y = e ^ { 2 \operatorname { log } x + 3 x } , x > 0 , \text { prove th – InterviewSolution

1.	y = e ^ { 2 \operatorname { log } x + 3 x } , x > 0 , \text { prove that } \frac { d y } { d x } = x e ^ { 3 x } ( 2 + 3 x )
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