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y=x is tangent to the parabola `y=ax^(2)+c`. If c=2, then the point of contact isA. (3,3)B. (2,2)C. (6,6)D. (4,4) |
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Answer» Correct Answer - D (4) If c=2, then the point of contact is `(1//2a,1//4a+2)`. Since it lies on the line y=x, we have `(1)/(2a),(1)/(4a)+2` `i.e," "a=(1)/(8)` Therefore, the point of contact is (4,4) |
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