Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)The above equation has an equilibrium co – InterviewSolution

1.	Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)The above equation has an equilibrium constant Keq=1025. What is the value of standard EMF for the reaction. (Given : 2.303RTF=0.0591 V)
Answer» $Z n (s) + 2 H^{+} (a q) \to Z n^{2 +} (a q) + H_{2} (g)$ The above equation has an equilibrium constant $K_{e q} = 10^{25}$ . What is the value of standard EMF for the reaction. (Given : $2.303 \frac{R T}{F} = 0.0591 V$ )

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