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51.

Valence bond theory explains the overlapping of atomic orbitals.(a) True(b) FalseThe question was posed to me during an interview.The above asked question is from Valence Bond Theory topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (a) True

Easiest explanation: Valence bond theory was initially introduced by London and Heitler and was developed by PAULING and others. It’s a CHEMICAL bonding theory that EXPLAINS the OVERLAPPING the atomic ORBITALS in order to form chemical bonds between atoms.

52.

The angle between two bonds in a linear molecule is _______(a) 108°(b) 180°(c) 74.5°(d) 90°The question was asked in examination.Query is from Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right choice is (b) 180°

The best I can explain: A LINEAR molecule has a HYBRIDIZATION sp, in which the bonds between the central atom and other atoms are separated by 180°. For EXAMPLE, let’s TAKE carbon dioxide, it’s SHAPE is given by O=C=O.

53.

What is the energy that is released upon the formation of an ionic compound known as?(a) Ionization energy(b) Lattice energy(c) Electron gain enthalpy(d) ElectropositivityThe question was posed to me during an interview for a job.My question is based upon Ionic or Electrovalent Bond in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct ANSWER is (B) Lattice energy

Explanation: When the ions are COMBINED to form an ionic compound that is a crystalline solid, a certain amount of energy is released and this is KNOWN as the lattice energy. Solubility, VOLATILITY, and hardness can be predicted from lattice energy.

54.

Atoms obtain octet configuration when linked with other atoms. This is said by _________(a) Lewis(b) Kossel(c) Langmuir(d) SidgwickThis question was addressed to me in homework.The above asked question is from Kossel-Lewis Approach to Chemical Bonding topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct answer is (a) Lewis

For explanation I would say: The above statement says that the atoms achieve a stable octet configuration when joined with other atoms through chemical bonds as postulated by Lewis. An example of this is the formation of NaCl MOLECULE where Na and CL transfer ELECTRONS to each other forming Na^+ and Cl^–.

55.

Highly electropositive Alkali metals are separated from highly electronegative halogens by _________(a) noble gases(b) oxygen family(c) f-block elements(d) 7^th periodThis question was posed to me during an internship interview.My doubt is from Kossel-Lewis Approach to Chemical Bonding in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT answer is (a) noble GASES

To ELABORATE: According to Kossel, Highly electropositive Alkali metals are separated from highly electronegative HALOGENS by noble gases. This is because Alkali metals are the 1^st group and halogens the 17^th group. Elements in 18^th group i.e. nobles are preceded by group 17 elements and succeeded by group 1 elements.

56.

Resonance does stabilize the molecule.(a) False(b) TrueI had been asked this question during an interview for a job.My doubt stems from Bond Parameters topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right option is (B) True

To explain: Resonance STABILIZES the molecule as the resonance hybrid comprises of less energy than other CANONICAL STRUCTURES. Resonance is made of many structures that change frequently in molecules in order to maintain stability in the molecule.

57.

Find out the correct Lewis symbol for the atom carbon among the following options.(a) .C:(b) :C.(c) :C:(d) .C.I have been asked this question by my school teacher while I was bunking the class.My query is from Kossel-Lewis Approach to Chemical Bonding in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct answer is (c) :C:

Explanation: An American CHEMIST G.N. Lewis CREATED Lewis symbols as a notation to REPRESENT the valance electrons in an atom. As the carbon atom has 4 electrons in its outer shell, it is represented by 4 dots AROUND it.

58.

A __________ overlap doesn’t result in the formation of a bond.(a) positive(b) negative(c) zero(d) rationalI had been asked this question in an international level competition.My doubt is from Valence Bond Theory topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right answer is (c) zero

The explanation: Zero OVERLAP means that the ORBITALS don’t overlap at all. When there is no overlapping the bond FORMATION doesn’t OCCUR. As we all know that the EXTENT of overlapping is dependent on the strength of the bond.

59.

