Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

A binary solid (A+B-) has a zinc blend structure with B- ion constituting the lattice and A+ion occupying the 25% tetrahedral voids. The formula of solid is _________

Answer»

A binary solid (A+B-) has a zinc blend structure with B- ion constituting the lattice and A+ion occupying the 25% tetrahedral voids. The formula of solid is _________

2.

What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?(a)(b)(c)

Answer»

What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?


(a)



(b)



(c)


3.

Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.

Answer»

Define
the term solution. How many types of solutions are formed? Write
briefly about each type with an example.

4.

GIVE THE IUPAC NAME : 1) CH3-CH (CH3)-CH2-CH(CH2-CH3)-COOH 2)CH3-CH(CH3)-CH2-CONH2 3)CH3-CH2-CH2-NH2

Answer» GIVE THE IUPAC NAME :
1) CH3-CH (CH3)-CH2-CH(CH2-CH3)-COOH
2)CH3-CH(CH3)-CH2-CONH2
3)CH3-CH2-CH2-NH2
5.

What is the structure of 2,3,4 trichloro methyl pen†an e?

Answer» What is the structure of 2,3,4 trichloro methyl pen†an e?
6.

20.4:4 Co-ordination is found in (1)ZnS (2)CuCl (3)AgI (4)All

Answer» 20.4:4 Co-ordination is found in (1)ZnS (2)CuCl (3)AgI (4)All
7.

Mendeleev’s periodic law states that the properties of elements are a periodic function of their

Answer»

Mendeleev’s periodic law states that the properties of elements are a periodic function of their


8.

The ether which is not cleaved by HI even at 525 K Options: C6H5OCH3 C6H5OC3H7 CH3–O–CH3

Answer» The ether which is not cleaved by HI even at 525 K
Options:

C6H5OCH3

C6H5OC3H7



CH3–O–CH3
9.

When particle enter uniform magnetic field at an angle alpha and return back at an angle beta then how could we define that path follows by negative charge particle is circular

Answer» When particle enter uniform magnetic field at an angle alpha and return back at an angle beta then how could we define that path follows by negative charge particle is circular
10.

Very pure hydrogen (99.9%) can be made by which of the following processes?

Answer» Very pure hydrogen (99.9%) can be made by which of the following processes?
11.

a car 2m long travelling at 30m/s overtakes another car 4m long travelling at 20m/s.the time taken by the first car to pass the second car is

Answer» a car 2m long travelling at 30m/s overtakes another car 4m long travelling at 20m/s.the time taken by the first car to pass the second car is
12.

Markovnikov's rule is applicable toCh2=ch2Ch3-ch2-ch3Ch3-ch=ch-ch3(Ch3) 2-c=c-(ch3) (c2h5)

Answer» Markovnikov's rule is applicable to
Ch2=ch2
Ch3-ch2-ch3
Ch3-ch=ch-ch3
(Ch3) 2-c=c-(ch3) (c2h5)
13.

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60×10−19C )

Answer»

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60×1019C )

14.

The diffusion current in a P-N junction is-

Answer»

The diffusion current in a P-N junction is-


15.

What will be the major product when Ph – Ph is mononitrated?

Answer»

What will be the major product when Ph – Ph is mononitrated?



16.

Half of the ring is uniformly positively charged and other half uniformly negatively charged. What is the electric field on the axis due to the ring.

Answer» Half of the ring is uniformly positively charged and other half uniformly negatively charged. What is the electric field on the axis due to the ring.
17.

Find the value of x in the equation xx−a+xx−b=2.

Answer» Find the value of x in the equation xxa+xxb=2.
18.

ntDelocalised molecular orbits are found inn nt1-H2n nt2-HS-n nt3-CH4n nt4-CO3-2n

Answer» ntDelocalised molecular orbits are found inn nt1-H2n nt2-HS-n nt3-CH4n nt4-CO3-2n
19.

Identify the correct order of acidic strength of CO2, CuO, CaO and H2O.

