,Na, Ti

Answer»


Solution :Non-zero oxidation states of O are -1, -2, +1 and +2 , that of CL are -1, +1, +3, +5 and +7 , that of F is -1 and +1 , that of P is -3, -2, +1, +3 and +5 , that of Sn is +2 and +4 , that of TI is +1 and +3 , that of Na is +1 and that Ti is +2 and +4.
Thus, only Na can EXIST in one non-zero oxidation state.
Discussion
3.

Among the following the number of compounds which react with react will Fehling's solution is :

Answer»


SOLUTION :N//A
Discussion
4.

Among the following , the number of compounds that can react with SnS_(2), the total number of BLACK coloured sulphides is

Answer»


SOLUTION :Pbs,CuS,HGS,`Ag_(2)S`,NiS,CoS,`Bi_(2)S_(3)`, are black (7)
MnS: buff . Coloured., `SnS_(2)`: Yellow.
Discussion
5.

Among the following, the number of compounds that can react with PCl_(5) to give POCl_(3) is : O_(2), CO_(2), SO_(2), H_(2)O, H_(2)SO_(4), P_(4)O_(10).

Answer»

<P>

Solution :these are :
(i) `2 PCl_(5) + O_(2) OVERSET(Delta)rarr 2POCl_(3) + 2Cl_(2)" ,"`
(ii) `[PCl_(5) rarr PCl_(3) + Cl_(2)" ,"" "2PCl_(3) + O_(2) rarr 2 POCl_(3)]`
(iii) `PCl_(5) + SO_(2) rarr POCl_(3) + SOCl_(2)`
(iv) `PCl_(5) + H_(2)O rarr POCl_(3) + 2HCl" ,"`
`POCl_(3)` further reacts with `H_(2)O` to GIVE `H_(3)PO_(4)`
`POCl_(3) + 3 H_(2)O rarr H_(3)PO_(4) + 3 HCl`
(v) `2PCl_(5) + H_(2)SO_(4) rarr 2 POCl_(3) + SO_(2)Cl_(2)+2HCl`
(VI) `6PCl_(5) + P_(4)O_(10) rarr 10 POCl_(3)`
Discussion
6.

Among the following the number of compounds that can act as dehydrating agent are …… Conc. H_(2)SO_(4),"Anhyd". CaCl_(2),Conc. HNO_(3), CaO, CuSO_(4).5H_(2)O, P_(2)O_(5)

Answer»


ANSWER :4
Discussion
7.

Among the following, the number of alcohols showing iodoform test is CH_(3)OH,CH_(3)CH_(2)OH,(CH_(3))_(2)CHOH,(CH_(3))_(3)COH,CH_(3)CHOHCH_(2)OH,CH_(3)CH_(2)CH_(2)CH_(2)OH,CH_(3)CH_(2)CH_(2)OH,CH_(3)CHOHCH(CH_(3))_(2),(C_(2)H_(5))_(2)CHOH.

Answer»


SOLUTION :Four (4) alcohols which contain the grouping `CH_(3)CHOH-` and hence give IODOFORM test are: `CH_(3)CH_(2)OH,CH_(3)CHOHCH_(3),CH_(3)CHOHCH_(2)CH_(3), and CH_(3)CHOHCH(CH_(3))_(2)`.
Discussion
8.

Among the following, the narrow spectrum antibiotic is :

Answer»

PENICILLIN G
Ampicillin
Amoxycillin
Chloramphenicol 

ANSWER :A
Discussion
9.

Among the following, the non-spontaneous reaction is

Answer»

`ROH+R'MgX to R'H+Mg(OR)X`
`RONa+NH_(3) to NaNH_(2)+ROH`
`RON a+H_(2)O to NaOH+ROH`
`ROH+HC-=CN atoRON a+HC-=CH`

Solution :The ACID strength follows the order:
`ROH gt HC-=CH gt NH_(3)R'H`
THEREFORE, a weaker acid `(NH_(3))` cannot displace a STRONGER acid (ROH) from its salt (RONa). THUS, reaction (b) is non-spontaneous.
Discussion
10.

Among the following the most stable complex is

Answer»

`FE(H_2O_6)]^(3+)`
`[Fe(NH_3)_6]^(3+)`
`Fe(CN)_6]^(3-)`
`[Fe(C_2O_4)_3]^(3-)`

ANSWER :D
Discussion
11.

