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x2 + y2 + 4x + 6y – 7 = 0, 4(x2 + y2) + 8x + 12y – 9 = 0 find the equation of the radical axis of the circles. |
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Answer» S – S' = 0 is radical axis. (x2 + y2 + 4x + 6y – 7) – (x2 + y2 + 2x + 3y - (9/4)) = 0 2x + 3y – (19/4) = 0 ⇒ 8x + 12y – 19 = 0 |
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