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∫x31+x2dx=a1+x232+b1+x2+C, then(a) a=13, b=1(b) a=-13, b=1(c) a=-13, b=-1(d) a=13, b=-1

Answer» x31+x2dx=a1+x232+b1+x2+C, then



(a) a=13, b=1(b) a=-13, b=1(c) a=-13, b=-1(d) a=13, b=-1


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