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Y² = 4x, x² = 4y find angle between two curves |
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Answer» Step-by-step EXPLANATION: Y^2=4X, X^2=4Y 2YDY/DX=4 , 2X=4DY/DX dy/dx=2/y , dy/dx=x/2 x^2=4√4x x^2=8√x x=16√2, then y=√(4*16√2) y=16 dy/dx=2/16=1/8 ,dy/dx=8√2 tanФ=2/16+8√2/1-2/16*8√2 |
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