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x2 + y2 – 4x – 6y – 12 = 0, x2 + y2 + 6x + 18y + 26 = 0 find the relative position of the pair of circles. |
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Answer» Centres of the circles are A (2,3), B(–3, – 9) radii are r1 = √(4 + 9 +12) = 5 r2 = √(9 + 81− 26) = 8 AB = √((2+ 3)2 + (3+ 9)2) = √(25+144) = 13 = r1 + r2 ∴ The circle touch externally. |
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