Which of the following molecules may have a dipole movement?(a) N2(b) CH4(c) BeF2(d) H2OThis question was posed to me in final exam.My question is based upon Bond Parameters topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct option is (d) H2O

To elaborate: The DIPOLE movement is given by the PRODUCT of charge and the distance of separation between atoms. It is EXPRESSED in Debye units (D). For the molecules N2, CH4 and BeF2 the net dipole movement is zero as they CANCEL each other due to symmetry. But water molecule due to its V-shape exhibits dipole movement.

60.

What is the bond order of CO?(a) 3(b) 2(c) 1(d) 4I got this question by my school principal while I was bunking the class.Asked question is from Bond Parameters topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct CHOICE is (a) 3

To ELABORATE: The number of bonds that are created between two atoms in a molecule is the bond ORDER of that bond. The molecule carbon monoxide CO has a triple bond between the carbon and oxygen, so it’s bond order is 3.

61.

What is the shape of water?(a) Triagonal(b) Triagonal bipyramidal(c) Bent(d) Square planarI got this question in homework.This interesting question is from Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct ANSWER is (c) Bent

The explanation is: The water molecule H-O-H has an arrangement of electrons in a tetrahedral. As it CONTAINS two bond pairs and lone pairs in the form of the molecule of TYPE AB3E2, it’s shape is bent i.e. neglecting the lone pairs.

62.

Ionization energy is always endothermic in nature.(a) False(b) TrueI had been asked this question during an online exam.My query is from Ionic or Electrovalent Bond topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT option is (b) True

For explanation: Ionization energy is the MINIMUM amount of energy that is required to remove an electron from a neutral ISOLATED gaseous atom. The symbolic representation is given by A(g) → A(g)^+ + e^–. It is always negative as it requires energy that is ENDOTHERMIC in NATURE.

63.

Which of the following molecule’s formation doesn’t include ionic bond?(a) LiCl(b) MgO(c) SnCl4(d) H2OThe question was posed to me in a job interview.I'd like to ask this question from Ionic or Electrovalent Bond topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct choice is (d) H2O

The best explanation: The molecules LiCl, MGO, and SnCl4 are formed by IONIC BONDS as they transfer electrons from an electropositive atom, that DONATES to the electronegative atom, that accepts. Whereas H2O has covalent bonds as it shares electrons.

64.

How many orbitals are included in sp^3d hybridization?(a) 5(b) 4(c) 3(d) 6This question was posed to me in an online interview.The origin of the question is Valence Shell Electron Pair Repulsion (VSEPR) Theory in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» RIGHT answer is (a) 5

For explanation I would say: The concept of mixing of atomic orbitals and formation of new hybridized atomic orbitals for the pairing of electrons through chemical BONDS. THEREFORE sp^3d hybridization included 5 orbitals namely 1 s-orbital, 3 p-orbitals, and 1 d-orbital.
65.

Electron gain enthalpy may be ________(a) exothermic(b) endothermic(c) both exothermic and endothermic(d) always zeroThis question was posed to me in an online interview.The origin of the question is Ionic or Electrovalent Bond topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct ANSWER is (c) both exothermic and endothermic

Easiest explanation: Electron GAIN enthalpy is the enthalpy change for an atom in the ground state to gain an electron. In the CASE of an exothermic REACTION, the VALUE of electron gain enthalpy is negative, which means that it is releasing energy and vice-versa when it’s positive.

66.

Which of the following doesn’t follow octet rule?(a) CH4(b) CCl4(c) HCl(d) NO2I have been asked this question in an online quiz.Query is from Kossel-Lewis Approach to Chemical Bonding in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT CHOICE is (d) NO2

The EXPLANATION is: Though octet rule is widely known, it does have a few limitations. The COMPOUND nitrogen dioxide NO2 doesn’t follow the octet rule. It’s a molecule with an odd number of electrons. Even the nitric oxide NO doesn’t follow.

67.

The bond enthalpy of H2O and OH are 502 KJ mol^-1 and 427 KKJ mol^-1. Then what is the average bond enthalpy?(a) 502 KJ mol^-1(b) 464.5 KJ mol^-1(c) 427 KJ mol^-1(d) 75 KJ mol^-1The question was posed to me in exam.Question is from Bond Parameters in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right answer is (b) 464.5 KJ mol^-1

The EXPLANATION is: We KNOW that H2O(G) → H(g) + OH(g); ΔH1 = 502 kJ mol^-1 and OH(g) → H(g) + O(g); ΔH2 = 427 kJ mol^-1. So the average bond ENTHALPY is given by their mean that is 427 + 502/2 = 464.5 KJ mol^-1. This method is used for polyatomic molecules like water.

