y ale seated in a lineample 4 : Find a relation between r and v such t

1.	y ale seated in a lineample 4 : Find a relation between r and v such that the point (x , y) is equidistantfrom the points (7, 1) and (3, 5).Solution : Let P(.he couid
Answer» ✔Let the Points be => => A ( x , y ) => B ( 7 , 1 ) => C ( 3, 5 ) ♦According to the given question -> => AB = AC ◾Applying Distance Formula , => √ ( x2 - x1 )² + ( y2 - y1 )² ♦Distance AB => => √ ( 7 - x )² + ( 1 - y )² => √ 49 + x² - 14x + 1 + y² - 2y => √ x² + y² + 50 - 14x - 2y .....................(1) ♦Distance AC => => √ ( x - 3)² + ( y - 5 )² => √ x² + 9 - 6x + y² + 25 - 10y => √ x² + y² + 36 - 6x - 10 y.....................(2) ◾Putting (1 ) and (2 ) Equal & Squaring both Sides , => x² + y² + 36 - 6x - 10y = x² + y² + 50 - 14x -2y => -8x + 8y + 16 = 0 => -8 ( x - y -2 ) = 0 => x - y = 2 => x = y + 2 Like my answer if you find it useful!

y ale seated in a lineample 4 : Find a relation between r and v such that the point (x , y) is equidistantfrom the points (7, 1) and (3, 5).Solution : Let P(.he couid

Answer»

✔Let the Points be =>

=> A ( x , y )

=> B ( 7 , 1 )

=> C ( 3, 5 )

♦According to the given question ->

=> AB = AC

◾Applying Distance Formula ,

=> √ ( x2 - x1 )² + ( y2 - y1 )²

♦Distance AB =>

=> √ ( 7 - x )² + ( 1 - y )²

=> √ 49 + x² - 14x + 1 + y² - 2y

=> √ x² + y² + 50 - 14x - 2y .....................(1)

♦Distance AC =>

=> √ ( x - 3)² + ( y - 5 )²

=> √ x² + 9 - 6x + y² + 25 - 10y

=> √ x² + y² + 36 - 6x - 10 y.....................(2)

◾Putting (1 ) and (2 ) Equal & Squaring both Sides ,

=> x² + y² + 36 - 6x - 10y = x² + y² + 50 - 14x -2y

=> -8x + 8y + 16 = 0

=> -8 ( x - y -2 ) = 0

=> x - y = 2

=> x = y + 2

Like my answer if you find it useful!