1.

you changes placed in vacuum experience force of 4*10-³ n if a dielectric medium of k=2 dielectric constant is placed in between them.calculate the new force​

Answer»

F= kq1q2/r²

F=2×q1q2/4π€€r

Force is INVERSELY PROPORTIONAL to dielectric constant of the medium

F1=F/2=2×10^-3

I HOPE this HELPS



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