Among the following the most stable compound is

Answer»

cis - 1,2 - cyclohexanediol
trans - 1,2 - cyclohexanediol
cis - 1,3 - cyclohexanediol
trans - 1,3 - cyclohexanediol

Solution :Trans configuration is more stable than cis configuration because in cis-configuration the H groups are thrown CLOSELY ENOUGH together to cause crowding or REPULSION. Again between 1,2-and 1,3-configuration, 1-3, the OH groups are placed further apart to MINIMISE the repulsion. Hence, more stable is 1,3-configuration.
Discussion
12.

Among the following, the most reactive towards alcoholic KOH is :

Answer»

`CH_(2) = CHBR `<BR>`CH_(3)COCH_(2)CH_(2)Br`
`CH_(3)CH_(2)Br`
`CH_(3)CH_(2)CH_(2)Br`

ANSWER :D
Discussion
13.

Among the following, the molecule with the highest dipole moment is

Answer»

`CH_(3)Cl`
`CH_(2)Cl`
`CHCl_(3)`
`C Cl_(4)`

Solution :(a) `CH_(3)Cl` have one Cl atom which is more electronegative so it will have HIGHEST DIPOLE moment.
Discussion
14.

Among the following the maximum covalent character is shown by the compound :

Answer»

`AlCl_(3)`
`MgCl_(2)`
`FeCl_(2)`
`SnCl_(2)`

Solution :Greater charge and small size cation cause more polarization and therefore, more covalent CHARACTER for that compound.
Discussion
15.

The main reactions occurring in blast furnace during extraction of iron from haematite are i.Fe_(2)O_(3)+3COto2Fe+3CO_(2) ii.FeO+SiO_(2)toFeSiO_(3) iii. Fe_(2)O_(3)+3Cto2Fe+3CO iv.CaO+SiO_(2)toCaSiO_(3)

Answer»

i and ii
III and IV
ii and iii
i and iv.

Solution :(B,D)
Discussion
16.

Among the following the least thermally stable is :

Answer»

`K_(2)CO_(3)`
`Na_(2)CO_(3)`
`BaCO_(3)`
`Li_(2)CO_(3)`

ANSWER :D
Discussion
17.

Among the following, the least stable resonance structure is :

Answer»




ANSWER :A
Discussion
18.

Among the following the least stable resonance structre is

Answer»




Solution :Two positive CHARGES PRESENT at the adjacent place, elevates the ENERGY, THUS LOWERS the stability most.
Discussion
19.

Among the following, the ions having same magnetic moment are

Answer»

`[TI(H_(2)O)_(6)]^(3+)`
`[Sc(H_(2)O)_(6)]^(3+)`
`VO^(2+)`
`[MN(H_(2)O)_(6)]^(3+)`

Solution :Both have ONE unpaired ELECTRON only.
Discussion
20.

Among the following the intensive property is (properties are)

Answer»

MOLAR conductivity
ELECTROMOTIVE force
Resistance
Heatcapacity

Solution :Molar conductivity and electromotive force (EMF) are INTENSIVE properties as these are size independent.
Discussion
21.

Among the following, the intensive property is (are)

Answer»

MOLAR conductivity
electromotive force
resistance
heat capacity

Answer :A::B
Discussion
22.

Among the following, the INCORRECT statement about colloids is :

Answer»

They can scatter light
The osmotic PRESSURE of a colloidal solution is of higher ORDER than the true solution at the same concentration
The range of diameters of colloidal particles is between 1 and 1000 nm
They are larger than small molecules and have HIGH molar mass

Solution :The osmotic pressure of the colloidal solutions is generally LOWER than a true solution of same. Concentration due to CHANCES of association of the particles.
Discussion
23.

Among the following the incorrect statement is

Answer»

Density of crystals remains unaffected due to Frenkel defect.
In bee unit cell the void space is 32%.
Density of crystals decreases due to Schottky defect
Electrical conduc6vityofmetals increases with INCREASE in TEMPERATURE

Solution :The electrical resistance of metals DEPENDS upon temperature. Electrical resistance decreases with decrease in temperature and becomes zero near the absolute temperature. Material in this state is said to possess super conductivity
Discussion
24.

Among the following the heaviest subatomic particle is

Answer»

Electron
Neutron
Proton
Positron

Answer :B
Discussion
25.

Among the following, the group of molecules that undergoes rapid hydrolysis is

Answer»

`SF_(6), Al_(2)Cl_(6), SiMe_(4)`
`BCl_(3), SF_(6),SiCl_(4)`
`BCl_(3), SiCl_(4), PCl_(5)`
`SF_(6),Al_(2)Cl_(6),SiCl_(4)`

Answer :C
Discussion
26.

