1.

Zero of x² + 2√3x - 60​

Answer»

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D = b^2 - 4ac

(2√3)^2 - 4 ( 1) (-60)

(4×3) + 240

12 + 240

252..

ZEROES = (-b^2 +_√b^2-4ac )/2A

(- (2√3)^2 +_√252 )/2×1

(-12 +_ √252)/2

zeroes :-

(- 12-√252)/2 and (-12+√252)/2

(-12-6√7)/2 and (-12+6√7)/2

-12 -3√7 and -12 +3 √7..


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