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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
The use of diamond as a gem depends on itsA. HardnessB. High refractive indexC. Purest form of carbonD. Chemical inertness |
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Answer» Correct Answer - B |
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| 152. |
Which of the following is a non metallic conductorA. CsB. CokeC. DiamondD. Graphite |
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Answer» Correct Answer - D |
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| 153. |
Graphite is a good conductor of electricity due toA. Its giant tetrahedral polymer structureB. Its high refractive indexC. Presence of free and mobile electronsD. High IP value of carbon |
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Answer» Correct Answer - C |
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| 154. |
Which of the following is true for diamondA. It is a good conductor of electricityB. It is very softC. It is a bad conductor of heatD. Diamond is made up of carbon, hydrogen and oxygen atoms |
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Answer» Correct Answer - C |
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| 155. |
The glittering nature of diamond is due toA. Gaint polymer structureB. High refractive indexC. High IP value of carbonD. High electro negativity of carbon |
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Answer» Correct Answer - B |
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| 156. |
The metallic character of the element of IV A groupA. Decreases from top to bottomB. Has no significanceC. Does not changeD. Increase from top to bottom |
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Answer» Correct Answer - D |
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| 157. |
The most commonly used reducing agent isA. `SnCl_(4)`B. HFC. `SnCl_(2)`D. `Cl_(2)` |
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Answer» Correct Answer - C |
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| 158. |
The nature of chemical bonding in diamond isA. MetallicB. Coordinate covalentC. IonicD. covalent |
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Answer» Correct Answer - D |
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| 159. |
The most commonly used reducing agent isA. `AlCl_(3)`B. `PbCl_(2)`C. `SnCl_(4)`D. `SnCl_(2)` |
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Answer» Correct Answer - D |
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| 160. |
compound that combines with haemoglobin of blood to form carboxy haemoglobin of blood to form carboxy haemoglobin isA. `N_(2)O`B. `OF_(2)`C. `CO_(2)`D. CO |
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Answer» Correct Answer - D |
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| 161. |
Silicon has a strong tendency to form polymers like silicones, the chain length of silicone polymer can be cntrolled by addingA. `MeSiCl_(3)`B. `MeSiCl_(2)`C. `Me_(2)SiCl`D. `Me_(4)Si` |
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Answer» Correct Answer - C |
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| 162. |
The following compound `(CH_(3))_(n) Si (Cl)_(4 n)` on hydrolysis and on subsequent polymerisation gives a branched chain silicone. What is the value of n? |
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Answer» Correct Answer - 1 |
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| 163. |
How many units of `SiO_(4)^(4-)` will be required for the formation of pyrosilicates ? |
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Answer» Correct Answer - 2 |
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| 164. |
Identify B in the following `H_(4)SiO_(4) underset(-H_(2)O) overset(1000^(0)C)to A underset(?)overset("Carbon")toB+CO`A. CorundumB. QuartzC. SilicaD. Carborundum |
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Answer» Correct Answer - D |
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| 165. |
Graphitie `underset(("oxidation"))overset("Strongoxidsing agent")to X("acid")` `underset("Dehydration")(--overset(Delta)(-)rarr)Y,Y is:`A. `C_(3)O_(2)`B. COC. `CO_(2)`D. `C_(12)O_(9)` |
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Answer» Correct Answer - D |
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| 166. |
The dehydration of malonic acid `CH_(2) (COOH)_(2)` with `P_(4)O_(10)` and heat giveA. Carbon monoxideB. Carbon sub oxideC. Carbon dioxideD. all the above |
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Answer» Correct Answer - B |
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| 167. |
The value of refractive index of diamond isA. 1.45B. 2.45C. 3.4D. 1.54 |
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Answer» Correct Answer - B |
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| 168. |
The hardness of diamond is due toA. Giant polymer structureB. High refractive indexC. Hexagonal layer lattice structureD. High electronegativity of carbon |