Among the following, the extensive variables are

Answer»

H (enthalpy)
P (PRESSURE)
E (internal energy)
V (VOLUME)

SOLUTION : H (enthalpy), E (internal energy) , V (volume)
Discussion
27.

Among the following, the false statement is :

Answer»

It is possible to CAUSE artificial rain by throwing electrified sand carrying charge opposite to the one on CLOUDS from an aeroplane.
Tyndall effect can be used to distinguish between a colloidal SOLUTION and a true solution.
Lyophilic sol can be coagulated by adding an electrolyte.
LATEX is a colloidal solution of rubber PARTICLES which are positively charged.

Solution :NA
Discussion
28.

Among the following, the essential amino acid is :

Answer»

Valine
ALANINE
SERINE
ASPARTIC ACID

Answer :A
Discussion
29.

Among the following the electron deficient compound is

Answer»

`BCl_(3)`
`"CCl"_(4)`
`PCl_(5)`
`BeCl_(2)`

Solution :In `BCl_(2)`, boron contains six electrons in its VALENCE shell so, it is capable to accommodate one PAIR of electrons. Hence it acts as Lewis acid or electron deficient (incomplete octate) compound. As we KNOW that Lewis acids are the substancehaving a tendency to accept a pair of electron.
Discussion
30.

Among the following, the correct statement is

Answer»

between `NH_3` and `PH_3, NH_3` is a BETTER electron donor BECAUSETHE LONE pairof electrons occupies sphericals-orbital and is less directional
between `NH_3 and PH_3,PH_3`is a betterelectron donorbecausethe lone pair of electrons occupies `sp^(3)`-orbital and is more directional
between `NH_3 and PH_3,NH_3` is a better electron donorbecause the lone pair of electrons occupies`sp^3`-orbitaland is more directional
between `NH_3 and PH_3, PH_3` is a betterelectron donorbecausethe lone pairof electrons occupiessphericals-orbitaland is less directional

Solution :`NH_(3)`is better electron donor because the lone pair of electrons occupies ` sp^(3)`-orbitaland is more directional .
Discussion
31.

Among the following , the correct statements (s) is (are)

Answer»

`Al(CH_(3))_(3)` has the three -centre two electrons bonds in its dimeric structure
The lewis acidity of `BCl_(3)` is GREATER than that `AlCl_(3)`
`AlCl_(3)` has the three-centre two electron bonds in the dimeric structure
`BH_(3)` has the three -centre two -electron bonds in the its dimeric structure

Solution :Structure of `Al_(2)(CH_(3))_(6)`

`rArr BCl_(3)` is STRONGER lewis acid due to small size of boron.
`rArr ` structure of `Al_2Cl_(6)`

`rArr` structure of `B_(2)H_(6)`
Discussion
32.

Among the following the correct order of acidity is

Answer»

`HClO_(2) LT HClO lt HClO_(3) lt HClO_(4)`
`HClO_(4) lt HClO_(2) lt HClO lt HClO_(3)`
`HClO_(3) lt HClO_(4) lt HClO_(2) lt HClO`
`HClO lt HClO_(2) lt HClO_(3) lt HClO_(4)`

ANSWER :B::C::D
Discussion
33.

Among thefollowing , the CORRECT statement is _________.

Answer»

between `NH_(3)` and `PH_(3), NH_(3)` is a better electron DONOR because the lone pair of electrons OCCUPIES shperical 's' orbital and it less directional
between `NH_(3)` and `PH_(3), NH_(3)` is a better electron donor because the lone pair of electrons occupies `sp^(3)` orbital and is more directional
between `NH_(3)` and `PH_(3), NH_(3)` is a better electron donor because the lone pair of electrons occupies `sp^(3)` orbital and is more directional .
between `NH_(3)` and `PH_(3), NH_(3)` is a betterelectron donor because the lone pair of electrons occupies spherical 's' orbital and is less directional.

Answer :C
Discussion
34.

Amongthe following , the correct order of acidity is -

Answer»

`HClO_(3) lt HClO_(4) lt HClO_(2) lt HCIO`
`HCIO lt HCIO_(2) lt HCIO_(3) lt HCIO_(4)`
`HCIO_(2) lt HCIO lt HCIO_(3) lt HCIO_(4)`
`HCIO_(4) lt HCIO_(2)lt HCIO_(3)`

ANSWER :C
Discussion
35.

