1.

.x2d²y- 8xdy+ 8y = log xdx?dx​

Answer»

′′ = D(D – 1) (D – 2)y where D = d/dt HENCE, the GIVEN d.e. BECOMES READ more on Sarthaks.com - HTTPS://www.sarthaks.com/365842/solve-x-3d-3y-dx-3-3x-2d-2y-dx-2-xdy-dx-8y-65cos-logx?show=365847#a365847



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