Answer»

Identify the correct order of acidic strength of CO2, CuO, CaO and H2O.


20.

6. What are Lossen rearrangement & Curtius reaction & their mechanism?

Answer» 6. What are Lossen rearrangement & Curtius reaction & their mechanism?
21.

25. How to calculate equivalent weight of acids? Give me all formulas and step by step explanation

Answer» 25. How to calculate equivalent weight of acids? Give me all formulas and step by step explanation
22.

Choose the correct relation for boiling point elevation constant (Kb)where :Tb is boiling point of pure solvent M is molar mass of the solventLvap is the molar enthalpy of vapourisation per gram of the solvent R is ideal gas constant(All quantities to be taken in SI units)

Answer»

Choose the correct relation for boiling point elevation constant (Kb)

where :



Tb is boiling point of pure solvent

M is molar mass of the solvent

Lvap is the molar enthalpy of vapourisation per gram of the solvent

R is ideal gas constant

(All quantities to be taken in SI units)


23.

17. The value of activation energy of a chemical reaction primarily depend on 1. Temperature 2. Nature of reacting species 3. Collision frequency 4. Concentration of reactants

Answer» 17. The value of activation energy of a chemical reaction primarily depend on 1. Temperature 2. Nature of reacting species 3. Collision frequency 4. Concentration of reactants
24.

If the threshold wavelength (λ0) for the ejection of an electron from a metal is 110 nm, then the work function for the photoelectric emission is: (Planck's constant (h) = 6.6×10−341.8×10−18 J s)

Answer»

If the threshold wavelength (λ0) for the ejection of an electron from a metal is 110 nm, then the work function for the photoelectric emission is:
(Planck's constant (h) = 6.6×10341.8×1018 J s)

25.

Which of the following reactions of glucose can be explained only by its cyclic structure? (a) Glucose forms pentaacetate (b) Blucose reacts with hydoxylamine to form an oxime (c) Pentaacetate of glucose does not reach with hydroxyl amine (d) Glucose is oxidised by nitric acid to gluconic acid

Answer»

Which of the following reactions of glucose can be explained only by its cyclic structure?
(a) Glucose forms pentaacetate
(b) Blucose reacts with hydoxylamine to form an oxime
(c) Pentaacetate of glucose does not reach with hydroxyl amine
(d) Glucose is oxidised by nitric acid to gluconic acid

26.

White phosphorous reacts with Sodium Hydroxide solution and disproportionates into Sodium ___ and ___ gas.

Answer»

White phosphorous reacts with Sodium Hydroxide solution and disproportionates into Sodium ___ and ___ gas.



27.

Select the in correct statement regarding resonatingstructures(1) Have same number of paired and unpairedelectrons(2) Have identical electronic arrangements(3) Have identical arrangements of all of the atoms(4) Have nearly same energies

Answer» Select the in correct statement regarding resonatingstructures(1) Have same number of paired and unpairedelectrons(2) Have identical electronic arrangements(3) Have identical arrangements of all of the atoms(4) Have nearly same energies
28.

2.Is Gold Amphoteric oxides?

Answer» 2.Is Gold Amphoteric oxides?
29.

Which compound is prepared by the following reaction?Xe (g)+2F2 (g)Ni vessel−−−−−−−−−→873 K, 6−7 atm

Answer»

Which compound is prepared by the following reaction?

Xe (g)+2F2 (g)Ni vessel−−−−−−−−873 K, 67 atm

30.

If half life period for a first order reaction is 2 hrs than find out time taken for 100 % completion .

Answer» If half life period for a first order reaction is 2 hrs than find out time taken for 100 % completion .
31.

Introduction of a methyl group in ammonia markedly increases the basic strength of ammonia in aq. solution, introduction of the second methyl group increases only marginally the basic strength of methyl amine in water. This is due to.

