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`XeF_(6)` (s) can be prepared by:A. Xe:`F_(2)` in 1:20 mole ratio and high pressure (60-70 bar) and temperature 573 KB. `Xe:F_(2)` in 1:5 mole ratio and pressure (7 bar) and temperature 873 KC. From product of (b), followed by an interaction with `O_(2)F_(2)` at 143 KD. Taking Xe in excess at atmospheric pressure (1 bar ) and temperature (673 K) |
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Answer» Correct Answer - A::C `Xe(g)+F_(2)(g) overset(673K,1 " bar") rarr XeF_(2)(s)` (xenon in excess) `Xe(g)+2Fe_(2)(g) overset(873K,1 " bar ")rarr XeF_(4)(s)` (1:5 ratio) ` Xe(g)+3F_(2)(g) overset(573K,60-70" bar") rarr XeF_(6)(s)` (1:20 ratio) `XeF_(4)+O_(2)F_(2) rarr XeF_(6)+O_(2)` |
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