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You measure two quantities as `A=1.0m+-0.2m`,`B=2.0m+-0.2m`. We should report correct value for `sqrt(AB)` asA. 1.4m`+-`0.4mB. 1.41`+-`0.15mC. 1.4m`+`0.3mD. 1.4m`+-`0.2m |
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Answer» Correct Answer - D Given, `A=1.0m+-0.2m`,`B=2.0+-0.2m` Let, `Y=sqrt(AB)=sqrt((1.0)(2.0)1.414m` Rounding off to two significant digit `Y=1.4m` (triangleY)/(Y)=(1)/(2)[(triangleA)/(A)+(triangleB)/(B)]` `=(1)/(2)[(0.2)/(1.0)+(0.2)/(2.0)]=(0.6)/(2xx2.0)` `impliestriangleY=(0.6Y)/(2xx2.0)=(0.6xx1.4)/(2xx2.0)=0.212` Rounding off to one significant digit `triangleY=0.2m` Thus, correct value for `sqrt(AB)=r+triangler=1.4+-0.2m` |
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