Answer»

Introduction of a methyl group in ammonia markedly increases the basic strength of ammonia in aq. solution, introduction of the second methyl group increases only marginally the basic strength of methyl amine in water. This is due to.



32.

The tendency of BF3,BCl3 and BBr3 to behave as Lewis acid decreases in the sequence

Answer»

The tendency of BF3,BCl3 and BBr3 to behave as Lewis acid decreases in the sequence

33.

To synthesize the given compound via an SN2 reaction, themost appropriate combination is:

Answer»

To synthesize the given compound via an SN2 reaction, themost appropriate combination is:


34.

In the following sequence of reactions,The compounds B and C respectively are :

Answer»

In the following sequence of reactions,



The compounds B and C respectively are :

35.

In a body centred unit cell, the particles are present at

Answer»

In a body centred unit cell, the particles are present at


36.

The strongest base in aqueous solution among the followingamines is(1) N-N-diethylethanamine(2)N-ethylethanamine (3)N-methylmethanamine (4)phenylmethanamine Aid with explanatio

Answer» The strongest base in aqueous solution among the followingamines is(1) N-N-diethylethanamine(2)N-ethylethanamine (3)N-methylmethanamine (4)phenylmethanamine Aid with explanatio
37.

A metal M readily forms water soluble MSO4. It also forms oxide MO which becomes inert on heating. Hydroxide M(OH)2 is insoluble in water but soluble in NaOH solution. What is M ?

Answer»

A metal M readily forms water soluble MSO4. It also forms oxide MO which becomes inert on heating. Hydroxide M(OH)2 is insoluble in water but soluble in NaOH solution. What is M ?

38.

The product (B) is:

Answer»
The product (B) is:
39.

what does 'two electron three center bond ' in structure of diborane mean ? Explai

Answer» what does 'two electron three center bond ' in structure of diborane mean ? Explai
40.

why N(SiH)3 is planar?

Answer» why N(SiH)3 is planar?
41.

What is heat of atomisation?

Answer» What is heat of atomisation?
42.

Calculate the molarity of water at 4∘C.Given: Density of water at 4∘C=1g mL−1

Answer»

Calculate the molarity of water at 4C.

Given: Density of water at 4C=1g mL1

43.

To prepare tert-butyl ethyl ether, the reagents required are:

Answer»

To prepare tert-butyl ethyl ether, the reagents required are:


44.

The boiling point of 1M aqueous solution of KNO3 is n nt1. 105.26 degree centigrade n nt2. 101.04 degree centigrade

Answer» The boiling point of 1M aqueous solution of KNO3 is n nt1. 105.26 degree centigrade n nt2. 101.04 degree centigrade
45.

percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. =78.4)then minimum molecular weight of peroxidase anhydrous enzyme is what??

Answer» percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. =78.4)then minimum molecular weight of peroxidase anhydrous enzyme is what??
46.

A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x×10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume : KMnO4 reacts only with Fe2+ in the solutionUse : Molar mass of iron as 56 g mol−1 )The value of y is .

Answer» A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x×102 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.

(Assume : KMnO4 reacts only with Fe2+ in the solution

Use : Molar mass of iron as 56 g mol1 )



The value of y is .
47.

How many moles of hydrogen are present in 20g of 85% pure NaHCO3.

Answer»

How many moles of hydrogen are present in 20g of 85% pure NaHCO3.


48.

16. If the volume of closed vessel in which the following simple reaction is carried out is reduced to one third of original volume the rate of the reaction becomes 2NO + O2 - 2NO2 1. One third 2. Three times 3. Nine times 4. Twenty seven times

Answer» 16. If the volume of closed vessel in which the following simple reaction is carried out is reduced to one third of original volume the rate of the reaction becomes 2NO + O2 - 2NO2 1. One third 2. Three times 3. Nine times 4. Twenty seven times
49.

Meaning of free electrons

Answer» Meaning of free electrons
50.

Those collisions which lead to the formation of products are called as:

Answer»

Those collisions which lead to the formation of products are called as: