This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the solubility of Al(OH)3, (Ksp=1×10−33) in a buffer solution having pH=4? |
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Answer» What is the solubility of Al(OH)3, (Ksp=1×10−33) in a buffer solution having pH=4? |
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| 2. |
Which of the following oxyacids of Sulphur have a peroxy –O–O– linkage? |
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Answer» Which of the following oxyacids of Sulphur have a peroxy –O–O– linkage? |
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| 3. |
Calculate free energy change for the following reaction at 298 K: 2NO(g)+Br2(l)→2NOBr(g) Given the partial pressure of NO is 0.1 atm and the partial pressure of NOBr is 2.0 atm and ΔG0f NOBr=82.4 kJ mol−1,ΔG0NO=86.55 kJ mol−1 |
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Answer» Calculate free energy change for the following reaction at 298 K: |
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| 4. |
Which of the following does not decolourise iodine? |
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Answer» Which of the following does not decolourise iodine? |
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| 5. |
Picric acid is[CPMT 1971, 80, 81; DPMT 1983;MP PMT 1990; BHU 1996] |
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Answer» Picric acid is[CPMT 1971, 80, 81; DPMT 1983;MP PMT 1990; BHU 1996] |
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| 6. |
Which of the following is the correct order of bond angle magnitudes? |
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Answer» Which of the following is the correct order of bond angle magnitudes? |
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| 7. |
The tendency to lose f electrons is more in actinide as compared to lanthanides. Give reason. |
| Answer» The tendency to lose f electrons is more in actinide as compared to lanthanides. Give reason. | |
| 8. |
The structural formula for Phosphinic acid is: |
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Answer» The structural formula for Phosphinic acid is: |
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| 9. |
Show that MPC + MPS = 1. |
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Answer» Show that MPC + MPS = 1. |
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| 10. |
In the Oswald process, Ammonia is catalytically oxidized to : |
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Answer» In the Oswald process, Ammonia is catalytically oxidized to : |
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| 11. |
The stability fo peroxide and superoxide of alkali metals increase as we go down to group. Explain giving reason. |
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Answer» The stability fo peroxide and superoxide of alkali metals increase as we go down to group. Explain giving reason. |
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| 12. |
Identify the compound Y in the following reaction. |
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Answer» Identify the compound Y in the following reaction.
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| 13. |
sp2 hybridization is shown by: |
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Answer» sp2 hybridization is shown by: |
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| 14. |
For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. |
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Answer» For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. |
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| 15. |
X will be: |
Answer» X will be: |
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| 16. |
For the reaction: 4NH3(g)+3O2(g)→2N2(g)+6H2O(l) at 298 K. Given that heat of formation of NH3(g) and H2O(l) are −46 kJ mol−1 and −286 kJ mol−1 respectively. Calculate heat of reaction at 298 K. |
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Answer» For the reaction: |
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| 17. |
Which has highest melting point |
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Answer» Which has highest melting point
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| 18. |
The charge/ size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, K+,Ca2+,Mg2+,Be2+ |
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Answer» The charge/ size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, K+,Ca2+,Mg2+,Be2+ |
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| 19. |
The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be: |
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Answer» The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be: |
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| 20. |
Two metallic oxides contain 27.6 % and 30 % oxygen respectively. If the formula of the first oxide is X3O4, what will be the formula of the second oxide? |
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Answer» Two metallic oxides contain 27.6 % and 30 % oxygen respectively. If the formula of the first oxide is X3O4, what will be the formula of the second oxide? |
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| 21. |
Mention the factors that affect the rate of a chemical reaction. |
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Answer» Mention the factors that affect the rate of a chemical reaction. |
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| 22. |
Acidity increases in the order |
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Answer» Acidity increases in the order |
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| 23. |
In a particular experiment, 310 g of phosphorous (P4) reacted with excess of oxygen to form P4O10 in 75% yield. Then P4O10 formed reacted with 54 g of water to give H3PO4. Amount of H3PO4 obtained (in gm) is : (Consider only two places after decimal for calculation) |
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Answer» In a particular experiment, 310 g of phosphorous (P4) reacted with excess of oxygen to form P4O10 in 75% yield. Then P4O10 formed reacted with 54 g of water to give H3PO4. Amount of H3PO4 obtained (in gm) is : (Consider only two places after decimal for calculation) |
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| 24. |
Potassium manganate (K2MnO4) is formed when: |
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Answer» Potassium manganate (K2MnO4) is formed when: |
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| 25. |
The atomic weight of Al is 27. When a current of 5 Faradays is passed through a solution of Al+3ions, the weight of Al deposited is |
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Answer» The atomic weight of Al is 27. When a current of 5 Faradays is passed through a solution of Al+3ions, the weight of Al deposited is |
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| 26. |
Three samples of the same gas A, B and C(γ=32) have initially equal volume. Now the volume of each sample is doubled. The process is adiabatic for A isobaric for B and isothermal for C. If the final pressures are equal for all three samples, the ratio of their initial pressures are |
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Answer» Three samples of the same gas A, B and C(γ=32) have initially equal volume. Now the volume of each sample is doubled. The process is adiabatic for A isobaric for B and isothermal for C. If the final pressures are equal for all three samples, the ratio of their initial pressures are |
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| 27. |
The percentage composition in a sample of CaCO3 is given as: Ca=40%;C=12%;O=48%. What will be the weight of Ca in 4 g of a sample of CaCO3 obtained from another source, if the law of constant proportions is true? |
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Answer» The percentage composition in a sample of CaCO3 is given as: Ca=40%;C=12%;O=48%. What will be the weight of Ca in 4 g of a sample of CaCO3 obtained from another source, if the law of constant proportions is true? |
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| 28. |
There are 10 identical containers of volume V, each of them have an ideal gas at a same temperature T. The first container has a pressure of 1 atm, the second one has a pressure of 2 atm, the third has a pressure of 3 atm and so on. The tenth container has a pressure of 10 atm. If all the 10 containers are connected by thin tubes, then what will be the final pressure (in atm)? |
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Answer» There are 10 identical containers of volume V, each of them have an ideal gas at a same temperature T. The first container has a pressure of 1 atm, the second one has a pressure of 2 atm, the third has a pressure of 3 atm and so on. The tenth container has a pressure of 10 atm. If all the 10 containers are connected by thin tubes, then what will be the final pressure (in atm)? |
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| 29. |
If Avogadro's number is A0, the number of sulphur atoms present in 200 mL of 1N H2SO4 is |
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Answer» If Avogadro's number is A0, the number of sulphur atoms present in 200 mL of 1N H2SO4 is |
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| 30. |
Xenon hexafluoride reacts with silica. How many orbitals are involved in the hybridisation of the xenon compound formed? |
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Answer» Xenon hexafluoride reacts with silica. How many orbitals are involved in the hybridisation of the xenon compound formed? |
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| 31. |
For an electron in the nth Bohr orbit of hydrogen atom, what will be the ratio of radius of orbit to its de-Broglie wavelength |
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Answer» For an electron in the nth Bohr orbit of hydrogen atom, what will be the ratio of radius of orbit to its de-Broglie wavelength |
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| 32. |
The molar solubility of Cd(OH)2 is 1.84×10−5M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH=12 is: |
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Answer» The molar solubility of Cd(OH)2 is 1.84×10−5M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH=12 is: |
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| 33. |
A solution of Sodium Hydroxide (NaOH) has a pH of 9. What will be the concentration of OH− ions? |
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Answer» A solution of Sodium Hydroxide (NaOH) has a pH of 9. What will be the concentration of OH− ions? |
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| 34. |
Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression? |
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Answer» Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression? |
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| 35. |
Write the structures of fragments produced on complete hydrolysis of DNA. How are they linked in DNA molecule? Draw a diagram to show pairing of nucleotide bases in double helix of DNA. |
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Answer» Write the structures of fragments produced on complete hydrolysis of DNA. How are they linked in DNA molecule? Draw a diagram to show pairing of nucleotide bases in double helix of DNA. |
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| 36. |
For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained. Calculate the rate constant. t(s)p(mm of Hg)035.036054.072063.0 |
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Answer» For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained. Calculate the rate constant. |
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| 37. |
An element X (Atomic mass = 25) exists as X4 in benzene. 51 g of saturated solution of X in benzene was added to 50.0 g of pure benzene. The resulting solution showed a depression in freezing point of 0.55 K. The solubility (in g) of X per 100 g of benzene is: (Kf for benzene=5.5 K kg mol–1) (Assume 100% association takes place.) |
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Answer» An element X (Atomic mass = 25) exists as X4 in benzene. 51 g of saturated solution of X in benzene was added to 50.0 g of pure benzene. The resulting solution showed a depression in freezing point of 0.55 K. The solubility (in g) of X per 100 g of benzene is: (Kf for benzene=5.5 K kg mol–1) (Assume 100% association takes place.) |
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| 38. |
Calculate the maximum kinetic energy of photoelectrons emitted when a light of frequency 2×1016 Hz is irradiated on a metal surface with threshold frequency (νo) equal to 8.68×1015 Hz |
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Answer» Calculate the maximum kinetic energy of photoelectrons emitted when a light of frequency 2×1016 Hz is irradiated on a metal surface with threshold frequency (νo) equal to 8.68×1015 Hz |
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| 39. |
P can not be: |
Answer» ![]() P can not be: |
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| 40. |
The following reaction occurs at 500 K. Arrange them in the order of increasing tendency to proceed to completion. (I) H2(g)+I2(g)⇌2HI(g); Kc=1.8×10−3 (II) N2O4⇌2NO2(g); Kc=3×10−3 (III) PCl5(g)⇌PCl3(g)+Cl2(g); Kc=1.3×10−4 (IV) 2SO3(g)⇌2SO2(g)+O2(g); Kc=1.3×10−5 |
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Answer» The following reaction occurs at 500 K. Arrange them in the order of increasing tendency to proceed to completion. |
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| 41. |
The correct order of boiling points of boron trihalides is: |
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Answer» The correct order of boiling points of boron trihalides is: |
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| 42. |
The reaction given below is a balanced reaction where a, b, c, d, e, f and g are the stoichiometric coefficients. aHgS+bHCl+cHNO3→dH2HgCl4+eNO+fS+gH2O Find a+b+c+d+e+f+g |
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Answer» The reaction given below is a balanced reaction where a, b, c, d, e, f and g are the stoichiometric coefficients. aHgS+bHCl+cHNO3→dH2HgCl4+eNO+fS+gH2O Find a+b+c+d+e+f+g |
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| 43. |
Pick out the pair of mesomeric forms : |
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Answer» Pick out the pair of mesomeric forms : |
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| 44. |
Two moles of helium gas undergoes a cyclic process, shown in figure. Assume the gas is ideal. The corresponding p-V diagram is best represented by |
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Answer» Two moles of helium gas undergoes a cyclic process, shown in figure. Assume the gas is ideal. The corresponding p-V diagram is best represented by |
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| 45. |
The ratio of Kinetic energy to the total energy of an electron in Bohr orbit is |
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Answer» The ratio of Kinetic energy to the total energy of an electron in Bohr orbit is |
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| 46. |
The number of moles of CH4 gas formed in the reaction are |
Answer» The number of moles of CH4 gas formed in the reaction are![]() |
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| 47. |
Which of the following pairs are isostructural? |
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Answer» Which of the following pairs are isostructural? |
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| 48. |
A dilute solution Contains “x” moles of solute “A” in 1 kg of solvent with molal elevation constant kb. The solute dimerises in the solution according to the following equation. The degree of association is α. 2A⇌A2 The von't Hoff factor will be |
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Answer» A dilute solution Contains “x” moles of solute “A” in 1 kg of solvent with molal elevation constant kb. The solute dimerises in the solution according to the following equation. The degree of association is α. |
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| 49. |
Anhydrous sodium acetate on heating with sodalime gives |
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Answer» Anhydrous sodium acetate on heating with sodalime gives |
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| 50. |
1 g of non-electrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40K. The freezing point depression constant of benzene is 5.12 K kg/mol. Find the molar mass of the solute. |
| Answer» 1 g of non-electrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40K. The freezing point depression constant of benzene is 5.12 K kg/mol. Find the molar mass of the solute. | |