[x²,y²]-3[X,2y]=[-2,9]

1.	[x²,y²]-3[X,2y]=[-2,9]
Answer» Answer: X/Y = 3/2 So X = 3Y/2 (X^2 + Y^2)/(X^2 - Y^2) Now replace the X VALUE from first equation = [ (3Y/2)^2 + Y^2] / [ ((3Y/2)^2 - Y^2] = [ (9Y^2/4) + Y^2] / [ (9Y^2/4) - Y^2] = [ (9Y^2 + 4Y^2)/4] / [ (9Y^2 - 4Y^2)/4] = (9Y^2 + 4Y^2) / (9Y^2 - 4Y^2) = 13Y^2 / 5Y^2 = 13/5 Step-by-step explanation: please mark it brainliest answer and please don't HESITATE to give me a THANKS for this answer and please follow me also

Answer»

Answer:

X/Y = 3/2 So X = 3Y/2

(X^2 + Y^2)/(X^2 - Y^2)

Now replace the X VALUE from first equation

= [ (3Y/2)^2 + Y^2] / [ ((3Y/2)^2 - Y^2]

= [ (9Y^2/4) + Y^2] / [ (9Y^2/4) - Y^2]

= [ (9Y^2 + 4Y^2)/4] / [ (9Y^2 - 4Y^2)/4]

= (9Y^2 + 4Y^2) / (9Y^2 - 4Y^2)

= 13Y^2 / 5Y^2

= 13/5

Step-by-step explanation:

please mark it brainliest answer and please don't HESITATE to give me a THANKS for this answer and please follow me also

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[x²,y²]-3[X,2y]=[-2,9]

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