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`Zn` Amalgan is prepated by electrolysis of aqueous `ZnCl_(2)` using `Hg` catode `(9gm)`. Current is passed through `ZnCl_(2)` solution for `1000` seconds to prepare a `Zn` Amalam with `25%Zn` by wt. (`Zn=65.4)`A. Current off `8.85` amp is passed in the process.B. Current of `5.65` amp is passed in the processC. Mass of `Zn` in Amalgam is `3gm`D. Mass of `Zn` in Amalgam is `6gm`. |
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Answer» Correct Answer - A::C::D Let `x` gm of `Zn` deposit of `9gm` of `Hg` `%` of `Zn` in Amalgam`=(m_(Zn)xx100)/(m_(Zn)xxm_(Hg))=x/(9+x)xx100=25` `:.x=3gm` Eq. of `Zn=(3xx2)/(65.4)` `(n_(Zn))/1=(n_(e^(-)))/2=Q/(2f)=("it")/(2f)` Current `i=6/(65.4)xx96500/1000=8.85amp.` |
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