Among the following, the correct order of acidity is :

Answer»

`HClO LT HClO_(2) lt HClO_(3) lt HClO_(4)`
`HClO_(2) lt HClO lt HClO_(3) lt HClO_(4)`
`HClO_(4) lt HClO_(2) lt HClO lt HClO_(3)`
`HClO_(3) lt HClO_(2) lt HClO_(2) lt HClO_(4)`

Solution :`underset(+1)underset(DARR)(HClO) lt underset(+3)underset(darr)(HClO_(2)) lt underset(+5)underset(darr)(HClO_(3)) lt underset(+7)underset(darr)(HClO_(4))`
Discussion
36.

Among the following the compound which has highest Boiling point is ?

Answer»




ANSWER :C
Discussion
37.

Among the following , the compound that undergoes nitration readily is

Answer»

BENZOIC acid
Toluene
Phenol
Nitrobenzene

Solution : PRESENCE of methyl group increases electron desnity at o- and p- positions. HENCE, it UNDERGOES nitration readily.
Discussion
38.

Among the following the compound that is both paramagnetic and colourless is….

Answer»

`K_(3)[Cu(CN)_(4)]`
`VOSO_(4)`
`K_(2)Cr_(2)O_(7)`
`(NH_(4))_(2)[TiCl_(6)]`

SOLUTION :`V^(4+)` has one UNPAIRED electron. And so it is paramagnetic
Discussion
39.

Among the following the compound that is both paramagnetic and coloured is:

Answer»

`K_2Cr_2O_`
`(NH_4)_2[TiCl_6]`
`VOSO_4`
`K_2[CU(CN)_4]`

ANSWER :C
Discussion
40.

Among the following, the compound that contains ionic, covalent and coordinate linkage is :

Answer»

`NH_(4)Cl`
NaCl
CAO
`NH_(3)`

Answer :A
Discussion
41.

Among the following, the compound that contains ionic, covalent and co-ordinate linkage is

Answer»

`NH_(4)CL`
NACL
CAO
`NH_(3)`

Solution :`[H-overset(H)overset("|")underset(H)underset("|")(N)to H]^(+)Cl^(-)`
Discussion
42.

Among the following the coloured compound is

Answer»

`CuCl`
`K_(3)[CU(CN)_(4)]`
`CUF_(2)`
 `[Cu(CH_(3)(CN)_(4)]BF_(4)`

Solution :In the CRYSTALLINE FORM `CuF_(2)` is blue coloured. Hence, (C) is the correct answer.
Discussion
43.

Among the following the chelate complexes are

Answer»

BIS (dimethyl glyoximate) nickel (II)
Potassium ethylenediaminetetracyanato chromate (III)
Tetrammine dicyanato coball (III) nitrate
Trans-diglycinato palladium (II)

Solution :en, gly, DMG, `EDTA^(4-)` etc., can form chelate complexes
Discussion
44.

Among the following, the chiral complex is :

Answer»

`[Cr(OX)_(3)]^(3-)`
`CIS-[PtCl_(2)(en)]`
`cis-[RhCl_(2)(NH_(3))_(4)]^(+)`
`TRANS-[PtCl_(2)(en)]`

Answer :A
Discussion
45.

Among the following, the branched chain polymer is

Answer»

POLYVINYL chloride
Bakelite
LOW DENSITY polythene
High densitypolythene

Solution :Low density polythene is obtained through free radical addition and hydrogen atom abstraction and hence has a highly BRANCHED structure.
Discussion
46.

Among the following the basic amino acid is

Answer»

Glycine
Argenine
Proline
CYSTEINE 

ANSWER :B
Discussion
47.

Among the following, the azeotropic mixture is:

Answer»

`"CC"l_(4)+CHCl_(3)`
`C_(6)H_(14)+C_(7)H_(16)`
`C_(2)H_(5)Br+C_(2)H_(5)Cl`
chlorobenzene + bromobenzene

Solution :`CHCl_(3)` and `"CC"l_(4)` form non-ideal SOLUTIONS HENCE, mixture is azeotropic.
Discussion
48.

Among the following, the alkene on ozonolysis giving rise to only one aldehyde as the product is :

Answer»

1-Butene
PROPANE
2-Butene
2-Methylprop-1-ene

SOLUTION :
Discussion
49.

Amongthe followingthe achiral amionacids is ……….

Answer»

2 - ethylalanime
2-methylglycine
2-hydroxymethylserine
TRYPTOPHAN

ANSWER :C
Discussion
50.

Among the following, the achiral amino acids is

Answer»

2-ethylalanine
2-methylglycine
2-hydroxymethyl SERINE
Tryptophan

Answer :C
Discussion