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(xxi) x2-(J3-2)x+2J3-=0 |
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Answer» x² - (√3 + 2)x + 2√3 = 0 x² - √3x - 2x + 2√3 = 0 x ( x - √3) - 2 ( x - √3) = 0 ( x - 2) ( x -√3) = 0 So, x = 2 and √3 |
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