y=m_{1} x+c_{1}, y=m_{2} x+c_{2} \text { and } x=0 \text { is } \frac{ – InterviewSolution

1.	y=m_{1} x+c_{1}, y=m_{2} x+c_{2} \text { and } x=0 \text { is } \frac{\left(c_{1}-c_{2}\right)^{2}}{2\left\|m_{1}-m_{2}\right\|}
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