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your answer wil2. A farmer moves along theboundary of a square field of side10 m in 40 s. What will be themagnitude of displacement of thefarmer at the end of 2 minutes 20seconds from his initial position?9:45 anl10:00 am10:15 am10:30 am10:45 am11:00 amfor |
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Answer» Total distance 40m in 40 sec.Total time taken by the farmer = 2 min 20 sec =140 sec Total rounds completed = 140/40 =3.5 rounds That means if the farmer starts from point A of the square field, he reaches point C. Therefore, displacement is AC. Assume ABC is a right angled triangle. Therefore, AC^2= AB^2 + BC^2 AC^2 = (10)^2 +(10)^2 AC^2 = 100+100 AC^2 = 200 AC = (200)^1/2 AC = 10×(2)½ |
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