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Z AB is a line segment and P is its mid-point. D andE are points on the same side of AB such thatBAD = < ABE and EPA-L DPB(see Fig. 7.22). Show that(ii) AD BE |
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Answer» EPA = ∠ DPB (Given) ⇒ ∠ EPA + ∠DPE = ∠ DPB + ∠DPE ∴ ∠APD = ∠BPE Consider Δ’s DAP and EBP AP = BP (Given P is midpoint of AB) ∠BAD = ∠ABE (Given) ∠APD = ∠BPE (Proved) Hence ΔDAP ≅ ΔEBP (By ASA congruence rule) ⇒ AD = BE (CPCT) |
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