68.

Ionic bonds easily form when electron when ionization energy of the metallic atom is _____ comparatively.(a) negative(b) constant(c) more(d) lessI had been asked this question in homework.This is a very interesting question from Ionic or Electrovalent Bond topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct answer is (d) less

To explain I WOULD say: The rate of formation of an ionic bond MAINLY depends on the tendency to become CATION and anion from their original ground states. The tendency is maximum for metallic atoms WHOSE ionization energy is less than the other atoms.

69.

Formation of a compound through ionic bond ______ the ionization energy of the metal ion.(a) does not depends on(b) depend on(c) is independent regarding(d) may or may not depend onThis question was posed to me in examination.Query is from Ionic or Electrovalent Bond in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» CORRECT option is (b) depend on

Easiest explanation: For the formation of the IONIC bond, the metal ion has to overcome to energy for the removal of an electron from its outer SHELL in order to become a cation, that is ionization energy. Therefore Formation of a COMPOUND through ionic bond depends on the ionization energy of the metal ion.
70.

Which of the following is not a homonuclear diatomic molecule?(a) H2(b) N2(c) O2(d) HClThis question was addressed to me in an interview.I want to ask this question from Valence Bond Theory topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT answer is (d) HCl

For EXPLANATION: The molecule that is FORMED from the same ELEMENT is known as a homonuclear molecule and the molecule that is made up of 2 atoms is CALLED a diatomic molecule. But HCl is not a homonuclear diatomic molecule as it has different atoms.

71.

The pi-bond involves __________(a) axial overlapping(b) side-wise overlapping(c) end to end type of overlapping(d) head-on overlappingThis question was posed to me in semester exam.Question is taken from Valence Bond Theory topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right OPTION is (B) side-wise overlapping

The best EXPLANATION: A pi-BOND is a TYPE of covalent bond in which the internuclear axes of the atoms are parallel to each other and for side-wise overlapping. The bond formed here is perpendicular to the internuclear axes.

72.

What’s the amount of lattice energy of NaCl?(a) 788 KJ mol^-1(b) 688 KJ mol^-1(c) 588 KJ mol^-1(d) 488 KJ mol^-1The question was asked by my college director while I was bunking the class.I need to ask this question from Ionic or Electrovalent Bond in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct answer is (a) 788 KJ mol^-1

To ELABORATE: NaCl’s lattice enthalpy is given by 788 KJ mol^-1. To disassociate one mole of NaCl into one mole of Na^+ and one mole of Cl^-1 into an infinite distance, we need 788 KJ mol^-1 of ENERGY. When the ions are combined to FORM an ionic compound that is a crystalline SOLID, a certain AMOUNT of energy is released and this is known as the lattice energy.

73.

A positive overlap is same as ________(a) out-phase overlap(b) negative overlap(c) zero overlap(d) in-phase overlapI had been asked this question in my homework.The above asked question is from Valence Bond Theory topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct option is (d) in-phase overlap

To explain I WOULD say: A positive overlap results in BOND formation. When 2 p-orbitals are in phase, both the positive lobes overlap, THUS CREATING a positive overlap and result in the bond formation, thus it is called in-phase overlap.

74.

Sharing or transfer of electrons from one atom to the other to attain stable octet configuration follows _______(a) Duet rule(b) Triplet rule(c) Octet rule(d) Septet ruleThis question was posed to me in an online interview.I'd like to ask this question from Kossel-Lewis Approach to Chemical Bonding topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct answer is (c) Octet rule

Best explanation: As per the electronic theory of chemical BOND that’s put forth by Lewis &KOSSEL states that the atoms follow the octet rule by sharing or transfer of electrons from ONE atom to the other to attain STABLE octet configuration.

75.

