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. .y591 9-2 50 9tan 62 рен0реж5 9 - 0059 |
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Answer» LHS =sin a -2sin ^3 a/ 2cos^3 a + cos a=sin a (1-2sin^2a)/ cos a ( 2cos2a+1)=sin a/cos a × 1-2sin2a/2cos2a+1=tan a × 2(1-sin2a)/2(1-sin2 a)+1=tana ×1/1=tan a=RHS |
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