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(y square + 5y) (y square + 5y -2) -24 = 0 |
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Answer» USE the laplace transform to solve the following INTIAL value problem: y"-4y'+5y=0 y(0)=0, y'(0)=1 Using Y for the Laplace transform of y(t), i.e. Y=L{y(t)}, FIND the equation you get by TAKING the Laplace transform of the differential equation _________________________________=0 Now solve for Y(s)=_______________________________ By completing the square in the denominator and inverting the transform, find y(t)=___________________________________ VIEW comments (1) Best answer100%(1 rating) This problem has been solved! |
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