Ionic bond formation depends on the arrangement of __________(a) molecule(b) atom(c) lattice(d) kernalI had been asked this question in a job interview.I would like to ask this question from Ionic or Electrovalent Bond topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» RIGHT choice is (c) LATTICE

For explanation I would say: Lattice of the crystalline compound is the ARRANGEMENT of positive and the negative IONS INSIDE a substance. It is dependent on the ease of formation of ionic bonds as per Kossel and Lewis Ionic bond formation.
76.

What is the shape of the molecule NH3?(a) Square pyramidal(b) V-shape(c) Triagonal pyramidal(d) TetrahedralThe question was asked during an online interview.My question is taken from Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct choice is (c) TRIAGONAL PYRAMIDAL

For explanation I would say: The molecule NH3 has a LONE pair and 3 bond pairs. As we know that the repulsion order is as follows: Lone pair-Lone pair is greater than Lone pair-Bond pair is greater than Bond pair-Bond pair. So the shape of molecule NH3 is TRIGONAL pyramidal, where the lone pair is away from the 3 bond pairs.

77.

The shape of the molecule depends on the _______(a) adjacent atom(b) valence electrons(c) surroundings(d) atmosphereThis question was posed to me in an online interview.This question is from Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right answer is (b) valence electrons

Easy explanation: As the postulate of Valence SHELL Electron PAIR Repulsion Theory (VSEPR), the shape of the molecule depends on the number of valence shell electron PAIRS AROUND the atom (both BONDED and non-bonded).

78.

Strength of the bond between the two atoms can be known from bond dissociation enthalpy.(a) True(b) FalseThe question was asked during an interview.This interesting question is from Bond Parameters in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» RIGHT option is (a) True

Easy explanation: Yes, it’s true. The energy that is used to break a MOLECULE into ATOMS is bond dissociation enthalpy. The HIGHER the bond dissociation energy, the STRONGER the bond between the atoms. So the strength of the bond between the two atoms can be known from bond dissociation enthalpy.
79.

Which of the following cannot be used to measure bond lengths?(a) Spectroscopy(b) X-ray diffraction(c) Electron diffraction(d) Young’s Double-slit methodThe question was asked in quiz.I want to ask this question from Bond Parameters topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct option is (d) Young’s DOUBLE-slit method

For explanation: The equilibrium distance between the nuclei of two BONDED atoms in a molecule is known as bond length. It can be measured by spectroscopy, X-ray diffraction, and electron diffraction. Young’s double slit method is used for determining electromagnetic spectra.

80.

The enthalpy change that occurs when an atom in the ground state gains an electron, is electron gain enthalpy.(a) True(b) FalseI had been asked this question in semester exam.I'm obligated to ask this question of Ionic or Electrovalent Bond topic in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct choice is (a) True

Explanation: Yes. electron gain enthalpy is the enthalpy CHANGE for an atom in the ground state to gain an electron. An atom gains an electron, thus FORMING negatively CHARGED ion also KNOWN as a cation. Symbolic representation is as follows: A(g) + e^– → A(g)^–.

81.

What’s the group valance of atoms in the halogen family?(a) 2(b) 1(c) 9(d) 7The question was asked in an interview for job.This interesting question is from Kossel-Lewis Approach to Chemical Bonding in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The CORRECT option is (b) 1

Explanation: The group valance can be calculated from Lewis symbols either by subtracting it from eight (more than 4) or having it equal (less than 4). The halogen family has 7 ELECTRONS in their outer orbit. So 8 – 7 = 1. Therefore the valency of the halogen family is 1.

82.

What is the electronic configuration of carbon in it’s excited state?(a) 1s^22s^22p^4(b) 1s^22s^22p^3(c) 1s^22s^22p^5(d) 1s^22s^12p^4This question was posed to me by my school teacher while I was bunking the class.My question is from Valence Bond Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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The correct option is (b) 1s^22s^22p^3

To explain I WOULD say: The electronic configuration of carbon in its GROUND state is GIVEN by 1s^22s^22p^4. When it’s in an excited state, that is when it loses an ELECTRON, that would be from 2p-orbital. So the excited state’s electronic configuration is 1s^22s^22p^3.

83.

