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X4 + x3 - 9x2 - 3x + 9 find the roots if two roots are √3 and -√3 |
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Answer» zero/s = - root 3 and root 3 x - root3 = 0 x + root3 = 0 (x - root3)^2 (x + root3)^2 (x)^2 - 3 x^4 + x^3 - 9x^2 - 3x + 9 / x^2 = x^2 + x - 3 for other zeros:- x^2 + x - 3 = 0 a = 1, b= 1, c= -3 D = b^2 - 4ac D = (1)^2 - 4 x 1 x -3 D = 13 1st root = -b + rootD/2a = -1 + root13/2 2nd root = -b - rootD/2a = -1 - root13/2 roots = -1 + root13/2 & -1 - root13/2 may it helps you plz mark as brainliest |
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