yThedomainoffunction f(x)fis

1.	yThedomainoffunction f(x)fis
Answer» Since there is a root so the inside root function should not be less than 0.. and the denominator should not be 0. so, \|x\| -2 ≠ 0 or x ≠ +2,-2 now lets take cases case)1 when \|x\| opens with +ve √(1-x)/(x-2) ≥ 0=> 1-x ≥ 0so x≤ 1 case)2 when \|x\| opens with -ve √(1+x)/-(x+2) ≥0 so, -(1+x) ≤0 or -1-x ≤0 so x≥ -1 then domain is x belongs to [-1,1]

Answer»

Since there is a root so the inside root function should not be less than 0.. and the denominator should not be 0.

so, |x| -2 ≠ 0 or x ≠ +2,-2

now lets take cases case)1 when |x| opens with +ve

√(1-x)/(x-2) ≥ 0=> 1-x ≥ 0so x≤ 1

case)2 when |x| opens with -ve √(1+x)/-(x+2) ≥0 so, -(1+x) ≤0 or -1-x ≤0 so x≥ -1

then domain is

x belongs to [-1,1]

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