Which of the following is correct regarding repulsive interaction?(a) Lone pair-Lone pair is greater than Lone pair-Bond pair is greater than Bond pair-Bond pair(b) Lone pair-Lone pair is less than Lone pair-Bond pair is less than Bond pair-Bond pair(c) Lone pair-Bond pair is greater than Lone pair-Lone pair is greater than Bond pair-Bond pair(d) Lone pair-Lone pair is greater than Lone pair-Bond pair is less than Bond pair-Bond pairThis question was posed to me in homework.Query is from Valence Shell Electron Pair Repulsion (VSEPR) Theory in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right option is (a) Lone pair-Lone pair is greater than Lone pair-Bond pair is greater than Bond pair-Bond pair

Explanation: The repulsive interactions follow the above ORDER. The lone PAIRS are localized on the CENTRAL atom, each bonded pair is shared between TWO ATOMS. So, the lone pair electrons in a molecule occupy more space as compared to the bonding pairs of electrons.

84.

In the covalent bond, atoms share electrons to achieve octet configuration.(a) True(b) FalseI have been asked this question during an online exam.My doubt stems from Kossel-Lewis Approach to Chemical Bonding topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right ANSWER is (a) True

Easiest explanation: In the year 1919, Langmuir postulated the theory of covalent bond and its formation by combining with LEWIS theory. An example of this is the formation of Cl2, Two ATOMS of Cl combine by sharing the 7^th electron in its OUTER shell.

85.

A double bond is made up of __________(a) Two sigma bonds(b) Two pi bonds(c) One sigma and one pi bond(d) Two sigmas and one pi bondThis question was addressed to me in class test.This key question is from Valence Shell Electron Pair Repulsion (VSEPR) Theory in division Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer» CORRECT answer is (c) ONE sigma and one pi BOND

Easiest EXPLANATION: A DOUBLE bond is formed chemically between two atoms that involve the bonding of four electrons. A double bond is formed with one sigma and one pi bond. The formation of molecules like ethane, oxygen involve double bonds.
86.

A pi bond is stronger than a sigma bond.(a) True(b) FalseI had been asked this question in an interview for internship.This intriguing question comes from Valence Bond Theory topic in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

Correct ANSWER is (b) False

For EXPLANATION I would say: A sigma bond is always stronger than the pi bond. As we know that the bond STRENGTH is DECIDED by the extent of orbital’s OVERLAPPING. The extent of overlapping is more in sigma bond than in a pi-bond.

87.

The covalent radius in a chlorine molecule and van der Waal’s radius between chlorine molecules respectively can be ________ & _________(a) 99pm, 198pm(b) 198pm, 99pm(c) 198pm, 198pm(d) 99pm, 99mThe question was asked in homework.This key question is from Bond Parameters in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct choice is (a) 99pm, 198pm

Explanation: The half of the distance between TWO covalently bonded similar atoms in the same molecule is called covalent RADIUS, whereas the half of the distance between two similar atoms of DIFFERENT MOLECULES in a solid is KNOWN as van der Waal’s radius. Therefore covalent radius is smaller than the van der Waal’s radius.

88.

The bond angle between the hydrogen atoms is _________(a) 104.5°(b) 104°(c) 105.4°(d) 105°I have been asked this question in quiz.My question is from Bond Parameters in section Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Right ANSWER is (a) 104.5°

To explain: The water molecule is the V-shape, so the ANGLE between hydrogen through oxygen is GIVEN → by 104.5°. As we know the angle between TWO bonds from the same atom that is bonded to different atoms is called the bond angle.

89.

Calculate the formal charge of the middle atom in the ozone molecule.(a) 1(b) -1(c) 0(d) -2I have been asked this question by my school principal while I was bunking the class.Question is taken from Kossel-Lewis Approach to Chemical Bonding topic in portion Chemical Bonding and Molecular Structure of Chemistry – Class 11

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Correct answer is (a) 1

To explain I would say: The formula for FINDING out the formula charge of an in a molecule = TOTAL number of valence ELECTRONS – total number of non-BONDING electrons – 1/2 (total number of bonding electrons). So here, a formal charge of central O is 6 – 2 – 6/2 = 1.