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Answer» Correct Answer - A |
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| 169. |
Statement-I : Tin (IV) chloride is a solid with high melting point. Statement -II : Tin (IV) chloride is an ionic compound.A. Both Statement -I and Statement -II are true and Statement -II is the correct explanation of Statement-I.B. Both Statement -I and Statement -II are true and Statement-II is not the correct explanation of Statement-I.C. Statement-I is true and Statement-II is falseD. Statement-I is false but Statement -II is true |
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Answer» Correct Answer - A |
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| 170. |
The ionic chloride isA. `CCl_(4)`B. `SiCl_(4)`C. `PbCl_(4)`D. `PbCl_(2)` |
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Answer» Correct Answer - D |
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| 171. |
Hybridisation of silicon atom in silica isA. spB. `sp^(2)`C. `sp^(3)`D. `sp^(3)d` |
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Answer» Correct Answer - C |
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| 172. |
The structure of crystalline silica is similar to that ofA. DiamondB. GraphiteC. SilicatesD. Silicic acid |
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Answer» Correct Answer - A |
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| 173. |
Which is the crystalline form of silicaA. AgateB. JasparC. OnyxD. Crystobalite |
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Answer» Correct Answer - D |
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| 174. |
The hybrid orbitals with 33.33% S-character are involed in the bonding of one of the crystalline allotropes of carbon. The allotrope isA. Carbon blackB. GraphiteC. DiamondD. Gas carbon |
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Answer» Correct Answer - B |
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| 175. |
Which of the following is not an allotrope of carbonA. GraphiteB. DiamondC. CokeD. Carborundum |
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Answer» Correct Answer - D |
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| 176. |
In graphite adjacent layers are separated by a distance ofA. `3.35 A^(0)`B. `1.54 A^(0)`C. `1.42 A^(0)`D. `2.45 A^(0)` |
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Answer» Correct Answer - A |
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| 177. |
The following are some statements about graphite: I. `C - C` bond lengths is `1.42 A^(@)` II. Distance between two successive layers is `3.35 A^(@)` III. Bond angle is `60^(@)` The correct statements is/areA. all are correctB. only I and IIC. only IID. only III |
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Answer» Correct Answer - B |
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| 178. |
`C_(60)` (fullerene) has the shape of a soccer ball, consider the following statements : I. Fullerene is an allotrope of carbon II. Fullerence has 5 and 6 membered rings III. All carbons in fullerene are `sp^(2)` hybridised. Identify the correct statements :A. I onlyB. III onlyC. I, II and IIID. I and II only |
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Answer» Correct Answer - C |
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| 179. |
Consider following statements : I: In diamond, each carbon atom by `sp^(3)` bonds II : Graphite has planar hexagonal layers of carbon atoms held together by weak van der Walls forces III: Silicon exists only in diamond structure due to its tendency to from `p pi-p pi` bonds to itself. In this:A. Only I and II are correctB. Only I is correctC. Only II and III are correctD. All are correct statements |
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Answer» Correct Answer - A::B::C::D |
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| 180. |
Which of the following metals in an important ingredient of transistors ?A. OsmiumB. GermaniumC. GoldD. Sodium |
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Answer» Correct Answer - B |
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| 181. |
Incorrect statements about silicates ?A. Sorosilicate has `(Si_(2)O_(7))^(6-)` unitB. Spodumene is a silicate ore of lithium has `(Si_(2)O_(5))^(n)^(2n-)`C. Amphiboles contain OH groups bonded to silicate ionD. Three oxygen atoms of `SiO_(4)^(4-)` tetrahedral units are shared in cylic silcates. |
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Answer» Correct Answer - B::C::D |
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| 182. |
Choose the incorrect statement (s) from the followingA. the anhydride of carbonic acid is `C_(3)O_(2)`B. there are two sigma and one pi bond in `CaC_(2)` moleculeC. `SiC` is called carborundumD. Tri silylamine is pyramidal |
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Answer» Correct Answer - A::B::D |
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| 183. |
The following molecules are trapped in the formation of molecular sievesA. `H_(2)O, NH_(3) CO_(2)`B. `H_(2) O, NH_(3) CO_(2)`C. `H_(2) S, NH_(3) CO_(2)`D. `H_(2) O, NH_(4) OH, CO_(2)` |
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Answer» Correct Answer - A |
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| 184. |
Statement-I: The value of x of `(Si_(4)O_(12))^(x-)` is 8 Statement-II: In `[Si_(4)O_(12)]^(x-)` every `SiO_(4)` tetrahedra unit having 2 oxygen shared and 2 oxygen unshared.A. Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-IB. Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-IC. Statement-I is True, Statement-II is False.D. Statement-I is False, Statement-II is True. |
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Answer» Correct Answer - A |
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| 185. |
How many oxygen atoms are expected to be shared by each `SiO_(4)^(4-)` tetrahedra to form a cyclic silicate ion `Si_(3)O_(9)^(6-)` |
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Answer» Correct Answer - B |
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| 186. |
Chemically zeolites areA. Alumino silicateB. Calcium alumino silicateC. Hydrated sodium alumino silicateD. Silicones |
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Answer» Correct Answer - C |
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| 187. |
Zeolites are used as (a) Ion exchangers , (b) Molecular sieves (c ) Water softener The correct uses areA. a,b onlyB. b,c onlyC. a,c, onlyD. a,b,c |
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Answer» Correct Answer - D |
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| 188. |
Chemically zeolites areA. Aluminio silicateB. Calcium alumino silicateC. Hydrated sodium alumino silicateD. Alkyl silicates |
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Answer» Correct Answer - C |
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| 189. |
In the softening of water when zeolites are exercised the following metal ion is replaced by `Na^(+)`A. `Ca^(+2)`B. `Ba^(+2)`C. `Be^(+2)`D. `Zn^(+2)` |
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Answer» Correct Answer - A |
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| 190. |
The vast majority of silicates are insoluble in water, except alkali metal silicate. The extreme stability of silciates is due to the donation of extra electrons from O atoms into the vacant 3d-orbital of Si. The `SiO_(4)` tetrahedral units may occur singly or may share one, two , three of four O atoms through comers giving rise to cycle groups, chains infinite layers of infinite three dimensional frame work. Select incorrect option for `(Si_(4)O_(11))_(n)^(6n-)`A. It is the formula of double chain silicateB. It is the formula of double chain silicateC. It is non planar polymeric anionD. Each silicon is surrounded by 2.5 oxygen |
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Answer» Correct Answer - C |
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| 191. |
Consider the following silicates (a) `BaTi(Si_(2)O_(9))` (b) `ZnCa_(2)Si_(2)O_(7)` Then calculate X+Y, where X and Y are total number of monovalent and divalent oxygen atoms in both silicates respectively. |
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Answer» Correct Answer - 3 |
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| 192. |
The Si-O bonds in silicates are.A. Very strongB. WeakC. Very weakD. Moderate |
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Answer» Correct Answer - A |
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| 193. |
Zeolites act asA. Atomic sievesB. Molecular sieves,C. Ionic sievesD. Radical sieves |
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Answer» Correct Answer - B |
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| 194. |
The Semiconductor of the following isA. GraphiteB. SiliconC. Gas CarbonD. Lead |
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Answer» Correct Answer - B |
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| 195. |
Which is not a characteristic propery carbon ?A. CatenationB. Multiple bond formationC. Availability of d- orbitals for bondingD. Allotropy |
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Answer» Correct Answer - C |
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| 196. |
Bent, spA. Trigonal, `sp^(2)`B. Octahedral, `sp^(3) d^(2)`C. Tetrahedral, `sp^(3)`D. |
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Answer» Correct Answer - D |
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| 197. |
Assertion: `C_(3)O_(2)` has linear structure. Reason: Each carbon atom in `C_(3)O_(2)` in `sp` -hydridized.A. Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-IB. Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-IC. Statement-I is True, Statement-II is False.D. Statement-I is False, Statement-II is True. |
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Answer» Correct Answer - A |
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